Melissa uses 3/5 as much water as Neil to water her plants. If Melissa uses 4 and 1/3 gallons of water, how much does Neil use?

20 to 25 minutes Transcription occurs at a rate of 40 nucleotides per second.

Given,

In the question:

If transcription progresses at the rate of 40 nucleotides per second.

To find the how long it would take to transcribe a sequence that is 3. 6 x 104 bases long?

Why is a nucleotide necessary?

Nucleotides have a variety of roles in animal physiology, including those of energy storage, transporters of activated metabolites for biosynthesis, structural moieties of coenzymes, and metabolic regulators.

Give an example of nucleotides and describe them.

A nucleotide is the fundamental part of nucleic acids (RNA and DNA). A nucleotide is made up of a nitrogen-containing base, a phosphate group, and a sugar molecule (either ribose in RNA or deoxyribose in DNA). The nucleotides used in DNA are adenine (A), cytosine (C), guanine (G), and thymine (T).

Hence, 20 to 25 minutes Transcription occurs at a rate of 40 nucleotides per second.

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a) Total surveyed students=1500

b) Drank alcohol or smoked cigarettes=1088.

c) Drank alcohol only=432

What is Venn Diagram?

A Venn diagram employs circles or other shapes that overlap to show the logical connections between two or more groups of objects. They frequently serve to visually group objects while highlighting how they differ and how they are similar.

Given, Alcohol drank → 857

         Smoked cigarettes → 639

         Illegal drugs used → 176

         Drank alcohol regularly and smoked cigarettes → 388

         Drank alcohol regularly and used illegal drugs →100

         Smoked cigarettes and used illegal drugs → 105

         Engaged in all three behaviors → 83

         Engaged for none of these → 358

         Notation used, Alcohol (A), Drugs (D), Cigarettes (C)

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Using the percentage, the amount of pure acid in 40 oz of 15% acid solution is 6 OZ.

In the given question,

The amount of pure acid in 40 oz of 15% acid solution is in OZ.

As we know that percentage is represent as a ratio of 100. So we solve it by converting the percentage.

So

=40×15%

So the simplified form is

=40×15/100

Simplifying

=6

Hence, the amount of pure acid in 40 oz of 15% acid solution is 6 OZ.

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Well the domain is the number of tickets and the range is the cost for those tickets.

So x = 1 when y = 125 (1 ticket is 125 dollars). Here is a reasonable domain and range comparision:

x = 1 , y = 125

x = 2, y = 250

x = 3, y = 375

x = 4, y = 500

ect...

The lower limit of the domain is 0 because you cannot have less than 0 tickets.

I hope this helps!

with 100 flips, the outcome is very likely to be 45 heads or even less.

just because you have a 50% chance of getting heads, does not necessarily mean that you will get heads at exactly 50%.

100 coin flips will not always produce a 50-50 outcome of heads or tails. This is due to the fact that random events, while predictable in the long run, are not 100% predictable in small cases. For example, if we flipped a fair coin a quadrillion times, the variability in the outcomes caused by the coin's randomness would amount to a fractional value so small that calculators might even round the percentage of heads to 50%. However, with 100 flips, the outcome is very likely to be 45 heads or even less.

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Answer:

y=9x

Step-by-step explanation:

For these x's and y's, we can notice that y is always equal to 9 times the value of x. 0 equals 9 * 0, 9 equals 9 * 1, 18 equals 9 * 2, 27 equals 9 * 3, and 36 equals 9 * 4.

We have just shown that y equals 9 times x, which is just y=9*x, or y=9x.

The zeroes of the polynomial is -7,-9 and the lesser x = -9, greater x = -7.

What is zeroes of polynomial?

We already know that a polynomial is an algebraic term with one or many terms. Zeroes of Polynomial are the real values of the variable for which the value of the polynomial becomes zero. So, real numbers, ‘m’ and ‘n’ are zeroes of polynomial p (x), if p (m) = 0 and p (n) = 0.

