One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other words, they stick together after the collision and move off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 25 m/s. The masses of the two objects are 3.0 and 8.0 kg. Determine the final speed of the two-object system after the collision for the case when the large-mass object is the one moving initially and the case when the small-mass object is the one moving initially.

Answer:

[tex]\vec{A} + \vec{B} = \vec{A} - \vec{B}[/tex] if and only if [tex]\vec{B}[/tex] is a zero vector.

Explanation:

An equation is true if and only if adding the same value to both sides of the equation (the value needs to be compatible) gives an equation that is also true.

Start with the [tex]\vec{A} + \vec{B} = \vec{A} - \vec{B}[/tex].

This equation is true if and only if [tex]\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}[/tex] ([tex]\vec{B}[/tex] is added to both sides of the original equation.)

Vector addition and subtraction are associative. Therefore, [tex]\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}[/tex] if and only if [tex]\vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right)[/tex], which is equivalent to [tex]\vec{A} + 2\, \vec{B} = \vec{A}[/tex].

[tex]\vec{A} + 2\, \vec{B} = \vec{A}[/tex] if and only if [tex]\left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A}[/tex] ([tex]\left(-\vec{A}\right)[/tex]is added to both sides of this equation,) which is equivalent to [tex]2\, \vec{B} = \vec{0}[/tex].

[tex]2\, \vec{B} = \vec{0}[/tex] if and only [tex]\displaystyle \frac{1}{2} \cdot \left(2\, \vec{B}\right) = \frac{1}{2} \cdot \vec{0}[/tex], which is equivalent to [tex]\vec{B} = \vec{0}[/tex]. That is: [tex]\vec{B}[/tex] is the zero vector.

In other words:

[tex]\begin{aligned}& \vec{A} + \vec{B} = \vec{A} - \vec{B}\\ &\iff \left( \vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B} \\ &\iff \vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right) \\ & \iff \vec{A} + 2\, \vec{B} = \vec{A} \\ & \iff \left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A} \\ &\iff 2\, \vec{B} = \vec{0} \\ &\iff \frac{1}{2} \cdot 2\,\vec{B} = \frac{1}{2} \cdot \vec{0} \\ &\iff \vec{B} = \vec{0}\end{aligned}[/tex].

Hence, [tex]\vec{A} + \vec{B} = \vec{A} - \vec{B}[/tex] if and only if [tex]\vec{B}[/tex] is the zero vector.

The question is incomplete, the complete question is;

Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles traveled in a straight line and some were deflected at different angles. Which statement best describes what Rutherford concluded from the motion of the particles? Some particles traveled through empty spaces between atoms and some particles were deflected by electrons. Some particles traveled through empty parts of the atom and some particles were deflected by electrons. Some particles traveled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms. Some particles traveled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.

Answer:

Some particles traveled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.

Explanation:

Rutherford first proposed the nuclear model of the atom after his landmark experiment.

In this experiment, alpha particles from a source was focused on a thin gold foil. Some of the particles passed through empty spaces within the atom but were deflected at different angles by a small area of high-density positive charge within an atom which Rutherford later called the atomic nucleus.

Hence the answer above.

Answer:

A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.

Explanation:

Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.

Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.

The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.

Hope this helps     :)

(I didn't know which type of bear so i did brown bear and grizzly bear)

Answer:

24.3 m/s

Explanation:

1 kmh = 0.27 m/s, that makes a conversion ratio of 0.27/1kmh

[tex]\frac{90 kmh}{1}[/tex] x [tex]\frac{0.27 m/s}{1 kmh}[/tex]

The "kmh" n the top and bottom cancel out. And  then you just multiply the top 90 x 0.27 and the bottom 1 x 1 to get

[tex]\frac{24.3 m/s}{1}[/tex]

and since its over 1 its just 24.3 m/s

Answer:

Assuming no air friction,

the time it takes to fall 10 m = t = √2h/g = √(20/9.8) = 1.43 s

horizontal distance = 5 m

horizontal speed = distance/time = 5/1.43 = 3.5 m/s  ANS

Explanation:

i hope this helps!

Answer:

what do I answer? not enough information

Ionisation: the loss or gain of an electron

It is dangerous because cells that have been ionised can either die, or can mutate incorrectly, which might cause cancer.

Answer:

Pyrometer, device for measuring relatively high temperatures, such as are encountered in furnaces. Most pyrometers work by measuring radiation from the body whose temperature is to be measured. Radiation devices have the advantage of not having to touch the material being measured.

Explanation:

Answer: The planets that have the closest average temperature is

1.) Mercury which is 800 degrees Fahrenheit

2.) Venus which is about 880 degrees Fahrenheit

Hope this helps :)

The planets Mercury and Venus has the closest average temperature

A planet is an astronomical object that orbits a star or stellar remnant that is large enough to be rounded by gravity, but not so large as to trigger thermonuclear fusion, and that is free of planetesimals in its locality

Planets are generally divided into two main types: large, low-density gas giants and smaller, rocky terrestrials.

