make (a) the subject of the formula (a)
a/2c
+
b/4 = 2

The answer is: B' = {1, 2, 3, 5, 7, 9} and C' = {1, 2, 3, 4, 5}, and A n (B'UC) = {2, 4, 5, 7}. This can be answered by the concept of Sets.

The complement of set B (denoted as B') in the universal set U is the set of natural numbers less than 11 that are not in B. The complement of set C (denoted as C') in the universal set U is the set of natural numbers less than 11 that are not in C. The intersection of set A with the union of sets B' and C (denoted as A n (B'UC)) is the set of elements that are common to set A and the union of sets B' and C, where B' is the complement of set B and C' is the complement of set C.

The universal set U consists of natural numbers less than 11: U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.

Set B' is the complement of set B in the universal set U, which means it contains all the elements of U that are not in B: B' = {1, 2, 3, 5, 7, 9}.

Set C' is the complement of set C in the universal set U, which means it contains all the elements of U that are not in C: C' = {1, 2, 3, 4, 5}.

The union of sets B' and C is the set of all elements that are in either B' or C or in both: B'UC = {1, 2, 3, 4, 5, 7, 9}.

The intersection of set A with the union of sets B' and C is the set of elements that are common to set A and the union of sets B' and C: A n (B'UC) = {2, 4, 5, 7}.

Therefore, the main answer is: B' = {1, 2, 3, 5, 7, 9} and C' = {1, 2, 3, 4, 5}, and A n (B'UC) = {2, 4, 5, 7}

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The second x distribution based on samples of size n=81 has a greater probability of P(6 < x < 10) than the first x distribution based on samples of size n=49 due to its wider z-score interval.

Assuming that both samples are taken from the same population with mean μ = 8, we can use the central limit theorem to approximate the sampling distribution of the sample mean for each sample size.

The central limit theorem states that the sampling distribution of the sample mean approaches a normal distribution with mean μ and standard deviation σ/sqrt(n), where σ is the population standard deviation (which we don't know, so we'll assume it's unknown) and n is the sample size.

Since we don't know σ, we can use the sample standard deviation s as an estimate of σ, and the standard error of the mean is then s/sqrt(n).

For the sample of size n=49, we have

Mean: μ = 8

Standard deviation: s/sqrt(n) = unknown/sqrt(49) = unknown/7

Standard error of the mean: s/sqrt(n) = unknown/7

For the sample of size n=81, we have

Mean: μ = 8

Standard deviation: s/sqrt(n) = unknown/sqrt(81) = unknown/9

Standard error of the mean: s/sqrt(n) = unknown/9

To determine which distribution has a greater probability of x being between 6 and 10, we need to calculate the z-scores for these values for each sampling distribution.

For the sample of size n=49

z-score for x=6: (6 - 8) / (unknown/7) = -14unknown/7

z-score for x=10: (10 - 8) / (unknown/7) = 14unknown/7

For the sample of size n=81:

z-score for x=6: (6 - 8) / (unknown/9) = -18unknown/9

z-score for x=10: (10 - 8) / (unknown/9) = 18unknown/9

We want to compare the probability of z-scores falling between -14unknown/7 and 14unknown/7 for the first sampling distribution, and between -18unknown/9 and 18unknown/9 for the second sampling distribution.

Since the z-score interval is wider for the second sampling distribution, it will have a greater probability of x falling between 6 and 10.

Therefore, the second x distribution based on samples of size n=81 has a greater probability of P(6 < x < 10) than the first x distribution based on samples of size n=49.

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The given question is incomplete, the complete question is:

Suppose an x distribution has mean μ = 8. Consider two corresponding x distributions, the first based on samples of size n = 49 and the second based on samples of size n = 81. For which x distribution is P(6 < x < 10) greater?

The function y = -4x² + 5x^(1/3) is both increasing and concave down on the interval ((5/24)^(3/5), ∞).

