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Given that m_JKL = 94º, m_KL) = 41°, and the radius of the circle is 10 units, find s, rounded to the nearest hundredth.
units
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Step-by-step explanation:
angle j + angle JKL + angle KLJ = 180(sum of angles in a triangle)
[tex]j + 94 + 41 = 180 \\ j + 135 = 180 \\ j = 180 - 135 \\ = 45[/tex]
Arc Length s =
given r = 10 units,
[tex] = (\frac{j}{360} ) \times 2\pi \: r \\ = ( \frac{45}{360} ) \times 2\pi(10) \\ = 0.125 \times 20\pi \\ = 2.5\pi \\ = 7.85units(nearest \: hundredth)[/tex]
Answer:
7.85 units
Hope this helped and have a good day :D
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