Answer:
I didn't understand questions properly. Sorry
Gas A: 5 liters at 20 °C
Gas B: 5 liters at 10 °C
Gas C: 5 liters at 40 °C
Gas D: 5 liters at 30 °C
Which gas has the greatest average molecular kinetic energy?
Gas A
Gas B
Gas C
Gas D
Answer:
Gas D
Explanation:
liters at 30 °C
A cook had a jar containing a sweet food and a jar containing a sour food. The image above shows the sweet and sour foods. At room temperature, both foods are liquids. The same amount of energy was transferred into both substances. Later, one of the foods had changed phase while the other had not. Which food changed phase, and how did it change? PLEASE ANSWER ASAP
Answer: One of the foods was sour and one was sweet
Explanation:
The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.
What is the maximum amount in moles of P2O5 that can theoretically be made from 161 g of P4 and excess oxygen
At a certain temperature, the solubility of aluminum hydroxide is (8.1x10^-13) M. What is the Ksp at this temperature?
Answer:
4.2x10⁻⁴ M or 0.032 g/L.
Explanation:
Hello!
In this case, for solubility product problems, we apply the concepts of equilibrium because an insoluble salt is ionized until a certain point limited by the solubility product constant, Ksp. Thus, we first write the ionization reaction of aluminum hydroxide at equilibrium:
[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)[/tex]
Next, we write the corresponding equilibrium expression:
[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]
Which in terms of [tex]x[/tex], the reaction extent, is:
[tex]Ksp=x*(3x)^3[/tex]
Because [tex]x[/tex] also represents the molar solubility of aluminum hydroxide at the considered temperature; now, we can write:
[tex]8.1x10^{-13}=x*(3x)^3[/tex]
Which can be solved for x as follows:
[tex]x=\sqrt[4]{\frac{8.1x10^{-13}}{27} } \\\\x=4.2x10^{-4}M[/tex]
Thus, the solubility is 4.2x10⁻⁴ M or mol/L and in g/L we have:
[tex]4.2x10^{-4}\frac{mol}{L}*\frac{78g}{1mol} =0.032\frac{g}{L}[/tex]
Best regards!
The SI unit for pressure, the pascal (Pa), is shorthand for
A. m2
B. N/m2
c. N
The pascal is sorthand for N/m^2
choose all the pairs of elements that will form a compound with an covalent/molecular bond
a. phosphorus and iodine
b. rubidium and fluorine
c. sulfur and chlorine
d. aluminum and bromine
Answer:
B
Explanation:
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
Answer:
5.7 moles of O2
Explanation:
We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:
2KClO3 —> 2KCl + 3O2
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.
Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.
Thus, 5.7 moles of O2 were obtained from the reaction.
Like Earth, the moon
A rotates and waxes
B goes through a cycle of phases
Crevolves and rotates
O
Dwaxes and wanes.
Which type of energy would running be?
Thermal
Light (solar)
Kinetic
Potential
Answer:
so here is the answer
Explanation:
Kinetic is the answer.
What are products of photosynthesis (2)
Answer:
Oxygen and simple sugars.
Explanation:
Water, sunlight and carbon dioxide is taken in to photosynthesise and the product would be oxygen that is breathed out through the stomata and simple sugars that are used as fuel for the plant.
The crust and upper mantle make up Earth's ____.
a. lithosphere
b. asthenosphere
c. core
d. continents
Answer:
a. the lithosphere
Explanation:
During a titration, 50.0 ml of 0.2M NaOH were required to neutralize 50.0ml of H3PO4. What's the concentration of the H3PO4 solution? Question 9 options: A) 0.07M B) 1.8M C) 0.6M D) 0.2M
Answer:
0.07 M
Explanation:
Given data:
Volume of NaOH = 50.0 mL
Molarity of NaOH = 0.2 M
Volume of H₃PO₄ = 50.0 mL
Concentration of H₃PO₄ = ?
Solution:
3NaOH + H₃PO₄ → Na₃PO₄ + 3H₂O
Number of moles of NaOH react:
Molarity = number of moles / volume in L
0.2 M = number of moles = 0.05 L
Number of moles = 0.01 mol
Now we will compare the moles of NaOH with H₃PO₄ .
