Answer: P = 10x^2 +6x + 4
Step-by-step explanation:
P = R-C
R = (3x^2 - x + 6)
C = (-7x^2 -7x + 2)
P = (3x^2 - x + 6) - (-7x^2 -7x + 2)
P = 3x^2 - x + 6 + 7x^2 +7x - 2
P = 10x^2 +6x + 4
..............................
Answer:
A rational number is a number that doesn't terminate or repeat
a non rational number is a number that terminates or repeats
so she basicelly got mixed up
Hope This Helps!!!
ASAP
Please show working out I will give out brainiest :)
Need all answers a lot of points
Which quantity of fruit contains an amount of vitamin C closest to the combined
amount of vitamin C in 50 g grams of acerola cherries and 150 g grams of
kiwifruit?
A. 2,000 g grams of black currants
B. 800 g grams of guava
C. 1,800 g grams of pineapple
D. 600 g grams of strawberries
Answer:
c would be the closest due to the total amount of vitamin c in the objects.
The quantity of fruit which contains an amount of vitamin C closest to the combined content is: C. 1,800 g grams of pineapple.
How to calculate the amount of vitamin.In this exercise, we would determine the amount of vitamin C that is present in a combination of 50 grams of acerola cherries and 150 grams of kiwifruit.
For acerola cherries:
100 grams of acerola cherries = 1678 mg.
50 grams of acerola cherries = X mg.
Cross-mutiplying, we have:
X = 83,900/100 = 839 mg.
For kiwifruit:
100 grams of kiwifruit = 105 mg.
150 grams of kiwifruit = Y mg.
Cross-mutiplying, we have:
Y = 15,750/100 = 157.5 mg.
Combine vitamins = 157.5 + 839 = 996.5 mg.
Based on intuition, we would choose 1,800 grams of pineapple.
100 grams of pineapple = 56 mg
1,800 grams of pineapple = Z mg.
Cross-mutiplying, we have:
Z = 100,800/100 = 1008 mg.
Thus, 996.5 mg of vitamin C is closest to 1008 mg.
Note: If you do the above computations for other quantities of fruit, you'll get a value far from 996.5 mg.
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Simplify the expression.
4+ 5(3x - 2) - 3x
O A. -187-6
ООО
O B. -18x-14
-
C. 12x - 6
O D. 12x+ 2 2
I need friends answer this and we will be besties
Answer:
12x - 6
Step-by-step explanation:
4 + 15x - 10 -3x
(15x - 3x) + (4-10)
12x - 6
please answer!!!!!!!!!!!
Answer 75-82 pls it would be amazing!!!!!
Answer:
75-82=-7
Step-by-step explanation:
e
ILL GIVE YOU BRAINLEST PLEASE HELP
Answer:
The expression is d(45) + 25 = c
Step-by-step explanation:
The expression is d(45) + 25 = c. Let's test it out to see if it is correct. We will test it out by substituting d and c.
Day 1:
For a day, the expression will be 1(45) + 25 = 70=> 45 + 25 = 70=> 70 = 70Day 2:
For two days, the expression will be 2(45) + 25 = 115=> 90 + 25 = 115=> 115 = 115Day 3:
For three days, the expression will be 3(45) + 25 = 160=> 135 + 25 = 160=> 160 = 160Day 4:
For four days, the expression will be 4(45) + 25 = 205=> 180 + 25 = 205=> 205 = 205Therefore, the expression is d(45) + 25 = c.
Hoped this helped.
evaluate the expression when p = 4. p^2+5 no links pls
Answer:
21
Step-by-step explanation:
when p is 4
p² + 5 = 4² + 5
16 + 5 = 21
is -54 colder than -127
Answer:
-127 is colder
Step-by-step explanation:
-54 is closer to 0 than -127 so -127 is colder
They are both negatives BUT! -127 is greater than -54 and the 0 is the begginging of frezing point
Find the distance between the origin and (-12,-9)
Answer:
Distance (d) = 15
Step-by-step explanation:
The given requires the distance between the point of origin, (0, 0), and (-12, 9). We can use the following distance formula for this problem:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]
Let (x₁, y₁) = (0, 0)
(x₂, y₂) = (-12, 9)
Substitute these values into the distance formula.
