Misrepresentations of physical stimuli are known as Absolute Threshold
What is stimulus?
A stimulus is a measurable change in the physical or chemical structure of an organism's internal or external environment in physiology. Sensitivity refers to an organism's or organ's ability to perceive external stimuli and respond appropriately (excitability). Sensory receptors can receive information from both inside and outside the body, such as touch receptors in the skin or light receptors in the eye, as well as chemoreceptors and mechanoreceptors. When a sensory receptor detects a stimulus, it can generate a reflex via stimulus transduction. A homeostatic control system's first component is frequently an internal stimulus. External stimuli, such as the fight-or-flight response, are capable of eliciting systemic responses throughout the body.
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Monochromatic light of 605 nm falls on a single slit of width 0.095 mm. The slit is located 85 cm from a screen. How far from the center is the first dark band?540 mm5,400 mm0.5 mm5.4 mm
The wavelength of the monochromatic beam is given as,
[tex]\lambda=605\text{ nm}[/tex]The value of the width of the slit is,
[tex]d=0.095\text{ mm}[/tex]The distance of the slit from the screen is,
[tex]D=85\text{ cm}[/tex]Thus, the distance of the dark band from the center is,
[tex]y=\frac{(2m+1)\lambda D}{d}[/tex]For the first dark band,
m=0,
Substituting all the known values,
The value of the distance of the dark band becomes,
[tex]\begin{gathered} y=\frac{605\times10^{-9}\times85\times10^{-2}}{0.095\times10^{-3}} \\ y=540000\times10^{-8}\text{ m} \\ y=5.4\text{ mm} \end{gathered}[/tex]Thus, the first dark band is 5.4 mm away from the center of the screen.
Hence, the correct answer is 5.4 mm.
An Olympic diver is on a diving platform 8.40 m above the water. To start her dive, she runs off of the platform with a speed of 1.2 m/s in the horizontal direction. What is the diver speed, in m/s, just before she enters the water?m/s
Given data
*The given distance above the water is s = 8.40 m
*The given initial speed of the Olympic diver is u = 1.2 m/s
*The value of the acceleration due to gravity is a = 9.8 m/s^2
The formula for the diver speed, in m/s, just before she enters the water is given by the equation of motion as
[tex]v^2=u^2+2as[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v^2=(1.2)^2+2\times9.8\times8.40 \\ v=12.88\text{ m/s} \end{gathered}[/tex]Hence, the diver speed, in m/s, just before she enters the water is v = 12.88 m/s
What is the mass of a truck if it produces a force of 13,607 N while accelerating at a rate of 2.9 m/s²?
Newton's Second Law.
We have the following data, provided in the exercise:
Mass (m) = ?
Force (F) = 13607 N
Acceleration (a) = 2.9 m/s²
To calculate the mass, we solve the following formula:
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}[/tex][tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}[/tex]
We substitute the data in the clear formula.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }[/tex]
We break down the units of Newton = Kg * m/s².
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }[/tex]
The mass of the truck is: 4692.07 Kilograms (Kg).How does a ramp make it easier to move a heavy object a certain distance?A by decreasing the distance the object movesB by decreasing the amount of work required to move the objectC by changing the direction in which the object movesDby decreasing the amount of force required to move the object
When lifting an object we are required to produce a force that is greater or equal than the weight of the object in order to be lifted:
When we use a ramp we have the following distribution of forces:
In the ramp, the force decomposes into two components. A component that is parallel to the ramp and a component that is perpendicular to the ramp. Now the force must be greater or equal to the parallel component of the ramp therefore, the amount of force required must be less. Therefore, the ramp makes it easier by decreasing the amount of force required to move the object.
By Decreasing the amount of force required to move an objectExplanation:
Objects, especially simple machines, make work easier. They do not decrease the amount of work done, but actually decrease the amount of force applied. The less force applied, the easier it is to do work. Simple machines and other objects that help make work easier decrease the amount of force required to move an object.
