Lukalu is rappelling off a cliff. The parametric equations that describe her horizontal and vertical position as a function of time are x ( t ) = 8 t and y ( t ) = − 16 t 2 + 100 and . How long does it take her to reach the ground? How far away from the cliff is she when she lands? Remember to show all of the steps that you use to solve the problem.

Answers

Answer 1

SOLUTION

Now the ground is assumed to be 0, so we have that

[tex]y(t)=0[/tex]

So, that means we have

[tex]\begin{gathered} y(t)=-16t^2+100 \\ 0=-16t^2+100 \\ 16t^2=100 \\ t^2=\frac{100}{16} \\ t=\sqrt{\frac{100}{16}} \\ t=\frac{10}{4} \\ t=2.5\text{ seconds } \end{gathered}[/tex]

Now, we have found t, which is how long it takes to get to the ground, you can plug it into x(t) to find the horizontal distance travelled, we have

[tex]\begin{gathered} x(t)=8t \\ x(2.5)=8\times2.5 \\ =20\text{ feet } \end{gathered}[/tex]

Hence it takes her 2.5 seconds to reach the ground

And she is 20 feet away from the cliff


Related Questions

Of the 100 million acres in California,
the federal government owns 45 million
acres. What percent is this?

Answers

Step-by-step explanation:

you do know what a percent is ?

1% is the 1/100 part of a whole.

when we have

100,000,000 (one hundred million),

how many 1/100 parts of that are

45,000,000 (45 million)?

well, 45.

45,000,000 is 45/100 of 100,000,000

in other words 45%.

the variable y varies directly as x. when x =20, y= 12 what is the value of y when x = 15a:7b:9c:18d:25

Answers

To direct variations use a rule of three, as follow:

[tex]\begin{gathered} \frac{?}{12}=\frac{15}{20} \\ \\ ?=12*\frac{15}{20} \\ \\ ?=\frac{180}{20} \\ \\ ?=9 \end{gathered}[/tex]Then, when x=15, y is 9Answer: B.9

Find the minimum value of
C = 6x + 3y
Subject to the following constraints:
x > 1
y ≥ 1
4x + 2y < 32
2x + 8y < 56

Answers

Answer:

  9

Step-by-step explanation:

You want the minimum value of objective function C=6x+3y, given the constraints x>1, y≥1, 4x+2y<32, and 2x+8y<56.

Minimum

The objective function has positive coefficients for both x and y, so it will be minimized when x and y are at their minimum values. The constraints tell you these minimum values are x=1 and y=1, so the minimum value of C is ...

  C = 6(1) +3(1) = 9

The minimum value of C is 9.

__

Additional comment

The value of x cannot actually be 1, so the value of C cannot actually be 9. However x may be arbitrarily close to 1, so C may be arbitrarily close to 9.

  C = 6x +3y   ⇒   x = (C -3y)/6

The x-constraint requires ...

  x > 1

  (C -3y)/6 > 1

  C -3y > 6 . . . . . . multiply by 6

  C > 6 +3y . . . . . . add 3y

The minimum value of y is exactly 1, so we have ...

  C > 6 +3(1)

  C > 9

Omar earns $7 each time he sweeps the house. He sweeps
the house 3 times. How much money does Omar earn?

Answers

Answer:

$21

Step-by-step explanation:

27 dollars from sweeping

please slove this for me-3(x+1)<15

Answers

-3(x+1)<15 ​

Divide both-side of the inequality by -3

(x + 1) > -5

subtract 1 from both-side of the inequality

x > -5 - 1

x > -6

Answer:

Step-by-step explanation:

-3(x+1)<15

Divide the inequality by -3, so we need to change the sides of the less than into greater than

x+1 > -5

x > -5 - 1

x > -6

20 pts, precalc, see attach
If f (x) = 3x2 + 5x − 4, then the quantity f of the quantity x plus h end quantity minus f of x end quantity all over h is equal to which of the following?

Answers

The numeric value for the given expression is as follows:

[tex]\frac{j(x + h) - j(x)}{h} = \frac{4^{x - 2}(4^h - 1)}{h}[/tex]

How to find the numeric value of a function or of an expression?

To find the numeric value of a function or of an expression, we replace each instance of the variable in the function by the desired value.