In order of increasing distance from the Sun, they are the four terrestrials, Mercury, Venus, Earth, and Mars, then the four gas giants, Jupiter, Saturn, Uranus, and Neptune

Given data ,

Let the first planet be represented as A

Let the second planet be represented as B

Now , the planets A and B have similar average temperature

where , the planets can have negative as well has very high temperatures

Now , when A = Mercury and B = Venus

Venus has 864 degrees Fahrenheit (462 degrees Celsius)

And , Mercury has 800 degrees Fahrenheit (430 degrees Celsius)

So , both Venus and Mercury has similar temperatures

Now , when A = Neptune and B = Uranus

Neptune has minus 353 degrees Fahrenheit (minus 214 degrees Celsius)

Uranus has minus 374 degrees Fahrenheit (minus 224 degrees Celsius)

So , both Neptune and Uranus has similar temperatures

Hence , the planets are Venus and Mercury

To learn more about planets click :

https://brainly.com/question/29765555

#SPJ6

okay this is kinda easy

What is the gravitational field strength on the moon?

The Moon has a gravitational field strength of 1.6 N/kg.

Answer:

Mass, M = 4 kilograms.

Explanation:

Given the following data;

Kinetic energy = 50 J

Velocity = 5 m/s

To find the mass of the object;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Making mass the subject formula;

[tex] M = \frac{2K.E}{V^{2}}[/tex]

Substituting into the equation, we have;

[tex] M = \frac{2*50}{5^{2}}[/tex]

[tex] M = \frac{100}{25}[/tex]

Mass, M = 4 kg

Answer:

3 amps

Explanation:

V = IR

I = [tex]\frac{V}{R}[/tex]

I =[tex]\frac{3}{1}[/tex]

I = 3 amps

Answer:

the energy required for the extension is 12.25 J

Explanation:

Given;

force constant of trampoline spring, k = 800 N/m

extension of trampoline spring, x = 17.5 cm = 0.175 m

The energy required for the extension is calculated as;

E = ¹/₂kx²

E = 0.5 x 800 x 0.175²

E = 12.25 J

Therefore, the energy required for the extension is 12.25 J

Answer:

counter clockwise

Explanation:

The observer in the Northern Hemisphere will notice that the stars near the NCP to move counter-clockwise

Counter - clockwise : The observer will observe this because the earth movement when viewed from the North pole is in a counterclockwise direction, hence the stars will appear to move in an ant-clockwise direction

Answer: 0.0328 A

Explanation:

Given

No of turns [tex]N=920[/tex]

Length of solenoid [tex]L=0.380\ m[/tex]

Magnetic field [tex]B=10^{-4}\ T[/tex]

the magnetic field at the center of the solenoid is

[tex]\Rightarrow B=\mu nI=\mu \dfrac{N}{L}I[/tex]

Putting values we get

[tex]\Rightarrow 10^{-4}=4\pi \times 10^{-7}\times \dfrac{920}{0.380}\times I\\\\\Rightarrow I=\dfrac{0.380\times 1000}{920\times 4\pi}=0.0328\ A[/tex]

Answer:

B

Explanation:

basically, because the ball "weighs" more now, it will hit the ground quicker. so technically gravity is more affective towards it. the piece of paper kind of floats it's way down. gravity isn't pushing on one force more, but because because the ball weighs more, it technically would be said so. hope this helps!

Answer:

the ball of paper, because it has less surface area.

Explanation:

Answer:

Option D. 5.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistance 1 (R₁) = 10 Ω

Resistance 2 (R₂) = 20 Ω

Resistance 3 (R₃) = 30 Ω

Voltage (V) = 120 V

Equivalent resistance (R) =?

The equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/20 + 1/30

Find the least common multiple (lcm) of 10, 20 and 30. The result is 60

Divide 60 by each of the denominators and multiply by their numerators respectively. We have:

1/R = (6 + 3 + 2)/60

1/R = 11/60

Invert

R = 60/11

R = 5.45 Ω

Thus, the equivalent resistance in the circuit is 5.45 Ω

Answer:

I belive it would be the first answer choice.

Explanation:

When the Mass is lower, the ball moves faster so it would have more kintetic energy

Answer:

Absorption

Explanation:

Answer:

option A 4kg is your answer

Explanation:

given

mass(m)=?

velocity (v)=5m/s

we have

kinetic energy =50J

1/2 ×{m×v²)=50

m×5²=50×2

m=100/25=4 kg

Answer: The color is orange, the state of matter is liquid

Explanation:

Answer:

Ideal independent sources can be batteries, DC generators or time-varying AC voltage supplies from alternators.

current dependable

Explanation:

Answer:

The right solution is "61.557 MJ". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 306 N

Drive,

D = 125 miles,

i.e.,

  = 201168

meters

As we know,

The work done will be:

= [tex]F\times S[/tex]

On substituting the given values, we get

= [tex]306\times 201168[/tex]

= [tex]61557408 \ J[/tex]

On converting it in "MJ", we get

= [tex]61.557\times 10^6 \ J[/tex]

= [tex]61.557 \ MJ[/tex]

Answer:

a=2.4m/s^2

Explanation:

Use V=vi+at

So, 13=25+a5

13-25=a5

[tex]\frac{-12}{5}[/tex]=a

a=2.4m/s^2