In the diagram, the radius is 7 and tangent AB has length of 24. Determine the length of OA rounded to the nearest whole number

In The Diagram, The Radius Is 7 And Tangent AB Has Length Of 24. Determine The Length Of OA Rounded To

Answers

Answer 1

Given the radius r and the tangent line AB, the length of the line OA is 24 units

How to determine the length OA?

The radius r and the tangent line AB meet at a right angle.

By Pythagoras theorem, we have:

AB² = OA² + r²

So, we have:

24² = OA² + 7²

Rewrite as:

OA² = 24² - 7²

Evaluate

OA² = 527

Take the square root of both sides

OA = 23

Hence, the length of OA is 24 units

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Related Questions

-3(v+1)-3

What is the answer I really need help

Answers

Answer:

=-3v-6

Step-by-step explanation:

Distribute:

=(−3)(v)+(−3)(1)+−3

=−3v+(−3)+(−3)

Combine like terms:

=(−3v)+(−3+(−3))

=−3v+−6

=-3v-6

Hope this helps, this was easy!

The answer is -3v-6

Helpppp pleaseeeee is

Answers

Answer:

Step-by-step explanation:a(1/2 - 1/8)/(2 - 1/2)

a. (4/8 - 1/8)/(4/2 - 1/2)

3/8 / 3/2

3/8 x 2/3 = 2/8 = 1/4

y - 1/8 = 1/4(x - 1/2)

y - 1/8 = 1/4x - 1/8

y = 1/4x

b. (1400 - 1200)/(1000 - 500)

     200/500 = 2/5

y -  1200 = 2/5(x - 500)

y - 1200 = 2/5x - 200

y = 2/5x + 1000

c. (41.85 - 13.95)/(3 - 1)= 27.90/2 = 13.95

 y - 13.95 = 13.95(x - 1)

y - 13.95 = 13.95x - 13.95

y = 13.95x

d. (2.34 - 0)/(15 - 0)= 2.34/15 = .16 or .156

    y = .16(x - 0)

y = .16x

or y = .156x

How do you find the volume of a square pyramid?

Answers

Answer:

to find volume of square pyramid use this formula

Step-by-step explanation:

[tex]volume = \frac{1}{3} a {}^{2} h[/tex]

12
What is the slope of the line that passes through the points (2, 3) and (8, 6)?

Answers

Answer:

Here is the ans...hope it helps

Solve for x.
4^0.2x + 6 = 43, enter your answe with four decimal places.

Answers

Answer:

13.0236

Step-by-step explanation:

4^0.2x +6=43

(2^2)^0.2x +6=43

2^2*0.2x +6=43

Thomas found a box that had a volume of 150 in3. He measured the height of the box to be 2 inches and the length was 10 inches more than the width. What is the width of the box?
7 inches
11 inches
15 inches
5 inches

Please Help!

Answers

The width of the box is 5 in if the volume of 150 in3. He measured the height of the box to be 2 inches, and the length was 10 inches more than the width.

What is a cuboid?

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape.

Volume of the box = l×w×h

150 = l×w×h

h = 2 in

l = 10+w

150 = (10+w)(w)(2)

150 = 2w(10+w)

After solving, we get:

w = 5 or w = -15

Width cannot be negative.

w = 5 in

Thus, the width of the box is 5 in if the volume of 150 in3. He measured the height of the box to be 2 inches, and the length was 10 inches more than the width.

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If stu=(13x-6), msu=(21x+8) and mut=143 find mst

Answers

The value of arc ST in the circle with center at point V is 125 degrees.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

mSU = 2 * ∠STU (angle at center is twice angle at circumference)

21x + 8 = 2(13x - 6)

x = 4

mSU = 21(4) + 8 = 92°

mSU + mUT + mST = 360° (angle in a circle)

92 + 143 + mST = 360

mST = 125°

The value of arc ST in the circle with center at point V is 125 degrees.

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Please help with this! Thanks

Answers

a) The arrangement of 9 paintings can be done 9 ways.

b) The arrangement of the 4 out of 9 paintings will be done as 21 ways.

What is the combination?

The arrangement of the different things or numbers in a number of ways is called the combination.

a) Here if she has 9 paintings so the number of the arrangements will be

[tex]^{9} C _2 =\dfrac{9!}{(9-1)!(1!)}\\\\\\^{9} C _2=\dfrac{9!}{8!}\\\\\\^{9} C _2= 9 \ ways[/tex]

b) The arrangement of the 4 out of 9 paintings will be

[tex]^{9}C_{4}=\dfrac{9!}{(9-4)!(4!)}\\\\\\\^{9}C_{4}=21 \ ways[/tex]

Therefore the arrangement of 9 paintings can be done 9 ways and the arrangement of the 4 out of 9 paintings will be done as 21 ways.

