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28. You are skiing on a mountain with an altitude of 1000 feet. The angle of depression is 19°. Find the distance you ski down the mountain. Draw a diagram to represent the situation. Round final answer to the nearest tenth.

First, we need to calculate the area of the room Jenny is tiling, which appears to be in the shape of a rectangle. The area is calculated by multiplying the length and width of the rectangle. If the measurements provided (2.6m and 11m) are for the length and width, then the area of the room would be:

Area = length x width

Area = 2.6m x 11m

Area = 28.6 m²

Next, we need to calculate how many packs of tiles Jenny needs to buy. Given that each pack covers an area of 3m², we divide the total area by the area each pack covers:

Number of packs needed = total area / area covered by one pack

Number of packs needed = 28.6m² / 3m² ≈ 9.53 packs

Since Jenny can't buy a fraction of a pack, she needs to purchase 10 packs of tiles.

The tiles are marked at £18.60, so before the discount, the total cost of the tiles would be:

Total cost = number of packs x price per pack

Total cost = 10 packs x £18.60 = £186

Jenny has a discount card which gives her a 25% discount off the marked price. The discount amount can be calculated as:

Discount = total cost x discount rate

Discount = £186 x 25% = £46.5

So, the cost of the tiles after the discount is:

Discounted price = total cost - discount

Discounted price = £186 - £46.5 = £139.5

Jenny has £100 to spend on the tiles. The extra amount Jenny needs is the difference between the cost of the tiles after the discount and the amount she has:

Extra amount needed = discounted price - amount Jenny has

Extra amount needed = £139.5 - £100 = £39.5

The question asks for the answer in pence, and there are 100 pence in a pound, so:

Extra amount needed in pence = extra amount needed in pounds x 100

Extra amount needed in pence = £39.5 x 100 = 3950 pence

Therefore, Jenny needs an extra 3950 pence to buy the tiles.

Answer:

8cm

Step-by-step explanation:

perimiter A = 11+11+4+4=30

perimiter B = 4+4+8+8=24

24+30=54

perimeter c =4+8+8+4+11+7+4=46

so perimiter of c is 8cm shorter than A and B total

hope this helps

Answer:

a. 36.65 in

b. 14.14 km²

Step-by-step explanation:

Solution Given:

a.

Arc Length = 2πr(θ/360)

where,

Here Given: θ=150° and r= 14 in

Substituting value

Arc length=2π*14*(150/360) =36.65 in

b.

Area of the sector of a circle = (θ/360°) * πr².

where,

Here  θ = 45° and r= 6km

Substituting value

Area of the sector of a circle = (45/360)*π*6²=14.14 km²

Answer:

[tex]\textsf{a)} \quad \overset{\frown}{AC}=36.65\; \sf inches[/tex]

[tex]\textsf{b)} \quad \text{Area of sector $ABC$}=14.14 \; \sf km^2[/tex]

Step-by-step explanation:

The formula to find the arc length of a sector of a circle when the central angle is measured in degrees is:

[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Arc length}\\\\Arc length $= \pi r\left(\dfrac{\theta}{180^{\circ}}\right)$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]

From inspection of the given diagram:

Substitute the given values into the formula:

[tex]\begin{aligned}\overset{\frown}{AC}&= \pi (14)\left(\dfrac{150^{\circ}}{180^{\circ}}\right)\\\\\overset{\frown}{AC}&= \pi (14)\left(\dfrac{5}{6}}\right)\\\\\overset{\frown}{AC}&=\dfrac{35}{3}\pi\\\\\overset{\frown}{AC}&=36.65\; \sf inches\;(nearest\;hundredth)\end{aligned}[/tex]

Therefore, the arc length of AC is 36.65 inches, rounded to the nearest hundredth.

[tex]\hrulefill[/tex]

The formula to find the area of a sector of a circle when the central angle is measured in degrees is:

[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Area of a sector}\\\\$A=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]

From inspection of the given diagram:

Substitute the given values into the formula:

[tex]\begin{aligned}\text{Area of sector $ABC$}&=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (6)^2\\\\&=\left(\dfrac{1}{8}\right) \pi (36)\\\\&=\dfrac{9}{2}\pi \\\\&=14.14\; \sf km^2\;(nearest\;hundredth)\end{aligned}[/tex]

Therefore, the area of sector ABC is 14.14 km², rounded to the nearest hundredth.

