look at the screenshot

Answer:

Fractions help children understand the nature of numbers and their interactions (e.g., the meaning of division). If a child doesn't understand how fractions work, it will interfere with his ability to learn algebra later.

Step-by-step explanation:

hope it helps you

Answer:

it is C.60.24. You are right

Answer:

481.65

Step-by-step explanation:

You like add all the expenses together to like give you a total amount. Once you have the total expense you like minus it from the money at hand

Answer:

I need help too so can you help me first  asap. all I  need is a one fact about The Immortal life of Henrietta lacks and an summary about swimming Olympic.

Answer:

1 and 2 is vertical angles and 4 and 3 are adjacent angles

Step-by-step explanation:

hello!

the answer to your question is 41!

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explanation:

- Step 1: Our output value is 100.

- Step 2: We represent the unknown value with [tex]x[/tex].

- Step 3: From step 1 above, [tex]100 = 100%[/tex]%

- Step 4: Similarly, [tex]x = 41%[/tex]%

- Step 5: This results in a pair of simple equations:

[tex]100 = 100% (1)[/tex]% (1)

[tex]x=41[/tex]% (2)

- Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both  equations have the same unit (%); we have

[tex]\frac{100}{x}[/tex] = [tex]\frac{100}{41}[/tex]

- Step 7: Again, the reciprocal of both sides gives

[tex]\frac{x}{100}[/tex] = [tex]\frac{41}{100}[/tex]

Therefore, 41% of 100 is 41.

hope this helps! have a great day! :D

Answer:

Here are the ones I've figured out

Step-by-step explanation:

I have yet to do the full-on picture. And for the picture thing, I don't know where to start. But I hope this helps you out in the meantime.

Answer:

16 yards gained

Step-by-step explanation:

I would add the yards that were gained first so 14 + 9

so we have 23 yards gained so far then subtract the yards loss so 23 - 7 is 16, so 16 yards were gained.

Answer:

x = 4

y = 2√5

z = 3√5

Step-by-step explanation:

There are 3 right triangles here, so we can create 3 expressions using Pythagoras' Theorem:

a² + b² = c²

(where a and b are the legs, and c is the hypotenuse)

smallest triangle:  x² + y² = (x + 2)²

medium triangle: (x + 1)² + y² = z²

largest triangle: (x + 2)² + z² = (x + x + 1)²

rewrite the smallest triangle expression to make y² the subject:

x² + y² = (x + 2)²

⇒ x² + y² = x² + 4x + 4

⇒  y² = 4x + 4

rewrite the medium triangle expression to make z² the subject, substituting y² = 4x + 4:

(x + 1)² + y² = z²

⇒ (x + 1)² + 4x + 4 = z²

⇒ x² + 2x + 1 + 4x + 4 = z²

⇒ z² = x² + 6x + 5

rewrite the largest triangle, substituting z² = x² + 6x + 5 and solve for x:

(x + 2)² + z² = (x + x + 1)²

⇒ (x + 2)² + x² + 6x + 5 = (2x + 1)²

⇒ x² + 4x + 4 + x² + 6x + 5 = 4x² + 4x + 1

⇒  2x² - 6x - 8 = 0

⇒  x² - 3x - 4 = 0

⇒ (x + 1)(x - 4) = 0

⇒ x = -1, x = 4

as x > 0, x = 4 only

Substitute found value for x into y² = 4x + 4 and solve for y:

y² = (4 x 4) + 4

⇒ y² = 20

⇒ y = √20 = 2√5

Substitute found value for x into z² = x² + 6x + 5 and solve for z:

z² = 4² + (6 x 4) + 5

⇒ z² = 45

⇒ z = √45 = 3√5

Step-by-step explanation:

Miss K has already graded 10 tests and is grading 9 every hour. We will add keep adding 9 starting from 10.

Mr. T has already graded 22 tests and is grading 7 per hour. We will keep adding 7 starting from 22.

