NEED HELP ASAP 40 POINTS GEOMETRY QUESTION PLEASE GIVE FULL ANSWER!!!Which of the lines listed below is perpendicular to the line with the equation ​

Answer:

7) r = -4

8) n = 1

9) x = 2

Step-by-step explanation:

Problem 7

Here, we have the equation 5 + 3r + 6 = -1. It looks like we need to solve for r, so let's go ahead and start by adding the constants 5 and 6.

5 + 3r + 6 = -1

3r + 11 = -1

Next, let's remove 11 from both sides to isolate r.

3r = -12

Finally, we can divide both sides by 3 to find the value of r.

r = -4

Problem 8

In this equation, it looks like we have to solve for n: -n + 2 + 3n = 4. So, let's start by combining like terms (-n and 3n).

-n + 3n + 2 = 4

2n + 2 = 4

Next, we can remove 2 from both sides to isolate r.

2n = 2

And finally, we can divide both sides by 2.

n = 1

Problem 5

This equation is a little trickier since we have a fraction. To remove this fraction, we can multiply both sides by 4.

(-6 + x)/4 = -1

4 × (-6 + x)/4 = 4 × -1

4/4 × (-6 + x)/1 = -4

-6 + x = -4

Finally, let's add 6 to both sides.

x = 2

Step-by-step explanation:

the question doesn't make sense and you need to rephrase the question.

Answer:

Hm? Is there meant to be a file, if so I can’t see it. :((

Step-by-step explanation:

Answer:

[tex]\huge\color{purple}\boxed{\colorbox{black}{Answer♡}}[/tex]

[tex] \frac{2}{ \sqrt{7} - 1} \\ = > \frac{2}{ \sqrt{7} - 1} \times \frac{ \sqrt{7} + 1}{ \sqrt{7} + 1} \\ = > \frac{2( \sqrt{7} + 1)}{ \sqrt{7} {}^{2} - 1 {}^{2} } \\ = > \frac{2 \sqrt{7} + 2}{7 - 1} \\ = > \frac{2( \sqrt{7} + 1)}{6} \\ = > \frac{ \sqrt{7} + 1}{3} [/tex]

[tex]\color{red}\boxed{\colorbox{skyblue}{Additional Information~}}[/tex]

( a + b ) × ( a - b ) = a² - b²

we earlier had 2 multiplied to rest of the numerator and 6 in the denominator..

we simply divided both the numerator as well as denominator by 2 and hence got the result obtained.

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hope helpful~

The required distance is 11.4 rounded to the tenth

If light intensity (I) is proportional (a) to the inverse square of distance (d) of a subject from a light  source, this is expressed as:

If a light intensity (I) is 516 lumens at the source and 4 lumens at a specific distance from the  source, the distance is calculated as:

l = a/d²

d² = a/l

d² = 516/4

d = √129

d = 11.4

Hence the required distance is 11.4 rounded to the tenth

Learn more on inverse variation here:https://brainly.com/question/13998680

Answer:

  g(x) = -4x^2 +(45/2)x +6

Step-by-step explanation:

A function is scaled horizontally by replacing x with x/k, where k is the expansion factor. Here, we want to expand the graph horizontally by a factor of 2, so the new function will be f(x/2).

  g(x) = f(x/2) = -16(x/2)^2 +45(x/2) +6

  g(x) = -4x^2 +(45/2)x +6

Answer:

Above is the answer, coupled with detailed step-by-step explanations. Thank you!

Answer:

m < 5 = 55.1 i think im not forsure

Step-by-step explanation:

Whenever the Transversal EF intersects parallel line AB and CD, the values of m∠5 and m∠7 are 55.1° and 124.9°, respectively.

An angle results from the intersection of two lines at a point. The term "angle" describes the width of the "gap" that exists between these two rays. It's represented by the symbol.

Angles are most frequently measured in degrees and radians, a measurement of roundness or rotation. Angles are a part of everyday existence.

As per the information provided in the question,

Since the transverse line, EF, intersects the line segment AB and CD, it creates equivalent, alternate, and other angles.

As a result, the m∠5 and m∠7 are as follows:

First, supplementary angles ∠5 and ∠7 are present. Since they add up to 180 degrees, they are equal.

Since alternate angles are equivalent, ∠5 is an alternative angle to ∠4. Therefore,

m∠5 ≅ m∠4

m∠5 = 55.1°

So,

m∠5 + m∠7  = 180°

55.1 + ∠7 = 180

∠7 = 180 - 55.1

m∠7 = 124.9°

To know more about an angle:

https://brainly.com/question/28451077

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Answer:

 B.  4200

Step-by-step explanation:

A suitable calculator can add the terms for you. (See attached)

__

The first term is 69, and the common difference is 75-69 = 6. The general term is ...

  an = a1 +d(n -1)

  an = 69 +6(n -1)

Then the 28th term is ...

  a28 = 69 +6(27) = 231

The average term is (a28 +a1)/2 = (231 +69)/2 = 150.

The sum is the number of terms multiplied by the average term:

  sum = 28×150= 4200

Answer:

24/100x175 = 42

Step-by-step explanation:

24/100x175 = 42

Answer:

A. 4

Step-by-step explanation:

I hope this helps you!!!

