let u(t) = 2t^3 (t^2-7)j-5k. compute the derivative of the following function.

hope this helps you.

Answer:

Step-by-step explanation:

The solution to the trigonometric expression is:

sin ( cos^-1 (1/2) + tan^-1 (1) )

= sin (60° + 45°)  (since cos^-1 (1/2) = 60° and tan^-1 (1) = 45°)

= sin 105°

= 0.966

The value of x is given as 2.045<133.158 deg

A complex number is a representation capable of being written as the combination of a and bi, where a and b exhibit themselves to be authentic numbers, while i stands as an imaginary unit that has been mathematically determined to calculate the result of -1 when squared.

The real part (a) of a complex number can be identified and contrasted against its imaginary contribution made by bi. By following certain regulations, these types of numbers are able to be increased, lessened, multiplied, and divided; providing a widely employed range of accurate calculations in mathematics, physics, engineering, and several other related fields.

Additionally, the complex plane offers a graphical means for displaying these numbers; wherein the real axis relates to the numerical form's real portion and the imaginary axis reflects the data's unreal part.

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Each Algebra ticket cost $5.125 for kids and $20.50 for adults, while each Geometry ticket cost $4.46 for pupils and $30.125 for adults.

For Algebra I:

Cost per student ticket = Total cost of student tickets / Number of student tickets

Cost per student ticket = $164.00 / 32

Cost per student ticket = $5.125

For Geometry:

Cost per student ticket = Total cost of student tickets / Number of student tickets

Cost per student ticket = $120.50 / 27

Cost per student ticket = $4.46 (rounded to two decimal places)

Next, we can find the cost of one adult ticket for each class using the same method.

For Algebra I:

Cost per adult ticket = Total cost of adult tickets / Number of adult tickets

Cost per adult ticket = $164.00 / 8

Cost per adult ticket = $20.50

For Geometry:

Cost per adult ticket = Total cost of adult tickets / Number of adult tickets

Cost per adult ticket = $120.50 / 4

Cost per adult ticket = $30.125

Therefore, the price of each ticket for Algebra I was $5.125 for students and $20.50 for adults, while the price of each ticket for Geometry was $4.46 for students and $30.125 for adults.

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Answer:

tan(A+B) = 84

Step-by-step explanation:

We can use the identity: tan(A+B) = (tanA + tanB) / (1 - tanA*tanB)

Given, tanA = 4/3

So, opposite side of angle A = 4, adjacent side of angle A = 3

Using the Pythagorean theorem, we get the hypotenuse of angle A = 5

Also, sin B = 8/17

So, opposite side of angle B = 8, hypotenuse of angle B = 17

Using the Pythagorean theorem, we get the adjacent side of angle B = 15

Now, we can find the value of tanB as opposite/adjacent = 8/15

Plugging in the values in the identity for tan(A+B), we get:

tan(A+B) = (4/3 + 8/15) / (1 - (4/3)*(8/15))

= (20/15 + 8/15) / (1 - 32/45)

= 28/15 / (13/45)

= (28/15) * (45/13)

= 84

Therefore, tan(A+B) = 84.

Hope this helps!

Step-by-step explanation:

126 ski sets  /  (3 ski sets / 5 snowboards)

= 126 * 5/3 = 210 snowboards

The example of non polyhydrons the length of a fields are equals to the cone and sphere. So, option (b) and (c) is rigth choices for answering this problem.

The solid objects which have faces (flat faces) are called polyhedra (singular is polyhedron) and the solid objects which have curved faces are called non-polyhedra. Some examples of non-polyhedra are sphere, cylinder, cone . A sphere is not a polyhedron because it is not composed of flat faces connected at straight edges, thus it does not form a shape. Cone is not a polyhedron because it has a curved surface. Rectangle is a polyhedron because it has a curved shape.

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Complete question:

Write the example of non polyhydrons the length of a fields and

a) a rectangular

b) cone

c) sphere

d) semi- circle

The equivalent expression is 0.75n - 7

An equivalent expression is defined as an algebraic expression that have the same solution but differ in their arrangement.