Interval notation: ((5/24)^(3/5), ∞)

To find the intervals where the function y = -4x² + 5x^(1/3) is both increasing and concave down, we need to take the first and second derivatives of the function.

First derivative:
y' = -8x + (5/3)x^(-2/3)

To find the critical points, we set y' = 0 and solve for x:
0 = -8x + (5/3)x^(-2/3)
8x = (5/3)x^(-2/3)
x = (5/24)^(3/5)

This critical point divides the x-axis into two intervals: (-∞, (5/24)^(3/5)) and ((5/24)^(3/5), ∞).

Second derivative:
y'' = -8x^(-4/3)

To determine concavity, we need to find where y'' is negative:
-8x^(-4/3) < 0
x^(-4/3) > 0
x > 0

So the function is concave down for all x > 0.

Therefore, the function y = -4x² + 5x^(1/3) is both increasing and concave down on the interval ((5/24)^(3/5), ∞).

Interval notation: ((5/24)^(3/5), ∞)

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The interest factor being referred to in the given table appears to be a compound interest factor.

The table contains a list of values corresponding to different time periods (end of year 6, 2, 3, 4, and 5) and their respective numerical values (1.06000, 1.12360, 1.19102, 1.26248, and 1.33823). These values represent the factor by which an initial amount would be multiplied in order to calculate the compound interest at the end of each time period. Compound interest refers to the interest that is calculated not only on the initial principal amount, but also on the accumulated interest from previous periods. Therefore, the table is showing the compound interest factor for different time periods.

The interest factors in the table are increasing, which means that the interest is compounding and accumulating over time. This suggests that the interest is being calculated based on a compound interest formula, such as the formula A = P(1 + r/n)^(nt), where A represents the final amount, P represents the principal amount, r represents the annual interest rate, n represents the number of times interest is compounded per year, and t represents the number of years. The values in the table are the result of applying this formula to different time periods with varying interest rates and compounding frequencies.

Therefore, based on the values and their increasing trend in the table, it can be concluded that the interest factor being referred to is a compound interest factor

Therefore, this table is related to compound interest.

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The perimeter of the island is 28 miles. To find the perimeter of the island, we need to add up the lengths of all four sides.

Perimeter is a term used in geometry to refer to the total length of the boundary of a two-dimensional shape. It is measured in units of length, such as meters or feet.

Similarly, the perimeter of a rectangle is the sum of the lengths of all four sides, with opposite sides being equal in length.

P = 2(l + w)

where P is the perimeter, l is the length, and w is the width.

P = 4s.

In general, the perimeter of any polygon can be found by adding up the lengths of all its sides.

The island is 4 miles wide and 10 miles long, so its perimeter would be:

P = 2(4) + 2(10)

P = 8 + 20

P = 28

Therefore, the perimeter of the island is 28 miles.

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The rate of change, based on y is a function of the distance traveled, z, and what it means is B. The ride costs $3 per mile.

The rate of change is the unit rate or the slope.

The rate of change also refers to the variable cost per unit.

The variable cost can be differentiated from the fixed cost since it varies according to the quantity involved.

Distance (mi), z Total Cost ($) y  Rate of Change

       0                        2                        $0

       1                         5                        $3 ($5 - $2)

      2                         8                        $3 ($8 - $5)

      3                         11                       $3 ($11 - $8)

      4                         14                       $3 ($14 - $11)

The Rate of Change = The Slope = Rise/Run = ($5 - $2)/(1 - 0)

Thus, based on the total cost of a ride-sharing trip, the unit rate is $3 per mile.

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The machine is not operating satisfactorily, and an adjustment is needed because the sample mean is outside the acceptable range.

Based on the given information, we need to determine if the soft-drink machine is operating satisfactorily and does not require any adjustment.

To do this, we will compare the sample mean (x) with the acceptable interval of the population mean (µ) as per the provided condition.