Given

f(x) = (x+8)² - 1

=x^2+64+16x-1

=x^2+16x+63

=x^2+7x+9x+63

=x(x+7)+9(x+7)

=(x+7)(x+9)

therefore, x=-7,-9

The lesser x = -9,

the greater x = -7.

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The key features of the graph of the exponential function are given as follows:

The y-intercept of a function gives the value of the function when it crosses the y-axis, that is, when x = 0, hence it is the initial number of mammals, which is of 120.

As x goes to infinity, the number of mammals will never be of zero but it will get very close to zero, hence the line y = 0 is the horizontal asymptote of the graph.

The graph is shown by the image given at the end of the answer.

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In the given coordinate plane, based on the given dilation the line r has slope 8 and coordinate (0,8)

Dilation:

Dilation refers the ratio of the given line to line by the scale factor.

Given

In the coordinate plane, line p has slope 8 and y-intercept (0, 5). Line r is the result of dilating line p by a factor of 3 with center (0, 3).

Here we need to find the the slope and y-intercept of line r.

Here we know that scale factor is 3.

Let us consider the slope of the line r will not change and the intercept is the addition of their ordinate will be.

So, it can be written as,

=> Intercept = 5 + 3

=> Intercept = 8

Therefore, the line r has slope 8 and coordinate (0.8).

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Answer:

Obtuse Angles

Step-by-step explanation:

Both < 3 and < 6 are visibly over 90° and less than 180°, so both are obtuse.

Answer:

With what?

Step-by-step explanation:

Answer:

Step-by-step explanation:

d

Answer:

the first one, the top left corner

Step-by-step explanation:

y- int = 5

no x int

The x value for each of the equation.

1)The x is 10 when the equation is 8=x-2

2)If x+2=-2, then the value of x is -4.

3)If 2=x+8, then the value of x is -6.

4)The x is -10 when the equation is x+8=-2

Given that,

The given equation are

1) 8=x-2

2) x+2=-2

3) 2=x+8

4)x+8=-2

We have to find the x value for each of the equation.

Take the equations,

1) 8=x-2

Adding 2 on both sides

8+2=x-2+2

10=x

The x is 10 when the equation is 8=x-2

2) x+2=-2

Adding 2 on both sides

x+2+2=-2+2

x+4=0

Adding -4 on both side

x+4-4=0-4

x=-4

If x+2=-2, then the value of x is -4.

3) 2=x+8

Subtracting 8 on both sides

2-8=x+8-8

-6=x

x=-6

If 2=x+8, then the value of x is -6.

4)x+8=-2

Adding -8 on both sides

x+8-8=-2-8

x=-10

The x is -10 when the equation is x+8=-2

Therefore, the x value for each of the equation.

1)The x is 10 when the equation is 8=x-2

2)If x+2=-2, then the value of x is -4.

3)If 2=x+8, then the value of x is -6.

4)The x is -10 when the equation is x+8=-2

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Probability that the coin lands heads exactly 11 times is 0.1602 so Option a is correct.

Given:

an unbiased coin is tossed 20 times.

The probability that the coin lands heads exactly 11 times:

P = n(E)/n(S)

n(S) = 2^tosses

= 2^20

= 1048576

n(E) = C(20,11)

= 20!/11!(20-11)!

= 20!/11!*9!

= 167960

Probability P = 167960/1048576

= 0.16017 ≈ 0.1602

Therefore Probability that the coin lands heads exactly 11 times is 0.1602 so Option a is correct.

