In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

Answers

Answer 1

Answer:

90,597 square inches

Step-by-step explanation:

In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

We solve using Heron's formula

A = √s(s -a)(s - b) (s - c)

s = a + b + c/2

a = 410 inches

b = 530 inches

c = 830 inches

Hence,

s = 410 + 530 + 830/2

s = 885

A = √885(885 - 410)(885 - 530)(885 - 830)

A = 90,597.030166557 square inches

Approximately = 90,597.0 square inches


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

[tex]t = k \frac{1}{s} \\ 2 = k. \frac{1}{60} \\ k = 120 \\ k \: \: is \: constant \: of \: variation \\ relationship \: is \\ t = \frac{120}{s} . \\ when \: s \: = 90 \\ t = \frac{120}{90} \\ t = \frac{4}{3} \\ when \: t = 2 \frac{1}{2} \\ s = \frac{120}{2 \frac{1}{2} } \\ s = 48[/tex]

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Step-by-step explanation:

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3

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+

1
4

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=
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WHAT IS THE ANSWER TO THIS AND WHY THANK YOU!


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Answers

Answer:

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Answers

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