Answer:

y=x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-4)/(4-2)

m=2/2

m=1

y-y1=m(x-x1)

y-4=1(x-2)

y=x-2+4

y=x+2

Answer:

450 cm area

Step-by-step explanation:

Formula 1/2*b*h

1/2*75*12cm

1/2*900

1*450cm

450 is area  PLEASE MARK BRAINLIEST :))

Answer:

5 feet per second

Step-by-step explanation:

Use the formula y2-y1/x2-x1. (10,50) is x1 and y1. 25 seconds and 125 feet is x2 and y2.

(125-50)/(25-10) = 75/15

We need to solve for the feet per (or 1) second, so we have to divide it by 15.

75/15= 5

So, the slope is 5 feet per second.

Answer:

121 cm²

Step-by-step explanation:

Square's area formula is

A=a²

where a stands for a side of the square

A=(11 cm)²

A=121 cm²

whenever you're talking of area you put cm²

Answer:

Given :

To Find :

Using Formula :

[tex]\star\small{ \underline{\boxed{\sf{\red{Area_{(Square)} = {(Side)}^{2}}}}}}[/tex]

Solution :

Substituting the given value in the required formula to find area of square :

[tex]{\dashrightarrow{\small{{\sf{Area_{(Square)} = {(Side)}^{2}}}}}}[/tex]

[tex]{\dashrightarrow{\small{{\sf{Area_{(Square)} = {(11)}^{2}}}}}}[/tex]

[tex]{\dashrightarrow{\small{{\sf{Area_{(Square)} = {(11 \times 11)}}}}}}[/tex]

[tex]{\dashrightarrow{\small{{\sf{Area_{(Square)} = {(121)}}}}}}[/tex]

[tex]{\dashrightarrow{\small{{\sf{Area_{(Square)} = 121 \: {cm}^{2}}}}}}[/tex]

[tex]{\star{\small{\underline{\boxed{\sf{\pink{Area_{(Square)} = 121 \: {cm}^{2}}}}}}}}[/tex]

Hence, the area of square is 121 cm².

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Answer :

4x + 9y = 27

Explanation :

Multiply the equation with 9

9( y = -4x/9 + 3 )

9y = -4x + 27

4x + 9y = 27

If 310 is 30% of some number x, then

0.30x = 310

⇒   x = 310/0.30

⇒   x = 310/(3/10)

⇒   x = 310 × 10/3

⇒   x = 3100/3 ≈ 1033.33

i.e

[tex]\\ \sf{:}\Rrightarrow y+5=-1+5=4[/tex]

New co-ordinates are

Answer:

000000004.8

Hope it help!

Answer:

54 minutes

Step-by-step explanation:

1) There are 60 minutes in an hour. So, you can do 60-36 to find the first value. (24)

2) Add 24 minutes to 30 and get 54 minutes.

Answer:

40°

Step-by-step explanation:

Answer:

171

Step-by-step explanation:

Answer:

171

Step-by-step explanation:

New value =

225 - Percentage decrease =

225 - (24% × 225) =

225 - 24% × 225 =

(1 - 24%) × 225 =

(100% - 24%) × 225 =

76% × 225 =

76 ÷ 100 × 225 =

76 × 225 ÷ 100 =

17,100 ÷ 100 =

171

Answer:

24,25,26

Step-by-step explanation:

Answer:24, 25, 26

Step-by-step explanation:

Divide the 75 by 3 because that is how many numbers you need. Then subtract 1 to get 24, add 1 to get 26, and also use 25.

Answer: what’s the full question??

Answer : pumpkin that is 12 pounds

Step - by - step explanation :

First, convert . . . what is 1.7 kilograms as pounds ?  3.74786 ( rounded is 4 pounds )

Second, compare . . . 4 < 12

Hope this helped ! :>

the length of the side of this square is [tex]4\sqrt{2} \:or \:5.65[/tex]cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²=[tex]\frac{64}{2}[/tex]

a²=32

doing square root on both side

[tex]\sqrt{a²}=\sqrt{32}[/tex]

a=±[tex]\sqrt{2*2*2*2*2}[/tex]

a=±2*2[tex]\sqrt{2}[/tex]

Since side of square is always positive so

a=4[tex]\sqrt{2}[/tex] or 5.65 cm

Answer:

Given :

↠ The diagonal of a square is 8 cm.

To Find :

↠ The length of the side of square.

Using Formula :

Here is the formula to find the side of square if diagonal is given :

[tex]\implies{\sf{a = \sqrt{2} \dfrac{d}{2}}} [/tex]

Where :

Solution :

Substituting the given value in the required formula :

[tex]{\dashrightarrow{\pmb{\sf{ \: a = \sqrt{2} \dfrac{d}{2}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times \dfrac{8}{2}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times \cancel{\dfrac{8}{2}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times 4}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = 4\sqrt{2}}}}[/tex]

[tex]{\dashrightarrow{\sf{\underline{\underline{\red{ \: a = 5.65 \: cm}}}}}}[/tex]

Hence, the length of the side of square is 5.6 cm.

[tex]\underline{\rule{220pt}{3pt}}[/tex]