Answer:
1.2 miles in 24 minutes
Step-by-step explanation:
3 miles per hour = .05 miles per minute
24 x 0.05 = 1.2
Remember that speed is defined as the rate of change of the position respect to the time, thus we can define the relation:
Distance = Spee*Time.
Using this we will get the solution: distance = 1.2 miles
Let's see how to get the solution:
We start with the given information:
Nathan rides for 24 minutes.His speed is 3 miles per hour.So we got a time and we also have a speed, but the time units in these are different.
So knowing that:
1 hour = 60 minutes
(1 hour/60 minutes) = 1
Then we can write:
24 minutes = (24 minutes)*(1 hour/60 minutes) = 0.4 hours
Then we have:
time = 0.4 hours
speed = 3 miles per hour.
Then, using the first equation, we get:
distance = (3 miles per hour)*0.4 hours = 1.2 miles.
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HELP ME PLEASE! how do you write 0.0370 as a scientific notation
Is every relation also a function? Explain
Answer:
no
Step-by-step explanation:
they are not
Answer:
Step-by-step explanation:
In fact, every function is a relation. However, not every relation is a function. In a function, there cannot be two lists that disagree on only the last element. This would be tantamount to the function having two values for one combination of arguments.
the cost of 3 boxes is
The function g(x) is a transformation of f(x). If g(x) has a y-intercept of -2, which of the following functions could represent g(x)?
A. g(x) = f(x) - 5
B. g(x) = f(x - 5)
C. g(x) = f(x) - 2
D. g(x) = f(x + 2)
Answer:
A.
Step-by-step explanation:
It just is trust
A cookie factory uses 3 bags of flour in each batch of cookies. The factory used 2 7/10 bags of flour yesterday. How many batches of cookies did the factory make.
BRAINLIEST TO THE CORRECT ANSWER! 20 POINTS!!
Maricella solves for x in the equation 4 x minus 2 (3 x minus 4) + 4 = negative x + 3 (x + 1) + 1. She begins by adding –4 + 4 on the left side of the equation and 1 + 1 on the right side of the equation. Which best explains why Maricella’s strategy is incorrect?
The statement that best explains why Maricella's strategy is incorrect based on the distribution property and order of operation is option A.
Recall:
When given an equation involving brackets, the distribution property must be applied first which involves multiplying every term in a bracket by the term outside the bracket.In the equation given, to solve for x, Maricella needs to apply the distribution property by using -2 to multiply each term in (3x - 4) and using +3 to multiply every term in (x + 1).
The next step will now be addition and subtraction of like terms.
Therefore, the statement that best explains why Maricella's strategy is incorrect based on the distribution property and order of operation is option A.
Learn more about distribution property on:
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Answer:
A!!!
Step-by-step explanation:
edge2022
How would you graph the solution to -5w + 9 = 14 on a number line?
Answer:
Step-by-step explanation:
w= -1
Your circle will be on the -1
Answer:
Taft
Step-by-step explanation:
what plus 80 and 70 equals 180
Answer:
30
Step-by-step explanation:
Take 80 and 70 and add them together to get: 130
Then subtract 130 from 180
To get: 30
:)
Answer:
30
Step-by-step explanation:
80 + 70 = 150
180- 150 = 30
therefore 80 + 70 + 30 = 180
Mr. Sanchez earns a 14% commission on the sales he makes for Sanchez
Rentals. How much commission would he make if he sold $3500 last
week?
not multi choice u type an answer !!!
if the first and fifteen terms of A.P. are 8 and -48 respectively, obtain the progression
Answer:
8, 4, 0, -4, - 8, .........
Step-by-step explanation:
The n the term of an AP is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and a₁₅ = - 48, then
8 + 14d = - 48 ( subtract 8 from both sides )
14d = - 56 ( divide both sides by 14 )
d = - 4
To obtain the progression subtract 4 from each term, that is
8, 4, 0, - 4, - 8, ......
Answer:
8, 4, 0, -4, -8, -12, -16, -20,...
Step-by-step explanation:
Arithmetic Progressions
The general term of an arithmetic progression (A.P.) is:
[tex]a_n=a_1+(n-1).r[/tex]
Where:
a1 = First term
an = Term number n
n = Number of the term
r = Common difference
We are given: a1=8, and a15=-48, n=15. Calculate r:
[tex]\displaystyle r=\frac{a_n-a_1}{n-1}[/tex]
[tex]\displaystyle r=\frac{-48-8}{15-1}[/tex]
[tex]\displaystyle r=\frac{-56}{14}[/tex]
r = -4
We can get the terms of the progression by subtracting 4 to the previous term.