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Answer:

3/32-pound cheese in 1 serving

Step-by-step explanation:

(3/8)/4=3/32 or 0.09375 lbs

Answer:

b i think

Step-by-step explanation:

becuase 45f in total and for every hour it decreses 2f the anwser would be b but i may be wrong

The mean of this distribution is 0.55

The standard error of this distribution is 0.0384

We have the following:

p=0.55

sample size, n=168

Mean of distribution:

Mean=true proportion of voters who support a restaurant

Mean=p=0.55

Hence, the mean of distribution is 0.55

Standard error of the distribution:

[tex]=\sqrt{\frac{p(1-p)}{n} }[/tex]

[tex]=\sqrt{\frac{0.55(1-0.55)}{168} }[/tex]

=0.0384

Hence, the standard error is 0.0384

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The questions was incomplete, the complete question is given below:

Suppose the true proportion of voters in the county who support a restaurant tax is 0.55. Consider the sampling distribution for the proportion of supporters with sample size n = 168.

What is the mean of this distribution?

What is the standard error of this distribution?

The each type of dinner cost is ribeye steak dinner cost is $20.05 and grilled salmon dinner cost is $16.74 by using the equation.

Given that,

On one particular day, a waitress served 12 grilled salmon dinners and 19 ribeye steak dinners for a total of $581.52. She made $581.59 on another day by selling 24 ribeye steak dinners and 6 grilled salmon entrees.

We have to find what was the price of each kind of dinner.

So,

We take R as a ribeye steak dinner and S as grilled salmon dinners.

We get,

19R+12S=$581.52 ---> equation(1).

24R+6S=$581.59 ----> equation(2).

Now Take the equation (2)

24R+6S=$581.59

6S=$581.59-24R

Multiply 2 on both sides of equation.

12S=$1163.18-48R

Now take the equation(1)

19R+12S=$581.52

Take the 12S as 12S=$1163.18-48R

19R+$1163.18-48R=$581.52

-29R=$581.52-$1163.18

-29R=-581.66

29R=581.66

R=581.66/29

R= $20.05

Now substitute R in 12S=$1163.18-48R

We get,

12S=$1163.18-48($20.05)

12S=$1163.18-962.4

12S=200.78

S=200.78/12

S=$16.74

Therefore, The each type of dinner cost is ribeye steak dinner cost is $20.05 and grilled salmon dinner cost is $16.74 by using the equation.

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In the given geometric sequence

a) The expression of the common ratio r = -6 and (m+8)/2

b) The possible value of m = -28

c) The possible value of r = -6

The geometric sequence is

-1 , 6, m+8

The the common ratio = second term / first term

= 6 / -1

= -6

The common ratio = third term /  second term

= (m+8)/6

The two expressions of common ratio is -6 and (m+8)/6

Part b

The third term = second term × common ratio

= 6 × -6

= -36

Then,

m +8  = -36

m = -36 + 8

m = -28

The possible value of m = -28

Part c

The possible value of r = -6

Hence, in the given geometric sequence

a) The expression of the common ratio r = -6 and (m+8)/2

b) The possible value of m = -28

c) The possible value of r = -6

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70-year-olds pay an extra $15708 for a 20-year term.

Given;

The average cost to a 50-year-old male for a $100,000 term life policy is $14. 34 per month. The same policy would cost a 70-year-old male $79. 79 per month.

A 70-year-average old's monthly expense (MAC) is $79.79

A 50-year-average old's monthly expense (MAC) is $14.34

MAC → Monthly Average Cost

To get how much more will the 70-year-old pay for a 20-year term;

We will multiply the monthly value by the yearly and solve the given data,

The extra amount paid = (MAC of 70 years old * 12 - MAC of 50 years old * 12) * 20 years term.

                                      = ($79.79 * 12 - $14.34 * 12) * 20

                                      = ($957.48 - $172.08) * 20

                                      = $15708

Hence, the excess amount 70-year-old pay for a 20-year term is $15708.

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Answer:

I believe it is the last option but I'm not completely sure because the pic is blurry. But if the beginning of the graph is at (-3, -4) then the last option is definitely correct.

Step-by-step explanation:

Remember h controls horizontal movement k controls vertical movements.

always remember to take the opposite of h.

;)

Answer:

A

Step-by-step explanation:

g(x) = f(x) + 3

Answer:

Step-by-step explanation:

You can use proportions to solve this.