Also, algebraic expressions are described as expression that consists of variables, constants, terms, coefficients and factors.

These expressions are also made up of arithmetic operations such as addition, subtraction, division, multiplication, bracket and parentheses.

From the information given as;

-3.5 (2- 1.5n) - 4.5n

expand the bracket

-7 + 5.25n - 4.5n

collect the like terms

0.75n - 7

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X can be any real number, there are infinite values of c that will make the system consistent and dependent.

To have an infinite number of solutions, the system must be consistent and dependent. Thus, we need to find the value of 'c' for which the third equation is a linear combination of the first two equations.

Multiplying the second equation by 3 and adding it to the third equation, we get:

2y - z + 3(2x + 3z) = 12.0 + 3(2.7)

Simplifying, we get:

2y - z + 6x + 9z = 20.1

6x + y + 13z = 20.1

Now we have a system of two equations with three variables. To have an infinite number of solutions, one of the variables must be a free variable. Let's solve for z:

z = (20.1 - 6x - y) / 13

Now we can substitute this expression for z into the first two equations:

3x + y + 4[(20.1 - 6x - y) / 13] = c

2x + 3[(20.1 - 6x - y) / 13] = 2.7

Simplifying, we get:

39x + 13y = 52c - 321.6

39x - 6y = 41.7

To have an infinite number of solutions, the two equations must be linearly dependent. We can multiply the second equation by 13 and add it to the first equation to eliminate y:

754x = 52c - 525.9

Solving for c, we get:

c = (754x + 525.9) / 52

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The following parts can be answered by the concept of Operations.

a) shl(x): The result of left shifting x by 1 bit is 0010 0100 0111 1010.

b) shr(x): The result of right shifting x by 1 bit is 0100 1100 0111 1011.

c) cil(x): The result of circularly left shifting x by 1 bit is 0010 0100 0111 1010.

d) cir(x): The result of circularly right shifting x by 1 bit is 1100 1101 1001 1110.

e) ashl(x): The result of arithmetic left shifting x by 1 bit is 0010 0100 0111 1010.

f) ashr(x): The result of arithmetic right shifting x by 1 bit is 1100 1101 1001 1110.

g) dshl(x): The result of double precision left shifting x by 1 bit is 0010 0100 0111 1010 0000.

h) dshr(x): The result of double precision right shifting x by 1 bit is 0000 1001 0100 1000 1111.

a) shl(x): Left shifting x by 1 bit means shifting all the bits in x to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010.

b) shr(x): Right shifting x by 1 bit means shifting all the bits in x to the right by 1 position. The rightmost bit is lost, and a 0 is shifted in from the left. Therefore, the result is 0100 1100 0111 1011.

c) cil(x): Circularly left shifting x by 1 bit means shifting all the bits in x to the left by 1 position, and the leftmost bit is shifted to the rightmost position. Therefore, the result is 0010 0100 0111 1010.

d) cir(x): Circularly right shifting x by 1 bit means shifting all the bits in x to the right by 1 position, and the rightmost bit is shifted to the leftmost position. Therefore, the result is 1100 1101 1001 1110.

e) ashl(x): Arithmetic left shifting x by 1 bit is similar to logical left shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 0010 0100 0111 1010.

f) ashr(x): Arithmetic right shifting x by 1 bit is similar to logical right shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 1100 1101 1001 1110.

g) dshl(x): Double precision left shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010 0000.

h) dshr(x): Double precision right shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the right by 1 position. The rightmost bit is lost, and the sign bit is duplicated to fill the leftmost bit positions. Therefore, the result is 0000 1001 0100 1000 1111

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The following parts can be answered by the concept of Operations.

a) shl(x): The result of left shifting x by 1 bit is 0010 0100 0111 1010.

b) shr(x): The result of right shifting x by 1 bit is 0100 1100 0111 1011.

c) cil(x): The result of circularly left shifting x by 1 bit is 0010 0100 0111 1010.