In the context of this problem, the function j(x) is given as follows:

[tex]j(x) = 4^{x - 2}[/tex]

At x = x + h, the numeric value of the function is found replacing the lone instance of x by x + h as follows:

[tex]j(x + h) = 4^{x + h - 2}[/tex]

For the fraction, the subtraction at the numerator is given as follows, applying properties of exponents:

[tex]j(x + h) - j(x) = 4^{x + h - 2} - 4^{x - 2} = 4^{x - 2}(4^h - 1)[/tex]

As the x - 2 term is common to both exponents.

Just dividing by h, the numeric value of the entire expression is given as follows:

[tex]\frac{j(x + h) - j(x)}{h} = \frac{4^{x - 2}(4^h - 1)}{h}[/tex]

Which means that the third option is correct.

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What is the P(A and B) if P(A) = 1/2 and P(B) = 2/7, where A and B are independent events?5/81/71/121/2

Answers

EXPLANATION:

To calculate the number of independent events that occur, the product of the probabilities of the individual events occurring must be calculated.

Therefore if A and B are independent events then:

P (A and B) = P (A) • P (B)

The exercise is as follows:

[tex]\begin{gathered} \frac{1}{2}\times\frac{2}{7}=\frac{2}{14};\text{ Now }we\text{ must take }square\text{ r}oot; \\ \frac{2}{14}=\frac{1}{7} \\ \text{ANSWER: }\frac{1}{7} \end{gathered}[/tex]

NOTE:

To obtain the product of two fractions, the numerators must be multiplied with each other and the denominators must also be multiplied with each other.

Which of the following is equivalent to 1,000,000?

Answers

The statement that  is equivalent to 1, 0 0 0, 0 0 0 is: C. 10 power of 6.

Determining the equivalent number

Given digit:

1,0 0 0,0 0 0

Hence,

When something  is equivalent to another things it implies or means  that both of them are the same  or correspond.

We know that 1,000,000 can be re- write as 1 Million and  1000 Thousands.

Now let determine or find the equivalent of 1,000,000 using scientific notation

Scientific notation  = 1,000,000

Scientific notation = 10^6

Based on the above  10^6 is equivalent to 1,000,000. We can justified it by pressing 10^6 on our calculator which will in turn gives us 1,000,000.

So,

1,000,000 = 10^6

Therefore we can conclude that the correct option is C based on the fact that 10  raise to power of 6 is the same as 1,0 0 0,0 0 0.

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The complete question is:

Which expression is equivalent to 1,000,000?

A .5 power of 10. B .6 power of 10. C. 10 power of 6. D. 10 power of 5

The perimeter of the figure is 18 units. Complete the statements to find the side lengths.


1. Find the distance from A to B. Explain how you found this distance.



2. Add the distances of the vertical and horizontal segments. These are the distances from A to B, B to C, and C to D. Show how you found the total.


3. Use the perimeter to find the length of segment AD. This is the distance from A to D. Explain how you found your answer.

Answers

Answer:

1.

the distance is 6 units

Explanation: you can just count the squares cince the line is straight and even if you use the Distance Formula... you'll get the same answer.

2.

A to B = 6 units

B to C = 4 units

C to D = 3 units

So...

6+4+3 = 13 units

3.

The distance between A to D is = 5 units

You can find the answer by using the Distance Formula.

which function is best represented by this graph?A) f(x) = -3x² + 2x + 1 B) f(x) = 3x² + 2x - 4C) f(x) = x² + x - 4D) f(x) = x² + 2x - 3

Answers

Answer:

From the graph, the roots of the equation are given below as

[tex]\begin{gathered} x=-3 \\ x=1 \end{gathered}[/tex]

These are the points where the curve cuts the x-axis

The y-intercepts of the graph is given below as

[tex](0,-3)[/tex]

Concept:

To find the equation of the graph, we will use the formula below

[tex]\begin{gathered} f(x)=a(x+3)(x-1) \\ x=0,y=-3 \\ -3=a(0+3)(0-1) \\ \frac{-3}{-3}=\frac{-3a}{-3} \\ a=1 \end{gathered}[/tex]