We are given that:
Population mean (µ) = 12 ounces
Standard deviation (σ) = 0.15 ounces
Sample size (n) = 81 drinks
Sample mean (x) = 11.8 ounces
z-score = ±1.960

Step 1: Calculate the standard error (SE) using the formula SE = σ/√n:
SE = 0.15/√81 = 0.15/9 = 0.0167

Step 2: Calculate the acceptable range using the provided z-score:
Lower limit = µ - z × SE

= 12 - 1.960 × 0.0167

≈ 11.967

Upper limit = µ + z × SE

= 12 + 1.960 × 0.0167

≈ 12.033

The acceptable range for the average content of the drinks is between 11.967 ounces and 12.033 ounces.

Since the sample mean (11.8 ounces) is outside this acceptable range, the machine is not operating satisfactorily, and an adjustment is needed.

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Answer:

y = |x| -1

Step-by-step explanation:

one unit downward would change the overall Y value by -1 unit

Answer:28

Step-by-step explanation: the whole angle has to sum to 90 ( 62 + x =90) so take away 90 from 62 to get x

Answer:

90

Step-by-step explanation:

just look at it with a ruler

Check the picture below.

[tex](8+16)(8)=(12+x)(12)\implies 192=144+12x \\\\\\ 48=12x\implies \cfrac{48}{12}=x\implies 4=x[/tex]

The measure of the length of the arc of the circle is s = 7.74 inches

Given data ,

The formula for calculating the arc length of a circle is given by:

s = r * θ

where:

s = arc length

r = radius of the circle

θ = angle in radians

Given that the radius of the circle is 8.6 inches and the angle measure is 0.9 radians

s = 8.6 * 0.9

s ≈ 7.74

Hence , the arc length is s = 7.74 inches

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No, you would be obtaining a convenience sample and not a random sample.(A)

By walking around your school campus and asking people you met how many keys they were carrying, you would be obtaining a convenience sample. A convenience sample is a type of non-random sampling method where the participants are chosen based on their availability and accessibility.

This method is not truly random, as it relies on your chance encounters with people and does not give every individual within the population an equal chance of being included in the sample.

A random sample, on the other hand, would involve selecting participants in a way that ensures each person has an equal opportunity to be chosen, which can reduce potential biases and increase the representativeness of the sample.(A)

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complete question:

If you walked around your school campus and asked people you met how many keys they were carrying, would you be obtaining a random sample? Chose the correct answer below.

A. No, you would be obtaining a convenience sample and a random sample.

B. Yes, you would be obtaining a random sample.

C. As long as you surveyed at least 100 people you would be obtaining a simple random sample.

D. No, you would be obtaining a biased sample.

To answer your question, it is possible to make a process more capable by doing all of the following things EXCEPT:
B. Making the specification limits wider

While ensuring that the process is centered (A) and ensuring the process is in control (C) contribute to improved process capability, making the specification limits wider (B) does not inherently make the process more capable, as it might lead to reduced quality and increased variability.

Process capability is a measure of how well a process can consistently produce output that meets the specification limits. It is influenced by various factors, including the centering of the process (A), the stability and control of the process (C), and the variability of the process output.

Centering the process (A) involves aligning the process mean or target value with the midpoint of the specification limits. This helps to minimize the potential for producing output that falls outside the specification limits, thereby improving process capability.

Ensuring the process is in control (C) means that the process is stable and predictable, with common causes of variation being identified and addressed. This helps to reduce variability in the process output, which in turn improves process capability.

On the other hand, widening the specification limits (B) without addressing the underlying causes of process variability does not inherently make the process more capable. In fact, it can lead to reduced quality and increased variability, as it allows for a larger range of output to be considered acceptable, even if it falls further from the ideal target value. This can result in increased defects and non-conforming output, negatively impacting process capability.

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To answer your question, it is possible to make a process more capable by doing all of the following things EXCEPT:
B. Making the specification limits wider

While ensuring that the process is centered (A) and ensuring the process is in control (C) contribute to improved process capability, making the specification limits wider (B) does not inherently make the process more capable, as it might lead to reduced quality and increased variability.