d) cir(x): The result of circularly right shifting x by 1 bit is 1100 1101 1001 1110.

e) ashl(x): The result of arithmetic left shifting x by 1 bit is 0010 0100 0111 1010.

f) ashr(x): The result of arithmetic right shifting x by 1 bit is 1100 1101 1001 1110.

g) dshl(x): The result of double precision left shifting x by 1 bit is 0010 0100 0111 1010 0000.

h) dshr(x): The result of double precision right shifting x by 1 bit is 0000 1001 0100 1000 1111.

a) shl(x): Left shifting x by 1 bit means shifting all the bits in x to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010.

b) shr(x): Right shifting x by 1 bit means shifting all the bits in x to the right by 1 position. The rightmost bit is lost, and a 0 is shifted in from the left. Therefore, the result is 0100 1100 0111 1011.

c) cil(x): Circularly left shifting x by 1 bit means shifting all the bits in x to the left by 1 position, and the leftmost bit is shifted to the rightmost position. Therefore, the result is 0010 0100 0111 1010.

d) cir(x): Circularly right shifting x by 1 bit means shifting all the bits in x to the right by 1 position, and the rightmost bit is shifted to the leftmost position. Therefore, the result is 1100 1101 1001 1110.

e) ashl(x): Arithmetic left shifting x by 1 bit is similar to logical left shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 0010 0100 0111 1010.

f) ashr(x): Arithmetic right shifting x by 1 bit is similar to logical right shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 1100 1101 1001 1110.

g) dshl(x): Double precision left shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010 0000.

h) dshr(x): Double precision right shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the right by 1 position. The rightmost bit is lost, and the sign bit is duplicated to fill the leftmost bit positions. Therefore, the result is 0000 1001 0100 1000 1111

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Answer:

Range

Step-by-step explanation:

Mean (Average) 34

Median 37

Mode All values appeared just once.

Range 41

Answer: Range

Step-by-step explanation:

Mean, means average, add all of the numbers and divide by how many there are.

Mean = [tex]\frac{(42+28+35+39+53+12+19+44)}{y\8}[/tex]  = 34

Median, put all the numbers in order and the middle number is your median.

12    19    28    35    39    42    44    53

                             |

The line indicates the middle.  Since the middle is not on a number, you must take the average of the 2 middle numbers.  Meaning add the 2 numbers and divide by 2

Median = (35+39)/2 = 37

Mode, the number that occurs the most times is the mode.  Since none of the numbers occurs more than once. There is no mode

Mode = none

Range, largest number minus smalles number.  The numbers range from 12 to 53

Range = 53-12 =41

If Mean=34

Median =37

Mode=none

Range=41     Range is highest

We can convert all the fractions to decimals and then arrange them in ascending order:

- 16/22 ≈ 0.727

- -5/18 ≈ -0.278

- 2/-21 ≈ -0.095

- -7/12 ≈ -0.583

Therefore, the ascending order would be:

2/-21 ≈ -0.095 < -5/18 ≈ -0.278 < -7/12 ≈ -0.583 < 16/22 ≈ 0.727

So the final arrangement in ascending order is:

2/-21, -5/18, -7/12, 16/22

The points (3,5) and (6,5) would be good choices for the line of best fit.

To find the line of best fit, we want to draw a straight line through the points that best represents the overall trend of the data. This line should pass through as many points as possible while minimizing the distance between the points and the line.

To find the two points that the line of best fit should pass through, we want to select points that are close to the overall trend of the data and are not outliers.

To find the equation of the line of best fit, we can use a method called linear regression. This involves finding the equation of the straight line that minimizes the sum of the squared distances between the line and the points on the scatter plot.

Once we have the equation of the line of best fit, we can use it to make predictions about the data.

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The evaluated value of the given trigonometric expression cos 76° – sin 14° is 0. The correct answer is option B.

The trigonometric expression is given as follows:

cos 76° – sin 14°

It is required to find the evaluated value of the given trigonometric expression.

