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Very Short Answer Type Questions
1. Name the nutrients present in our food which give mainly energy to our body.
2. Name the nutrient which is needed for the growth and repair of our body. Proteins
3. Name the main carbohydrate which we eat in our food. I heat Rica maizes Pearl Potato
4. Which carbohydrate is present in wheat, rice and potatoes ? Plants
5. Name two foods each rich in (a) fats, and (b) starch. Batterheen
6. Name the major nutrients in our food.Combshed soles Fats Rooten mineral water Vitamin
7. Name the vitamin which is required for maintaining good eyesight Witamin A
8. Name the vitamin which keeps the teeth, gums and joints healthy, and helps fight diseases. 14
9. Name the vitamin which is necessary for the normal growth of bones and teeth Wermico
10. Which vitamin is produced in the human body when skin is exposed to sunlight ? uamu-D
11. Name the main vitamin present in (a) oranges, and (b) carrots. Worthing
12 Name an important mineral present in (a) apple, and (b) sea-fish.
13. Which mineral is needed to make haemoglobin present in our red blood cells.
14. In addition to calcium, which other mineral is needed for making bones and teeth ? (chum, Pha
15. Name a mineral which is needed for keeping bones and teeth healthy.
16. Which mineral is needed for the proper functioning of thyroid gland ?
17. Name two food materials which contain a lot of water. Fresh forest
18. Name the component of our food which helps prevent constipation. bulk oftend, wollte man
Vegetable
19. What is the other name of roughage? Dletary Abu
29Which component of food is mainly made of indigestible carbohydrate 'cellulose'?
21. The examples of carbohydrates are : sugar, cellulose, glucose and starch. Which of these carbohydrate
provides roughage in our food ?
22. Name two components of food which do not provide any nutrients.Cellulog
23. Fill in the following blank with a suitable word :
Iron is an important constituent of.........present in our blood. Hemoglobin
Short Answer Type Questions
24. What is the function of fats in our body? Name​

Answer:

250w

Explanation:

W=Fd

W= 250 x 4= 1000J

P=E/t=1000/4s=250w

Answer:

The work done will be "763 J". A further explanation is given below.

Explanation:

The given values are:

[tex]Q_1=1000 \ J[/tex]

Temperature,

[tex]T_1=900^{\circ} C[/tex]

i.e,

    [tex]=1173[/tex]

[tex]T_2=5^{\circ}C[/tex]

i.e.,

    [tex]=278[/tex]

As we know,

⇒  [tex]\eta =1-\frac{T_2}{T_1}[/tex]

On substituting the values, we get

⇒     [tex]=1-\frac{278}{1173}[/tex]

⇒     [tex]=\frac{1173-278}{1173}[/tex]

⇒     [tex]=\frac{895}{1173}[/tex]

⇒     [tex]=0.763[/tex]

then,

⇒  [tex]W=\eta Q_1[/tex]

⇒       [tex]=0.763\times 1000[/tex]

⇒       [tex]=763 \ J[/tex]

Answer:

Hope this helps!  can I have brainliest im trying to level up.

Explanation:

Bumper cars are a great place to see Sir Isaac Newton’s three laws of motion in action. Here’s how:

Newton’s First Law: Every object in motion continues in motion and every object at rest continues to be at rest unless an outside force acts upon it.

This is because all objects have inertia – the property of matter that resists changes to the object’s motion.

Newton found that if a ball is sitting on a table, it will stay sitting there because that is what it ‘wants’ to do.

If the ball is set in motion, it will keep traveling in a straight path because, again, that is what it ‘wants’ to do.

An object in motion will not stop, slow down, or change its direction unless an outside force acts on it (such as gravity, friction, and air resistance).

When you are riding in a bumper car and end up in a collision with another bumper car, you feel a jolt. This is because your body’s inertia wants it to keep traveling in the direction it was moving with the car even though your bumper car has now suddenly stopped.