Process capability is a measure of how well a process can consistently produce output that meets the specification limits. It is influenced by various factors, including the centering of the process (A), the stability and control of the process (C), and the variability of the process output.

Centering the process (A) involves aligning the process mean or target value with the midpoint of the specification limits. This helps to minimize the potential for producing output that falls outside the specification limits, thereby improving process capability.

Ensuring the process is in control (C) means that the process is stable and predictable, with common causes of variation being identified and addressed. This helps to reduce variability in the process output, which in turn improves process capability.

On the other hand, widening the specification limits (B) without addressing the underlying causes of process variability does not inherently make the process more capable. In fact, it can lead to reduced quality and increased variability, as it allows for a larger range of output to be considered acceptable, even if it falls further from the ideal target value. This can result in increased defects and non-conforming output, negatively impacting process capability.

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Answer:

35.17yd

Formula used = 2*pie+r

Dimensions of the corral with maximum area are;

x = 200 ft
y = 100 ft

We'll use the given terms and solve for x and y.

1. Write the equation for the perimeter of the corral.
The corral has three sides of the rectangle (2x + y) and half the circumference of the semicircle (0.5 × π ×  y). The total fencing is 600 ft.
Equation: 2x + y + 0.5 × π ×y = 600

2. Solve for y in terms of x.
y(1 + 0.5 × π) = 600 - 2x
y = (600 - 2x) / (1 + 0.5 × π)

3. Write the equation for the area of the corral.
The corral's area is the sum of the rectangle area (x × y) and the semicircle area (0.5 × π × (y/2)²).
Equation: A(x) = x × y + 0.5 × π × (y/2)²

4. Substitute y in the area equation.
A(x) = x × [(600 - 2x) / (1 + 0.5 × π)] + 0.5 × π × ([(600 - 2x) / (1 + 0.5 × π)]/2)²

5. Find the derivative of the area equation with respect to x.
A'(x) = dA/dx

6. Set the derivative equal to zero and solve for x.
A'(x) = 0

7. Calculate the corresponding y value using the equation in step 2.

After performing the above calculations, you'll find the dimensions of the corral with maximum area:

x = 200 ft
y = 100 ft

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The variable that is the explanatory or predictor variable is advertising expenditure since the organisation wants to forecast income from advertising spend. Option D is correct.

The company wants to understand the relationship between their spending on internet-based advertising and their revenue. To do this, they need to determine which variable is the explanatory (or predictor) variable and which variable is the response (or outcome) variable. The explanatory variable is the variable that is thought to have an effect on the response variable.

In this case, the company wants to predict their revenue based on their spending on advertising, so the amount spent on advertising is the explanatory variable. The response variable is the variable that is being measured or observed, which in this case is the revenue generated by the company. By analyzing the relationship between these two variables, the company can make informed decisions about how much to spend on advertising to maximize their revenue. Option D is correct.

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The area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).

To find the area enclosed by the curve r=2sin(θ) 3sin(9θ), we first need to determine the limits of integration for θ.

Since the curve is periodic with period 2π/9 (due to the 9 in the second term), we only need to consider the portion of the curve in the interval [0, 2π/9].

Next, we need to convert the polar equation to rectangular coordinates, which can be done using the formulas x = r cos(θ) and y = r sin(θ).

Plugging in the given equation, we get:

x = 2sin(θ) cos(θ) + 3sin(9θ) cos(θ)
y = 2sin(θ) sin(θ) + 3sin(9θ) sin(θ)

Now we can find the area enclosed by the curve by integrating over the given interval:

A = ∫[0,2π/9] (1/2) [x(θ) y'(θ) - y(θ) x'(θ)] dθ

Using the formulas for x and y, we can find the derivatives x'(θ) and y'(θ):

x'(θ) = 2cos(θ) cos(θ) - 2sin(θ) sin(θ) + 27cos(9θ) cos(θ) - 27sin(9θ) sin(θ)
y'(θ) = 2cos(θ) sin(θ) + 2sin(θ) cos(θ) + 27cos(9θ) sin(θ) + 27sin(9θ) cos(θ)

Substituting these expressions into the formula for A and evaluating the integral, we get:

A = (243π/64) - (3√3/16)

Therefore, the area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).