So the answer is-
A ramp makes work easier by decreasing the amount of force required to move an object
A marble is rolled down a ramp. The ramp has a slope of 0.2 for the first meter and then 0.1 for the second meter. Describe how the acceleration and velocity of the marble will be different when it has traveled 1.5 meters as compared to when it has traveled 0.5 meters
The velocity and acceleration of the marble will be greater when it travels 1.5 m compared to 0.5 m.
What is velocity?
The velocity of an object is the rate of change of displacement with time.
The velocity of the marble after it has travelled the given distance is calculated as follows;
v² = u² + 2as
where;
v is the final velocity of the marbleu is the initial velocity of the marbles is the distance travelled by the marblea is the acceleration of the marbleAssuming the marble started from rest, without initial velocity, our final equation becomes.
v² = 0² + 2as
v² = 2as
v = √2as
From the final equation, the velocity of the marble increases with increase in the distance travelled by the marble.
Also, since acceleration is defined as the rate of change of velocity with time. As the velocity increases, the acceleration of the marble increases as well.
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Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2.10 m/s. If the other skater acquires a speed of 3.81 m/s, what is her mass in kilograms?
The mass of the second skater is equal to 27 Kg, which acquires a speed of 3.81 m/s.
What is law of conservation of linear momentum?According to the law of conservation of momentum, the sum of the momentum of the two objects before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ and u₂ are the initial speed while v₁ & v₂ is their final speed.
The linear momentum can be described as the product of the mass times the velocity of the object. Conservation of momentum is a characteristic held by an object where the total amount of momentum remains the same.
Given the initial speed of the skaters is equal to zero so u₁ = u₂ =0
The mass of the one skater, m₁ = 49 Kg
The first skater acquires the speed, v₁ = 2.10 m/s
The speed acquired by the second skater, v₂ = -3.81 m/s
From the law of conservation of momentum, we can find the mass of another skater:
m₁ u₁ + m₂ u₂ = m₁v₁ + m₂ v₂
49 × 0 + m₂ ×0 = 49 × (2.10) + m₂ × (- 3.81)
m₂ = -49 × (2.10)/ (- 3.81)
m₂ = 27 Kg
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A train car with a mass of 14 kg and speed of 30 m/s is traveling to the right. Another train car with a mass of 26kg is moving with an unknown velocity. After the collision, the 14 kg train car is stuck to the 26 kg train car with a combined velocity of 12 m/s
From the Law of Conservation of Linear Momentum, when two particles get stuck together after a collision, it follows that:
[tex]m_1v_1+m_2v_2=(m_1+m_2)v_f[/tex]In this case, the initial velocity of the second particle is unknown. Isolate it from the equation:
[tex]v_2=\frac{(m_1+m_2)v_f-m_1v_1}{m_2}[/tex]Replace the given data to find the value of v₂:
[tex]\begin{gathered} m_1=14kg \\ v_1=30\frac{m}{s} \\ \\ m_2=26kg \\ v_2=\text{ unknown} \\ \\ v_f=12\frac{m}{s} \\ \\ \Rightarrow v_2=\frac{(14kg+26kg)(12\frac{m}{s})-(14kg)(30\frac{m}{s})}{26kg}=2.3077...\frac{m}{s} \\ \\ \therefore v_2\approx2.3\frac{m}{s} \end{gathered}[/tex]Therefore, the initial velocity of the 26-kg car is approximately 2.3m/s.
A pencil is viewed through a concave lens. Which of the following best describes the image?A.RealB.InvertedC.VirtualD.Enlarged
A concave lens produces a virtual image like the one seen in the diagram (we know is virtual since it is on the same side to the original object), we also see that the image is smaller, and not inverted.
Therefore, the only option that describes this image is C which is virtual.
Ricardo, of mass 72 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 39 kg canoe. When the canoe is at rest in
the placid water, they exchange seats, which are 3.2 m apart and symmetrically located with respect to the canoe's center. Ricardo
notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and calculates Carmelita's mass. What is it?
Ricardo notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and the mass is 49 kg.
What is mass?Mass is defined as a measurement of the fundamental attribute of all stuff, inertia.
Mass is also defined as a physical body's total amount of matter.
