One of the legs of a right triangle measures 16 cm and the other leg measures 8 cm. Find the measure of the hypotenuse. If necessary, round to the nearest tenth.

Answer:

[tex]d=\sqrt{53}[/tex]

Step-by-step explanation:

We need to find the distance between two points i.e. (−5,−1) and (−3,−8).

It can be calculated using distance formula as follows :

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

We have, x₁ = -5, x₂ = -3, y₁ = -1 and y₂ = -8

Put all the values,

[tex]d=\sqrt{(-8-(-1))^2+(-3-(-5))^2}\\\\d=\sqrt{49+4}\\\\d=\sqrt{53}[/tex]

So, the distance between the points is equal to [tex]\sqrt{53}[/tex]

Step-by-step explanation:

Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points in simplest radical form(-3,5) and (-5,-2)

Answer:

area of the rectangle

(3X²+5)(2X-3)

=3X²(2X-3)+5(2X-3)

=6X³-9X²+10X-15

Answer:

1 to 10 = Pointer Finger

1 to 100 = Ring Finger

1 to 1000 = Ring Finger

Step-by-step explanation:

Every time she counts 10 on her fingers starting from 1 it either lands on her Index Finger or Ring Finger in a pattern of starting first on her index finger for 10 then ending up on her Ring Finger for 20 and 30 the going back to her Index finger for 40 and 50 and so on. Using this you can figure out 100 and 1000.

If the girl counts from 1 to 100, then finger stops at ring finger.

In mathematics, a pattern is a recurrent arrangement of numbers, forms, colours, and other elements. Any event or object can be related to the Pattern. An arrangement of numbers is referred to as a pattern when it is done in a certain way. Sometimes a pattern is referred to as a series.

Given that, a little girl starts by calling her thumb 1, the pointer finger 2, middle finger 3, ring finger 4, and pinky finger 5.

One complete round is 8 count.

1) The girl counts from 1 to 10

So, 10/8 here, 2 is remainder.

2 means she stops at pointer finger

2) The girl counts from 1 to 100

Here, 100/8

Thus, quotient = 12 and remainder = 4

So, 4 means she stops at ring finger

2) The girl counts from 1 to 1000

Here, 1000/8

Thus, quotient = 125 and remainder = 0

So, 0 means she stops at thumb

Therefore, if the girl counts from 1 to 100, then finger stops at ring finger.

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Step-by-step explanation:

the surface area is my head times my leg which is basically my eyes

Answer:

(E) 9

Step-by-step explanation:

[tex]\frac{(3^{2008})^2-(3^{2006})^2}{(3^{2007})^2-(3^{2005})^2} = \\\frac{(3^{2007+1})^2-(3^{2007-1})^2}{(3^{2007})^2-(3^{2007-2})^2} = \\\frac{(3^{2007})^2(3^{2}-3^{-2} )}{(3^{2007})^2(1-3^{-4} )} =\\\frac{9-\frac{1}{9} }{1-\frac{1}{81} }=\\\frac{80}{9}:\frac{80}{81} = \\\frac{80}{9}*\frac{81}{80} = \frac{81}{9} = 9[/tex]

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

This is considered quadrant II

Answer:

Step-by-step explanation:

If you have a square of side [tex]l[/tex], its diagonal would be [tex]l\sqrt{2}[/tex], and its area [tex]l^2[/tex]

If the big square has a area of 900, this implies that its side is [tex]\sqrt{900}[/tex], so the two diagonal of squares 2 and 4 added together would be [tex]\sqrt{900}[/tex], therefore one diagonal wold be [tex]\frac{\sqrt{900}}{2}[/tex]. and its side [tex]\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}[/tex]. The area (of one square) is [tex](\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}[/tex]

finally the two areas combined (squares 2 and 4) would be 225

Answer:

425

Step-by-step explanation:

I used help from the guy above me to find 2 and 4 so look at theirs for those. (Thank You). For 1 and 3. Each one is 1/9 of the big square. So each one is 1/9*900=100 100*2=200. And then we add 225+200=425.