Miss K: 19, 27, 36. ( Took 3 hours to reach 36 tests)

Mr T: 29, 36. (Took 2 hours to reach 36 tests)

It will take Miss K 3 hours and Mr T 2 hours to have graded the same amount of tests (36).

Sorry if I'm wrong

Step-by-step explanation:

Soln

From the above diagram

Height = h = 4cm

Let a&b = upward and downward lengths respectively.

That is:

a = 13cm

b = 16cm

recall that the formula used mathematically in solving/calculating the area of a trapezium is

Area = 1/2×(a+b)×h

Area = 1/2×(13+16)×4

Area = 1/2×(29)×4

Area = (29)×2

Area = 58cm²

Answer & step-by-step explanation:

Look at the equation: you can rewrite it as [tex]y= x^2+4x+4 +1 = (x+2)^2+1[/tex]

Now the first term of the sum is at worst 0 (when [tex]x=-2[/tex]) so the sum is no less than 1.

Correct answer is the last option. Graph is the one in the photo, the thin red line is the axis - equation [tex]x=-2[/tex], vertex has coordinate [tex](-2;1)[/tex], Y intersect is [tex](0;5)[/tex] and has no x intercepts. extra points as needed if you want a more accurate graph, mine is sketched on paint so don't expect great quality

Answer:

Undefined

Step-by-step explanation:

Given that the equation [tex]x=-4[/tex] is a vertical line that intersects the x-axis at [tex]x=-4[/tex], there is only a change in [tex]y[/tex], but no change in [tex]x[/tex]. Thus, the rate of change is undefined since you cannot divide by 0.

Answer:

  24 square units

Step-by-step explanation:

For such questions it is convenient to choose the "base" to be a segment that is aligned with one of the coordinate axes. Here, the horizontal segments will serve. Their length is the difference between the x-coordinates of the end points, -2 -(-6) = 4, for example.

The height is measured perpendicular to the base, so will be the difference between the y-coordinates of the horizontal segments: 2 -(-4) = 6.

The area is given by the formula ...

  A = bh

  A = 4·6 = 24 . . . square units

Answer:

yes

Step-by-step explanation:

Answer:

Either 2.4 boxes or 6

Step-by-step explanation:

10% of 40 is 4

60% of 40 is 24

Either 2.4 boxes or 6

Answer:

81=5+b, 81-5=b, 81-b=5

Step-by-step explanation:

We can write the equation in terms of 81, b, or 5. Let's first start by writing it in terms of 81. We are already given that 5+b=81 therefore...

5+b=81 OR 81=5+b (transitive property)

Now, let's write the equation in terms of b.

5+b=81

Subtract 5 from both sides (subtraction property of equality)

5-5+b=81-5

b=81-5 OR 81-5=b (transitive property)

Lastly, let's write the equation in terms of 5.

5+b=81

Subtract b from both sides (subtraction property of equality)

5+b-b=81-b

5=81-b OR 81-b=5 (transitive property.

Answer:

first make everything inches so you have at least 62 inches and at most 73 inches, now create it.

Step-by-step explanation:

62<x<=73

Answer: 62 < x [tex]\leq[/tex] 73

Step-by-step explanation:

5 feet and 2 inches all in inches would be 62 (12 inches per foot, multiplied by five equals 60, add 2). 6 feet and 1 inch would be 73 inches (12 inches per foot, multiplied by six equals 72, add 1).

Since this inequality has words such as "more than" we have to use # < x. But since at most also applies, we have to use x [tex]\leq[/tex] #.

All her siblings are over 62 inches, so 62 < x. Remember the at most 73 inches, which would be 73 [tex]\geq[/tex] x. We can conclude that the inequalities would be expressed as 62 < x [tex]\leq[/tex] 73.

Answer:

1, 2, 5

Step-by-step explanation:

All of those selections are more than 0.3

Answer:

1,2,5

Step-by-step explanation:

I was taking the test that had the same question

Answer:

Step-by-step explanation:

As we use prime factorization for 200, we get 2 × 2 × 2 × 5 × 5 = 200. So, the only prime factors of 200 are 2 and 5.

