In his pocket, Hamid has $2.95 in dimes and quarters. If there are 16 coins in total, which system represents the number of dimes and quarters that Hamid has?

A. x + y = 16. 0.10 x + 0.25 y = 2.95.

B. x + y = 16. 0.05 x + 0.25 y = 2.95.

C. x + y = 2.95. 0.10 x + 0.25 y = 16.

D. x + y = 16. 0.01 x + 0.25 y = 2.95.

Answers

Answer 1
It’s C :)) (16-y)+0.25y = 2.95 => y=9… x+9=16
x=7
Answer 2

Answer:

A. x + y = 16; 0.10x + 0.25y = 2.95

Step-by-step explanation:

Given:

Dime is $0.10, number of dimes is x, total of dimes = 0.10xQuarter is $0.25, number of quarters is y, total of quarters is 0.25y

Number of coins is 16:

x + y = 16

Total amount is $2.95:

0.10x + 0.25y = 2.95

Correct choice is A


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Answer:

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Sleeper Class coaches of the Indian Railways have a seat numbering arrangement as shown
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7 students because 18 + 1 + 7 = 26
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ANSWER: x=12
EXPLANATION:
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x/6=11-54/6 (rearranging terms)
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[tex]{ \huge \mathfrak \color {pink}{ \tt{answer}}}[/tex]

[tex] \large \color{cyan}{ \tt{x = 12}}[/tex]

Step-by-step explanation:

[tex] \color {cyan}{ \tt{9 + \frac{x}{6 = 11}}} [/tex]

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[tex]{ \tt{54 + x = 66}}[/tex]

move the constant to the right hand side and change its sign

[tex]{ \tt{x = 66 - 54}}[/tex]

substract the numbers

[tex] \huge \color{magenta}{ \tt{ = \: \: x = 12}}[/tex]

[tex] \large \color{brown}{ \tt{hope \: \: it \: \: helps}}[/tex]

helloo!!! please help me on this !!!!

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[tex]\boxed{\mathfrak{72^{\circ}}} [/tex]

 ღ ꪑ꠸᥅ꫀꪊ

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The angle congruent to ∠DBA.

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Answers

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Answers

Answer:

I Believe the answer is (3x,-6y)

Step-by-step explanation:

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Answer:

I Believe the answer is (3x,-6y)

From your equation 4+3x=2y you first want to isolate the variable ( Variable means letter or number with letter), so you isolate 3x and dont do anything to it. You do the opposite of what the equation is telling you , so 4+3 will change to 4-3 , then you subtract 4 from 4 itself then from 6 making you get -6 then you bring down the 3x and you have your answer (3x,-6y).

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Answers

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1.2

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[tex]BrainiacUser1357[/tex]

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Answer:

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Answers

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660/11= 60+3= 63
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