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The volume of the tetrahedron is 1/18 cubic units.

To find the volume of the given solid, we can use a triple integral over the region of the volume of the tetrahedron is 1/18 cubic units.that corresponds to the solid.

The tetrahedron is enclosed by the coordinate planes (x=0, y=0, z=0) and the plane 3x + y + z = 2.

To set up the triple integral, we need to find the bounds of integration for x, y, and z.

From the equation of the plane, we can solve for z in terms of x and y:

z = (2 - 3x - y)/3

Since z=0 is one of the coordinate planes bounding the tetrahedron, we can set (2 - 3x - y)/3 = 0 and solve for y in terms of x:

y = 2 - 3x

Similarly, since y=0 is another bounding plane, we can set (2 - 3x - y)/3 = 0 and solve for x in terms of y:

x = (2 - y)/3

Finally, since x=0 is the third bounding plane, we don't need to solve for anything.

Therefore, the bounds of integration are:

0 ≤ x ≤ 2/3

0 ≤ y ≤ 2 - 3x

0 ≤ z ≤ (2 - 3x - y)/3

The volume of the tetrahedron is then given by the triple integral:

V = ∭[tex]_ R dV = \int _0 ^{2/3} \int _ 0 ^ 2-3x \int _0 ^{(2-3x-y)/3} dz dy dx[/tex]

Evaluating this integral yields:

V = 1/18

Therefore, the volume of the tetrahedron is 1/18 cubic units.

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We can use the tangent function to find the angle of elevation:

tan(theta) = opposite / adjacent

where opposite is the height of the kite and adjacent is the length of the string.

tan(theta) = 122 / 325

theta = arctan(122/325)

Using a calculator, we find that theta is approximately 20.2 degrees.

However, this angle is not the angle of elevation that we want. We want the angle between the string and the ground, which is the complement of theta:

90 - theta = 90 - 20.2 = 69.8

Rounding to the nearest degree, the angle of elevation is approximately 70 degrees.

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[tex]\textcolor{blue}{\small\texttt{If you have any further questions,}}[/tex] [tex]\textcolor{blue}{\small{\texttt{feel free to ask!}}}[/tex]

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The value of r is 0.953.

The correlation coefficient i.e., r is calculated by the formula,

r = nΣxy - (Σx)(Σy)/√(nΣx²-(Σx)²)(nΣy²-(Σy)²

where n = 5 is the sample size.

We create a table of required values,

x        y          x²          y²           xy

4        2         16           4             8  

5        9         25         81            45

8        10        64         100         80

9        12         81         144         108

13       23       169        529        299

∑ 39      56        355       858        540

Substitute the values in the formula,

r = (5 × 540 - (39)(56))/(√(5 × 355 - (39)²)(5 × 858 - (56)²))

r = (2700 - 2184)/(√(254)(1154)

r = 516/√(293116)

r = 516/541.4018

r = 0.953

Therefore, the value of r is 0.953.

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Domain = (-∞, -6]

Range = [2, ∞)

Domain = [-6, 1]

Range = [2, 3]

Domain = [1, ∞]

Range = [3, ∞]

We have,

The domain on the graph is the x-values and the range is the y-values corresponding to the x-values.

The graph of the function has three parts:

x - values:

1)

-∞ to x = -6

2)

x = -6 to x = 1

3)

x = 1 to ∞

y - values:

1)

y = 2 to ∞

2)

y = 2 to y = 3

3)

y = 3 to ∞

Now,

The domain is the x-values.