The length of side BC is approximately 3.725 cm.

In triangle ABC, we are given that angle BAC is 40 degrees, angle ABC is 20 degrees, and side AB measures 7 cm. We need to find the length of side BC.

To solve this problem, we can use the law of sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides.

Applying the law of sines, we have:

sin(ABC) / BC = sin(BAC) / AB

Since sin(ABC) = sin(20 degrees) and sin(BAC) = sin(40 degrees), we can substitute these values into the equation:

sin(20 degrees) / BC = sin(40 degrees) / 7 cm

Now, we can rearrange the equation to solve for BC:

BC = (7 cm * sin(20 degrees)) / sin(40 degrees)

Using a calculator to evaluate the trigonometric functions, we find that sin(20 degrees) ≈ 0.3420 and sin(40 degrees) ≈ 0.6428. Substituting these values into the equation:

BC ≈ (7 cm * 0.3420) / 0.6428

BC ≈ 3.725 cm

Therefore, the length of side BC is approximately 3.725 cm.

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Answer:

Step-by-step explanation:

pic is not clear

Answer:

D. 48

Step-by-step explanation:

When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.

56 = 1/2(160 - ?)

112 = 160 - ?

? = 160 - 112 = 48

Answer:

The sixth angle is 115°.

Step-by-step explanation:

Number of sides in a hexagon = n =6

Sum of interior angles = (n−2)180°

= (6−2)180 ∘

= 720

∴ Let the six angle of hexagon be x.

⇒ x + 123 + 124 + 118 + 130 + 110 = 720°

⇒ x + 605 = 720°

⇒ x = 720 - 605

⇒ x = 115

Answer:

--------------------------

Area is the product of two dimensions hence the ratio of areas of similar figures is the square of the scale factor.

Let the area of the enlarged shape be A, and the scale factor be k = 6.

Then we have the area of the larger shape:

The group of individuals fitting a description is called option D: Population, this is because, in statistics, a population is seen as am entire group of individuals, items, or elements that tends to have or share a common characteristics.

The term "population" describes the complete group of people or things that you are interested in investigating. It is the group of individuals or thing(s) about which you are attempting to draw conclusions.

There are infinite and finite populations. A population with a set quantity of people or things is said to be finite. An endless population is one that has an infinite amount of people or things.

Therefore, the correct option is D

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See full text below

A group of individuals fitting a description is the _____

Which of the term below fit the description above.

A.census

B.sample

C.parameter

D.population

Answer: 6+9x or 9x + 6

Step-by-step explanation:

Multiply 3 by each of the numbers inside the parentheses

The answer is:

Work/explanation:

To simplify this expression, we will use the distributive property:

[tex]\sf{3(2+3x)}[/tex]

Distribute the 3:

[tex]\sf{3\cdot2+3\cdot3x}[/tex]

Simplify

[tex]\sf{6+9x}[/tex]

Answer:

x = 4

Step-by-step explanation:

By property, if two tangents are drawn from an external point , then they are equal

⇒ 2x + 3 = 11

⇒ 2x = 11 - 3

⇒ 2x = 8

⇒ x = 8/2

⇒ x = 4

Answer:

x = 4

Step-by-step explanation:

To find the value of x, we can use the Two-Tangent Theorem.

The Two-Tangent Theorem states that if two tangent segments are drawn to a circle from the same external point, the lengths of the two tangent segments are equal.

Therefore:

[tex]\begin{aligned}AD &= AB\\\\2x+3&=11\\\\2x+3-3&=11-3\\\\2x&=8\\\\\dfrac{2x}{2}&=\dfrac{8}{2}\\\\x&=4\end{aligned}[/tex]

Therefore, the value of x is 4.

Reason:

If CD was parallel to AB, then triangles CDE and ABE would be similar. In turn it would mean that EA/EC = EB/ED is a true proportion.

Let's calculate each side separately.

Both decimal values are approximate.

The two values don't match up which makes EA/EC = EB/ED to be false.

Since EA/EC = EB/ED is false, we know that triangles CDE and ABE are not similar. Therefore, CD is not parallel to AB.

