Joe earned $130 one week and $125.50 the next week. After depositing these amounts in his account, he had a total of $335.
How much was already in his account before he deposited the $130 and $125.50?

Step-by-step explanation:

20n 20394848484848575

The impulse on the body is 20 kg-m/s, the final speed of the body is 2m/s, and the distance covered within the time interval is 0.5m.

Force is the strength applied on an object with mass to change its state of motion.

The mass of the body is 10kg.

The force applied on the object is 40N.

The time for which the force is applied is 0.5 sec.

The impulse on the body is calculated by,

Impulse =  Force * Time

Impulse = 40 * 0.5

Impulse = 20 kg-m/s

The final speed of the body is given by

v = u + at

Assuming the initial speed = 0

v = at

Acceleration =  Force / mass

Acceleration = 40/10

a = 4 m/s²

v = 4 * 0.5

v = 2 m/s

The distance covered within the time interval is given by,

s = ut + (1/2) at²

s = (1/2) at²

s = (1/2) 4 * 0.5 *0.5

s = 0.5 m

To know more about Force

https://brainly.com/question/13191643

#SPJ5

Answer:

6.32

Step-by-step explanation:

Answer: 6.32

Step-by-step explanation:

Step-by-step explanation:

52 + 14 < 3x

66 < 3x

66/3 < x

22 < x

Answer:

x > 22

Step-by-step explanation:

52- 3x<-14

-3x < -14 -52

-3x < -66

x > 22

Answer:

The last one 4x4

Step-by-step explanation:

Answer:

last one, D.

Step-by-step explanation:

Answer: -18

Step-by-step explanation:

Answer:

Step-by-step explanation:

To find the x-intercept and y-intercept of the equation we need to understand what is an intercept. Intercept means to intersect/cut so x-intercept means the equation cuts the x-axis and y-intercept means the equation cuts the y-axis.

So if the equation cuts the x-axis the coordinate should be [tex](x,0)[/tex]  and if the equation cuts the y-axis the coordinate should be [tex](0,y)[/tex] , and since the equation satisfies these both points in other words these two points lie on the line they can be put into the equation. So here we go,

For x-intercept

[tex]x+2y=10\\x+2(0)=10\\x=10[/tex]

so the x-intercept is (10,0)

For y-intercept

[tex]x+2y=10\\0+2y=10\\2y=10\\y=10/2\\y=5[/tex]

so the y-intercept is (0,5)

I also have attached an example of how intercepts looks like you can take a look i plotted the graph an you can see our answers check out.

Answer:

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ. Is this information sufficient to prove triangles DEF and OPQ congruent through SAS? Explain your answer.

Step-by-step explanation:

can  you help me?

Answer:

25.748

Step-by-step explanation:

If you multiply 4.1 by 3.14, your answer comes out to 12.874. Multiply that by 2 and you get your answer of 25.748. Hope this helps.

Answer:

2af+bf = 2af+bf

Step-by-step explanation

f(x) = 4x2 – 3x. =  x(4x−3)

Answer: When sales are greater than 2000 then  José's monthly earnings sre more than those of Maris.

Step-by-step explanation:

Let  x= Total sales

For José, monthly salary = $3,500

Commission percentage =  8% =0.08

Monthly earnings= Monthly salary + (Commission percentage) x (Total sales)

Monthly earnings= 3500 +0.08 x

For Maris, monthly salary = $3,900

Commission percentage =  6%

Monthly earnings= 3900 +0.06 x

When José's monthly earnings > Maris's monthly earnings

then, 3500 +0.08 x > 3900 +0.06 x

Subtract 3500 from both sides, we get

0.08 x > 400+0.06x

Subtract 0.06x from both sides, we get

0.02x>400

Divide both sides b 0.02

x> 20000

When sales are greater than 2000 then  José's monthly earnings sre more than those of Maris.

Answer:

X > 7

Step-by-step explanation:

4(x + 3) < 6x – 2

4x + 12 < 6x -2

-6x            -6x

-2x + 12 < -2

-12           -12

-2x < -14

-----     -----

-2         -2

x > 7

The < change because it was divided by a negative number

Answer:

39

Step-by-step explanation:

Answer:

32.4825

hope this helped :)

C: 2x+20=60

2x=40

x=20

D: 3x+10=100

3x=90

x=30

Answer:

Sam sokey 0.5 hours biking and 3.5 hours walking

Step-by-step explanation:

Here, we want to know the number of hours spent walking and biking

Mathematically; distance = speed * time

Let the number of hours spent walking be x and the number of hours spent biking be y

Mathematically;

x + y = 3 •••(i)

distance spent walking = 4 * x = 4x miles

distance spent biking = 12 * y = 12y miles

4x + 12y = 20

divide through by 2

2x + 6y = 10 ••••••(ii)

From i , x = 4-y

Substitute this into ii

2(4-y) + 6y = 10

8 - 2y + 6y = 10

8 + 4y = 10

4y = 10-8

4y = 2

y = 2/4 = 0.5 hours

The number of hours spent walking = 4-0.5 = 3.5 hours

The time Nate left his house is 8 : 40 am

After leaving his house, Nate drove 15 minutes to take his oldest daughter to the middle school . Therefore,

Then he drove ten minutes to take his two younger daughters to the elementary school. Therefore,

He drove twenty-five minutes to work. Therefore,

He arrived at work at 9:30 am. The time he left home can be calculated as follows:

Total time spent on the road = 15 + 10 + 25 = 50 minutes

Therefore,

Time he left home = 9:30 - 50 = 8 : 40 am

learn more on time here: https://brainly.com/question/25923001?referrer=searchResults

Answer:

2.68

Step-by-step explanation:

Answer:

-16

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

16+(-32)= -16

Answer: E=15

Step-by-step explanation: If you add 13 and 2 it adds up to 15, so E would have to be 15

Answer:

15

Step-by-step explanation:

to solve this you would need to add 13 and 2 since it's inverse operation of subtraction which would give you 15 since 15-2=13

Answer:

She can never travel a distance of 1 foot for the given condition.