Thus, the first terms of the progression are:
8, 4, 0, -4, -8, -12, -16, -20,...
y= (x + 4)2 + 8
how do you simplify this equation
Answer:
Step-by-step explanation:
you could distribute and combine like terms
y=(x+4)2+8
y=2x+8+8
y=2x+16
PLEASE HELP HURRY!! What is the value of x?
Find the slope pls help me I need this
Answer: 3/2x
Step-by-step explanation: it going up 3 units and right 2 units. And since slope is rise/ run it 3/2x
How many solutions does the following equation have?
4(x-2)-2=2x+2x-10
Answer:
all real numbers
Step-by-step explanation:
(PLEASEEE HELP I DONT UNDERSTAND) Which of the following equations represents a linear NON-proportional function?
A) y=3x+0
B) y=x/4
C) y=7x
D) y=2/5x+7
What is the slope of this line? Enter your answer as a fraction in simplest term.
∀x∀y(((x ≥ 0) ∧ (y < 0)) → (x – y > 0))
A. A non-negative number - a negative number is positive.
B. For any two real numbers, the first is non-negative, the second is negative, and the difference is positive.
C. For every non-negative number, one can find a negative number so that the first number minus, the second is positive.
D. One can find a non-negative number and a negative number so that the first minus, the second is positive.
E. One can find a non-negative number so that for any positive number chosen, the first number minus, the second is positive.
Answer:
B. For any two real numbers, the first is non-negative, the second is negative, and the difference is positive.
Step-by-step explanation:
To answer this question, I'll analyse the mathematical statements one at a time
The analysis is as follows:
∀x -> This means real number x
∀y -> This means real number y
(x ≥ 0) -> Such that real number x is greater than or equal to 0. In other words, x is positive
∧ -> and
(y < 0)-> y is less than 0. In other words, y is negative
So, there are two real numbers: x and y
→ (x – y > 0) -> Their difference is greater than 0. In other words, their difference is positive
When the analysis above is compared to the list of given options; the option that match is B.
Hence, option B answers the question.
PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((
Answer:
-12
Step-by-step explanation:
Answer:
-12
Step-by-step explanation:
Its -12 for sure!!!!!
Factorise
b) x + 3x - 40
Sally buys a pair of shoes that are discounted 60% off the original price. If Sally pays $50 for the shoes, what was the original price of the shoes?
Answer:
90$
Step-by-step explanation
Step 1: You need to find how much was the 60% discount
Step 2: To find that multiply .6 by 50 you will get 30
Now you know how much was 60% discount
Step 3: Add 30(the discount) + 50(the prce sally pays) = 90 (the oriagnal price)
-7.8× (- 1.5)
plz help ASAP
Answer:
11.7
Step-by-step explanation:
(−7.8)(−1.5)
Hope ths helps
Alguém pode me ajudar por favor???????????
Answer:
The asnwer is the first one
Step-by-step explanation:
thx for the poins
Write a linear equation to represent this
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Question 3 of 20 -
E
ZahraouiAziz Midterm Geometry Pt 1 2020-2021 Question: 134
A line segment has an endpoint at (4.6). If the midpoint of the line segment is (1,5), what are the.coordinates of the point at the other endorine ne segment?
O (3, 1)
O (-2,4)
O (7.7)
O (5, 11)
Chrome OS. 28m)
Switched network connection
Your connection
has switched td al
Previous
O
Fo
Answer: most likely be (7,7) not sure right or wrong but i tried so yeah
Step-by-step explanation:
i need the answer asap i’ll make you the brainliest
Answer
the second one
Which of the following sets of numbers could represent the three sides of a triangle?
1) {15, 23, 37}
2) {6,8,14}
3) {7, 22, 30}
4) {7, 21, 30}
Answer:
NONE
Step-by-step explanation:
You have to do a² + b² = c²
To do it you have to put the three numbers from least to greatest for it to work. They already are so that's good.
15² + 23² = 37² (solve)
225 + 529 = 1369
754 ≠ 1369
6² + 8² = 14² (solve)
36 + 64 = 196
100 ≠ 196
7² + 22² = 30²
49 + 484 = 900
433 ≠ 900
7² + 21² = 30²
49 + 441 = 900
490 ≠ 900
I don't know what happened, but none of these would work.
I even used a pythagorean theorem calculator to check my work and none of them match.