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On a coordinate plane, square P Q R S is shown. It has points (0, 4), (4, 4), (0, 0), and (4, 0).
Prove the diagonals of the square with vertices P(0, 4), Q(4, 4), R(0, 0), and S(4, 0) are perpendicular bisectors of each other.
Step 1: Calculate the slope of the diagonals.

The slope of diagonal PS is

.

The slope of diagonal QR is


Step 2: Calculate the midpoint of the diagonals.

The midpoint of PS is


The midpoint of QR is

.

The diagonals of the square are perpendicular bisectors because the diagonals are

Answers

Answer:

Step-by-step explanation:

Answer: The answers are:  -1,  1, (2, 2), (2, 2), & perpendicular and share the same point.

Step-by-step explanation: Trust Me! Answer is correct in Edge.

Good Luck! :)

The slope of diagonal PS is -1 The slope of diagonal QR is 1The midpoint of PS is (2, 2) The midpoint of QR is (2, 2)The diagonals of the square are perpendicular bisectors because the diagonals are perpendicular and share the same point.

find the area use 22/7 for π​

Answers

Answer:

~201

Step-by-step explanation:

Use the area formula:  [tex]A=\pi r^2[/tex]

22/7 x 64 = 201.14

which rounds to 201

Coach Jamison wants to celebrate the final win of the school’s softball season with a trio to the local fast food place. The team buys 26 delicious burritos and 27 orders of savory chips for $86.90. A few of the players are still hungry so the coach buys 14 more burritos and 9 more orders of chips for $40.70. If you don’t include tax, what is the price of a burrito and the price of an order of chips?

Answers

The price of Burritos is $ 2.2 and the price of savory chips is $1.1

What is system of equations ?

A system of equations is a set or collection of equations that you deal with all together at once.

Linear equations (ones that graph as straight lines) are simpler than non-linear equations, and the simplest linear system is one with two equations and two variables.

The price of 26 delicious burritos and 27 orders of savory chips for $86.90

4 more burritos and 9 more orders of chips for $40.70

Let us consider the price of Burritos is x

and the price of savory chips is y

from the first statement we can form the equation

26*x +27*y = 86.9

and from the second statement we can form the equation

14*x + 9*y= 40.70

To determine the price of each we have to solve these system of equations.

On solving using elimination method

16x = 35.2

x = $2.2

and y = $1.1

Therefore the price of Burritos is $ 2.2 and the price of savory chips is $1.1.

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The price of Burritos is $ 2.2 and the price of savory chips is $1.1

What is system of equations ?

A system of equations is a set or collection of equations that you deal with all together at once.

The price of 26 delicious burritos and 27 orders of savory chips = $86.90

The price of 14 more burritos and 9 more orders of chips = $40.70

Let us consider the price of Burritos is x

and,  the price of savory chips is y

Now,

26x +27y = 86.9

and

14* + 9*= 40.70

On solving above two equation, we get

16x = 35.2

x = $2.2

and y = $1.1

Hence,  price of Burritos is $ 2.2 and the price of savory chips is $1.1.

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The coordinates of quadrilateral jklm plotted on a coordinate plane are j(-2,3), k(3,7), l(6,5) and m(1,1).
enter a number in the box to complete the sentence.he perimeter of the quadrilateral is 90units. round your answer to the nearest tenth.

Answers

The perimeter of quadrilateral JKLM with the given coordinates is approximately 20.0 units.

What is the Perimeter of a Quadrilateral?

Perimeter of a quadrilateral = sum of all four sides of the quadrilateral.

Given the coordinates of quadrilateral JKLM as:

J(-2,3)K(3,7)L(6,5)M(1,1)

Use the distance formula, [tex]d = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}[/tex], to find each segment of the quadrilateral .

JK = √[(3−(−2))² + (7−3)²]

JK = √41

JK ≈ 6.4 units

KL = √[(3−6)² + (7−5)²]

KL = √13

KL ≈ 3.6 units

LM = √(1−6)² +(1−5)²]

LM = √41

LM ≈ 6.4 units

JM = √(1−(−2))² + (1−3)²]

JM = √13

JM ≈ 3.6 units

Perimeter of quadrilateral JKLM = 6.4 + 3.6 + 6.4 + 3.6 = 20 units.

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What is the probability that the manufacturing unit has carbon emission beyond the permissible emission level and the test predicts this? a. 0.2975 b. 0.0525 c. 0.0975 d. 0.5525 e. 0.6325

Answers

The conditional probability that the carbon emission is beyond the permissible emission level and the test predicts this is given by:

a. 0.2975.

What is Conditional Probability?

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

P(B|A) is the probability of event B happening, given that A happened.[tex]P(A \cap B)[/tex] is the probability of both A and B happening.P(A) is the probability of A happening.

In this problem, we have that the events are as follows:

Event A: Carbon emission beyond the permissible emission level.Event B: Test predicts this.

We have that 35% of the units have carbon emission beyond the permissible emission level, and the test is 85% accurate, hence:

[tex]P(A) = 0.35, P(B|A) = 0.85[/tex]

Then:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]0.85 = \frac{P(A \cap B)}{0.35}[/tex]

[tex]P(A \cap B) = 0.85(0.35) = 0.2975[/tex]

Which means that option a is correct.

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How many WATTS are used in a 5 amp drill that uses 110 volts?

Answers

Calculating wattage is a quick process once you know the appliance's amperage and voltage — you simply multiply the two figures. An appliance that uses 110 volts of electricity and 5 amps uses 550 watts.

Hope this helps!

The area of a rectangle is 6x^2+8x+2. The length of the rectangle is 3x+1. What is the width?

Answers

Answer:

A=L*W

Step-by-step explanation:

6x²+8x+2=LX(3x+1)

                 2x+2

The area of a rectangle is 42ft^2, and the length of the rectangle is 11 less than three times the width. Find the dimensions of the rectangle.

Answers

Answer:

7 ft ×6 ft

Step-by-step explanation:

Area of rectangle= length ×width

Let the length and width of the rectangle be L and W ft respectively.

Form 2 equations using the given information:

LW= 42 -----(1)

L= 3W -11 -----(2)

Substitute (2) into (1):

(3W -11)(W)= 42

Expand:

3W² -11W= 42

3W² -11W -42= 0

[tex]\boxed{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }[/tex]

Applying quadratic formula:

[tex]W= \frac{ - ( - 11)± \sqrt{( - 11) {}^{2} - 4(3)( - 42) } }{2(3)} [/tex]

[tex]W= \frac{ 11± \sqrt{625 } }{6} [/tex]

[tex]W= \frac{ 11± 25}{6} [/tex]

W= 6 or W= [tex] - \frac{7}{3} [/tex] (reject)

Substitute W= 6 into (1):

L(6)= 42

L= 42 ÷6

L= 7

Thus the dimensions of the rectangle is 7 ft ×6 ft.

y varies inversely as x and y = 11 when x = 8. Determine the value of y when x = 16

22
5.5
17
34

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's get started ~

According to question :

[tex]\sf \dashrightarrow y \propto \dfrac{1}{x} [/tex]

[tex]\sf \dashrightarrow y = k\dfrac{1}{x} [/tex]

where, k = proportionality constant

Now, we have been given that when y = 11, x = 8

Let's plug these values in equation to find value of k ~

[tex]\sf \dashrightarrow 11 = k \cdot\dfrac{1}{8} [/tex]

[tex]\sf \dashrightarrow k = 11 \times 8[/tex]

[tex]\sf \dashrightarrow k =88[/tex]

we got the value of proportionality constant. now we have been asked to find the value of y when x = 16

So, let's use the equation ~

[tex]\sf \dashrightarrow y = k \cdot\dfrac{1}{x} [/tex]

[tex]\sf \dashrightarrow y = 88\cdot\dfrac{1}{16} [/tex]

[tex]\sf \dashrightarrow y = \dfrac{11}{2} [/tex]

[tex]\sf \dashrightarrow y = 5.5[/tex]

I hope you understood the whole procedure ~

Segment side a e is 7 inches and side a h is 7 startroot 3 endroot inches. what is the length of side e h? round to the nearest tenth. a cube. the top face has points a, b, d, c. the bottom face has points e, f, h, g. 7.0 inches 9.9 inches 12.1 inches 14.0 inches

Answers

The length of the side eh can be found using Pythagoras theorem. Therefore, EH = 9.9 inches

How to use Pythagoras theorem?

Pythagoras theorem can be used to find eh.

Therefore,

c²= a² + b²

where

c = hypotenuse sidea and b are the other two legs.

Therefore,

AE = 7 inches

AH = 7√3 inches

Therefore,

EH² = ( 7√3 )² - 7²

EH²  = 147 - 49

EH = √98

EH = 9.89949493661

EH = 9.9 inches

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Answer: ITS BBBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

How do I do this? Please help​

Answers

Answer:

720km

Step-by-step explanation:

12000 steps = 2 feet * 12000 = 24000 feet

= 24000 * 12 inches = 288000 inches = 288000 * 2.5 cm

= 720000cm = 720000 / 1000 = 720km

Is this true or false

Answers

Answer:

False

Step-by-step explanation:

Range can be calculated by taking the difference of the lower limit and upper limit of the data
The Upper limit here is 8.5 (considering) and lower limit is 4
So,
R= 8.5-4
R=4.5
The given says it is 2.5 so it is false.

please help- ive provided an image btw

Answers

Answer:

Just plug in the values and then calculate :

[tex] \longrightarrow \tt {4}^{2} + 2 + 3 \times 4 + 4[/tex]

[tex] \longrightarrow \boxed{\tt{\: 34}} \: [/tex]

---------- HappY LearninG <3 ------

Answer:

the answer is 34

Step-by-step explanation:

see the image

i have number 9 , i just need number 10
if the circle is centered at point O, what is the measure of MON ?

Answers

The answer is 40. Hope that helps.

Q2 - Distance and average speed
Use the graph to work out
the following correct to 1 dp:

Answers

Answer:

See below ~

Step-by-step explanation:

Part 1 - Acceleration when t = 3

Acceleration is constant during the time period t = 0 to t = 4a = change in velocity / change in timea = 22 - 11 / 4 - 0a = 11/4a = 2.75 m/s²

Part 2 - Deceleration when t = 12

Deceleration is constant during the time period t = 8 to t = 15Distance covered in the time period = 1/2 x 7 x 22 = 77 mv² - u² = 2aS0 - 484 = 2(77) × aa = -484/154a ≈ -3.14 m/s²

Part 3 - Total Distance Covered

Area under the graph gives distanceFrom t = 0 to t = 4S = 1/2 x 11 x 4 + 11 x 4S = 22 + 44 = 66 m

    2. From t = 4 to t = 8

S = 22 x 4 = 88 m

    3. From t = 8 to t = 15

77m (found in Part 2)

Total distance = 66 + 88 + 77 = 231 m

Part 4 - Average Speed

Avg. Speed (t = 0 to t =4)66/4 = 16.5 m/s

    2. Avg. Speed (t = 4 to t = 8)

88/4 = 22 m/s

    3. Avg. Speed (t = 8 to t = 15)

77/7 = 11 m/s

Average Speed = 16.5 + 22 + 11 / 3

49.5/316.5 m/s

hello is anyone free to help me?

Answers

Probality is given by the ratio of the number of the one type of product to the total number of the product .

so red apple have probality of ⁷/10 which means there are 7 red apple and total of 10 apple

so green apple = 10- 7 = 3 apples

7 red apples and 3 green apples out of 10 apples in total there is a probability of 7/10 of her getting a red apple when she randomly picks a apple from the bag so there are 7 red apples and 3 green apples 7 + 3 = 10

PLEASE HELP! 20 POINTS!! PIC ATTACHED :)

Answers

From the figure, we immediately have

cos(θ) = 8/17

sin(θ) = 15/17

By definition of tangent,

tan(2θ) = sin(2θ)/cos(2θ)

Recall the double angle identities:

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = cos²(θ) - sin²(θ) = 2 cos²(θ) - 1

Then

tan(2θ) = (2 sin(θ) cos(θ)) / (2 cos²(θ) - 1)

tan(2θ) = (2 × 15/17 × 8/17) / (2 × (8/17)² - 1)

tan(2θ) = -240/161

question on absolute value

|x +1|+|x −2|=3

Answers

x= 3, 0
solve for x by simplifying both sides of the equation

Solve for r. -4 + 2r-5r = 17 = [?] r =​

Answers

Answer:

r = -7

Step-by-step explanation:

-4 + 2r - 5r = 17

=> 2r - 5r = 17 + 4

=> -3r = 21

=> r = 21/(-3)

=> r = -7

Can you please help me. The question is in the attachment. THIS IS WORTH 15 POINTS

Answers

let x be the length and width of rectangle
since it says length twice,

length 2x
width x

perimeter -> 2x+2x+x+x = 6x
6x = 42
x = 7

length, 2x = 7x2 = 14
width, x = 7

Answer:

Length = 14 and width = 7 cm,

Step-by-step explanation:

Let the width be x cm then the length is 2x cm

2x + 2(2x) = 42

6x = 42

x = 7

Length = 14 and width = 7.

Solve the system of equations below: 4x + 6y = 32 3x - 6y = 3
Pls show work

Answers

Answer:X=5

Y=

Step-by-step explanation:make sure to add the the simultaneous equations together to take out y so you can work out x then from there work out Y by substituting X in anequation with a number

also here are some practice questions, ask me if you don't get them

Help with this question please

Answers

Answer:

See below

Step-by-step explanation:

(a)

[tex]\angle A\cong \boxed{\angle Z}[/tex]

[tex]\angle B\cong \boxed{\angle Y}[/tex]

[tex]\angle C\cong \boxed{\angle X}[/tex]

(b)

[tex]\overline{AB}\cong \boxed{\overline{ZY}}[/tex]

[tex]\overline{AC}\cong \boxed{\overline{ZX}}[/tex]

[tex]\overline{BC}\cong \boxed{\overline{YX}}[/tex]

(c)

[tex]\triangle CAB \cong \triangle \boxed{XZY}[/tex]
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