As per question,
Let's refer to Ricardo's mass as MR and Carmelita's mass as MC.
Let the two-person system's center of mass, which is believed to be closer to Ricardo, be x meters from the center of the canoe's length L and mass m.
MC(L/2 +x) = mx + MR(L/2-x).
It is derived from the second law of parallel forces, which states that the sum of the moments of mass moving clockwise and counterclockwise is equal.
The canoe's center has now moved twice as far from its initial location.
So, x = 46/2 = 23 cm = 0.23 m
MC = MR (L / 2x) - mx / L / 2 + x
MC = 72 ( 3.2 / 2 - 0.23 ) - 39 x 0.23 / 3.2 / 2 + 0.23
MC = 72 ( 1.6 - 0.23 ) - 39 x 0.23 / 1.6 + 0.23
MC = 72 x 1.37 - 8.97 / 1.83
MC = 98.64 - 8.97 / 1.83
MC = 49 kg
Thus, Ricardo notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and the mass is 49 kg
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Alyse runs to her classroom which is 20 meters away. She forgets her physics book in her locker and must return 20 meters in the direction from whence she came. If her total trip takes 3 minutes, what is Alyse’s average velocity? NEED HELPP ASAPPPP!!!!!
The average velocity of Alyse is 0 m/s.
What is the average velocity of an object or a person?The average velocity of a person is the average of all the velocities of moving as it moves.
Velocity on its own is the ratio of the displacement of a body and the time taken for that displacement.
Mathematically:
Average velocity = total displacement / time takenDisplacement is a vector quantity that measures the distance traveled by a moving body in a specific direction.
Hence, average velocity and velocity are both vector quantities.
Displacement takes a measure of the shortest possible distance along a straight line from the beginning of the motion until the end of the motion.
Calculating the average velocity of Alyse:
Assuming the initial direction is positive and n=backeard direction is negative:
Total displacement = 20 m + - (20 m)
Total displacement = 0 m
total time = 3 minutes
Average velocity = 0 m/ 3
Average velocity = 0 m/s
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on landing the plane touches a runaway with a speed of 65 m/s the figure shows the of the speed of the plane after one second. calculate the acceleration of the plane during its landing
Answer:
Correct option is B)
Given, initial velocity is u=0m/s
Final velocity is v=88.3m/s and traveled distance, d=1365m
Let a be the acceleration of the plane.
Using v
2
−u
2
=2ad
∴ (88.3)
2
−0
2
=2a(1365)
⟹ a=2.86m/s
2
Solve any question of Motion in a Straight Line with:-
Explanation:
hope it helps
To solve this we must be knowing each and every concept related to acceleration. Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
What is acceleration?Acceleration is the rate during which velocity varies over time, both in terms of speed and direction. A point or object travelling in a straight path is accelerated if something accelerates or decelerates.
Regardless of whether the speed remains constant, motion on such a circle gets accelerated because of direction is always changing. Both tangential to acceleration in all other types of motion.
initial velocity u=0m/s
Final velocity v=88.3m/s
distance, d=1365m
v²-u²=2as
substituting all the given values in the above equation, we get
88.3²-0²=2×1365×a
a=2.86m/s²
Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
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if a child on a skateboard has a total momentum of 86.94kgm/s and a speed of 2.3m/s, calculate the total mass of the child and skateboard
The graph below shows the number of sunspots observed between 1750 and 2000.
Based on the graph, which of these statements is most likely correct about the periods 1800 to 1850 and 1900 to 1950?
A) There was decrease in global temperatures.
B) There was increase in global temperatures.
C) There was no significant change in solar activity.
D) There was no significant change in global climate.
Based on the graph, during the periods 1800-1850 and 1900-1950, there was a increase in global temperature.
Sunspots is an activity on the surface of the Sun that manifest as transient, darker-than-the-neighboring-areas spots. These parts on which it occurs have lower surface temperatures because magnetic flux concentrations there prevent convection from occurring.
Sunspot can increase the temperature of earth but by only a margin of about 0.05 to 0.1 Celsius.
As we can see from the graph that during the year 1800-1850 and 1900-1950 that number of sunspots is increasing continuously. So, there will a slight increase will be noticed in the global temperature.