As per the angle of cosine and sine relation: cos (90 – θ) = sin θ.

It can be rewritten as follows:

Here, cos 76 as cos (90 – 14)

And, cos 76 = cos (90 – 14) = sin 14  

cos 76° – sin 14°  = sin 14° – sin 14°

cos 76° – sin 14°  =  0

Therefore, the evaluated value of the given trigonometric expression is 0.

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The complete question is as follows:

Evaluate cos 76° – sin 14°.

A. 1

B. 0

C. -1

D. 2

The statement which does not represent the distance is

C) In 3 hours car will travel the distance of 160 miles and D).

What is proportion?

A percentage is created when two ratios are equal to one another. We write proportions to construct equivalent ratios and to resolve unclear values.

Here the car can travel 55 miles in one hour.

Then in 1.5 hour distance traveled by car is x.

Using proportion,

=> x = 55*1.5 = 82.5 miles

Now in 2 hours distance traveled by car = 55*2=110 miles

In 2.5 hours distance traveled by car  = 55*2.5 = 137.5 miles

In 3 hours distance traveled by car = 55*3 = 165 miles.

Then distance = 55t . where t = time

Hence the statement which does not represent the distance is

C) In 3 hours car will travel the distance of 160 miles and D).

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To find the length of the curve, we need to use the formula:

length = ∫[a,b] √[dx/dt)^2 + (dy/dt)^2] dt

In this case, a=0, b=4, and:

dx/dt = 6t
dy/dt = 6t^2

So, we can plug these values into the formula and integrate:

length = ∫[0,4] √[(6t)^2 + (6t^2)^2] dt
length = ∫[0,4] √[36t^2 + 36t^4] dt
length = ∫[0,4] 6t√(1 + t^2) dt

This integral is not easy to solve analytically, so we'll use numerical methods to approximate the answer. Using a numerical integration method such as Simpson's Rule or the Trapezoidal Rule, we can get:

length ≈ 244.36

So the exact length of the curve x = 6 + 3t^2, y = 6 + 2t^3 for 0 ≤ t ≤ 4 is approximately 244.36 units.
To find the exact length of the curve x = 6 + 3t^2, y = 6 + 2t^3 for 0 ≤ t ≤ 4, you can use the arc length formula:

Length = ∫[√(dx/dt)^2 + (dy/dt)^2] dt from t=0 to t=4

First, find the derivatives dx/dt and dy/dt:
dx/dt = 6t
dy/dt = 6t^2

Now, square the derivatives and find their sum:
(6t)^2 + (6t^2)^2 = 36t^2 + 36t^4

Take the square root of the sum:
√(36t^2 + 36t^4)

Now, integrate the expression with respect to t from 0 to 4:
Length = ∫[√(36t^2 + 36t^4)] dt from t=0 to t=4

This integral is not easy to evaluate directly, and numerical methods are usually required. To obtain an approximate value, you can use an appropriate numerical integration technique, like Simpson's Rule or a computer algebra system.

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Answer:

5.0 inches

Step-by-step explanation:

The formula for the volume of a sphere is:

[tex]\boxed{V=\dfrac{4}{3}\pi r^3}[/tex]

where r is the radius of the sphere.

Given a sphere has a volume of 65.5 cubic inches, substitute V = 65.5 into the formula and solve for the radius, r:

[tex]\begin{aligned}\implies \dfrac{4}{3}\pi r^3&=65.5\\\\3 \cdot \dfrac{4}{3}\pi r^3&=3 \cdot 65.5\\\\4\pi r^3&=196.5\\\\\dfrac{4\pi r^3}{4 \pi}&=\dfrac{196.5}{4 \pi}\\\\r^3&=15.636973...\\\\\sqrt[3]{r^3}&=\sqrt[3]{15.636973...}\\\\r&=2.50063840...\; \sf in\end{aligned}[/tex]

The diameter of a sphere is twice its radius.