Hope this helps :)

Answer

coochie man

Step-by-step explanation:

Answer:

Tan B = 15 / 8

Step-by-step explanation:

Giveb the triangle :

The hypotenus :

Using Pythagoras rule :

Hypotenus² = 15² + 8²

Hypotenus² = 225 + 64

Hypotenus = 17

Tan B:

Using the trigonometric relation :

Tan B = opposite / Adjacent

Tan B = 15 / 8

Answer:

6 inches

Step-by-step explanation:

460 ÷ 6 = 76.666666.

512 ÷ 76.666666 = 6.672

6.672 rounded to a whole number is 6.

Note:

Pls notify me if my answer is incorrect for the other users that will see this message.

-kiniwih426

Answer:6

Step-by-step explanation:

Answer:

B and C

Step-by-step explanation:

Required

Select graphs that are dilated by a scale factor greater than 1

For graph A:

Graph A is smaller than the original graph. This indicates dilation with a scale factor less than 1

For graph B:

Graph B is bigger than the original graph and is dilated over (0,0). This indicates dilation with a scale factor greater than 1

For graph C:

Graph C is bigger than the original graph; however, it is not dilated over (0,0). This indicates dilation with a scale factor greater than 1

For graph D:

Graph D is bigger than the original graph; however, it is not only dilated but also flipped over (i.e. rotated).

Hence, b and c is true

Answer:

y = -2x + 20

Step-by-step explanation:

Use the linear equation, y = mx + b, where m is the slope and b is the y intercept.

In this situation, the y intercept is 20, since the starting amount of gasoline is 20 gallons.

The slope will be -2, since 2 gallons are drained per minute.

Plug in these values:

y = mx + b

y = -2x + 20

So, the linear equation is y = -2x + 20

Answer:

3.99kg

Step-by-step explanation:

you can find it by 4kg minus 1 g that stills counts as rounding

Answer:

[tex](x - 6)^2 + (y - 2)^2 = 4[/tex]

Step-by-step explanation:

Required

The equation of the circle

The equation of a circle is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where:

[tex]Center = (h,k)[/tex]

[tex]radius \to r[/tex]

From the graph, we have

[tex](h,k) = (6,2)[/tex]

[tex]r = 2[/tex]

So:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex] becomes

[tex](x - 6)^2 + (y - 2)^2 = 2^2[/tex]

[tex](x - 6)^2 + (y - 2)^2 = 4[/tex]

Answer:

46305

Step-by-step explanation:

Answer:

x = 7 , -1

Step-by-step explanation:

SOLUTION :-

[tex]4(x-3)^2-11 = 53[/tex]

[tex]=> 4(x-3)^2-11+11=53+11[/tex]

[tex]=> 4(x-3)^2 = 64[/tex]

[tex]=> \frac{4(x-3)^2}{4} = \frac{64}{4}[/tex]

[tex]=> (x-3)^2 = 16[/tex]

[tex]=> \sqrt{(x-3)^2} = \sqrt{16}[/tex]

[tex]=> x-3 = +4 \; or -4[/tex]

Here , x will have two values -

1) [tex]x-3 = 4[/tex]

[tex]=> x = 4 + 3 = 7[/tex]

2) [tex]x - 3 = -4[/tex]

[tex]=> x = -4 + 3 = -1[/tex]

VERIFICATION :-

When x = 7 ,

[tex]4(x-3)^2 - 11 = 4(7 - 3)^2 - 11[/tex]

                       [tex]= 4 \times 4^2 - 11[/tex]

                       [tex]= 4 \times 16 - 11[/tex]

                       [tex]= 64 - 11[/tex]

                       [tex]= 53[/tex]

When x = -1 ,

[tex]4(x-3)^2 - 11 = 4(-1 - 3)^2 - 11[/tex]

                       [tex]= 4 \times (-4)^2 - 11[/tex]

                       [tex]= 4 \times 16 - 11[/tex]

                       [tex]= 64 - 11[/tex]

                       [tex]= 53[/tex]

