Mention three significant of water in coal fired power station

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Answer 1

Water in coal-fired power stations is used for cooling, steam generation, and pollution control, including capturing sulfur dioxide and cooling exhaust gases. Efficient water recycling helps minimize environmental impact.

Water plays a critical role in coal-fired power stations. The power stations need large quantities of water for a variety of purposes. Water is primarily used to cool the power plant, maintain a safe temperature in the boilers, and also to generate steam. In this context, this answer will discuss three significant uses of water in coal-fired power stations. Significant uses of water in coal-fired power stations1. Cooling: Power stations require water for cooling purposes. When water is used for cooling, it absorbs the heat produced by the combustion process. Cooling towers are responsible for releasing the heated water, which is then reused.2. Steam generation: Water is required to generate steam, which is used to rotate turbines and generate electricity. The water used to generate steam must be treated to prevent the accumulation of harmful minerals, which can damage the power plant.3. Pollution control: Water is utilized to reduce air pollution. Flue gas desulfurization systems utilize water to capture sulfur dioxide from power plants. Water is also used to cool exhaust gases that are produced during combustion.In conclusion, the three significant uses of water in coal-fired power stations include cooling, steam generation, and pollution control. These processes require large amounts of water, which is why coal-fired power stations are often located near water sources. By recycling water, power stations can conserve water and minimize their environmental impact.

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Related Questions

The composition of a compound is 28.73% K, 1.48% H, 22.76% P, and 47.03% O. The molar mass of the
compound is 136.1 g/mol.
I

Answers

The compound has an empirical formula of [tex]K_2H_2P_2O_8[/tex] and a molecular formula of [tex]K_2HPO_4[/tex].

The given compound has a percent composition of K = 28.73%, H = 1.48%, P = 22.76%, and O = 47.03%. Its molar mass is 136.1 g/mol. To determine its molecular formula, we need to find its empirical formula and calculate its molecular formula from its empirical formula.The empirical formula is the smallest whole number ratio of atoms in a compound. It can be determined by converting the percent composition of the elements into their respective moles and dividing each by the smallest number of moles calculated. The moles of K, H, P, and O in 100 g of the compound are: K = 28.73 g x (1 mol/39.1 g) = 0.734 molH = 1.48 g x (1 mol/1.01 g) = 1.46 molP = 22.76 g x (1 mol/30.97 g) = 0.736 molO = 47.03 g x (1 mol/16.00 g) = 2.94 molDividing each by the smallest number of moles gives the following ratios: K = 0.734/0.734 = 1H = 1.46/0.734 = 2P = 0.736/0.734 = 1.002O = 2.94/0.734 = 4. The empirical formula of the compound is [tex]K_2H_2P_2O_8[/tex]. To calculate the molecular formula, we need to determine the factor by which the empirical formula should be multiplied to obtain the molecular formula. This can be done by comparing the molar mass of the empirical formula to the molar mass of the compound.The molar mass of [tex]K_2H_2P_2O_8[/tex] is: [tex]M(K_2H_2P_2O_8)[/tex] = (2 x 39.1 g/mol) + (2 x 1.01 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol) = 276.2 g/mol. The factor by which the empirical formula should be multiplied is: M(molecular formula)/M(empirical formula) = 136.1 g/mol/276.2 g/mol = 0.4935. The molecular formula is obtained by multiplying the empirical formula by this factor: [tex]K_2H_2P_2O_8 * 0.4935 = K_2HPO_4[/tex]. Therefore, the molecular formula of the compound is [tex]K_2HPO_4[/tex].The molecular formula of the given compound having a composition of 28.73% K, 1.48% H, 22.76% P, and 47.03% O with a molar mass of 136.1 g/mol is [tex]K_2HPO_4[/tex]. The empirical formula of the compound is [tex]K_2H_2P_2O_8[/tex]. The compound's molecular formula is calculated by determining the factor by which the empirical formula should be multiplied to obtain the molecular formula. The factor is M(molecular formula)/M(empirical formula) = 136.1 g/mol/276.2 g/mol = 0.4935. The molecular formula of the compound is obtained by multiplying the empirical formula by this factor, resulting in the molecular formula [tex]K_2HPO_4[/tex].

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The correct question would be as

The composition of a compound is 28.73% K. 1.48% H, 22.76% P, and 47.03% O. The molar mass of the compound is 136.1 g/mol. What is the Molecular Formula of the compound?

[tex]KH_2PO_4\\KH_3PO_4\\K_2H_4P_20_{12}\\K_2H_3PO_6[/tex]

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