Hence,

By substituting the values, we will have

[tex]\begin{gathered} f(x)=a(x+3)(x-1) \\ f(x)=1(x+3)(x-1) \\ f(x)=x^2-x+3x-3 \\ f(x)=x^2+2x-3 \end{gathered}[/tex]

Hence,

The function of the graph is

[tex]f(x)=x^2+2x-3[/tex]

OPTION D is the right answer

Help pleaseeeeeeeeeeeee

Answers

First, notice that we have in total 15 items. Then, we have that the probabilities are:

[tex]\begin{gathered} \text{ \# of items with yellow: }3 \\ \Rightarrow P(Yellow)=\frac{3}{15}=\frac{1}{5} \\ \text{ \# of items with purple: 2} \\ \Rightarrow P(Purple)=\frac{2}{15} \\ \text{ \# of items striped: 4} \\ \Rightarrow P(not\text{ striped)}=1-P(striped)=1-\frac{4}{15}=\frac{11}{15} \\ \text{ \# of items solid: 5} \\ \Rightarrow P(solid)=\frac{5}{15}=\frac{1}{3} \\ \text{ \#items with polka dot: 3} \\ \Rightarrow P(not\text{ polka dot) = 1 - P(polka dot) = 1-}\frac{3}{15}=\frac{4}{5} \end{gathered}[/tex]

Mary’s credit card company charges 16% interest on her outstanding credit card balance each month. Her minimum payment is $20 each month. Mary’s credit card bill is $70 in January. Mary only pays the minimum amount each month, and she does not spend any additional money on her credit card. How long, in months, will it take her to pay off her bill from January?

Answers

Answer:

Step-by-step explanation:

ionoknionoinponpoihj

Answer:

Step-by-step explanation:

tipptrptprprprptprtprptpprtprtpprtprptprtprptprtprptr

Help me pretty please I need help

Answers

Answer:i have no idea good luck

Step-by-step explanation:

Answer:

4,3 DONT BE MAD IF IM WRONG

Explain why the volume of these two stacks of quarters are equal? Use Cavaliens principle in your explanation (If you need to)

Answers

Given the word problem, we can deduce the following information:

1. Two stacks of 18 pennies each are shown.

To determine if the volumes of the given stacks of quarters are equal, we note that Cavelieri's Principle states:

The volumes of two solids are equal if the areas of the corresponding sections drawn parallel to some given plane are equal.

Since each penny in both stacks has the same base area and has the same number of pennies. Therefore, the volumes of the given stacks are equal.

A school offers band and chorus classes. The table shows the percents of the 1200 students in the school who are enrolled in band, chorus, or neither class. How many students are enrolled in both classes?

Class Enrollment
Band 34%
Chorus 28%
Neither 42%

Answers

168 students are enrolled in both classes.

This is a problem from set theory. We can solve this problem by following a few steps easily.

First of all, we have to calculate the students present in both classes.

Student present in both classes = the total student - the student not enrolled in both classes.

So the percentage of the students enrolled in both classes or any of one class is ( 100% - 42% ) = 58%.

Now, the students only enrolled in chorus class is ( 58% - 34%) = 24%

So, the students who joined both classes is ( 28%- 24%)= 4%

The total student is 1200, then 4% of the total student is

( 1200 × 14 )/100 = 168 students.

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Solve the following inequality algebraically. [tex] |x - 1| \leqslant 13[/tex]

Answers

lx-1 l ≤ 13

There are 2 solutions:

x-1 ≤ 13

and

x-1 ≥ -13

Solve each one

x-1 ≤ 13

add 1 to both sides of the equation

x-1+1≤ 13+1

x ≤ 14

x-1 ≥ -13

Add 1 to both sides:

x-1+1 ≥-13+1

x ≥ -12

-12 ≤ x ≤ 14

You will purchase snacks for the painting class. You have abudget of $40. You want to buy fruit and granola bars. Fruit costs $4 perpound, and the granola bars are $1 each. You need at least 20 granolabars. What combinations of fruit and granola bars can you buy?My variables- f-fruits g-granola

Answers

Writing inequalitiesWhat we know?