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12\:-\:0)^2\:+\:(9-0)^2}}[/tex]
Perform the required subtraction within each parenthesis:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12)^2\:+\:(9)^2}}[/tex]
Next, take the squared values of -12 and 9 under the radical:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{144\:+\:81}}[/tex]
Add 144 and 81:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{225}}[/tex]
Distance (d) = 15
Answer:Therefore, the distance between the point of origin and (-12, 9) is 15.
-
Drag the steps for drawing a graph of the function f(x) = 2(x+4)2 - 3 to
arrange them in the correct order. It might help you to draw the graph as
you arrange the steps.
Plot the vertex (-4,-3).
Draw the axis of symmetry x=-4.
Reflect the points over the axis of symmetry and plot (-5, -1), (-6,5), and (-7,15).
Apply the 2x? pattern, from the vertex go right 1 up 2 and plot (-3,-1).
Apply the 2x² pattern again, from the vertex go right 2 up 8 and plot (-2,5).
Apply the 2x² pattern a 3rd time, from the vertex go right 3 up 18 and plot (-1,15)
Draw a U shaped parabola
The shape of the graph of quadratic functions is the shape of a parabola.
The steps for drawing a graph of the function f(x) = 2·(x + 4)² - 3 arranged in the correct order are;
(a) Plot the vertex (-4, -3)(b) Apply the 2·x² pattern, from the vertex go right 1 up 2 and plot (-3, -1)(c) Apply the 2·x² pattern again, from the vertex go right 2 up 8 and plot (-2, 5)(d) Apply the 2·x² pattern a 3rd time, from the vertex go right 3 up 18 and plot (-1, 15)(e) Draw the axis of symmetry x = -4(f) Reflect the points over the axis of symmetry and plot (-5, -1), (-6, 5), and (-7, 15)(g) Draw a U shaped parabola.Reasons:
The given function is; f(x) = 2·(x + 4)² - 3
The function is given in the vertex form; f(x) = a·(x - h)² + k
Therefore, the vertex, (h, k) = (-4, -3)
Step (a);
The vertex can be plotted on the graph
Plot the vertex (-4, -3)Step (b);
Given that the quadratic term is 2·x², the pattern that can be used for the points from the vertex is therefore, 2·x²
From the vertex (-4, -3) apply the 2·x² pattern by going to the right 1 unit and up 2 × 1² = 2 units to get the point (-4 + 1, -3 + 2) = (-3. -1)
Apply the 2·x² pattern, from the vertex go right 1 up 2 and plot (-3, -1)Step (c);
To get the next point, the 2·x² pattern is applied with x = 2, to the vertex to get; (-4 + 2, -3 + (2×2²)) = (-2, 5)
Apply the 2·x² pattern again, from the vertex go right 2 up 8 and plot (-2, 5)Step (d);
A third point on the graph relative to the vertex is obtained again by applying the 2·x² pattern again to the vertex with x = 3, to get;
(-4 + 3, -3 + (2 × 3²)) = (-1, 15)
Apply the 2·x² pattern a 3rd time, from the vertex go right 3 up 18 and plot (-1, 15)Step (e);
The axis of symmetry can be drawn with a vertical line passing through the vertex, which is the line, x = -4
The line x = -4 can be drawn on the graph next
Draw the axis of symmetry x = -4Step (f);
The points obtained relative to the vertex (-3, -1), (-2, 5), (-1, 15) can reflected about the axis of symmetry x = -4, to get;
(-3, -1) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-5, -1)
(-2, 5) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-7, 5)
(-1, 15) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-7, 15)
Reflect the points over the axis of symmetry and plot (-5, -1), (-6, 5), and (-7, 15)Step (g);
The parabola that is U shaped can be drawn from the points plotted in the steps above.
Draw a U shaped parabolaLearn more about drawing the graph of a quadratic function here:
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samuel goes to a store and buys an item that costs x dollars. he has a coupon for 15% off, and then a 6% tax is added to the discounted price. write an expression in terms of x that represents the total amount that samuel paid at the register.
Answer:
I think you might be able to work with this: 0.15 * x - x + x * 0.06
Step-by-step explanation:
The item's cost is X.