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Two audio speakers are placed on a vertical rail. Speaker A is placed at head-level while Speaker B is place at some variable height, Δy, above Speaker A. Both speakers receive simultaneous input from a sine-wave generator so the speakers each produce a pure sinusoidal sound wave with a wavelength of 0.880 meters. Calculate the lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by person standing Δx=6.38 meters directly in front of Speaker A.
The lowest height at which speaker B can be placed above speaker A to produce the lowest sound to the person standing in front of A by superposition and wave interference is ∆y ≈ 2.41 m.
What is the superposition principle?The superposition principle states that the magnitude of the resulting wave when two waves overlap is the sum of the disturbance of the individual waves.
The given parameters are;
Height of speaker B above speaker A = ∆y
Wavelength of the wave = 0.880 meters
Distance between the person standing directly in front of speaker A and speaker A, ∆x = 6.38 meters
Required;
The minimum height of speaker B above speaker A that produces the minimum sound to the person in front of speaker A
Solution;
The minimum sound is given when there is destructive interference of the waves produced by the speakers
When there is destructive interference, the peak of the wave from speaker A coincides with the through of the wave from speaker B which gives;
Distance between a peak and the through of a wave = 0.5 × The wavelength
Therefore, for minimum sound, we have;
Distance from the person to speaker B = 6.38 m + 0.5 × (The wavelength)
Which gives;
Distance from the person to speaker B = 6.38 m + 0.5 × 0.88 m = 6.82 m
Pythagorean theorem is used to find the height of speaker B above speaker A as; ∆y = √(6.82² - 6.38²) ≈ 2.41
The height of speaker B above A is approximately 2.41 meters
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The lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by a person standing Δx=6.38 meters directly in front of Speaker A is
[tex]\Delta y=1.62m[/tex]
This is further explained below.
What is the lowest height?Generally, For a person, to hear sound minimum, sound waves from speakers A and B should meet at point P, in opposite phases, so path diff. should be
[tex]x=(2 n+1) \frac{\lambda}{2},[/tex]
[tex]\lambda[/tex]= wavelength
[tex]for $\Delta y$ to be minimum $\Rightarrow x=\frac{\lambda}{2}$ \\\\from figure, in $\triangle A B P$$$\Delta x^2+\Delta y^2=\Delta x^{\prime 2}=\text { (2) }$$[/tex]
Path diff. will be x=B P-A P
[tex]\begin{aligned}& \quad x=\Delta x^{\prime}-\Delta x \\\\&\Delta x^{\prime}-\Delta x=\frac{\lambda}{2} \quad x=\frac{\lambda}{2} \quad \text { from eq (1) } \\\\&\left.\Delta x^2+\Delta y^2-3.01=0.41 \quad \quad \quad \quad \lambda=0.820 \mathrm{~m}\right] \\\\&\Delta x^2+\Delta y^2=3.42 \\\\&\Delta y^2=(3.42)^2-(3.01)^2 \quad \Delta x=3.01 \mathrm{~m} \\\\&\Delta y=1.62 \mathrm{~m}\end{aligned}[/tex]
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Joshua rode his bicycle from his school to home. The total distance covered in this journey was 800 meters and the total time taken was 7 minutes. What is the average speed of joshuas bicycle in this journey
Answer: 6,857.14m/h (6.86km/h or 1.90m/s)
Explanation:
Explain why planets orbit the sun instead of traveling off into space
Answer:
gravity
Explanation:
The gravity of the Sun keeps the planets in their orbits. They stay in their orbits because there is no other force in the Solar System which can stop them.
A parking lot is going to be 60 m wide and 240 m long. which dimensions could be used for a scale model of the lot?A. 90 in x 360 cmB. 1 m x 3 mC. 20 cm x 80 cmD. 120 cm x 480 m
Answer:
C. 20 cm x 80 cm
Explanation:
The dimensions of the scale model have the same ratio of the original dimensions. The ratio of the original dimenstions is
240/60 = 4
Then, the ratio for each option is
A. 360/90 = 4
B. 3/1 = 3
C. 80/20 = 4
D. 480/120 = 4
Therefore, B is not a correct option.