Therefore, if the radius is 2.50063840... inches, then the diameter is:

[tex]\begin{aligned}\implies d&=2r\\&=2 \cdot 2.50063840...\\&=5.00127681...\\&=5.0\; \sf in\;(nearest\;tenth)\end{aligned}[/tex]

Therefore, the diameter of a sphere with a volume of 65.5 cubic inches is 5.0 inches, to the nearest tenth of an inch.

Answer:

5 cm

Step-by-step explanation:

The formula to find the volume of a sphere is:

[tex]\sf V =\frac{4}{3} \pi r^3[/tex]

Here,

V ⇒ volume ⇒ 65.5 cm³

r ⇒ radius

Let us find the value of r.

[tex]\sf V =\frac{4}{3} \pi r^3\\\\65.5=\frac{4}{3} \pi r^3\\\\65.5*3=4 \pi r^3\\\\196.5=4 \pi r^3\\\\\frac{196.5}{4} =\pi r ^3\\\\49.125=\pi r^3\\\\\frac{49.125}{\pi} = r^3\\\\15.63=r^3\\\\\sqrt[3]{15.63} =r\\\\2.5=r[/tex]

Let us find the diameter now.

d = 2r

d = 2 × 2.5

d = 5 cm

Answer:

34

Step-by-step explanation:

Note that maximum profit is $26. This point is obtained when the baker has made 4 batches of chocolate chip cookies and 2 bactches of oatmean raisons cookies.

Lets define x as the number of batches of chocolate chip cokies

We want to maximize profit, which is given by:

P = 5x + 3y

subject to the constraints:

4x + 2y ≤ 20 (egg constraint)

3x + 3y ≤ 18 (flour constraint)

x, y ≥ 0 (non-negativity constraint)

We can rewrite the constraints as:

2x + y ≤ 10

x + y ≤ 6

Graphing these constraints on a coordinate plane, we see that the feasible region is a triangle with vertices at (0,0), (0,6), and (4,2)

See agraph attached.

We want to find the point (x,y) within this region that maximizes P.

One way to do this is to calculate P at each vertex of the feasible region:

P(  0,0) = 0

P (0, 6) = 3(6) = 18

P (4,2) =
5(4) + 3(2) =

26

So the point of profit maximization is at  $ 26.

Thica can happen when the baker is baking 4 batches of chocolate chip cookies and 2 batches of oatmeal raisin cookies.

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Answer:

RS = 24, so tan R = 18/24 = 3/4

As the sequence {an} is a sequence of constant random variables, it means that each term in the sequence has the same value with probability 1.

If an → a, then for any ε > 0, there exists an integer N such that for all n ≥ N, |an - a| < ε. This means that the probability of an being within ε of a is 1, which can be written as: lim P(|an - a| < ε) = 1

n→∞

Since this is true for any ε > 0, we can rewrite the above as: lim P(|an - a| < δ) = 1

n→∞ where δ is any positive number.

Now, if an → Pa, then for any ε > 0, there exists an integer N such that for all n ≥ N, P(|an - a| < ε) > 1 - δ. This means that the probability of an being within ε of a is greater than 1 - δ, which can be written as: lim P(|an - a| < ε) ≥ 1 - δ

n→∞

Again, since this is true for any ε > 0, we can rewrite the above as:

lim P(|an - a| < δ) ≥ 1 - δ

n→∞

Comparing the two limits, we see that they are equivalent. Therefore, an → a is equivalent to an → Pa.

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a. Bella should estimate her cost per year to be $17,150.

b. It looks like Bella's family is contributing more than her estimated cost per year, so she may not need to contribute anything.