Budget: $40

Fruit: $4/pound

Granola bars: $1 each

At least 20 granolas

Let's call

f: number of pounds of fruit

g: number of granola bars

Therefore

The total cost of fruit is given by: $4 · f

The total cost of granola is given by: $1 · g

The total cost of everything is given by: $4 · f + $1 · g

Since budget: $40 then

$4 · f + $1 · g = $40

4f + g = 40

g > 20 means we have at least 20 granolas

4f + g > 20 means that we have at least 20 granolas, that cost $20, since 4f + g = 40 and 40 > 20

1118 11 + 600-1110
[tex]12 \times (5 + 4)[/tex]

Answers

Answer:

111811 + 600 - 1110

111871 - 1110

= 110761

12 × (5+4)

60+4

= 64

1,857.205 round each number to the place of the underlined digit.0 is the underlined digit

Answers

Answer:

1,857.21

Explanation:

In the number: 1,857.205

The digit after 0 is 5.

Since it is a number between 5 and 9, we round up to obtain:

[tex]1,857.205\approx1,857.21\text{ (to the nearest hundredth)}[/tex]

Last year Collin's salary was $45,000. Because of furlough days, this year his salary was $30,000. Find the percent decrease.Round to the the nearest tenth of a percent

Answers

ANSWER:

33.3%

STEP-BY-STEP EXPLANATION:

We can calculate the value of the percentage starting from the following equation:

[tex]45000-x\cdot45000=30000[/tex]

We solve for x:

[tex]\begin{gathered} -x\cdot45000=30000-45000 \\ x=\frac{15000}{45000} \\ x=\frac{1}{3}=0.333 \\ \text{ in the percent form:} \\ 0.333=33.3\text{\%} \end{gathered}[/tex]

The percentage that decreased was 33.3%

On the first day of summer break, Katie and her friends go to the theater to see the latest action movie, Dark Emperor: Fist of Vengeance. After Katie buys a ticket, she also buys a bucket of popcorn and a soda for $9.25. In all, Katie spends $23.25 at the movie theater. Which equation can you use to find the cost c of Katie's ticket?

Answers

We have the following information:

c is the cost of Katie's ticket; a bucket of popcorn and a soda cost $9.25, we determine c by using the following expression:

[tex]c=23.25-9.25\Rightarrow c=14[/tex]

(This assuming there is no additional information).

Answer:1234567890

Step-by-step explanation:

hguhouhujnkujnuhb uj kj bk

There are two box containing only yellow and black pens

Answers

SOLUTION; Concept

Step1: Identify the giving information in the question

BOX A contains

[tex]\begin{gathered} 9\text{ yellow pens} \\ 6\text{ Black pens } \end{gathered}[/tex]

BOX B contains

[tex]\begin{gathered} 9\text{ yellow pens } \\ 11\text{ black pens} \end{gathered}[/tex]

Step2: Find the probability of each event

Event 1: Choosing a green pen from the Box B

[tex]\begin{gathered} \text{ Since there is no gr}een\text{ pen in the box, then probability of choosing a gr}en\text{ box in Box B is 0} \\ \text{then probability of choosing a gr}en\text{ box in Box B is 0} \\ Pr(E1)=0 \end{gathered}[/tex]

Event 2: Choosing a black pen from the Box B

[tex]P(E2)=\frac{11}{9+11}=\frac{11}{20}=0.55[/tex]

Event 3: Choosing a yellow or black pen from the Box A

Since Box A contains only a yellow or black pen then the probability is

[tex]Pr(E3)=1[/tex]

Event 4: Choosing a yellow pen from box A

Since there are 9 yellow pens in box A, the probability of choosing the yellow pen is

[tex]Pr(E4)=\frac{9}{9+6}=\frac{9}{15}=0.6[/tex]

Probability describes the likelihood of the event.

Hence From least likely to most likely the occurrence of the event is arranged as follows according to the probability of each event

[tex]\text{Event }1\rightarrow\text{ Event 2}\rightarrow\text{ Event 4}\rightarrow\text{ Event 3}[/tex]

A textbook store sold a combined total of 217 sociology and history textbooks in a week. The number of history textbooks sold was 77 less than the number of
sociology textbooks sold. How many textbooks of each type were sold?

