Respuesta:
0,114 m³
Explicación:
El volumen del cohete será igual a la suma de los volumenes del cilindro y del cono
Volumen del cilindro
El cilindro tiene un radio (r) de 0,25 m y una altura (h) de 0,5 m. Podemos encontrar su volumen usando la siguiente formula.
Vcil = π × r² × h
Vcil = π × (0,25 m)² × 0,5 m = 0,098 m³
Volumen del cono
El cono tiene un radio (r) de 0,25 m y una altura (h) de 0,25 m (la mitad de 0,5 m). Podemos encontrar su volumen usando la siguiente formula.
Vcono = 1/3 × π × r² × h
Vcono = 1/3 × π × (0,25 m)² × 0,25 m = 0,016 m³
Volumen del cohete
Vcohete = Vcil + Vcono = 0,098 m³ + 0,016 m³ = 0,114 m³
Find the measure of the arc indicated. Assume that lines which appear tangent are tangent.
Answer:
Minor Arc AC = 360 - 235 = 125°
[tex]mABC = \frac{Major \ arc - Minor \ arc}{2} = \frac{235 - 125}{2} = \frac{110}{2} = 55[/tex]
The diagram shows a campground in the shape of a right triangle. You walk along a path from the camp office
at point c to your campsite at point D on a path that bisects the right angle C. Determine how far you are from
the picnic area at Point A to the nearest tenth of a meter.
Help If you know the answer plz!
Answer:
2
Step-by-step explanation:
Answer:
2t
Step-by-step explanation:
3t-t is the same as 3-1, so it equals 2t
Find the measure of the missing angle
128°
Help plz
Answer:
52 degrees
Step-by-step explanation:
a line is 180 degrees so just subtract 128 from 180 which is 52
I NEED THIS QUICK no links !!!!! (math)
answer: the answer is c
What is the area, in square units, of trapezoid AEDC shown below?
Area of this trapezoid is 264 unit²
What is the area of a trapezoid?Area: ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides.
Given perpendicular distance as 12 and parallel sides as 20,24 units respectively.
Thus Area is (20+24 /2) ×12=264 units²
Hence, the Area of trapezoid is 264 unit²
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Please help. Image up top.
Answer:
6/5t + 4/15s - 3
Step-by-step explanation:
(-4/5t + 5/3s) + (-3 -7/5s + 2t)
You can only add like terms together so convert like terms to have the same denominator:
(-4/5t + 25/15s) + (-3 - 21/15s + 10/5t)
Get rid of the parentheses:
-4/5t + 25/15s - 3 - 21/15s + 10/5t
Combine like terms:
6/5t + 4/15s - 3
HELP ASAP
Solve for x.
x = [?]
X - 6
8x + 24
Answer:
x=18
Step-by-step explanation:
Both angles are supplementary angles and form 180
Set your formula up as following
(x-6) + (8x+24) = 180
x+8x-6+24=180
9x=180+6-24
9x=162
x=162/9
x=18
Now substitute 18 for x to get your angles and check your work .
A recipe for lemonade requires 10 parts of water to every 6 parts of lemon juice. How many cups of water should be added to 30 cups of lemon juice to make the lemonade? I dont understand how many "parts" of water = 1 cup
Answer:
50 cups
Step-by-step explanation:
ratio of water to juice = 10 : 6 = 5 : 3
amount of cup = (5 x 30) / 3 = 50
11/3 as a decimal pls help
Answer:
3.7 rounded
Step-by-step explanation:
Just divide 11/3
Simplify.
Rewrite the expression in the form z”. Z5 • Z6
Answer:
Simplify.
Rewrite the expression in the form z”. Z5 • Z6Simplify.
Rewrite the expression in the form z”. Z5 • Z6
Answer:
Simplify.
Rewrite the expression in the form z”. Z5 • Z6Simplify.
Rewrite the expression in the form z”. Z5 • Z6
The number of employees in each industry in Seattle was recorded and rounded to the nearest
10 thousand. The results are displayed in the dot plot above. According to the dot plot, what is
the median number of employees, in thousands?
Answer:
20
Step-by-step explanation:
Rob's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 adult tickets and 1 student ticket
for a total of $15. The school took in $69 on the second day by selling 9 adult tickets and 7 student tickets. What is the price each
of one adult ticket and one student ticket?