Newton’s Second Law: The greater the mass of an object, the harder it is to change its speed.

(More force is needed to move it.)

You already know this law and practice it in your everyday life. Something that is small, such as a pebble, is much easier to pick up and throw than something that is large and heavy, such as a boulder.

When riding in the bumper cars, you may have noticed that people who weigh less tend to get pushed around more than people who weigh more.

The more mass (weight) an object has, the more force it takes to move it.

And since all the bumper cars usually have the same top velocity, the cars carrying more mass will never travel as far as the cars carrying less mass after a collision.

Newton’s Third Law: For every action, there is an equal and opposite reaction.

If two bumper cars traveling at the same speed and carrying the same amount of weight run into each other, they will bounce off and move an equal distance away from each other.

And based on the second law, if there is a difference in the amount of weight being carried in the two cars, the car with less weight will travel farther away from the point of impact than the car carrying more weight.

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

Answer:

a. E = 900000 J = 900 KJ

b. ΔT = 8.18 °C

c. Cost = $ 7.2  

Explanation:

a.

The energy can be given by:

[tex]E = Pt[/tex]

where,

E = Energy = ?

P = Power = 500 W

t = time = (0.5 h)(3600 s/1 h) = 1800 s

Therefore,

[tex]E = (500\ W)(1800\ s)[/tex]

E = 900000 J = 900 KJ

b.

The change in temperature of room air is given by the following formula:

[tex]0.5E = mC\Delta T\\[/tex]   (since 50% of energy is used to heat air)

where,

m = mass of air = 50 kg

C = specific heat of air = 1.1 KJ/kg.°C

ΔT = Change in temperature of air = ?

Therefore,

[tex](0.5)(900\ KJ) = (50\ kg)(1.1\ KJ/Kg.^oC)\Delta T[/tex]

ΔT = 8.18 °C

c.

First, we will calculate the total energy consumed:

[tex]E = (0.5\ KW)(6\ h/d)(30\ d)\\E = 90\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(90\ KWh)[/tex]

Cost = $ 7.2

Answer:

The amount of energy carried by a wave is related to the amplitude of the wave

Explanation:

A high energy wave is characterized by a high amplitude; a low energy wave is characterized by a low amplitude.  The energy imparted to a pulse will only affect the amplitude of that pulse.

Hope this helped!!!

Answer:

2) center mass

3) when work is done by a system, energy is released

Explanation:

Answer:

32km per hour

Explanation:

Explanation:

In first case v = a t

==> a t = 40 km p h

Now distance covered S1 + S2 + S3

S1 = 1/2 a t^2 and S3 = 1/2 a t^2

But S2 = 3t * 40 = 120 t km

Hence total distance = at^2 + 120 t

Time taken (total) = t + 3t + t = 5 t

Hence average speed = at^2 + 120 t / 5 t

Cancelling t we have at + 120 / 5 = 40 + 120 / 5 = 160/5 = 32 km per hour

Answer:

Atoms

Explanation:

Atoms make up everything

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

[tex]T = \frac{t}{n}[/tex]

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

[tex]T = \frac{135\ s}{98}[/tex]

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

[tex]T = 2\pi \sqrt{\frac{l}{g}}[/tex]

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

[tex](1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}[/tex]

g = 11.2 m/s²

Explanation:

V= Current × Resistance

V= 400mA × 5kohms

V= 2000V

Answer:

A. Build a nest.

Explanation:

It wont do any of the other things and they need a place to sleep and lay eggs plus it is a bird

The heron birds belong to Ardeidae family. Some of the species among them are referred to as egrets or bitterns rather than a heron. A heron bird  build a nest during Spring. The correct option is A.

The heron is known as a long-legged, long-necked, fresh water and coastal birds. It a medium to large size bird with long necks and legs. They exhibit sexual dimorphism in size. The two male and female sex of the same species show distinct attributes beyond their difference in sexual organs.