So he has a coupon for 15%, so the cost of the item times 0.15 = how much he's getting as a discount, for example: A toy robot costs 13.46, Jenny has a coupon for 25% off, to find out how much she paid, multiply 0.25 by 13.46 which equals about 3.37, so 13.46 - 3.37 = 10.09
So 0.15 (the coupon price) * x (the item's original price) - x (the items orignal price) + x * 0.06 (the sales tax)
Comment if you need any help T^T
Use your knowledge of isosceles and equilateral triangle‘s to find the requested information.
Find m
Answer:
48 degrees
Step-by-step explanation:
6y=8y-16
y=8
8(8)-16= ?
64-16=
Answer:
∠ P = 48°
Step-by-step explanation:
Since NM = PM then the triangle is isosceles with base angles being congruent, then
∠ P = ∠ N , that is
8y - 16 = 6y ( subtract 6y from both sides )
2y - 16 = 0 ( add 16 to both sides )
2y = 16 ( divide both sides by 2 )
y = 8
Then
∠ P = 8y - 16 = 8(8) - 16 = 64 - 16 = 48°
1. Reduce the ratio to the simplest form:
a)5:10=_____.
b)60:54=____.
Answer:
1:2 by division of 5
10:9 by division of 6
If A = 2x – y + 3xy, B = x + 2xy and C = 3y + xy, find the value of A + B + C
[tex]A+B+C\\\\=(2x-y+3xy)+(x+2xy) +(3y+xy)\\\\=3x+2y+6xy[/tex]
The value of the expression A + B + C is equal to 3x - 2y + 4xy.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Given, Are three expressions A = 2x - y + 3xy, B = x + 2xy and C = 3y + xy.
Now, A + B + C is equal to the sum of their values which is,
= (2x - y + 3xy) + (x + 2xy) + (3y + xy).
Now, we'll combine the like terms,
= 2x + x - y + 3y + 3xy + xy.
= 3x - 2y + 4xy.
So, The value of the expression A + B + C is equal to 3x - 2y + 4xy.
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Replace the power with a product and then transform the product into a polynomial. (1-y)^2
Answer:
1-2y+y^2
Step-by-step explanation:
(1–y)^2
(1-y) * (1-y)
FOIL
first: 1*1 =1
outer: 1*-y = -y
inner: -y *1 = -y
last: -y*-y = y^2
Add together: 1+-y-y+y^2
Final answer1-2y+y^2
Credit:
wegnerkolmp2741o
He solved it earlier.
Can i get some help :
Answer:
b = [tex]\frac{7}{12}[/tex]
Step-by-step explanation:
b + [tex]\frac{2}{3}[/tex] = 1 [tex]\frac{1}{4}[/tex] ← change to an improper fraction
b + [tex]\frac{2}{3}[/tex] = [tex]\frac{5}{4}[/tex]
Multiply through by 12 ( the LCM of 3 and 4 ) to clear the fractions
12b + 8 = 15 ( subtract 8 from both sides )
12b = 7 ( divide both sides by 12 )
b = [tex]\frac{7}{12}[/tex]
Answer:
The value of b is 7/12.
Step-by-step explanation:
Question :
Solve for b.
[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]
Enter your answer as a fraction in simplest form in the box.
[tex]\implies{\sf{b = \square}}[/tex]
[tex]\begin{gathered}\end{gathered}[/tex]
Solution :
[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]
Converting the mixed fractions into improper fraction.
[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{(1 \times 4) + 1}{4}}}}[/tex]
[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{(4)+ 1}{4}}}}[/tex]
[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{4+ 1}{4}}}}[/tex]
[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{5}{4}}}}[/tex]
Now, transporting LHS to RHS.
[tex]{\implies{\sf{b= \dfrac{5}{4} - \dfrac{2}{3}}}}[/tex]
Taking LCM of denominators and subtracting.
[tex]{\implies{\sf{b= \dfrac{(5 \times 3) - (2 \times 4)}{12}}}}[/tex]
[tex]{\implies{\sf{b= \dfrac{(15) - (8)}{12}}}}[/tex]
[tex]{\implies{\sf{b= \dfrac{15 - 8}{12}}}}[/tex]
[tex]{\implies{\sf{b= \dfrac{7}{12}}}}[/tex]
[tex]{\star{\red{\underline{\boxed{\sf{b= \dfrac{7}{12}}}}}}}[/tex]
Hence, the value of b is 7/12.