Answer:

CD is not parallel to AB

Step-by-step explanation:

According to the Side Splitter Theorem, if a line parallel to one side of a triangle intersects the other two sides, then this line divides those two sides proportionally.

Therefore, if CD is parallel to AB, then EA : AC = EB : BD.

Substitute the values of the line segments into the equation:

[tex]\begin{aligned}EA : AC &= EB : BD\\\\28:20&=16:10\\\\\dfrac{28}{20}&=\dfrac{16}{10}\\\\1.4 &\neq 1.6\end{aligned}[/tex]

As 1.4 does not equal 1.6, then CD is not parallel to AB.

Answer:

measure of arc JL = 55°

measure of angle PKJ = 27.5°

Sure! Here’s the solution:

F(x)=k9−kx2​​

First, let’s square both sides to get rid of the square root:

F(x)2=k9−kx2​

Now, let’s multiply both sides by k to isolate the term with x^2:

kF(x)2=9−kx2

Next, let’s move all terms to one side of the equation:

kF(x)2+kx2=9

Finally, let’s factor out x^2:

x2(k+kF(x)2)=9

And solve for x^2:

x2=k+kF(x)29​

Answer:

Step-by-step explanation:

To show the work for evaluating the function f(x) = √(9 - kx^2) / k, we can follow these steps:

9 - kx^2

(9 - kx^2) / k

√((9 - kx^2) / k)

The probability that all four cards are clubs is approximately 0.0026. Option A.

To understand why, let's break down the calculation. In a well-shuffled deck, there are 13 clubs out of 52 cards.

When dealing the first card, there are 13 clubs out of the total 52 cards, so the probability of getting a club on the first draw is 13/52.

For the second card, after the first club has been removed from the deck, there are now 12 clubs left out of the remaining 51 cards. Therefore, the probability of getting a club on the second draw is 12/51.

Similarly, for the third card, after two clubs have been removed, there are 11 clubs left out of the remaining 50 cards. The probability of drawing a club on the third draw is 11/50.

Finally, for the fourth card, after three clubs have been removed, there are 10 clubs left out of the remaining 49 cards. The probability of drawing a club on the fourth draw is 10/49.

To find the probability of all four cards being clubs, we multiply the probabilities of each individual draw:

(13/52) * (12/51) * (11/50) * (10/49) ≈ 0.0026.

This calculation takes into account the fact that the deck is being dealt without replacement, meaning that the number of available clubs decreases with each draw.

The third option, 1/4, is incorrect because it assumes that each card dealt is independent and has an equal probability of being a club. However, as cards are drawn without replacement, the probability changes with each draw. So Option A is correct.

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Note the complete question is

A 52-card deck contains 13 cards from each of the four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. You deal four cards without replacement from a well-shuffled deck so that you are equally likely to deal any four cards.

What is the probability that all four cards are clubs?

A.) 13/52 ⋅ 12/51 ⋅ 11/50 ⋅ 10/49 ≈0.0026

B.) 13/52 ⋅ 12/52 ⋅ 11/52 ⋅ 10/52 ≈0.0023

C.) 1/4 because 1/4 of the cards are clubs

Answer:

(a) The graph is entirely above the x-axis and rises from left to right, more steeply than the graph of y = 5^x.

(b) The second coordinate of the point with first coordinate 0 is 2.

The second coordinate of the point with first coordinate 1 is 10.

Answer:

p =1 0

Step-by-step explanation:

x³(x - y)⁹ - y³(x - y)⁹ = (x - y)⁹[x³ - y³]

= (x - y)⁹(x - y)(x² + y² + xy)

= (x - y)¹⁰(x² + y² + xy)

where p = 10 and q = 1

Answer:

p = 10

Step-by-step explanation:

Given expression:

[tex]x^3(x-y)^9 - y^3(x-y)^9[/tex]

Factor out the common term (x - y)⁹:

[tex](x-y)^9(x^3- y^3)[/tex]

[tex]\boxed{\begin{minipage}{5cm}\underline{Difference of two cubes}\\\\$x^3-y^3=(x-y)(x^2+y^2+xy)$\\\end{minipage}}[/tex]

Rewrite the second parentheses as the difference of two cubes.

