Last week the Stock A increased by 0.35%. If it had been selling for $150.00, how much did it increase? (round to the nearest penny)

Answer:

1x0.8=0.8 ,10x0.08=0.8 and 100x0.008=0.8

Step-by-step explanation:

Answer:

i think its C

Step-by-step explanation:

I dunno i just think its C

Answer: The percent decrease is 98.44 brainliest please :)

Answer:

20 inches

Step-by-step explanation:

80 / 4 = 20 !!!!! <3

Answer:

2.4m+1.8b−32.6

Step-by-step explanation:

Group like terms together

1. 2.4 m + \left( - 125 + 92.4 \right) + 1.8 b2.4m+(−125+92.4)+1.8b

2 . Add or subtract the numbers

2.4 m- 32.6 + 1.8 b2.4m−32.6+1.8b

3 . Rearrange the expression

2.4 m + 1.8 b- 32.62.4m+1.8b−32.6

Answer:

2.4m+1.8b-32.6

Step-by-step explanation:

2.4m- 125 + 1.8b+ 92.4​

2.4m+1.8b-32.6

Answer:

all of them

Step-by-step explanation:

Answer:

m=-2

Step-by-step explanation:

Answer:

Ok, that‘s not a question, it‘s a statemen. So what‘s your point

Step-by-step explanation:

Answer:

line dancing, square dancing, etc

Step-by-step explanation:

Answer: square dancing, circle dancing, line dancing.

Hope this helps... Stay safe and have a great day/night!!! :D

Answer/Step-by-step explanation:

Let's find the measure of the angles of ∆QNP.

∆QMN is am isosceles ∆, because it has two equal sides. Therefore, its base angles would be the same. Thus:

m<MNQ = ½(180 - 48) (one of the base angles of ∆QMN)

m<MNQ = ½(132) = 66°

Next, find m<QNP

m<QNP = 180° - m<MNQ (linear pair angles)

m<QNP = 180° - 66° (Substitution)

m<QNP = 114°

Next, find m<P

m<P = 180 - (m<QNP + m<PQN) (sum of ∆)

m<P = 180 - (114 + 33)

m<P = 180 - 147

m<P = 33°

Thus, in ∆QNP, there are two equal angles, namely, <P and <PQN.

An isosceles ∆ had two equal base angles. Therefore, ∆QNP must be an isosceles ∆.

An isosceles triangle is that the triangle must have two sides of equal length.

Triangle QNP is isosceles triangle because, QN = PN

In triangle QMN,  

        Since,  QM = QN

 So,  ∠QMN = ∠QNM

By property of triangle:

∠MQN + ∠QNM + ∠QMN = 180

   48 + 2 ∠QNM = 180

              ∠QNM = [tex]\frac{180-48}{2}[/tex] = 66  degree

  So, ∠QMN = ∠QNM = 66 degree

from figure,

    ∠QNM + ∠QNP = 180

                    ∠QNP = 180 - 66 = 114 degree.

In triangle QNP,  

              ∠QNP + ∠PQN + ∠QPN = 180

                        ∠QPN = 180 - 33 - 114 = 33 degree

Since,     ∠QNP = ∠QPN = 33 degree

Therefore, triangle QNP is isosceles triangle.

Learn more:

https://brainly.com/question/19414224

The required terms are 7, 3 and 0. The correct option is (c).

What is an arithmetic sequence?

An arithmetic sequence is a kind of sequence of numbers where the difference of any two consecutive terms are the same.

This difference is known as the common difference of the sequence.

The given sequence is as below,

33, 25, 18, 12, …….

The difference between the consecutive terms is given as,

D₁ = 25 - 33

    = -8

D₂ = 18 - 25

     = -7

D₃ = 12 - 18

    = -6

It is clear that the difference between the consecutive terms are in arithmetic progression.

Thus, the next differences can be found as,

D₄ = -6 + 1

     = -5

D₅ = -5 + 1

    = -4  

And, D₆ = -4 + 1

             = -3

The next three terms of the sequence can be written as,

12 - 5 =7, 7 - 4 = 3, 3 - 3 = 0.

Hence, the next three terms of the given sequence are 7, 3 and 0.

To know more about arithmetic sequence click on,

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#SPJ2

Answer:

(Choice B) Keeping A constant and decreasing B

(Choice C) Increasing A and keeping B constant

Step-by-step explanation:

Let us analyze these two options.

2√a - b /5

(Choice B) Keeping A constant and decreasing B

Let a = 100 and b= 30

2√100 - 30/5

= 2(10) - 6

= 20 -6= 14

But if A is kept constant and B is decreased to 20

2√100 - 20/5

= 2(10) - 4

= 20 -4= 16

We see the expression value has increased from 14 to 16.

Similarly analyzing Option C

(Choice C) Increasing A and keeping B constant

Let a = 100 and b= 30

2√100 - 30/5

= 2(10) - 6

= 20 -6= 14

Now increasing A to 121 and keeping B constant would give

Let a = 100 and b= 30

2√121 - 30/5

= 2(11) - 6

= 22 -6= 16

This also increases the expression's value

But the other two choice A and D do not give the same result.

Let a = 100 and b= 30

2√100 - 30/5

= 2(10) - 6

= 20 -6= 14

(Choice A)

Keeping A constant and increasing B

2√100 - 40/5

= 2(10) - 8

= 20 -8= 12

This decreases the value .

Also

(Choice D)

Decreasing A and keeping B constant

2√81 - 40/5

= 2(9) - 8

= 18 -8= 10

This also decreases value

The correct choices are B and C

Answer:

the acutal solution is B and D

Answer:

square root of 16

Step-by-step explanation:

1809.56ft³ <<<<<<<<<<<<<<<<Answer

Answer:

452.7 ft³

Step-by-step explanation:

sooooo first you find the radius of the base.