NaOH : H₃PO₄
3 : 1
0.01 : 1/3×0.01 = 0.0033
Concentration of H₃PO₄:
Molarity = number of moles / volume in L
Molarity = 0.0033 mol / 0.05 L
Molarity = 0.07 M
Answer:
A.) 0.07M
Explanation:
I got it right in class!
Hope this Helps!! :))
True or False some synthetics are safer than their natural counterparts
Answer:
The answer is False
hope this helpes
How are scientific questions answered? OA. Through feelings and guesses
B. Through likes and dislikes
C. Through beliefs and opinions
D. Through measuring and observing
Calculate the following equation (2.55 -0.7)*4.3
Answer:
-7.6755
Explanation:
Calculate
I calculate it
Is CO2
an atom or a molecule and is it a pure element or a
compound?
a. Atom, Compound
b. Molecule, Pure element
c. Molecule, Compound
Answer:
C
Explanation:
CO2 is a molecule because it is compose of atoms which made it a molecule, it can also be call a compound.
Answer:
I believe it is c. Molecule, Pure compound
Explanation:
this is because it is composed of atoms which create molecule.
Constants: A: MW = 150 g/mol; B: = MW 100 g/mol; C: MW = 200 g/mol. 2.0 g C was made from 4.5 g A and 4.0 g
a. Calculate the yield for the following reaction: 3A + B -> C
b. Calculate the yield for the following reaction: 2A + 3B -> C
c. Calculate the yield for the following reaction: A + B->3C
Answer:
a. 100%
b. 133%
c. 300%
Explanation:
To find yield first we need to determine theoretical yield converting each reactant to moles and find limitng reactant for each reaction:
Moles A:
4.5g * (1mol / 150g) = 0.03 moles
Moles B:
4.0g * (1mol / 100g) = 0.04 moles
a. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 3 moles A) = 0.01 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 3 moles A) = 0.01 moles of C.
0.01 moles of C * (200g / mol) = 2g are produced.
Yield is:
2g / 2g * 100 = 100%
b. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (3 mole B / 2 moles A) = 0.045 moles of B
As there are 0.04 moles of B, B is limiting reactant.
Theoretical moles and mass of C are:
0.04 moles B * (1 mole C / 3 moles B) = 0.0133 moles of C.
0.0133 moles of C * (200g / mol) = 2.67g are produced.
Yield is:
2.67g / 2g * 100 = 133%
c. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 1 moles A) = 0.03 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 1 moles A) = 0.03 moles of C.
0.03 moles of C * (200g / mol) = 6g are produced.
Yield is:
6g / 2g * 100 = 300%
A water carbonating system is used at home and operates by providing CO2 at 5.0 atm.
Required:
a. Estimate the molar concentration of the CO2.H2O solution it produces.
b. After some weeks of use, the pressure in the water carbonating plant mentioned in the previous exercise has fallen to 2.0 atm. Estimate the molar concentration of CO2 in the carbonated water it produces at this stage.
Answer:
a. 0.17 M
b. 0.066 M
Explanation:
a.
Step 1: Given and required data
Pressure of CO₂ (P): 5.0 atm
Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹
Step 2: Calculate the molar concentration (C) of CO₂
We will use Henry's law.
C = k × P
C = 3.3 × 10⁻² M atm⁻¹ × 5.0 atm
C = 0.17 M
b.
Step 1: Given and required data
Pressure of CO₂ (P): 2.0 atm
Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹
Step 2: Calculate the molar concentration (C) of CO₂
We will use Henry's law.
C = k × P
C = 3.3 × 10⁻² M atm⁻¹ × 2.0 atm
C = 0.066 M
What is the noble gas electron configuration of aluminum (Al)?
Answer:
[Ne] 3s² 3p¹
Explanation:
50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
Answer:
8.279
Explanation:
The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.