[tex](x-y)^9(x-y)(x^2+y^2+xy)[/tex]

[tex]\textsf{Apply\:the\:exponent\:rule:} \quad a^b\cdot \:a^c=a^{b+c}[/tex]

[tex](x-y)^{9+1}(x^2+y^2+xy)[/tex]

[tex](x-y)^{10}(x^2+y^2+xy)[/tex]

Comparing the rewritten original expression with the given expression:

[tex](x-y)^{10}(x^2+y^2+xy)=(x-y)^p(x^2+y^2+qxy)[/tex]

We can see that [tex](x-y)^p[/tex] corresponds to [tex](x-y)^{10}[/tex] in the given expression.

Therefore, we can conclude that p = 10.

Answer:

4/3

Step-by-step explanation:

1/3:(1/4) = (1/3)/(1/4) = 1/3*4 = 4/3

The cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.

The period of the function y = cos(x) is 2π.

To understand the period of the cosine function, we need to examine its graph. The cosine function is a periodic function that oscillates between -1 and 1 as x varies. It repeats its pattern over regular intervals.

The cosine function completes one full cycle from 0 to 2π radians (or 0 to 360 degrees). This means that within this interval, the cosine function goes through one complete oscillation, starting from its maximum value of 1, then going through its minimum value of -1, and returning back to 1.

Since the cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.

This means that for any value of x, the value of cos(x) will repeat after an interval of 2π.

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Answer:

To evaluate -15 + 7 - (-8), we can simplify the expression by first removing the double negative.

-15 + 7 + 8 = 0

Therefore, the answer is 0.

Step-by-step explanation:

The answer is:

Work/explanation:

Remember the integer rule,

[tex]\bullet\phantom{4444}\sf{a-(-b)=a+b}[/tex]

Similarly

[tex]\sf{-15+7-(-8)}[/tex]

[tex]\sf{-15+15}[/tex]

Simplify fully.

[tex]\sf{0}[/tex]

Answer:

It's A

Step-by-step explanation:

Use the following models to show the equivalence of the fractions 35 and 610 a) Set model

Use the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set model

Answer:

Yes, a sinusoidal function is a great way to model temperatures over a 24-hour period because the pattern of temperature changes tends to be cyclic.

A sinusoidal function can be written in the general form:

D(t) = A sin(B(t - C)) + D

where:

- A is the amplitude (half the range of the temperature changes)

- B is the frequency of the cycle (which would be `2π/24` in this case because the temperature completes a full cycle every 24 hours)

- C is the horizontal shift (which is determined by the fact that the minimum temperature occurs at 6 AM)

- D is the vertical shift (which is the average of the maximum and minimum temperature)

Given the information you've provided, let's fill in the specifics:

- The high temperature for the day is 95 degrees.

- The low temperature is 75 degrees at 6 AM.

The amplitude, A, is half the range of temperature changes. It's the difference between the high and the low temperature divided by 2:

A = (95 - 75) / 2 = 10

The frequency, B, is `2π/24` because the temperature completes a full cycle every 24 hours.

The horizontal shift, C, is determined by the fact that the minimum temperature occurs at 6 AM. The sine function hits its minimum halfway through its period, so we want to shift the function to the right by 6 hours to make this happen. In our case, this means C = 6.

The vertical shift, D, is the average of the maximum and minimum temperature:

D = (95 + 75) / 2 = 85

So the equation for the temperature, D, in terms of t (the number of hours since midnight) is:

D(t) = 10 sin((2π/24) * (t - 6)) + 85

This equation represents a sinusoidal function that models the temperature over a day given the information provided.

The area of the green part of the tree is 55. 5cm²

The formula for area of a triangle is given as;

Area = 1/2bh

Substitute the values, we have;

Area = 1/2 × 6 × 7

Area = 21cm²

Area of trapezium is expressed as;

Area = a + b/2 h

Substitute the values, we have;

Area = 5 + 7/2 (3) + 4 + 7/2 (3)

expand the bracket, we have;

Area = 18 + 16.5

Area = 34.5 cm²

Total area = 34.5 + 21 = 55. 5cm²

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A. The distribution of X can be represented as X ~ N(μ, σ). B. 1918 is the sample mean. C. The probability that a randomly selected district had fewer than 2009 votes for President Clinton is approximately 0.5641.