Step-by-step explanation:

In every jump, she goes 1/2 as far as her prior jump.

In the 1st jump, she covered a distance, d_1= \frac 1 2 foot.

The distance covered in the 2nd jump

[tex]d_2= \frac 12 \times d_1 = = \frac 12 \times \frac 12= \frac 1 4[/tex] (given)

So, the distanve covered in the 3rd jump

[tex]=\frac 12 \times d_2= \left(\frac 1 2\right )^2\times \frac 1 2= \left(\frac 1 2\right)^{3-1}\times \frac 1 2.[/tex]

Similarly, the distance covered in the [tex]r^{th}[/tex] jump

[tex]=\left(\frac 12 \right)^{r-1}\times \frac 1 2.[/tex]

Assuming she requires [tex]n[/tex] jumps to travel 1 foot of distance.

So, the sum of all the distances covered in n jumps = 1 foot

[tex]\Rightarrow \frac 1 2 + \frac 1 4 + \cdots + \left(\frac 12 \right)^{r-1}\times \frac 1 2+\cdots+ \left(\frac 12 \right)^{n-1}\times \frac 1 2=1[/tex]

[tex]\Rightarrow \frac 1 2 + \left(\frac 12 \right)^2 + \cdots + \left(\frac 12 \right)^{r}+\cdots+ \left(\frac 12 \right)^{n}=1[/tex]

This a geometric progression, G.P., of [tex]n[/tex] terms having common ration, r= 1/2 and the first term [tex]a_1= 1/2[/tex].

As sum of all the n terms of  G.P [tex]=\frac {a_1(r^n-1)}{r-1}[/tex],

[tex]\Rightarrow \frac {1/2((1/2)^n-1)}{1/2-1}=1[/tex]

[tex]\Rightarrow - \left(\left(\frac 1 2\right)^n-1\right)=1[/tex]

[tex]\Rightarrow \left(\frac 1 2\right)^n-1=-1[/tex]

[tex]\Rightarrow \left(\frac 1 2\right)^n=-1+1=0[/tex]

[tex]\Rightarrow \frac {1}{2^n}=0[/tex]

This is only possible, mathematically, when [tex]n\rightarrow \infty[/tex], But in real life situation reaching infinity is not possible.

Hence, she can never travel a distance of 1 foot for the given condition.

you add the fractions together

1 5/12+1 3/4+2 1/3 is 4 3/1 which simplifies to 7

multiply 7 by 10.50 and get 73.5

ANSWER= $73.50

Answer:

10/24 or 5/12

Step-by-step explanation:

If you add both boys and girls you will get 24 which is the total students and the number of boys us 10 so it would be 10/24 or simplified would be 5/12.

:) Hope this helps

Answer:

x = 50

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition

x = 10 when y = 40, then

40 = 10k ( divide both sides by 4 )

4 = k

y = 4x ← equation of variation

When y = 200, then

200 = 4x ( divide both sides by 4 )

50 = x

Answer:

[tex]v=\frac{145}{8}[/tex]

Step-by-step explanation:

[tex]\frac{5}{v}=\frac{2}{7.25}[/tex]

[tex]\frac{5}{v}=\frac{2}{\frac{725}{100}}[/tex]

[tex]v=\frac{2}{\frac{5^2*29}{2^2*5^2}}[/tex]

[tex]v=\frac{145}{8}[/tex]

Answer:

2 times

Step-by-step explanation:

you do the equation 180 + 180 and get 360 or you can multiply 180 x 2 and get 360. Hope this helps you!

Answer:

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number.

Any number that can be written as a fraction with integers is called a rational number . For example, 17 and −34 are rational numbers

Answer:

C. it cannot be a whole number

Step-by-step explanation:

Answer:

Step-by-step explanation:

First you determine the variables x and y as:

x: the value for student tickets

y: the value for chaperone tickets.

Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:

x= y +2

On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:

59x + 6y = 508

Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:

[tex]\left \{ {{x=y+2} \atop {59x+6y=508}} \right.[/tex]

Solving for x, the price of a student ticket:

Rearranging  the first equation,

y = x - 2

Replacing in the second equation and solving for x:

59*x + 6*(x -2)=508

59*x + 6*x -12=508

65*x -12=508

65*x= 508 +12

65*x= 520

[tex]x=\frac{520}{65}[/tex]

x=8

The cost of a student ticket is 8$

Answer:

x = −2

Step-by-step explanation:

4x + 1 = x − 5

Subtract 1 from both sides

4x + 1 − 1 = x − 5 − 1

Simplify

4x = x − 6

Subtract x from both sides

4x −x = x − 6 − x

Simplify

3x = −6

Divide both sides by 3

[tex]{\frac{3x}{3}[/tex]=[tex]\frac{-6}{3}[/tex]

Simplify

x = −2

Answer:

The polynomials can be identified by noting which expressions contain only the operations of addition, subtraction, multiplication, and non-negative integer exponents. The non-polynomial expressions will be the expressions which contain other operations. Explain why the non-polynomial expressions are not polynomials.