Answer:

5*5*2*2*2

Step-by-step explanation:

200 divided by 2 is 100. 100 divided by 2 is 50. 50 divided by 2 is 25. 25 divided by 5 is 5

Answer:

The answer is -33.

Step-by-step explanation:

To solve the given equation we will follow the PEDMAS rule.

PEDMAS stands for :

Solving the question by PEDMAS rule :

[tex]\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 - \Big( - 27 - 31\Big) + 40\bigg\}}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 - \Big( - 58\Big) + 40\bigg\}}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 + 58 + 40\bigg\}}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 + 98\bigg\}}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{29 - \Big\{ \: 62 \: \Big\}}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{29 - 62}}}\end{gathered}[/tex]

[tex]\begin{gathered}{\implies{\sf{ - 33}}}\end{gathered}[/tex]

[tex]\begin{gathered} \star{\underline{\boxed{\sf{\red{ - 33}}}}}\end{gathered}[/tex]

Hence, the answer is -33.

[tex]\rule{300}{2.5}[/tex]

Answer:

616

Step-by-step explanation:

The equation to find the area of a trapezoid is:  A = ½ (b[tex]^1[/tex]+b²) h.

b1=43

b2=45

h=14

Plug the variables in and solve.

[tex]A=\frac{1}{2} (43+45)14[/tex]

[tex]A=\frac{1}{2} (88)14[/tex]

[tex]A=\frac{1}{2} (1232)[/tex]

[tex]A=616[/tex]

Answer:

Step-by-step explanation:

Givens

h = 14

b1 = 34

b2  = 45

Formula

A = (b1 + b2)*h /2                   Substitute into the formula

Solution

A = (34 + 45)*14/2                 Combine the brackets

A = (79) * 14/2                       Do the division

A = 79 * 7

Area = 553  cm^2

Answer:

1/72

Step-by-step explanation:

Probability of getting a 4 on white cube is:

P(W) · P(4) = 1/2 × 1/6 = 1/12

P(R) · P(>4) = 1/2 × 2/6 = 1/6

multiply both probabilities:  1/12 × 1/6 = 1/72

Answer:

24

Step-by-step explanation:

1050-82=968

968/40=24.2

the answer is 24 because the create has to be a whole

Answer:

20 cm

Step-by-step explanation:

Think of a large cone, 30 cm high, and a small cone of x height.

The scale factor of a volume of the cube of the scale factor of linear dimensions.

The cubic root of 1/27 is 1/3.

This means that the height of the small cone is 1/3 the height of the large cone.

The large cone has height 30 cm.

The small cone has height 10 cm.

30 cm - 10 cm = 20 cm

Answer: 20 cm

Answer:

D) [tex]37.1\times 10^{-4} \ \textsf{kilograms}[/tex]

Step-by-step explanation:

[tex]7.42 \times 10^{-10} \times5 \times 10^6[/tex]

[tex]\implies 7.42 \times 5 \times 10^{-10} \times 10^6[/tex]

[tex]\implies 37.1\times 10^{-10} \times 10^6[/tex]

[tex]\implies 37.1\times 10^{-10+6}[/tex]

[tex]\implies 37.1\times 10^{-4}[/tex]

Answer:

c

hopefully this will help you

[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 9\ cm}\end{picture}[/tex]

[tex] \\ [/tex]

[tex] \\ [/tex]

[tex] \\ [/tex]

[tex] \\ [/tex]

[tex] \\ [/tex]

We know:-

[tex] \bigstar \boxed{ \rm Area \: of \: circle = \pi {r}^{2} }[/tex]

[tex] \\ [/tex]

So:-

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times {9}^{2}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times 9 \times 9 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times 81 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\bf Area \: of \: circle = 25434 \: unit^2\\ [/tex]

[tex] \\ \\ [/tex]

.°. Option D is correct