Additionally, we don't use A because the units for length and width are different
And we don't use D because the measures are too long for a model.
Therefore, the answer is
C. 20 cm x 80 cm
4. Betsy wants to use her own weight to lift a 1,500-newton box. She weighs 500 newtons. Suggest input and output arm lengths that would allow Betsy to lift the box with a lever. Draw a lever and label the input and output arms with the lengths and forces.
Answer:
Explanation:
Given:
F₁ = 500 N
F₂ = 1.500 N
____________
L₁ - ?
L₂ - ?
Moment rule:
M₁ = M₂
F₁*L₁ = F₂*L₂
F₂ / F₁ = 1.500 / 500 = 3
L₁ / L₂ = 3
L₁ = 3*L₂
If L₂ = 0.5 m
then L₁ = 3*0.5 = 1.5 m
A car goes from rest to velocity of 108 km/h north in 0.2 hours. What is the car's acceleration?
Answer:
21.6
Explanation:
bc acceleration is equal to 108 times 0.2
The steeper the slope of a current vs voltage graph, the _________ the resistance.A. Not enough infoB. LowerC. The sameD. Greater
The slope of the graph current vs voltage can be explained with the next
[tex]\begin{gathered} V=IR \\ I=\frac{V}{R} \end{gathered}[/tex]In this case, current vs voltage means that current is y axis, and voltage is x axis. Based n that, the equation is the second one
[tex]I=\frac{V}{R}[/tex]And the slope is the inverse of the resistance. Dont forget that current - voltage is different to voltage - current
A chemical reaction separates water into hydrogen gas and oxygen gas. Which of the following statements is true about the mass of the water and the combined mass of the two gases
Answer:
The mass of the water is greater than the combined mass of the two gases
When two coherent waves combine destructively to create a minimum, what is the smallest phase difference possible in Degrees and Radians?
180° or π Radians is the smallest phase difference possible When two coherent waves combine destructively to create a minimum
Two waves of the same wavelength that are entirely out of phase with one another might cancel one another out or interact negatively. When there is a 180 degree or larger radian phase difference, this happens. Only when the two waves have the same amplitude do they completely cancel out. Partially destructive superposition occurs when two waves that are entirely out of phase yet have different amplitudes. The intensity is 0.
Superposition is the phenomenon in which the combined displacement of two combining waves is equal to their vector sum.
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The force diagram below is for a 10 kg object. Determine its acceleration.
As the buoyant force balances the weight of the object.
Thus, there is no motion of the object in the vertical direction.
Whereas, the force acting on the object towards the right is more than the drag force.
Thus, the net force acting on the object along the horizontal direction is,
[tex]F_{net}=F_T-F_{drag}[/tex]Substituting the known values,
[tex]\begin{gathered} F_{\text{net}}=35-10 \\ F_{\text{net}}=25N_{} \end{gathered}[/tex]According to Newton's second law, the net force acting on the object in terms of the acceleration of the object is,
[tex]F_{\text{net}}=ma[/tex]where m is the mass, and a is the acceleration,
Substituting the known values,
[tex]\begin{gathered} 25=10\times a \\ a=\frac{25}{10} \\ a=2.5ms^{-2} \end{gathered}[/tex]Thus, the acceleration of the object is 2.5 meters per second.
H
Hint: first convert the given final speed (in mph) to find ft/s, then solve for the distance and acceleration.
ANSWER
[tex]\begin{gathered} Dis\tan ce=149.56ft \\ Acceleration=4.14ft/s^2 \end{gathered}[/tex]EXPLANATION
First, we have to find the acceleration of the bicyclist.
To do that, we apply the formula:
[tex]a=\frac{v-u}{t}[/tex]where u = initial velocity
v = final velocity
t = time
Let us convert the speed given to feet per second. To do that, multiply the speed by 1.46667:
[tex]\begin{gathered} 24\cdot1.46667 \\ \Rightarrow35.2mph \end{gathered}[/tex]The bicyclist started from rest, so the initial speed is 0 ft/s.