The range is the y-values.

Now,

Each part can be considered as having different functions.

So,

Domain = (-∞, -6]

Range = [2, ∞)

Domain = [-6, 1]

Range = [2, 3]

Domain = [1, ∞]

Range = [3, ∞]

Thus,

Domain = (-∞, -6]

Range = [2, ∞)

Domain = [-6, 1]

Range = [2, 3]

Domain = [1, ∞]

Range = [3, ∞]

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So, the Wronskian of the given pair of functions [tex]e^2^t[/tex] and [tex]e^\frac{-3t}{2}[/tex] is -3.5[tex]e^\frac{t}{2}[/tex] .

To find the Wronskian of the given pair of functions, 1. [tex]e^2^t[/tex] and [tex]e^\frac{-3t}{2}[/tex], you can follow these steps:

Step 1: Write the given functions as y1(t) and y2(t):
y1(t) = [tex]e^2^t[/tex]
y2(t) =  [tex]e^\frac{-3t}{2}[/tex]

Step 2: Calculate the derivatives of the functions:
y1'(t) = 2 [tex]e^2^t[/tex]
y2'(t) = (-3/2) [tex]e^\frac{-3t}{2}[/tex]

Step 3: Calculate the Wronskian using the determinant formula:
W(y1, y2) = | y1(t)  y2(t)  |
                  | y1'(t) y2'(t)|

W(y1, y2) = | [tex]e^2^t[/tex]       [tex]e^\frac{-3t}{2}[/tex]   |
                  | 2 [tex]e^2^t[/tex]  (-3/2) [tex]e^\frac{-3t}{2}[/tex] |

Step 4: Evaluate the determinant:
W(y1, y2) = [tex]e^2^t[/tex]  * (-3/2) [tex]e^\frac{-3t}{2}[/tex]  -  [tex]e^\frac{-3t}{2}[/tex]  * 2 [tex]e^2^t[/tex]

Step 5: Simplify the expression:
W(y1, y2) = (-3/2) [tex]e^\frac{t}{2}[/tex]  - 2 [tex]e^\frac{t}{2}[/tex]
W(y1, y2) = -3.5 [tex]e^\frac{t}{2}[/tex]

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The probability that both of the selected letters are same letters is 1/10 or 0.1.

First, we need to determine the total number of ways to select two letters from the word "examination".

The word "examination" has 11 letters. Therefore, there are 11 ways to choose the first letter, and 10 ways to choose the second letter (since we cannot choose the same letter again).

So, the total number of ways to select two letters from "examination" is 11 * 10 = 110.

Next, we need to determine the number of ways to select two same letters.

We can choose any of the 11 letters, and the second letter must be the same as the first letter.

So, there are 11 ways to choose the same pair of letters.

Therefore, the probability of selecting two same letters is:

11 / 110 = 1 / 10

So, the probability that both of the selected letters are same letters is 1/10 or 0.1.

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If A be a 5 × 4 matrix and let b and c be two vectors in [tex]R^5[/tex] and we are told that Ax = b is inconsistent, then the number of solutions for A * x = c could be unique, infinite, or none, based on the given information.

Since A is a 5x4 matrix and b and c are vectors in [tex]R^5[/tex], we know that A * x = b and A * x = c are systems of linear equations with x being a 4x1 vector.
We are given that A * x = b is inconsistent, which means it has no solutions. Now, let's analyze the system A * x = c.
1. If A * x = c has a unique solution, it would mean that there is a vector x for which the system A * x = b is inconsistent but A * x = c is consistent. This is possible.
2. If A * x = c has infinitely many solutions, it would mean that the system A * x = c has a free variable and there are infinitely many combinations of x that satisfy the equation. This is also possible.
3. If A * x = c has no solution (inconsistent), then both systems A * x = b and A * x = c would be inconsistent, which is also possible.
Therefore, the number of solutions for A * x = c could be unique, infinite, or none, based on the given information.