Hope this helps!
give me answer.1 to 100 plus. like:1+2+3+4+5+6+7+8+9+10+11.........
Answer:
5,050
Step-by-step explanation:
Use sigma notation to add all the numbers together (∑)
john is 2 years younger than his sister, annie. Last year, John was half Annie's age. How old are john and Annie now?
Answer:
John is 3 and Annie is 5 because to be half of someone's age while being to years younger it would have to be 2 and 4 - but then a year passed and so the are now 3 and 5.
Step-by-step explanation:
The present age of John is 3 years
The present age of Annie is 5 years
Given that John is 2 years younger than Annie's age
Let the present age of John be "J"
Let the present age of Annie be "A"
According to the given situation
[tex]\rm J = A -2........(1)\\[/tex]
One year ago the age of John = [tex]\rm J-1[/tex]
One year ago the age of Annie = [tex]\rm A -1[/tex]
According to the given situation
[tex]\rm\dfrac{A-1}{2}= J-1.........(2)[/tex]
On solving for equations (1) and (2) we get
A = 5 and J = 3
So the present age of Annie is 5 years
The present age of John is 3 Years
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There are 2 girls for every 5 boys at baseball game. If there are 56 total in attendance. How many girls and boys are there?
Answer:
girls: 16
boys: 40
Step-by-step explanation:
girls : boys
2 : 5
let the total number of people be (2+5)x.
2x + 5x = 56
7x = 56
x = 8
therefore, no. of girls = 2 x 8 = 16
no. of boys = 5 x 8 = 40
This is a question on ratio and proportions + forming and solving equations. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)
HELP IT'S URGENT.
Please show workings.
No 4 (see image)
Answer:
(i) (b² - 2ac)/c²(ii) (3abc - b³)/a³Step-by-step explanation:
α and β are the roots of the equation:
ax² + bx + c = 0Sum of the roots is:
α + b = -b/aProduct of the roots is:
αβ = c/aSolving the following expressions:
(i)
1/α² + 1/β² =(α² + β²) / α²β² =((α + β)² - 2αβ) / (αβ)² = ((-b/a)² - 2c/a) / (c/a)² = (b²/a² - 2c/a) * a²/c² = b²/c² - 2ac/c² =(b² - 2ac)/c²----------------
(ii)
α³ + β³ =(α + β)(α² - αβ + β²) =(α + β)((α + β)² - 3αβ) = (α + β)³ - 3αβ(α + β) =(-b/a)³ - 3(c/a)(-b/a) =-b³/a³ + 3bc/a²= 3abc/a³ - b³/a³=(3abc - b³)/a³[tex] \huge \underline{\tt Question} :[/tex]
If α and β are the roots of the equation ax² + bx + c = 0, where a, b and c are constants such that a ≠ 0, find in terms of a, b and c expressions for :
[tex] \tt \dfrac{1}{\alpha ^2} + \dfrac{1}{\beta ^2}[/tex]α³ + β³[tex] \\ [/tex]
[tex] \huge \underline{\tt Answer} :[/tex]
[tex] \bf \dfrac{1}{\alpha ^2} + \dfrac{1}{\beta ^2} = \dfrac{b^2 - 2ac}{c^2 }[/tex][tex] \bf \alpha ^3 + \beta ^3 = \dfrac{ - b^3 + 3abc}{a^3}[/tex][tex] \\ [/tex]
[tex] \huge \underline{\tt Explanation} :[/tex]
As, α and β are the roots of the equation ax² + bx + c = 0
We know that :
[tex] \underline{\boxed{\bf{Sum \: of \: roots = \dfrac{- coefficient \: of \: x}{coefficient \: of \: x^2}}}}[/tex][tex] \underline{\boxed{\bf{Product \: of \: roots = \dfrac{constant \: term}{coefficient \: of \: x^2}}}}[/tex][tex] \tt : \implies \alpha + \beta = \dfrac{-b}{a}[/tex]