The act of deleting items from a collection is represented by subtraction. Subtraction is denoted by the minus sign. For instance, suppose there are nine oranges stacked. If four oranges are then transferred to a basket, there will now be nine oranges left in the stack (9 – 4).

a. To estimate Bella's cost per year, we need to subtract her financial aid from the total cost of attendance. Let's assume the total cost of attendance is $30,000 per year. Then, Bella's estimated cost per year would be:

Total cost of attendance - Financial aid = Estimated cost per year

$30,000 - $9,750 - $3,100 = $17,150

Therefore, Bella should estimate her cost per year to be $17,150.

b. If Bella's family is contributing $20,000 towards her expenses each year, she needs to contribute the remaining amount. To calculate how much she needs to contribute each year, we can subtract her family's contribution from her estimated cost per year:

Estimated cost per year - Family contribution = Bella's contribution

$17,150 - $20,000 = -$2,850

It looks like Bella's family is contributing more than her estimated cost per year, so she may not need to contribute anything. However, it's important to keep in mind that these are just estimates and actual costs may vary.

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Answer:

First, we need to find the volume of the cylinder:

V = πr^2h = π(7.6 cm)^2(16.2 cm) = 2,945.27 cm^3

Next, we can find the amount of trace elements collected:

0.091 g/cm^3 x 2,945.27 cm^3 = 267.68 g

Rounded to the nearest tenth, Valeria collected approximately 267.7 grams of the trace element.

The features of the quadratic function are given as follows:

The function is decreasing on the following interval:

(1.5, ∞).

First we look at the vertex of the quadratic function, which is the turning point, with coordinates x = 1.5 and y = 6, hence it is given as follows:

(1.5, 6).

Hence the axis of symmetry is of x = 1.5, which is the x-coordinate of the vertex.

The function is concave down, hence the increasing and decreasing intervals are given as follows:

The x-intercepts are the values of x for which the graph crosses the x-axis, when the y-coordinate is of 0, hence they are given as follows:

(-1, 0) and (4,0).

The y-intercept is the value of y when the graph crosses the y-axis, when the x-coordinate is of zero, hence it is given as follows:

(0,4).

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The probability that X+Y=1 is 0.5.

To find the probability that X+Y=1, given that X is a Bernoulli random variable with P(X=1)=0.8 and Y is a Bernoulli random variable with P(Y=1)=0.5, follow these steps:

1. First, find the probabilities for the complementary events, i.e., P(X=0) and P(Y=0).
  P(X=0) = 1 - P(X=1) = 1 - 0.8 = 0.2
  P(Y=0) = 1 - P(Y=1) = 1 - 0.5 = 0.5

2. Now, consider the two possible cases where X+Y=1:
  a) X=1 and Y=0: P(X=1) * P(Y=0) = 0.8 * 0.5 = 0.4
  b) X=0 and Y=1: P(X=0) * P(Y=1) = 0.2 * 0.5 = 0.1

3. Finally, sum the probabilities of the two cases:
  P(X+Y=1) = P(X=1, Y=0) + P(X=0, Y=1) = 0.4 + 0.1 = 0.5

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The probability that X+Y=1 is 0.5.

To find the probability that X+Y=1, given that X is a Bernoulli random variable with P(X=1)=0.8 and Y is a Bernoulli random variable with P(Y=1)=0.5, follow these steps:

1. First, find the probabilities for the complementary events, i.e., P(X=0) and P(Y=0).
  P(X=0) = 1 - P(X=1) = 1 - 0.8 = 0.2
  P(Y=0) = 1 - P(Y=1) = 1 - 0.5 = 0.5

2. Now, consider the two possible cases where X+Y=1:
  a) X=1 and Y=0: P(X=1) * P(Y=0) = 0.8 * 0.5 = 0.4
  b) X=0 and Y=1: P(X=0) * P(Y=1) = 0.2 * 0.5 = 0.1

3. Finally, sum the probabilities of the two cases:
  P(X+Y=1) = P(X=1, Y=0) + P(X=0, Y=1) = 0.4 + 0.1 = 0.5

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The correct option is (B) [tex]A^-1, B^-1[/tex], and [tex]C^-1[/tex], shows that ABC is also invertble

Since A, B, and C are invertible matrices, they have inverse matrices [tex]A^-1, B^-1,[/tex] and [tex]C^-1,[/tex] respectively.

To show that ABC is invertible, we can introduce a matrix D such that (ABC)D = I and D(ABC) = I, where I is the identity matrix.