Answers

Answer:

there were 246 chemistry textbooks and 169 psychology textbooks sold

Step-by-step explanation:

Let

c = the number of chemistry textbooks sold

p = the number of psychology textbooks sold

a textbook store sold a combined total 415 chemistry and psychology textbooks in a week

c + p = 415

the number of chemistry textbooks sold was 77 more than the number of psychology textbooks sold

c = 77 + p

by solving the system of equations

c + p = 415

c = 77 + p

we find

c = 246 chemistry textbooks

p = 169 psychology textbooks

six men can complete a certain work in 20 days .how many men are required to complete the same work in 12 days ?

Answers

6 men complete the work in 20 days.

In 1 day it takes:

6 x20 = 120 men

You need to do the same work done in 20 days, in one day. (more manpower)

So, to finish the work in 12 days:

120 men / 12 days = 10 men

Dog Owners5. A city council wants to know if residents would like a dogpark. They sent a survey to every household in the city.The results of those who responded are shown in the tableat the rightNumbexof Dogs inHouseholdNumber ofHouseholds0513a What is an appropriate first step in finding the experimentalprobability that a household has 2 or more dogs?12182 or more129Find the product of the number of households withone dog and the number with two or more dogs.Find the difference of the number of households with twoor more dogs and the number with no dogs.© Find the sum of the number of households for each category.Find the difference of the number of households with no dogsand the number with one dog or more.b. What is the experimental probability that a householdhas 2 or more dogs?

Answers

Given:

A table represents a survey to know if residents would like a dog.

a) What is an appropriate first step in finding the experimental probability that a household has 2 or more dogs?

The first step is to find the total households

So, the answer will be option C

Find the sum of the number of households for each category.

b) What is the experimental probability that a household has 2 or more dogs?

First, the total number of households = 513 + 218 + 129 = 860

And the number of households has 2 or more dogs = 129

So, the probability = 129/860 = 0.15 = 15%

So, the answer will be 15%

HELP PLEASE ASAP!!!!!!!!!!

Answers

Answer:

a b

Step-by-step explanation:websites and etc helped.


Solve 5 and 6
for 40 POINTS

Answers

Answer:

A= 184.4 yards

Step-by-step explanation:

couldnt figure out b

Find the average rate of change of f(x) = - 2x ^ 2 - x from x = 1 to x = 6 . Simplify your answer as much as possible .

Answers

The average rate of change of a function in the interval [a,b] is given by:

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

In this case we have that a=1 and b=6; plugging these values in the formula above we have:

[tex]\begin{gathered} \frac{-2(6)^2-6-(-2(1)^2-1)}{6-1}=\frac{-2(36)-6-(-2(1)-1)}{5} \\ =\frac{-72-6-(-2-1)}{5} \\ =\frac{-78-(-3)}{5} \\ =\frac{-78+3}{5} \\ =\frac{-75}{5} \\ =-15 \end{gathered}[/tex]

Therefore, the average rate of change in the interval is -15

FV - OVSolve for FV in the scientific formula A =Twhere FV and OV are variables.FV =Pls help

Answers

FV=OV +TA

1) To solve for a variable means let that variable isolated on one side of the equation.

[tex]A=\frac{FV-OV}{T}[/tex]

2) Since we want to solve for FV, let's multiply it crossed like this

[tex]\begin{gathered} TA=FV-OV \\ -FV+TA-TA=-OV-TA \\ -FV=-OV-TA \\ FV=OV\text{ +TA} \end{gathered}[/tex]

3) So now we can solve for FV, all that's left are the figures for OV and TA.

On average, Peter goes through three fish hooks in order to catch 7 fish. How many hooks can he expect to use if he needs to catch 189 fish?

Answers

By solving a proportional relation, we conclude that he needs 81 hooks to catch 189 fish.

How many hooks can he expect to use if he needs to catch 189 fish?

We assume there is a proportional relationship of the form:

F = k*H

where:

F = number of fish.k = constant of proportionality.H = number of hooks.

We know that with 3 hooks he catches 7 fish, then we can replace that:

7= k*3

7/3 = k

So the proportional relation is:

y = (7/3)*x

Then if he wants to get 189 fish we can write:

189 = (7/3)*x

And solve this for x:

189*(3/7) = x =81

He will need 81 hooks.

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