[tex]\begin{gathered}\end{gathered}[/tex]
Verification :
[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]
Substituting the value of (b=7/12)
[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]
Converting mixed fractions into improper fraction
[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{(1 \times 4) + 1}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{(4) + 1}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{4 + 1}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{5}{4}}}}[/tex]
Taking LCM of denominators in LHS and adding.
[tex]{\implies{\sf{ \dfrac{(7 \times 1) + (2 \times 4)}{12} = \dfrac{5}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{(7) + (8)}{12} = \dfrac{5}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{7 + 8}{12} = \dfrac{5}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{15}{12} = \dfrac{5}{4}}}}[/tex]
Cutting the fraction to simplest form.
[tex]{\implies{\sf{ \cancel{\dfrac{15}{12}} = \dfrac{5}{4}}}}[/tex]
[tex]{\implies{\sf{ \dfrac{5}{4}= \dfrac{5}{4}}}}[/tex]
[tex]{\star{\red{\underline{\boxed{\sf{LHS = RHS}}}}}}[/tex]
Hence Verified!
[tex]\underline{\rule{220pt}{3.5pt}}[/tex]
How many fifths are there in the fraction 21/5?
Answer:
21
Step-by-step explanation:
1/5 x 21 = 21/5
In \triangle KLM,△KLM, \overline{KL}\cong \overline{MK} KL ≅ MK and \text{m}\angle M = 43^{\circ}.m∠M=43 ∘ . Find \text{m}\angle L.m∠L.
Based on the definition of an isosceles triangle, the measure of angle L is: 43°
Recall:
An isosceles triangle has two side lengths that are equal in size, and also the angles opposite the equal sides are congruent.Given that KL ≅ MK in △KLM, it means △KLM is an isosceles triangle.
If m∠M = 43°, therefore, m∠M = m∠L (equal angles directly opposite KL and MK).
This implies that: m∠L = 43°
In summary, based on the definition of an isosceles triangle, the measure of angle L is: 43°
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How many Centimeters?
22
23
24
25
26
27
28
29
30
31
Answer:
10
Step-by-step explanation:
15 POINTS HELP PLZ
Which expression is equal to f(x) - g(x)?
Answer:
B) x^3-x^2-8x-2
Step-by-step explanation:
Expand the equation of g(x) to standard form
f(x) = x^3-4x+2
g(x) = x^2-4x+4
Subtract like terms in the equation and solve for the answer.
f(x) - g(x) = x^3-x^2-4x-4x+2-4
x^3-x^2-8x-2
Identify an example of a pair of skew line from the box below
Answer:
AB, CD
Step-by-step explanation:
Skew lines do not lie in the same plane, and do not intersect. One such pair is AB and CD.
__
Additional comment
Any of the lines, and any of the lines that intersect its diagonally-opposite edge will be skew lines.
For example, the opposite edge to line BC is line EG. Lines that intersect EG are ED, EF, GA, GH. All of those four lines are skew with respect to line BC.
What are the equations for the asymptotes of this hyperbola?
Y^2/36 - x^2/121=1
Answer:
[tex]\huge{\mathfrak{Solution}}[/tex]
[tex]\huge{\bold{ \frac{ {y}^{2} }{36} - \frac{ {x}^{2} }{121} = 1 }}[/tex]
[tex]\huge{\bold{ \frac{(y - k) {}^{2} }{ {a}^{2} } - \frac{(x - h) {}^{2} }{ {b}^{2} } = 1 \: is \: the \: standard \: equation \: with \: center \: (h ,k),semi-axis \: a \: and \: semi-conjugate \: -axis \: b.}}[/tex]
[tex]\huge\boxed{\mathfrak{We \: get,}}[/tex]
[tex](h,k) = (0,0),a = 6,b = 11[/tex]
[tex]For \: hyperbola \: assymtoms \: are \: y = + \frac{a}{b} (x - h) + k[/tex]
[tex]Therefore,y = \frac{6}{11} (x - 0) + 0,y = - \frac{6}{11} (x - 0) + 0[/tex]
[tex]\large\boxed{\bold{y = \frac{6x}{11},y = - \frac{6x}{11} . }}[/tex]
If y²/36 - x²/121 = 1, the asymptotes are y = (36/121) x and y = -(36/121) x.
To find the equations for the asymptotes of the hyperbola represented by the equation y²/36 - x²/121 = 1, we can compare it with the standard form of a hyperbola:
(y - k)² / a² - (x - h)² / b² = 1
where (h, k) represents the center of the hyperbola.