Therefore, the acceleration is:
[tex]\begin{gathered} a=\frac{35.2-0}{8.5} \\ a=4.14ft/s^2 \end{gathered}[/tex]Now, to find the distance traveled, apply the formula:
[tex]s=ut+\frac{1}{2}at^2[/tex]Therefore, the distance traveled is:
[tex]\begin{gathered} s=(0\cdot8.5)+\frac{1}{2}\cdot4.14\cdot8.5^2 \\ s=\frac{1}{2}\cdot4.14\cdot8.5^2 \\ s=149.56ft \end{gathered}[/tex]Two ways to modulate a wave are to change the wave's ___ (AM) or the wave's__ (FM).
Answer:
AM - amplitude modulation
FM - frequency modulation
if may 20 is a last quarter moon, when could you expect the first quarter moon to occur?
In the early afternoon or high in the sky around the time, the sun is setting.
The crescent moon rises around noon and sets around midnight. It can be seen near the horizon in the evening or high in the sky as the sun sets. If you live in the northern hemisphere, the first quarter moon appears as the right half of the illuminated surface. Occurs when the moon is at right angles to the sun as seen from Earth.
The right half of the moon appears bright and the left half appears dark. During the period from the new moon to the first quarter moon, the illuminated part of the moon grows larger day by day and continues to grow until the full moon. The first quarter is also called the crescent moon because 50% of its surface is briefly illuminated by the sun. Usually, he takes 3 nights. Each phase of the moon has a profound effect on humans and the earth.
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Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]
For parallel plate capacitors the capacitance C=Aϵ0/d
dAϵ 0
Area, A Cd/ ϵ0 = 1 * 1×[tex]10^{-3}[/tex]/8.85× [tex]10^{-12}[/tex]
= 1.13×10 8 m 2.
The capacitance depending on geometry is given by the formula C=ϵ⋅Ad C = ϵAd. where C is the capacitance value A is the area of each plate, and d is the distance between the plates. plates, and ϵ is the dielectric constant of the material between the plates of the parallel capacitor.
The governing equations for capacitor design are C = εA/d where C is the capacitance. ε is the permittivity, a term that describes how well a dielectric holds an electric field. A is the area of the parallel plates. d is the distance between the two conductive plates. This is shown below. To calculate the total capacitance of multiple capacitors connected in this way, sum the individual capacitances.
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-%deviation from expected value (show calculations) in relation between frequency and radius.
When an object moves in a circular trajectory with a uniform speed, a centripetal force is needed to keep it in that trajectory. In the experiment, the hanging mass is used to keep the tension of the string constant. The tension is equal to the weight of the hanging mass, and it is responsible for keeping the rubber stopper in a circular trajectory.
The centripetal acceleration of a particle in a circular trajectory with radius r and frequency f is:
[tex]a_c=(2\pi f)^2r[/tex]On the other hand, if the mass of the hanging object is M and the mass of the rubber stopper is m, according to Newton's Second Law of Motion, the relationship between the tension of the string and the centripetal acceleration is:
[tex]\begin{gathered} \Sigma F=ma_c \\ \\ \Rightarrow T=m(2\pi f)^2r \\ \\ \Rightarrow Mg=m(2\pi f)^2r \end{gathered}[/tex]If we isolate f from that expression, we get a theoretical relationship between the radius and the frequency:
[tex]\begin{gathered} \Rightarrow(2\pi f)^2=\frac{Mg}{mr} \\ \Rightarrow2\pi f=\sqrt{\frac{Mg}{mr}} \\ \\ \therefore f=\frac{1}{2\pi}\sqrt{\frac{Mg}{mr}} \end{gathered}[/tex]To find the expected value for the frequency for different values of r, replace M=200g, m=15.3g, g=9.81m/s^2 and the different values of r:
[tex]\begin{gathered} f_{10cm}=\frac{1}{2\pi}\sqrt{\frac{(200g)(9.81\frac{m}{s^2})}{(15.3g)(0.10m)}}\approx5.70Hz \\ \\ f_{15cm}=\frac{1}{2\pi}\sqrt{\frac{(200g)(9.81\frac{m}{s^2})}{(15.3g)(0.15m)}}\approx4.65Hz \\ \\ f_{20cm}=\frac{1}{2\pi}\sqrt{\frac{(200g)(9.81\frac{m}{s^2})}{(15.3g)(0.20m)}}\approx4.03Hz \\ \\ f_{25cm}=\frac{1}{2\pi}\sqrt{\frac{(200g)(9.81\frac{m}{s^2})}{(15.3g)(0.25m)}}\approx3.60Hz \\ \\ f_{30cm}=\frac{1}{2\pi}\sqrt{\frac{(200g)(9.81\frac{m}{s^2})}{(15.3g)(0.30m)}}\approx3.29Hz \end{gathered}[/tex]On the other hand, we can find the experimental measurements for the frequency depending on the radius using the information provided in the table.