We can use the associative property of matrix multiplication to rearrange the product ABCD as follows:

(ABC)D = A(BCD)

Since A, B, and C are invertible, their product ABC is also invertible. Therefore, we can write:

(ABC)D = A(BCD) = I

Multiplying both sides of the equation by [tex]A^-1,[/tex] we get:

[tex]A^-1(ABC)D = A^-1[/tex]

Using the associative property again, we can rearrange the left-hand side as follows:

[tex]A^-1(ABC)D = (A^-1AB)CD = ICD = D[/tex]

Substituting ICD with D, we get:

[tex](A^-1AB)CD = D[/tex]

Since[tex]A^-1A[/tex] is equal to the identity matrix I, we can simplify the equation as follows:

BCD = D

Now we can use a similar approach to show that D(ABC) = I. Multiplying both sides of the equation (ABC)D = I by [tex]C^-1,[/tex] we get:

[tex](ABC)DC^-1 = C^-1[/tex]

Using the associative property, we can rearrange the left-hand side as follows:

[tex]A(BCD)C^-1 = AIC^-1 = A^-1[/tex]

Substituting BCD with D, we get:

[tex]AD^-1C = A^-1[/tex]

Multiplying both sides by [tex]C^-1[/tex], we get:

[tex]AD^-1CC^-1 = A^-1C^-1[/tex]

Since [tex]CC^-1[/tex] is equal to the identity matrix I, we can simplify the equation as follows:

[tex]AD^-1 = A^-1C^-1[/tex]

Multiplying both sides by BC, we get:

[tex]ABCD^-1 = B(A^-1C^-1)C = BI = B[/tex]

Therefore, we have shown that ABC has an inverse matrix D, which implies that ABC is invertible.

Answer: The correct option is (B) [tex]A^-1, B^-1,[/tex] and [tex]C^-1[/tex]exist.

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The null and alternative hypothesis: H0: p = 0.35, HA: p ≠ 0.35

What is hypothesis?

A hypothesis is an idea or explanation that is proposed and then tested through research and analysis to determine if it is supported by evidence or not. In statistics, a hypothesis is a statement about a population parameter, such as a mean or proportion, that is either true or false.

In this situation, we want to test whether the percentage of CEOs with an MBA has changed or not. We can set up two hypotheses, the null hypothesis (H0) and the alternative hypothesis (HA). The null hypothesis is the default position, which we assume to be true unless there is sufficient evidence to reject it. The alternative hypothesis represents the opposite of the null hypothesis, and it is what we want to test for.

In this case, the null hypothesis is that the percentage of CEOs with an MBA is equal to 35%, which means there is no change in the proportion. The alternative hypothesis is that the percentage of CEOs with an MBA is different from 35%, which implies a change in the proportion. Therefore, we have:

H0: P = 0.35

HA: P ≠ 0.35

where P represents the proportion of CEOs with an MBA.

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(a) The conditional PDF is f_X(x|A) = 1/14 for -7 ≤ x ≤ 7 and 0 otherwise.

A continuous uniform random variable defined on the interval (-9, 9) and the event A = {X: |X| ≤ 7}.


The event A implies that the random variable X lies in the interval [-7, 7]. In this interval, X is still uniformly distributed.

Since the length of the interval is 14, the PDF is 1/14, indicating a constant probability density within the given interval. Outside of this interval, the probability density is 0, as the event A does not cover those values of X.

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The image is plotted and attached

The rectangle started with ABCD. Then following the reflection along line AC. point B and point D swapped so we have B' replacing D and D' replacing B.

180 degrees rotation through C, resulted to B'' D'' and A'. Point C maintains it's position since the rotation is about point C.

Enlargement by a factor of 2 results to C' B''' D''' A'' and this is the final image.

While the reflection and rotation preserves the geometry, the enlargement affects the geometry, producing a rectangle with a bigger size twice the initial size

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Answer:

42°

Step-by-step explanation:

Measured with potractor