Almost all the heron species are found in water and they are essentially non-swimming water birds which feed on the margins of lakes, ponds, sea, rivers and swamps. The small species of heron are generally referred to as the dwarf bittern.

The nesting season indicates the time of year during which birds build nests and lay eggs in them. In most cases bring up their young. It is in the spring season lot of food are available.

Thus the correct option is A.

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#SPJ3

62.5 m/s

Explanation:

Answer:

Explanation:

1. loftily - To do something in an arrogant manner.

He answered her in a loftily manner.

2) dispute - This is an argument or a disagreement.

There is a dispute between the friends.

3) diverged - To move in a different direction or separate from others.

The road diverged here to my town.

4) jostle - To come in contact, push, or collide with someone in a crowd .

The boy jostled his way through the crowd.

5) souvenirs - Something kept ad a reminder or taken as a memory of something or someone.

Before his dad died, he gave James his watch as a souvenir.

6) coveted - Something or someone that's greatly envied or desired.

James always covered power but didn't eventually get it.

Answer:

0.9m/s

?

Explanation:

Answer:

(a)  0.273 A

(b) 4.368 V

(c) 1.638 V

Explanation:

From the question,

(a) Applying ohm's law

V = IR'...................... Equation 1

Where V = Voltage of the battery, I = Current in each of the resistor, R' = Total resistance of the combined resistors

Since the Two resisstors are connected in series,

(i) The same current flows through both resistors

(ii) The total resistor (R') = R₁+R₂

Therefore,

V = (R₁+R₂)I

Make I the subject of the equation

I = V/(R₁+R₂)................. Equation 2

Given: V = 6 V, R₁ = 16 Ω, R₂ = 6 Ω

Substitute into equation 2

I = 6/(16+6)

I = 6/22

I = 0.273 A

(b) The potential difference across the first resisto

V₁ = IR₁...................... Equation 3

Given: I = 0.273 A, R₁ = 16 Ω

Substitute these values into equation 3

V₁ = 0.273(16)

V₁ = 4.368 V

(c) The Potential difference across the second resistor is

V₂ = IR₂.................... Equation 4

V₂ = 0.273×6

V₂ = 1.638 V

Answer: I believe hydrogen cyanide, carbon monoxide, and ammonia are the three chemicals involved, but im not sure

Given the wavelength of the visible light photon, the energy of the photon is 3.54 × 10⁻¹⁹J

Given the data in the question;

Wavelength of visible light; [tex]\lambda = 560.6 nm = 5.606*10^{-7}m[/tex]

Speed of light; [tex]c = 2.998 * 10^8 m/s[/tex]

Planck's constant; [tex]h = 6.626 * 10^{-34} J.s[/tex]

The energy and wavelength of light are related by the equation:

[tex]E = \frac{hc}{\lambda}[/tex]

Where E is energy of photon in Joules, h is Planck's constant, c is the speed of light and λ is the wavelength,

We substitute our given value into the equation

[tex]E = \frac{(6.626*10^{-34}J.s)(2.998*10^8m/s)}{5.606*10^{-7}m} \\\\E = \frac{(1.986*10^{-25}J.m}{5.606*10^{-7}m}\\\\E = 3.54 * 10^{-19}J[/tex]

Therefore, given the wavelength of the visible light photon,  the energy of the photon is 3.54 × 10⁻¹⁹J

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Answer:

Wavelength = 0.66 meters

Explanation:

Given the following data;

Speed = 330 m/s

Frequency = 500 Hz

To find the wavelength;

Mathematically, wavelength is calculated using this formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Substituting into the equation, we have;

[tex] Wavelength = \frac {330}{500} [/tex]

Wavelength = 0.66 meters

Answer:

Explanation:

they trade velocities... so the Satellite now is going 5000 m/s  

The moment of inertia of Pulley is 8.89 kgm².

