John is pushing (horizontally) on a 100 kg bench with a force of 380 Newtons. What is the size of the friction force acting on the bench if the coefficient of static friction is 0.4? Where will the bench be 10 seconds after John starts pushing

Answers

Answer 1

Answer:

dx = 0

Explanation:

The Force of Friction = N * coefficient of static friction

N = m * g

=> The Force of Friction = m * g * coefficient of static friction

The Force of Friction = 100 * 10 * 0.4 = 400 (N)

The Force of Friction > The Force of John

=> It won't move!

Answer 2

The bench will not move because the friction force is more than john's applied force. Friction force= 392 N

Calculation

[tex]f_{k} =[/tex][tex]u_{k} *F_{N}[/tex]

where,

[tex]f_{k}[/tex] is friction force,

[tex]u_{k}[/tex] is coefficient of friction.

[tex]F_{N}[/tex] is the normal force

⇒[tex]f_{k} =0.4(100*9.8)=392 N[/tex].

Hence Force applied by john, 380N is less than the Frictional force, 392N.

What is friction?The resistance to motion of one object moving in relation to another is known as friction.It is not regarded as a fundamental force like gravity or electromagnetic.The interplay of small bumps on the surfaces of objects as they rub together is thought to be the primary source of friction, though scientists are not entirely certain of this.Particles that stick out above the rest can be found on even the most smooth surfaces.As the objects move, these high points collide and scrape against one another, creating resistance.Friction is brought on by this unwillingness to move.Sliding friction, fluid friction, and rolling friction are the three primary categories into which friction can be categorized. The items that are moving and the force being applied to them determine the type of friction.

To learn more about friction, refer to https://brainly.com/question/24338873

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Answers

Answer:

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------------------------------------------------------

(1) F net = F + f

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