and
[tex] \tt : \implies \alpha\beta = \dfrac{c}{a}[/tex]
[tex] \\ [/tex]
Now, let's solve given values :
[tex] \bf \: \: \: \: 1. \: \dfrac{1}{\alpha ^2} + \dfrac{1}{\beta ^2}[/tex]
[tex] \tt : \implies \dfrac{\beta ^2 + \alpha ^2}{\alpha ^2 \beta ^2}[/tex]
[tex] \tt : \implies \dfrac{\alpha ^2 + \beta ^2}{\alpha ^2 \beta ^2}[/tex]
[tex] \\ [/tex]
Now, by using identity :
[tex] \underline{\boxed{\bf{a^2+ b^2 = (a+b)^2 -2ab}}}[/tex][tex] \tt : \implies \dfrac{(\alpha + \beta)^2 - 2 \alpha\beta}{(\alpha\beta)^2}[/tex]
[tex] \\ [/tex]
Now, by substituting values of :
[tex] \underline{\boxed{\bf{\alpha + \beta = \dfrac{-b}{a}}}}[/tex][tex] \underline{\boxed{\bf{\alpha\beta = \dfrac{c}{a}}}}[/tex][tex] \tt : \implies \dfrac{\Bigg(\dfrac{-b}{a}\Bigg)^2 - 2 \times \dfrac{c}{a}}{\Bigg(\dfrac{c}{a}\Bigg)^2}[/tex]
[tex] \tt : \implies \dfrac{\dfrac{b^2}{a^2} - \dfrac{2c}{a}}{\dfrac{c^2}{a^2}}[/tex]
[tex]\tt : \implies \dfrac{\dfrac{b^2}{a^2} - \dfrac{2ac}{a^{2} }}{\dfrac{c^2}{a^2}}[/tex]
[tex]\tt : \implies \dfrac{\dfrac{b^2 - 2ac}{a^2 }}{\dfrac{c^2}{a^2}}[/tex]
[tex]\tt : \implies \dfrac{b^2 - 2ac}{\cancel{a^2} } \times \dfrac{ \cancel{a^2}}{c^2}[/tex]
[tex]\tt : \implies \dfrac{b^2 - 2ac}{c^2 }[/tex]
[tex] \\ [/tex]
[tex] \underline{\bf Hence, \: \dfrac{1}{\alpha ^2} + \dfrac{1}{\beta ^2} = \dfrac{b^2 - 2ac}{c^2 }}[/tex]
[tex] \\ [/tex]
[tex] \bf \: \: \: \: 2. \: \alpha ^3 + \beta ^3 [/tex]
[tex] \\ [/tex]
By using identity :
[tex] \underline{\boxed{\bf{a^3+ b^3 = (a+b)(a^2 -ab + b^2)}}}[/tex][tex] \tt : \implies (\alpha + \beta)(\alpha ^2 - \alpha\beta + \beta ^2)[/tex]
[tex] \tt : \implies (\alpha + \beta)(\alpha ^2 + \beta ^2 - \alpha\beta)[/tex]
[tex] \\ [/tex]
By using identity :
[tex] \underline{\boxed{\bf{a^2+ b^2 = (a+b)^2 -2ab}}}[/tex][tex] \tt : \implies (\alpha + \beta)(\alpha + \beta)^2 -2 \alpha\beta - \alpha\beta)[/tex]
[tex] \tt : \implies (\alpha + \beta)((\alpha + \beta)^2 -3 \alpha\beta)[/tex]
[tex] \\ [/tex]
Now, by substituting values of :
[tex] \underline{\boxed{\bf{\alpha + \beta = \dfrac{-b}{a}}}}[/tex][tex] \underline{\boxed{\bf{\alpha\beta = \dfrac{c}{a}}}}[/tex][tex] \tt : \implies \Bigg(\dfrac{-b}{a}\Bigg)\Bigg( \bigg(\dfrac{-b}{a} \bigg)^2 -3 \times \dfrac{c}{a}\Bigg)[/tex]
[tex] \tt : \implies \Bigg(\dfrac{-b}{a}\Bigg)\Bigg(\dfrac{b^2}{a^2} - \dfrac{3c}{a}\Bigg)[/tex]
[tex]\tt : \implies \Bigg(\dfrac{-b}{a}\Bigg)\Bigg(\dfrac{b^2}{a^2} - \dfrac{3ac}{a^{2} }\Bigg)[/tex]
[tex]\tt : \implies \Bigg(\dfrac{-b}{a}\Bigg)\Bigg(\dfrac{b^2 - 3ac}{a^2} \Bigg)[/tex]
[tex]\tt : \implies \dfrac{-b}{a} \times \dfrac{b^2 - 3ac}{a^2} [/tex]
[tex]\tt : \implies \dfrac{ - b(b^2 - 3ac)}{a \times a^2} [/tex]
[tex]\tt : \implies \dfrac{ - b^3 + 3abc}{a^3} [/tex]
[tex] \\ [/tex]
[tex] \underline{\bf Hence, \: \alpha ^3 + \beta ^3 = \dfrac{ - b^3 + 3abc}{a^3}}[/tex]