At the equivalence point, we have
[tex]$n_{NaOH}=n_{HNO_2}$[/tex]
= 25.00 x 0.200
= 5.00 m-mol
= 0.005 mol
Volume of the base that is added to reach the equivalence point is
[tex]$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$[/tex]
Number of moles of [tex]$NO^-_{2}=n_{HNO_2}$[/tex]
= 0.005 mol
Volume at the equivalence point is 25 + 5 = 30.00 mL
Therefore, concentration of [tex]$NO^-_{2}= \frac{5}{30}$[/tex]
= 0.167 M
Now the ICE table :
[tex]$NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$[/tex]
I (M) 0.167 0 0
C (M) -x +x +x
E (M) 0.167-x x x
Now, the value of the base dissociation constant is ,
[tex]$K_w=K_a \times K_b$[/tex] [tex]$(K_w \text{ is the ionic product of water })$[/tex]
[tex]$K_b =\frac{K_w}{K_a}$[/tex]
[tex]$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$[/tex]
= [tex]$2.174 \times 10^{-11}$[/tex]
Base ionization constant, [tex]$K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$[/tex]
[tex]$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$[/tex]
[tex]$x= 1.9054 \times 10^{-6}$[/tex]
So, [tex]$[OH^-]=1.9054 \times 10^{-6 } \ M$[/tex]
pOH =- [tex]$\log[OH^-]$[/tex]
= [tex]$- \log(1.9054 \times 10^{-6} \ M)$[/tex]
=5.72
Now, since pH + pOH = 14
pH = 14.00 - 5.72
= 8.279
Therefore the ph is 8.279 at the end of the titration.
Titration is a chemical process used to determine the concentration of an unknown sample from the known sample. At the equivalence point, the pH is 8.279.
What is the equivalence point?In titration, the point at which the titrant neutralizes the unknown analyte solution is called the equivalence point.
The moles of equivalence point of sodium hydroxide and nitrous acid are:
[tex]\begin{aligned}\rm n_{NaOH} &= \rm n _{HNO_{2}}\\\\&= 25.00 \times 0.200\\\\&= 0.005 \;\rm mol\end{aligned}[/tex]
The volume of the added base is 5.00 mL.
The moles of nitrogen dioxide are 0.005 moles and the volume at the equivalence point is 30 mL.
The molar concentration of nitrogen dioxide will be, 0.167 M.
From the ICE table, the base dissociation constant is calculated as:
[tex]\begin{aligned}\rm K_{w} &= \rm K_{a} \times K_{b}\\\\\rm K_{b} &= \dfrac{1 \times 10^{-14}}{4.6 \times 10^{-14}}\\\\&= 2.174 \times 10^{-11}\end{aligned}[/tex]
The ionization constant of the base is given as,
[tex]\begin{aligned}\rm K_{b} &= \rm \dfrac{[HNO_{2}][OH^{-}]}{[NO_{2}^{-}]}\\\\2.174 \times 10^{-11} &= \rm \dfrac{x^{2}}{0.167- x}\\\\&= 1.905 \times 10^{-6} \end{aligned}[/tex]
Now, pOH is calculated as:
[tex]\begin{aligned} \rm pOH &=\rm - log [OH^{-}]\\\\&= \rm -log (1.905 \times 10^{-6})\\\\&= 5.72\end{aligned}[/tex]
The pH of the titration is calculated as:
[tex]\begin{aligned} \rm pH + pOH &= 14\\\\\rm pH &= 14.00 - 5.72\\\\&= 8.279\end{aligned}[/tex]
Therefore the pH is 8.27.
Learn more about pH here:
https://brainly.com/question/22821782
What happens when an atom becomes to gain a -1 charge it will
when an atom gains or loses an electron, it becomes an ion. Ions formed by the loss of an electron have a positive charge, and those formed by gaining an electron have a negative charge. Positive ions are called cations, and negative ions are called anions.
digital divide,cyberbullying and computer addiction are the common problems that some people encountered.what did you know about it?