To do so, remember that the frequency is equal to the average number of spins from the three trials over the time.
The experimental values for the frequencies are:
[tex]\begin{gathered} f_{10cm-exp}=\frac{35+34+32}{3\times10s}\approx3.37Hz \\ \\ f_{15cm-exp}=\frac{31+29+27}{3\times10s}\approx2.90Hz \\ \\ f_{20cm-exp}=\frac{27+27+25}{3\times10s}\approx2.63Hz \\ \\ f_{25cm-exp}=\frac{25+23+24}{3\times10s}\approx2.40Hz \\ \\ f_{30cm-exp}=\frac{26+23+20}{3\times10s}\approx2.30Hz \end{gathered}[/tex]To find the percent deviation from the expected value, use the following formula:
[tex]\%dev=\frac{f_{exp}-f}{f}\times100\%[/tex]Then, the percent deviations from the expected values are:
[tex]\begin{gathered} \%dev_{10cm}=\frac{3.37Hz-5.70Hz}{5.70Hz}\times100\%\approx-40.9\% \\ \\ \%dev_{15cm}=\frac{2.90Hz-4.65Hz}{4.65Hz}\times100\%\approx-37.6\% \\ \\ \%dev_{20cm}=\frac{2.63Hz-4.03Hz}{4.03Hz}\times100\%\approx-34.7\% \\ \\ \%dev_{25cm}=\frac{2.40Hz-3.60Hz}{3.60Hz}\times100\%\approx-33.3\% \\ \\ \%dev_{30cm}=\frac{2.30Hz-3.29Hz}{3.29Hz}\times100\%\approx-30.1\% \end{gathered}[/tex]Aristotle's rhetorical triangle tells us that effective messages show awareness of
ethos, pathos, and logos
logic, emotion, and values
speaker, audience, and purpose
thought, voice, and opinion
Aristotle's rhetorical triangle tells us that effective messages show awareness of ethos, pathos, and logos. The correct answer to the question is option A.
What is Aristotle's rhetorical triangle?
Aristotle taught that a speaker's effective messages show awareness of the ethos, pathos, logos triangle, which expresses the idea that a good argument must be ethically, emotionally, and logically sound.
Ethos is a Latin word which means for ethics. This emphasize that that effective messages should show trust. The audience should be able to be confident of the source of information.Pathos talks about to the emotions.Logos is the Latin word for logic. The messages would be verified by the audience. The speaker would ensure there are facts backing up claims.In summary, Aristotle's rhetorical triangle shows that the Logos, Ethos, and Pathos are very important when giving an effective message.
Learn more about Aristotle's rhetorical triangle here: https://brainly.com/question/28261664
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Descriptions
A. Research that is designed to describe the characteristics or behaviors of a person or particular population
B. The thing the researcher changes in the experiment
C. Research that attempts to test cause and effect between two things
D. The thing that is influenced by another variable in an experiment
E. Research that attempts to assess the relationship between two aspects of human behavior
Fill in the blank with the letter of the description that best matches the term.
Descriptive Studies
PLEASE HELP!! IF SOMEONE KNOWS THE REST PLEASE TELL ME! THANKYOU!
Answer:
I think it is C
Explanation: