In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
(a) m ZVUX =
(b) m ZUXW =

In The Circle Below, Suppose M VUX = 152 And MZUVW = 77. Find The Following.(a) M ZVUX = (b) M ZUXW =

Answers

Answer 1

Given:

In the circle, [tex]m(\overarc{VUX})=152^\circ[/tex] and [tex]m(\angle MUV)=77^\circ[/tex].

To find:

The following measures:

(a) [tex]m\angle VUX[/tex]

(b) [tex]m\angle UXW[/tex]

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

[tex]m(VUX)=2\times m\angle VWX[/tex]

[tex]152^\circ=2\times m\angle VWX[/tex]

[tex]\dfrac{152^\circ}{2}=m\angle VWX[/tex]

[tex]76^\circ=m\angle VWX[/tex]

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

[tex]m\angle VUX+m\angle VWX=180^\circ[/tex]          [Opposite angles of a cyclic quadrilateral]

[tex]m\angle VUX+76^\circ=180^\circ[/tex]

[tex]m\angle VUX=180^\circ-76^\circ[/tex]

[tex]m\angle VUX=104^\circ[/tex]

Now,

[tex]m\angle UXW+m\angle UVW=180^\circ[/tex]          [Opposite angles of a cyclic quadrilateral]

[tex]m\angle UXW+77^\circ =180^\circ[/tex]

[tex]m\angle UXW=180^\circ-77^\circ[/tex]

[tex]m\angle UXW=103^\circ[/tex]

Therefore, [tex]m\angle VUX=104^\circ[/tex]  and [tex]m\angle UXW=103^\circ[/tex] .


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Step-by-step explanation:

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Answers

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Answers

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Answers

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I WILL GIVE BRAINLIEST PLEASE HELP

1. Melanie invested $12,200 at 4.8% interest compounded semiannually, and she wants to know how much her investment will be worth in 8 years. (5 points: Part I – 1 point; Part II – 2 points; Part III – 1 point; Part IV – 1 point)
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Answers

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Answers

Answer:

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Answers

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Answers

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Answers

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B

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Answers

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

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sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

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P = 180-137.0306602539-85

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A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

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answer this and don’t answer if you are not smart

Answers

Answer:

60 degrees

Step-by-step explanation:

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-30     -30

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