The angular acceleration of the pulley is calculated as follows;

[tex]\alpha = \frac{\omega_f - \omega _i}{t}[/tex]

where;

Final angular velocity in radian per second is calculated as

[tex]\omega _f = 17 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 \ s} = 1.78 \ rad/s[/tex]

Now, solve for angular acceleration

[tex]\alpha = \frac{1.78-0}{5} \\\\\alpha = 0.36 \ rad/s^2[/tex]

The the moment of inertia of Pulley is determined using the formula for torque.

Iα = Fr

I = Fr/α

I = (16 x 0.2)/(0.36)

I = 8.89 kgm²

Thus, the moment of inertia of Pulley is 8.89 kgm².

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Answer:

A: Alpha decay.

Explanation:

The transmutation of ²³⁸U is a nuclear reaction that yields ²³⁴Th and an alpha particle.

Now, Alpha decay is a radioactive decay whereby an atomic nucleus emits an alpha particle which then changes into an atom with a mass number that is decreased by four and atomic number decreased by 2.

In this case, mass number is reduced from 238 to 234. Thus, it's an alpha decay.

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. The correct form is: A [tex]+10\,\mu C[/tex] charge and a [tex]-10\,\mu C[/tex] at a distance of 0.3 meters.

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)

Where:

[tex]F[/tex] - Electrostatic force, in newtons.

[tex]\kappa[/tex] - Electrostatic constant, in newton-square meters per square coulomb.

[tex]|q_{A}|,|q_{B}|[/tex] - Magnitudes of electric charges, in coulombs.

[tex]r[/tex] - Distance between charges, in meters.

If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]|q_{A}| = |q_{B}| = 10\times 10^{-6}\,C[/tex] and [tex]r = 0.3\,m[/tex], then the magnitude of the electrostatic force is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]

[tex]F = 9.987\,N[/tex]

In consequence, correct answer is B.

Answer:

the speed of an object is 9.42 m/s

Explanation:

The computation of the speed of an object is given below:

v = 2πr ÷ t

where

v denotes the speed

r denotes the radius

r denotes the time

So,

= 2 × 3.14 × 0.75 ÷ 0.50

= 9.42 m/s

Hence, the speed of an object is 9.42 m/s

the same would be considered and relevant too

Answer:

1.33

Explanation:

For an optical instrument, the magnification ratio of the apparent diameter of the image to that of the object.

Mathematically, from the given information;

Magnification[tex]= \dfrac{n_{water}}{n_{air}}[/tex]

where;

[tex]n_{water} =1.33\\ \\ n_{air} = 1.00[/tex]

[tex]= \dfrac{1.33}{1.00} \\ \\= \mathbf{1.33}[/tex]

Answer:

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Explanation:

Let's start by calculating each force.

Gravitational force

             F =[tex]G \frac{m_1m_2}{r^2}[/tex]  

let's calculate

             F = 6.67 10⁻¹¹  1  1 / 1²

             F = 6.67 10⁻¹¹ N

Electric force

             F = [tex]k \frac{q_1q_2}{r^2}[/tex]  

indicates that the charge is q = 10 C

            F = 9 10⁹ 10 10 / 1²

            F = 9 10¹¹ N

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Answer:

11.25J

Explanation:

15=(output/75)x100

output =(75x15)/100=11.25J

Answer:

1 / i + 1 / o = 1 / f     thin lens equations

i = o f / (o - f)   rearranging

Lens 1:   object = 30 cm    f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm    distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

It can be deduced that the final image's distance from Lens 2 will be 30.8 cm.

By using the Lens formula, the distance will be calculated thus:

1/v + 1/u = 1/15.2

1/v + 1/30.0 = 1/15.2

v = 30.8cm

In this case, the image formed will be to the right.

Lastly, the overall magnification of the lens pair will be:

M = (30.8/30.0)[(-28.4/40.7 - 30.8)]

M = -2.94.

In conclusion, the magnification is -2.94.

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