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Answer :- The value of dzdt at (x, y) = (4, 0) is 0

To find dzdt at (x, y) = (4, 0) given z^3 = x^3 y^2, dxdt = 3, and dydt = 2, follow these steps:

1. Write down the given equation: z^3 = x^3 y^2
2. Differentiate both sides with respect to t (using the chain rule and product rule): 3z^2(dzdt) = 3x^2(dxdt) * y^2 + x^3 * 2y(dydt)
3. Plug in the given values dxdt = 3, dydt = 2, and (x, y) = (4, 0): 3z^2(dzdt) = 3(4^2)(3) * 0^2 + 4^3 * 2(0)(2)
4. Since y = 0, the right side of the equation becomes 0: 3z^2(dzdt) = 0
5. However, we are given z > 0, which means z is not equal to 0. Thus, we can divide both sides by 3z^2: dzdt = 0

So, the value of dzdt at (x, y) = (4, 0) is 0.

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The calculated value of the area of the figure  is 157 sq ft

From the question, we have the following parameters that can be used in our computation:

Composite figure

The shapes in the composite figure are

This means that

Area = Parallelogram + trapezoid

Using the area formulsa on the dimensions of the individual figures, we have

Area = 8 * 6.5 + 1/2 * (15 + 20) * 6

Evaluate

Area = 157

Hence, the area of the figure below  is 157 sq ft

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We can use the z-score associated with the 80th percentile to calculate the upper bound of the interval using the formula: sample mean + 0.84*(σ/√n).

To round the answer to at least two decimal places, we need to know the values of n and σ. Without that information, we can't provide a specific numerical answer.

To find the 80th percentile of the sample mean, we first need to calculate the sample mean and standard deviation. Let's assume we have a sample of size n and we know the population standard deviation σ.

Using the central limit theorem, we know that the sample mean follows a normal distribution with mean μ and standard deviation σ/√n. Since we don't know the population mean μ, we can use the sample mean as an estimate.

Next, we need to find the z-score associated with the 80th percentile. We can use a z-table or a calculator to find that z = 0.84.

Finally, we can use the formula for the confidence interval of the sample mean:

sample mean ± z*(standard deviation/√n)

Plugging in the values, we get:

sample mean ± 0.84*(σ/√n)

Since we're looking for the upper bound of the 80th percentile, we only need to consider the positive value of the interval:

sample mean + 0.84*(σ/√n)

This represents the value that separates the top 20% of sample means from the bottom 80%.

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The word problem's solution states that 86 adult tickets were sold on that particular day.

A mathematical statement that demonstrates the equality of two expressions is called an equation. The two expressions are separated by the equal character "=". Variables, constants, and mathematical operations like multiplication, division, addition, subtraction, exponents, etc. may be used in the equations on either side of the equal sign.

Assume that "c" represents the number of child tickets sold and "a" represents the number of adult tickets sold.

From the information provided, we understand that:

A young person's ticket costs $6.10

A ticket for an adult costs $9.40.

There have been 136 tickets sold in total.

$1027.60 has been earned in total from the selling of tickets.

To express the provided information, we can put up two equations:

c + a = 136 (Equation 1: amount of tickets sold overall)

6.10c + 9.40a = 1027.60 (Equation 2: the total amount made from ticket sales)

Equation 1 can be used to express "c" in terms of "a" in order to solve for "a":

c = 136 - a

By entering this expression in place of "c" in Equation 2, we obtain:

6.10(136 - a) + 9.40a = 1027.60

By enlarging and streamlining this equation, we arrive at:

830.96 - 2.3a = 1027.60

830.96 from both sides is subtracted to arrive at:

-2.3a = 196.64

By multiplying both sides by -2.3, we obtain:

a ≈ 85.5

We can round this up to 86 as "a" denotes the quantity of adult tickets that were sold. As a result, 86 adult tickets were sold on that particular day.

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