D. The probability is approximately 0.0725.

E. The first quartile for votes for President Clinton is approximately 1544.

a. The distribution of X is normally distributed. Therefore, the distribution of X can be represented as X ~ N(μ, σ), where μ is the mean and σ is the standard deviation.

b. In this context, 1918 is the sample mean. It represents the average number of votes per district in the sample of 40 election districts in Alaska.

c. To find the probability that a randomly selected district had fewer than 2009 votes for President Clinton, we need to calculate the z-score and then use the standard normal distribution table (or a calculator with a normal distribution function). The z-score can be calculated as follows:

z = (x - μ) / σ

where x is the value we're interested in (2009 votes), μ is the population mean (1918 votes), and σ is the standard deviation (554 votes).

z = (2009 - 1918) / 554 ≈ 0.164

Using the standard normal distribution table or a calculator, we can find that the probability corresponding to a z-score of 0.164 is approximately 0.5641.

Therefore, the probability that a randomly selected district had fewer than 2009 votes for President Clinton is approximately 0.5641.

d. To find the probability that a randomly selected district had between 1955 and 2056 votes for President Clinton, we need to calculate the z-scores for both values and then use the standard normal distribution table.

For 1955 votes:

z1 = (1955 - 1918) / 554 ≈ 0.066

For 2056 votes:

z2 = (2056 - 1918) / 554 ≈ 0.248

Using the standard normal distribution table or a calculator, we can find the cumulative probabilities corresponding to z1 and z2. Then, we subtract the cumulative probability for z1 from the cumulative probability for z2 to find the probability between these two values.

P(1955 < X < 2056) = P(X < 2056) - P(X < 1955)

Using the standard normal distribution table or a calculator, we can find these probabilities and subtract them to find the desired probability.

P(1955 < X < 2056) = P(X < 2056) - P(X < 1955)

≈ 0.5989 - 0.5264

≈ 0.0725

So, the probability is approximately 0.0725.

e. The first quartile corresponds to the 25th percentile of the distribution. To find the first quartile for votes for President Clinton, we need to find the value of X such that 25% of the districts have fewer votes.

Using the standard normal distribution table or a calculator, we can find the z-score corresponding to the 25th percentile, which is -0.6745. Then we can calculate the value of X using the z-score formula:

-0.6745 = (X - 1918) / 554

Solving for X:

X - 1918 = -0.6745 × 554

X - 1918 = -374.167

X ≈ 1543.833

Rounding to the nearest whole number, the first quartile for votes for President Clinton is approximately 1544.

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(a) The average cost in 2011 is  $2247.64.

(b) A graph of the function g for the period 2006 to 2015 is: C. graph C.

(c) Assuming that the graph remains accurate, its shape suggest that: A. the average cost increases at a slower rate as time goes on.

Based on the information provided, we can logically deduce that the average annual cost (in dollars) for health insurance in this country can be approximately represented by the following function:

g(x) = -1736.7 + 1661.6Inx

where:

x = 6 corresponds to the year 2006.

For the year 2011, the average cost (in dollars) is given by;

x = (2011 - 2006) + 6

x = 5 + 6

x = 11 years.

Next, we would substitute 11 for x in the function:

g(11) = -1736.7 + 1661.6In(11)

g(11) = $2247.64

Part b.

In order to plot the graph of this function, we would make use of an online graphing tool. Additionally, the years would be plotted on the x-axis while the average annual cost would be plotted on the x-axis of the cartesian coordinate as shown below.

Part c.

Assuming the graph remains accurate, the shape of the graph suggest that the average cost of health insurance increases at a slower rate as time goes on.

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Answer:

[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[

Step-by-step explanation:

[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[

Answer:

[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[

Step-by-step explanation:

what this is?

The property that is illustrated by the statements is Transitive. Option C

Using the principle of transitivity, if two objects are equal to a third, they are also equal to one another.

From the information given, we have that;

< ABC = <DEF

< DEF = < XYZ

This simply proves that < ABC and < XYZ are both equivalent to < DEF in this situation.

By using the transitive property, we can determine that A ABC and A XYZ are also equal. This attribute enables us to construct relationships between many elements based on their equality to a shared third element and to connect logically equalities.

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