You are paying $116.64 for 3 gallons of paint, so you could write this as:

\frac{116.64}{3}

Since the question is asking for price PER CUP, you want to convert 3 gallons to cups. 3 gallons = 48 cups. So now you can rewrite this as:

\frac{116.64}{48 cups}

In order to find the cost per cup, you can set up a proportion that solves for the price, x

\frac{116.64}{48 cups}  = \frac{x}{1 cup}

Solve for x by cross multiplying:

48x = 116.64

x = $2.43

It costs $2.43 per cup of paint

Answer: c

Step-by-step explanation:

The solution to the system of equations, using elimination, is given as follows:

x = 0.0135, y = -0.2767, z = -0.1024.

The solution to the system of equations is obtained using the elimination method, as the variables are written as functions of each other and then solved.

The system in this problem is composed by the equations presented as follows:

From the first equation, the variable z is written as function of variables x and y, as follows:

z = 5x - 3y - 1.

Replacing in the second equation, we have that:

x + 4y - 6(5x - 3y - 1) = -1

-29x + 22y = -7.

Replacing in the third equation, we have that:

2x + 3y + 4(5x - 3y - 1) = -1

22x - 9y = 3.

Hence the system is now:

Multiplying the first equation by 9 and the second by 22, we have that:

Adding the equations, the solution for x is obtained as follows:

223x = 3

x = 3/223

x = 0.0135.

Then the solution for y is obtained as follows:

-261(0.0315) + 198y = -63

y = (-63 + 261(0.0315))/198

y = -0.2767.

The solution for z is:

z = 5(0.0135) - 3(-0.2767) - 1 = -0.1024,

The problem asks to solve the system of equations using the elimination method.

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In the given situation, the work done by gravity is zero as any work done during a downward part of the motion as undone during the upward parts.

Work refers to the measurement of energy transfer that happens when an object is moved over a distance by an external force which is applied in the direction of the displacement. Hence, the work done is given by the multiplication of force and displacement in the direction of force i.e., W = F x d. As in the given case, the displacement d = 0 as the particle returns to the same point. The work done by gravity would measure the displacement along the y-axis and as the total displacement is zero, hence, work done will be zero.

Note: The question is missing the figure which is attached.

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The confidence interval at a 90% is 29.533 ≤ μ ≤ 40.467

Given that

mean = 35

standard deviation = 15

We compute the confidence interval as follows:

μ =¯ˣ± ME

Where:

To calculate the margin of error, we will use the t-distribution since the sample is very small n<30. Thus, our margin of error will be calculated as:

ME = t ×[tex]\frac{s}{\sqrt{n} }[/tex]

Where:

t = is the t-score at the 90% confidence level

degree of freedom df = 24 -1 =23

s = 15 is the standard deviation and,

n =24 is the sample size.

From the t-distribution tables, we will read the values of t at a critical value [tex]\alpha[/tex] = 0.10, and the degree of freedom is 23. This will give t= 1.714.

Thus, the margin of error is:

ME = 1.714 ×[tex]\frac{15}{\sqrt{23} }[/tex]

ME = 1.714 ×3.19

ME = 5.467

the confidence interval for the population mean is equal to:

μ = 35 ± 5.467

29.533 ≤ μ ≤ 40.467

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If the wait() and signal() semaphore operations are not executed atomically, then mutual exclusion may be violated as a wait operation atomically decrements the value associated with a semaphore.

Semaphores refers to integer variables utilized to solve the critical section problem by using two atomic operations, wait and signal that are used for process synchronization. The wait operation decreases the value of its argument S, if it is positive and if S is negative zero or negative, then no operation occurs. The signal operation increases the value of its argument S. Operation wait() and signal() must be completely atomic or else it violates the mutual exclusion. Mutual exclusion refers to the property of process synchronization which asserts that “no two processes can exist in the critical section at any given point of time”.

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