Answer:

y = -2

Step-by-step explanation:

_____________________

Answer:

-3/4

Step-by-step explanation:

Have a nice day

Answer:

118.8 cubic inches

Step-by-step explanation:

volume of a cone is

[tex]vol \: = \frac{1}{3} \times \pi \times \frac{ {d}^{2} }{4} \times h[/tex]

where d is base diameter and

h is cone height.

hence

[tex]vol \: = \frac{1}{3} \times \pi \times \frac{ {5.5}^{2} }{4} \times 15 \\ = \pi \times \frac{30.25}{4} \times 5 \\ = 118.8 \: cu \: in[/tex]

The volume of the cone-shaped mold is 118.73 in³

Volume is the measure of the capacity that an object holds. For example, if a cup can hold 100 ml of water up to the brim, its volume is said to be 100 ml.

Given that a cone shaped mold is filled with the cake batter, the height of the mold is 15 inches, and the base diameter is 5.5,

We need to find the volume of the mold,

Volume of the cone = π × radius² × height / 3

= 3.14 × 2.75² × 15 / 3

= 118.73

Hence, the volume of the cone-shaped mold is 118.73 in³

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midpoint= (x, y)

where x=(x1 + x2)/2

y=(y1 + y2)/2

x1=-3, x2=6, y1=5, y2=-11

so x=(-3 + 6)/2= 3/2

y=(5 + -11)/2= (5-11)/2= -6/2= -3

so mid point =(3/2, -3)

hope this helps

Answer:

1/16 ;4 ; 16

Step-by-step explanation:

Given that :

f(x) = 1/4^-x

f(-2) = 1/4^-(-2)

f(-2) = (1/4)^2

f(-2) = (1/16)

f(1) = 1/4^-1

f(1) = 1 / (1/4)^1

f(1) = 1 * 4/1 = 4

f(2) = 1/4^-2

f(1) = 1 / (1/4)^2

f(1) = 1 / (1/16)

f(1) = 1 * 16/1 = 16

Answer:

( x - (-1) )^2 + ( y - (-1) )^2 = 3^2

Step-by-step explanation:

The equation of a circle is ( x - h )^2 + ( y - k )^2 = r^2, r is the radius.

(h,k) is the coordinates for the center point.

In this image, it appears K is 3 units away from any point on the circle, making 3 the radius.

Our equation is now ( x - h )^2 + ( y - k )^2 = 3^2

Now, we need to find the coordinate of K; the center point.

K's x is -1 and K's y is also -1.

Our equation is now:

( x - (-1) )^2 + ( y - (-1) )^2 = 3^2

Answer:

B. binomcdf(100, 0.5, 35)

Step-by-step explanation:

Binomcdf function:

The binomcdf function has the following syntax:

binomcdf(n,p,a)

In which n is the number of trials, p is the probability of a success in a trial and a is the number of sucesses.

35 or fewer heads come up when flipping a coin 100 times.

100 coins are flipped, which means that n = 100.

Equally as likely to be heads or tails, so p = 0.5

35 or fewer heads, so a = 35.

Then

binomcdf(n,p,a) = binomcdf(100,0.5,35)

The correct answer is given by option B.

Answer:

A

Step-by-step explanation:

More than $0 but less than $2800

The correct option is (A).

Data is referred to as a collection of information gathered by observations, measurements, research, or analysis. It may comprise facts, figures, numbers, names, or even general descriptions of things. Data can be organized in the form of graphs, charts, or tables for ease in our study. Data scientists help in analyzing the collected data through data mining.

Given:

Deandra traded $2800 for Swiss francs.

So, she would have More than $0 but less than $2800.

This is because she will not get the same amount back she has only has more than 0 and less than 2800.

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Answer:

d. static

Step-by-step explanation:

This is a question about Java programming.

A class contains information about it's members(objects). Private, public or inline variables must be related to an object, that is, an object has to be created before the variable is acessed.

Static variables, otherwise, may pertain to the class, and not to the object, that is, and thus, the correct answer is given by option d.