In the given equation, we have y²/36 - x²/121 = 1. To put it in standard form, we need to divide both sides by 1 (which is essentially dividing by 1 on the right side):
y²/36 - x²/121 = 1 / 1
Now, we can see that a² = 36 and b² = 121.
To find the equations of the asymptotes, we use the center (h, k) and the values of a and b. The asymptotes of a hyperbola have equations of the form:
y = k ± (a/b)(x - h)
In this case, the center (h, k) is (0, 0), a² = 36, and b² = 121:
The equations for the asymptotes are:
y = 0 ± (36/121) x
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Tim is 40 lbs less than his bother. If together they weigh 220, how much does Tim weigh?
Answer:
90lbs
Step-by-step explanation:
If Tim weights 90lbs, his brother must weigh 130lbs which add to make 220lbs
A function is described by the equation f(x) = x² +5. The replacement set for the independent
variable is {1, 5, 7, 12}. Which of the following is contained in the corresponding set for the
dependent variable?
Answer:
5
Step-by-step explanation:
5 =5 +5+5=5+5
Someone please answer this and not one of those bot links answer it someone an actual person please answer it I’ll give you brainliest…
Answer:
1) y = 13.5x + 12) y = 12x + 43) Sam won the raceStep-by-step explanation:
Part 1Sam's car is 1 ft in front of the start line and its speed is 13.5 ft/s.
The distance after x seconds is:
y = 13.5x + 1Part 2Alice's car the speed 12 ft/s and after 3 seconds is 40 ft in front of the start line.
The distance after x seconds is:
y = 12(x - 3) + 40 = 12x - 36 + 40 = 12x + 4Part 3After 15 seconds the distance from the start line is:
Sam ⇒ y = 13.5*15 + 1 = 203.5 ftAlice ⇒ y = 12*15 + 4 = 184 ftAs we see Sam is further from the start line than Alice
Gabriella and her children went into a restaurant where they sell hotdogs for $4 each and tacos for $2 each. Gabriella has $30 to spend and must buy a minimum of 9 hotdogs and tacos altogether. Also, she must buy no less than 2 hotdogs. If xx represents the number of hotdogs purchased and yy represents the number of tacos purchased, write and solve a system of inequalities graphically and determine one possible solution.
A possible solution to the inequality is 2 hotdogs and 8 tacos.
Let x represents the number of hotdogs purchased and y represents the number of tacos purchased.
Gabriella has $30 to spend and must buy a minimum of 9 hotdogs and tacos altogether.
Hence:
4x + 2y ≤ 30 (1)
x + y ≥ 9 (2)
Also:
x ≥ 2 (3)
A possible solution to the inequality is 2 hotdogs and 8 tacos.
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Please help WILL MARK BRAINLIST!!!!
Answer:
22
Step-by-step explanation:
2x+x-2=2x+9
3x-2=2x+9
x-2=9
x=11
MN=2x
MN=2(11)
MN=22
Equation of the line that passes through (-6,-5) and (-3,0)
Answer:
y=(5/3)x + 5
Step-by-step explanation:
Every line is in the form: y = ax+b. If some points are on this line, they satisfy this equation. So we can write:
-5 = a(-6) + b
0 = a(-3) + b
It's a system of equations. We can solve them by subtracting the second equation from the first:
-5-0 = -6a - (-3a) + b - b
That becomes:
-5 = -3a
Therefore:
a = 5/3
Now we plug this value in the second equation of the system, and find the value of b:
0 = 5/3*(-3) +b
b=5
The final line equation will be: y=(5/3)x + 5
y = [tex]\frac{5}{3}[/tex]x + 5
Explanation:First, find the slope. The formula to find slope can be defined as [tex]\frac{y_2-y_1}{x_2-x_1}[/tex].
Given points (-6, -5) and (-3, 0), we can substitute those values in and find that the slope for this line will be [tex]\frac{5}{3}[/tex].
Using slope-intercept form, our equation so far is y = [tex]\frac{5}{3}[/tex]x + b. To find b, we substitute the coordinates of any point and solve. Doing so gets us a value of 5 for b.
Therefore, our final answer is y = [tex]\frac{5}{3}[/tex]x + 5.