Answer:
this is not chemistry
Explanation:
not chemistry
What is the mass ratio and atomic ratio for cl2o7
Answer:
Mass ratio: 71:112
Atomic ratio: 2:7
Explanation:
1. To get the mass ratio of of the compound Cl2O7, the following steps are followed:
- The atomic mass of Cl = 35.5g/mol, O = 16g/mol
- The mass of each element in the compound is as follows:
Cl2 = 35.5(2) = 71g
O7 = 16(7) = 112g
The mass ratio is the ratio of one mass of an element to another in the compound, hence, the mass ratio is 71:112
- The molar mass of the compound, Cl2O7, is determined:
71 + 112 = 183g/mol
- The mass percent of each element is determined by dividing the mass of each element present by the Molar Mass:
Cl = 71/183 = 0.3879 × 100 = 38.8%
O = 112/183 = 0.612 × 100 = 61.2%
2. Atomic ratio is the ratio of one atom in a molecule to another. It can be calculated this:
In Cl2O7, there are 9 total atoms (2 atoms of Cl + 7 atoms of oxygen).
Hence, that atomic ratio of Cl to oxygen in Cl2O7 is 2:7
The mass ratio of Cl₂O₇ is 71:112 and atomic ratio of Cl₂O₇ is 2:7.
What is mass ratio and atomic ratio?Mass ratio define as the ratio of the masses of constitute particles of the compound and atomic ratio is define as the ratio of the numbers of atoms present in that compound.
Given compound = Cl₂O₇
Mass of chlorine = 2×35.5 = 71g
Mass of oxygen = 7×16 = 112g
Mass ration of Cl₂O₇ is 71:112
And atomic ratio of Cl₂O₇ is 2:7
Hence, 71:112 is the mass ratio and atomic ratio is 2:7.
To know more about mass ratio, visit the below link:
https://brainly.com/question/14403176
Can gravity be considered a force? Explain your reasoning
Answer:
I think that gravity can be considered a force.
Explanation:
As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.
Hope this helped! :)
7)
According to your lab procedure, identify the chemicals necessary to produce NH3(g).
Write a net ionic equation for the generation of NH3(g).
Answer:
Explanation:
Chemicals to produce NH₃ ( ammonia )
1 ) Ammonium chloride ( NH₄Cl )
2 ) Calcium hydroxide Ca(OH)₂
2NH₄Cl + Ca(OH)₂ = CaCl₂ + 2NH₃ + 2H₂O.
Net Ionic equation
2NH₄⁺ ( aq ) + 2OH⁻ (aq ) = 2NH₃(g) + 2H₂O .
Which one of the following is not an alcohol?
A) acetone
B) glycerol
C) ethanol
D) cholesterol
E) ethylene glycol
Answer:
I think it's b because I heard the others
The correct answer is option A: acetone.
For a substance to be classified as an alcohol it must posses the -OH functional group. Compounds that posses this -OH functional group usually have the ending -ol.
Acetone is a ketone, this is evidenced by the ending -one. It has the functional group -C=O.
Hence, acetone is not alcohol. The structure of acetone is shown in the image attached.
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If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
Answer:
[tex][Cu^{2+}]=0.041 M[/tex]
Explanation:
Hello!
In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:
[tex][Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}[/tex]
[tex][Cu^{2+}]=0.041 M[/tex]
Best regards!
which materials conduct heat most easily
Answer:
Metal, Copper, and Alluminum
Explanation: It is what it is
Two containers, A and B, contain the same number of gas particles. Container A's particles are at a temperature of 40 C and a speed of 3 m/s. Container B's particles are at a temperature of 20 C and a speed of 1 m/s. In which container will there be greater pressure: Container A or Container B? Explain how this can be determined.
Answer:
A
Explanation:
as the temperature and speed is higher pressure will be higher
as the temperature is higher particles will be more active
and as speed is they will collide with more force
so the pressure will be higher in container B
An aqueous solution of potassium hydroxide is standardized by titration with a 0.187 M solution of nitric acid. If 22.7 mL of base are required to neutralize 29.4 mL of the acid, what is the molarity of the potassium hydroxide solution?
Answer:
Explanation:
29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .
moles contained in nitric acid solution
= .0294 x .187 moles
= 5.5 x 10⁻³ moles
This must have been reacted with same amount of moles of base
moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles
molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³
= .24 M .