Answer:
Adult Tickets =$3
Student Tickets =$6
Step-by-step explanation:
3×3=9 9+6=15
9×3=27
7×6=42
27+42=67
Solve using the Quadratic Formula
5x2-3x-7=0
A)
B)
C)
D)
Answer:
C) [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Standard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]Step-by-step explanation:
Step 1: Define
Identify
5x² - 3x - 7 = 0
↓
a = 5, b = -3, c = -7
Step 2: Solve for x
Substitute in variables [Quadratic Formula]: [tex]\displaystyle x=\frac{3 \pm \sqrt{(-3)^2-4(5)(-7)}}{2(5)}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle x=\frac{3 \pm \sqrt{9-4(5)(-7)}}{2(5)}[/tex][√Radical] Multiply: [tex]\displaystyle x=\frac{3 \pm \sqrt{9+140}}{2(5)}[/tex][√Radical] Add: [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{2(5)}[/tex][Fraction] Multiply: [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]Expand and combine like terms.
(4m^5) – 5m^6) (4m^5 + 5m^6) =
Answer:
[tex]16m^{10} -25m^{12}[/tex]
Step-by-step explanation:
hope this helps :)
The expand and combination like terms (4m^5) – 5m^6) (4m^5 + 5m^6) is -9m^12 + (16)m^10.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.
We are given that;
The equation=(4m^5) – 5m^6) (4m^5 + 5m^6)
Now,
To expand the expression, we need to multiply each term inside the first parentheses by each term inside the second parentheses. This gives us:
(4m^5 - 5m^6) (4m^5 + 5m^6) = 4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6
To simplify the expression, we need to use the exponent rule that a^b * a^c = a^(b + c) and combine the terms that have the same base and exponent. This gives us:
4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6 = 16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6)
To further simplify the expression, we need to add the exponents and simplify the coefficients. This gives us:
16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6) = 16m^10 + 20m^11 - 20m^11 - 25m^12
To combine like terms, we need to add or subtract the coefficients of the terms that have the same base and exponent. This gives us:
16m^10 + 20m^11 - 20m^11 - 25m^12 = (16 - 25)m^12 + (20 - 20)m^11 + (16)m^10
= -9m^12 + (0)m^11 + (16)m^10
= -9m^12 + (16)m^10
Therefore, the equation will be equal to -9m^12 + (16)m^10.
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Find the measure of angle C
Answer:
ajnasnnanananandbabbabbansbansbz svabsvsb
Bacteria are taking over the kitchen sink. Right now, there are 375 microbes of bacteria. They double every hour.
Is the function describe above a growth or decay function?
Answer: The function described in this scenario above is a “Growth Function”
Have a nice day!
Suppose f(x) = x^3 +3. Find the graph of f(2/3x)
Answer:
First, when we have a function f(x), an horizontal dilation of scale factor k, is written as:
g(x) = f(x/k)
Then f((2/3)*x) is an horizontal dilation of scale factor 3/2 of the function f(x).
(The graph will be a little bit wider than the graph of f(x))
Also, knowing that f(x) = x^3 + 3
Then:
f((2/3)*x) = ( (2/3)*x)^3 + 3
= (8/27)*x^3 + 3
And the graph of this function is shown below:
Stanley attempted to simplify the expression below.
−4●(2.5x−1.25)−3x
His work, step by step, is shown below.
Step 1: −4●{(2.5x+(−1.25)}−3x
Step 2:−10x+(−5)−3x
Step 3:−10x−3x+(−5)
Step 4: −13x−5
In which step did he make his first error simplifying the expression?
If the interest of a sum at 7.5% p.a in 4 years is Rs. 1050, find the sum
~Refer to the attachment for the solution.
[tex] \to \bf { Sum = 3500 } [/tex]
3(2^2x+3)-5(2^x+2)-156=0
Answer: [tex]x=3.0206[/tex]
Step-by-step explanation:
Given
[tex]3(2^{2x}+3)-5(2^x+2)-156=0[/tex]
Replace [tex]2^x[/tex] by [tex]y[/tex]
We can write
[tex]\Rightarrow 3(y^2+3)-5(y+2)-156=0\\\Rightarrow 3y^2+9-5y-10-156=0\\\Rightarrow 3y^2-5y-157=0\\\\\Rightarrow y=\dfrac{5\pm \sqrt{25-4(3)(-157)}}{2\times 3}\\\\\Rightarrow y=\dfrac{5+43.69}{6}\\\\\Rightarrow y=8.115\\\Rightarrow 2^x=8.115\\\therefore \quad x=3.0206[/tex]
In the question, "35 is what percent of 40?" what is the 35?
Answer:
35 is the 'is' and 40 is the 'of'
Step-by-step explanation:
is/of = %/100
35/40 = x/100
cross-multiply to get:
40x = 3500
x = 3500/40
x = 87.5
Name the side that’s opposite to angle A. (Geometry)
1.) AB
2.) AC
3.) BC
Answer:
The answer gonna be A and C because their both is the same length
Answer:
BC
Step-by-step explanation:
The side opposite the right angle is called the hypotenuse. It is the largest side right angled triangle.If you stand at A in the triangle ABC, the side BC is opposite to you and the side BC is next to you. We therefore say that BC is the opposite side to angle A and AB is the adjacent side ti angle A.
Classify this expression
Answer:
8.
[tex]8. - 1. - 44 [/tex]
9
177*((177+(9-4+7)) +90/8=
Answer:
33464.25
Step-by-step explanation:
Using BODMAS : brackets, division, multiplication, addition
[tex]177\times ((177+(9-4+7)) +\frac{90}{8}\\\\177\times (177+12) +\frac{90}{8}\\\\177\times 189 +\frac{90}{8}\\\\\\177 \times 189 + 11.25\\\\33453 + 11.25\\\\33464.25[/tex]
Answer:
35444.25
Step-by-step explanation:
OFC by computing them
Find the area of a triangle with a height of 5 ft and a base of 4 ft.
Answer:
5 x 4 = 20, 20 divided by 2 ( x 1/2 ) = 10
Step-by-step explanation:
Formula area of a Triangle:
B(base) x H(height) x 1/2(basically just dividing by 2)
You take a bus from your neighborhood to your school. The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m. The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m. You arrive at the bus stop at 7:33 a.m. Find the probability that you missed both the express bus and the local bus. Express your answer as a fraction in simplest form.
Answer:
[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.
Step-by-step explanation:
Uniform distribution:
An uniform distribution has two bounds, a and b.
The probability of getting a value lower than x is:
[tex]P(X < x) = \frac{x - a}{x - b}[/tex]
The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m.
6 minutes, so [tex]a = 0, b = 6[/tex]
You arrive at 7:33, so if x < 3, you lose the express bus:
[tex]P_E = P(X < 3) = \frac{3 - 0}{6 - 0} = \frac{3}{6} = \frac{1}{2}[/tex]
The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m.
10 minutes, so [tex]a = 0, b = 10[/tex]
[tex]P_B = P(X < 3) = \frac{3 - 0}{10 - 0} = \frac{3}{10}[/tex]
Find the probability that you missed both the express bus and the local bus.
[tex]p = P_E*P_B = \frac{1}{2}*\frac{3}{10} = \frac{3}{20}[/tex]
[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.
The probability that you missed both the express bus and the local bus is 3/20
The individual probability of a uniform distribution is calculated as:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
For the express bus
At 7:30 am, a = 0
At 7:36 am, b = 6
You arrived at 7:33 am; this means that:
x = 3
For you to miss the express bus, it means that the express bus left before 7:33 am.
i.e. x < 3
So, the probability that you miss the express bus is:
[tex]P(X < 3) = \frac{3 - 0}{6 - 0}[/tex]
[tex]P(X < 3) = \frac{3}{6}[/tex]
[tex]P(X_E < 3) = \frac{1}{2}[/tex]
For the local bus
At 7:30 am, a = 0
At 7:40 am, b = 10
You arrived at 7:33 am; this means that:
x = 3
For you to miss the local bus, it means that the local bus left before 7:33 am.
i.e. x < 3
So, the probability that you miss the local bus is:
[tex]P(X < 3) = \frac{3 - 0}{10 - 0}[/tex]
[tex]P(X_L < 3) = \frac{3}{10}[/tex]
So, the probability that you miss both bus is:
[tex]P(Both) = P(X_E < 3) * P(X_L < 3)[/tex]
This gives
[tex]P(Both) = \frac 12 * \frac 3{10}[/tex]
[tex]P(Both) = \frac 3{20}[/tex]
Hence, the probability that you missed both the express bus and the local bus is 3/20
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What is the height h of the flagpole in meters?
A. 10m
B. 12m
C. 18m
D. 20m
What is the domain of f?
A survey of 125 freshmen business students at a local university produced the results listed below. How many students took history and math, but not music? 30 took history; 32 took math; 33 took music; 14 took history but not math; 9 took math and music; 13 took history and music; 2 took all three
Answer:
Total Number of students taking Math and History and not music are 68.
Number of students who took both math and history at the same time is 6.
Step-by-step explanation:
History = 30
Math = 32
Music= 33
Math and Music= 9
History and Music= 13
History and Music and Math = 2
History but not math = 14
We have to find students taking history and math but not music.
Total number of students = 125
From the figure number of students taking Math and History and not music are
=30+6+32= 68
Number of students who took both math and history at the same time is 6.