Radius=16/2=8

now you find the area of the base:

Area of a circle=2(pi)(radius)=50.3 ( rounded up to the nearest 10ths)

now to get the volume:

volume of a cylinder=Base*hight=50.3*9= 452.7 ft³

Answer:

yes, it is

Step-by-step explanation:

plug in the point (1, -1) (x,y) into the equation y = 9x - 10

-1 = 9(1)-10

-1 = 9-10

-1=-1

Answer:

Bob had x apples and Mary had 2 apples. After Bob received 3 more apples from his mother, Bob had more apples than Mary. How many apples did Bob have at first?

Step-by-step explanation:

The inequality sign > shows that x + 3 is more than 2.

Answer:

35.015

Step-by-step explanation:

see attached image

Answer:

answer is c

Step-by-step explanation:

C is the only one with the correct slope

Answer:

The closest equivalent of the ratio of a to c will be:

a/c=1.680

Step-by-step explanation:

As 'a' is 63% of x

so

[tex]a=0.63x[/tex]

As 'c' is 3/8 of x

so

c=3/8

Thus, the closest equivalent of the ratio of a to c will be:

a/c = (0.63x)/(3/8x)

      = 1.680

Therefore, the closest equivalent of the ratio of a to c will be:

a/c=1.680

Answer:

-3x+6y=42

-3x+6y-42=0

-x+2y-14=0

x-2y+14=0

Answer:

Step-by-step explanation:

Slope intercept form: y = mx + c

-3x + 6y = 42

        6y = 3x + 42

          y = [tex]\frac{3}{6}x + \frac{42}{6}[/tex]

      y = [tex]\frac{1}{2}x + 7[/tex]

Answer:

Choice D. 17:850

Answer:

D

Step-by-step explanation:

17/7=2.42857142857

multiply 350 by that big number=850 So D

Answer:

-3+(-5)=-8

-5+(-3) is also -8

Step-by-step explanation:

if the parenthesis is separating the + and - then you just add the numbers and add the symbol.

Answer:

ans= 12-x=r1 coin...

Step-by-step explanation:

hope u can do..

Answer:

125.3 yards

Step-by-step explanation:

He wants them to run the  so 110^2+60^2 =which is 125.3.

Hope this helps plz mark brainliest :D

it's probably 17424 feet

Answer:

a) The horizontal asymptote of [tex]C(t)[/tex] is [tex]c = 0[/tex].

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.  

c) The time at which the concentration is highest is approximately 1.291 hours after injection.

Step-by-step explanation:

a) The horizontal asymptote of [tex]C(t)[/tex] is the horizontal line, to which the function converges when [tex]t[/tex] diverges to the infinity. That is:

[tex]c = \lim _{t\to +\infty} \frac{t}{3\cdot t^{2}+5}[/tex] (1)

[tex]c = \lim_{t\to +\infty}\left(\frac{t}{3\cdot t^{2}+5} \right)\cdot \left(\frac{t^{2}}{t^{2}} \right)[/tex]

[tex]c = \lim_{t\to +\infty}\frac{\frac{t}{t^{2}} }{\frac{3\cdot t^{2}+5}{t^{2}} }[/tex]

[tex]c = \lim_{t\to +\infty} \frac{\frac{1}{t} }{3+\frac{5}{t^{2}} }[/tex]

[tex]c = \frac{\lim_{t\to +\infty}\frac{1}{t} }{\lim_{t\to +\infty}3+\lim_{t\to +\infty}\frac{5}{t^{2}} }[/tex]

[tex]c = \frac{0}{3+0}[/tex]

[tex]c = 0[/tex]

The horizontal asymptote of [tex]C(t)[/tex] is [tex]c = 0[/tex].

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.  

c) From Calculus we understand that maximum concentration can be found by means of the First and Second Derivative Tests.

First Derivative Test

The first derivative of the function is:

[tex]C'(t) = \frac{(3\cdot t^{2}+5)-t\cdot (6\cdot t)}{(3\cdot t^{2}+5)^{2}}[/tex]

[tex]C'(t) = \frac{1}{3\cdot t^{2}+5}-\frac{6\cdot t^{2}}{(3\cdot t^{2}+5)^{2}}[/tex]

[tex]C'(t) = \frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right)[/tex]

Now we equalize the expression to zero:

[tex]\frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right) = 0[/tex]

[tex]1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} = 0[/tex]

[tex]\frac{3\cdot t^{2}+5-6\cdot t^{2}}{3\cdot t^{2}+5} = 0[/tex]

[tex]5-3\cdot t^{2} = 0[/tex]

[tex]t = \sqrt{\frac{5}{3} }\,h[/tex]

[tex]t \approx 1.291\,h[/tex]

The critical point occurs approximately at 1.291 hours after injection.

Second Derivative Test

The second derivative of the function is:

[tex]C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}-\frac{(12\cdot t)\cdot (3\cdot t^{2}+5)^{2}-2\cdot (3\cdot t^{2}+5)\cdot (6\cdot t)\cdot (6\cdot t^{2})}{(3\cdot t^{2}+5)^{4}}[/tex]

[tex]C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}- \frac{12\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}[/tex]

[tex]C''(t) = -\frac{18\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}[/tex]

If we know that [tex]t \approx 1.291\,h[/tex], then the value of the second derivative is:

[tex]C''(1.291\,h) = -0.077[/tex]

Which means that the critical point is an absolute maximum.

The time at which the concentration is highest is approximately 1.291 hours after injection.

Answer:

$26.25

Step-by-step explanation:

1.25 per day

21 days

1.25 × 21 = 26.25

Answer:

52.35-1.58= 50.77

Step-by-step explanation: