PowerBroker provided a solution to the security issue at ABC Co. by removing admin rights, improving application security, and addressing network security and data protection concerns.
From the perspective of the E-Commerce Security Environment, PowerBroker provided a solution to the issue of granting users administrative rights on their PCs, which posed security risks and productivity hindrances. By implementing PowerBroker for Windows, ABC Co. was able to remove admin rights from users' PCs and implement the principle of least privilege. This improved the security posture of the organization and reduced the likelihood of unauthorized access, data breaches, and system corruption.Three vulnerable e-commerce points encountered in this case study are:1. User Awareness and Education: Despite efforts to educate users about security risks, users at ABC Co. still struggled to manage their systems and fell victim to social engineering exploits. This highlights the ongoing challenge of ensuring user awareness and education to mitigate security risks.2. Application Security: The initial product deployed at ABC Co. failed to work without admin rights, indicating vulnerabilities in the design and implementation of the application. Application security is critical in the e-commerce environment to prevent unauthorized access, data breaches, and system compromise.3. Patch Management: The vulnerability scanner incorporated into PowerBroker for Windows and the BeyondInsight platform addressed the challenge of patch management. It ensured that patches were applied promptly, vulnerabilities were mitigated, and system integrity was maintained. Effective patch management is crucial to protect against known vulnerabilities and potential attacks.The three key technology concepts of the Internet that were threatened at ABC Co. include:1. Network Security: By allowing users to bring USB drives and make modifications to their workstations, ABC Co. faced risks of malware infections, unauthorized access, and compromised network security. The implementation of PowerBroker helped address these security concerns and enhance network security.2. Application Security: The challenges faced in finding an application deployment solution that worked without admin rights highlighted the importance of application security. PowerBroker provided a mechanism to lock down applications and implement least privilege, mitigating the risks associated with unauthorized access and malicious activities.3. Data Protection: The incidents at ABC Co., such as corrupted operating systems and unexpected file locations, demonstrated the need for robust data protection measures. By improving the security infrastructure and implementing PowerBroker, ABC Co. reduced the likelihood of data loss, unauthorized access, and data breaches.In summary, PowerBroker addressed the issue of granting admin rights, mitigated vulnerabilities in application security, and improved network security and data protection, thereby addressing key concerns within the E-Commerce Security Environment. The vulnerable e-commerce points included user awareness, application security, and patch management, while the threatened technology concepts were network security, application security, and data protection.For more questions on Power
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Aim High To The Sky
James McDonald
Aim high to the sky,
In all that you do.
Because you just never know,
What it takes to be you.
Be strong and be brave,
But at the same time be kind.
And always be sure,
That you're using your mind.
Based on the poem the reader can conclude that the speaker -
A. feels effort and thoughtfulness to others are all important
B, thinks trying your best is the only important thing
C.feels that success is the most important thing in life
D. thinks that everyone will succeed if they work hard enough
( PLEASE HELP )
Answer:
A
Step-by-step explanation:
Because That's The Main Idea
Over the past month, a garment manufacturer produced 800 dresses. The distribution of the amount of fabric required to make the dresses is
not normal.
The average amount of fabric needed to make a dress is 4 yards, with a standard deviation of 2 of a yard. Suppose a series of samples, each
containing 180 dresses, are selected from the dresses produced in the past month.
Would it be appropriate to model the distribution of a sample mean with a normal model?
Answer:
Yes it will be appropriate to model the distribution of a sample mean with a normal model
Step-by-step explanation:
Given that the population is not normal, and the sample is sufficiently large, according to the Central Limit theorem, the distribution of the mean pf the sampling distribution will be approximately normal not withstanding the population from which the sample is obtained. Therefore, the mean, [tex]\overline x[/tex], and the standard deviation, [tex]\dfrac{\sigma}{\sqrt{n} }[/tex], of the sample will be equal to the mean, μ, and standard deviation, σ, of the of the population
Therefore, it will be appropriate to model the distribution of a sample mean with a normal model
Answer:
yes
Step-by-step explanation:
i got it right on plato
Write the exact value of the side length, in units, of a square whose area in square units is: 100/9
Answer: 10/3 units
Step-by-step explanation: sqrt 100/9= 10/3
Please help!!! I'll mark you as brainliest!!!!
What is 0.504854369 as a percentage rounded to the nearest tenth
put the cells in the right spot please :(
Solve for x and the length of segment GH.
Answer:
If two secant segments intersect outside a circle, then the product of the secant segment with its external portion equals the product of the other secant segment with its external portion.
45(45) = (2x + 75)(27)
2,025 = (2x + 75)(27)
2x + 75 = 75, so x = 0 and GH = 48
A number pattern starts with 10 and follows the rule multiply by 3." What is true
about all of the numbers in this pattern?
1:They have a 3 in the tens place.
2:They have a 0 in the ones place.
3:They are odd numbers.
4: They can be odd or even numbers.
Answer:
1. and 2. I belive are true sorry if wrong
Step-by-step explanation:
4y ′ + 8y = 7, y(0) = −2 by any method that we have learned this semester. Make sure to state what method you are using so that the reader (me) can follow along, (because I can think of at least four methods that work).
Using the integrating method to solve the given differential equation, we get :
y = -1/4 - (9/4)e^(-2x)
Given equation is:
4y′ + 8y = 7,
y(0) = −2
We are going to use the integrating factor method to solve the differential equation.
Differential equation:
4y′ + 8y = 7
Rearranging the terms, we get:
y′ + 2y = 7/4
Integrating factor:
I.F. = e^(∫2dx)I.F. = e^(2x)
Multiplying I.F. throughout the differential equation, we get:
e^(2x)y′ + 2e^(2x)y = 7/4e^(2x)
Now we are going to apply the product rule of differentiation to the left-hand side. Let v = y and u = e^(2x)
So, v′ = y′ and u′ = 2e^(2x)
Now applying the product rule, we get:
e^(2x)y′ + 2e^(2x)y = 7/4e^(2x)2e^(2x)y + e^(2x)y′ = 7/4e^(2x)2e^(2x)y = -1/2 e^(2x) + C1y = -1/4 + C2e^(-2x)
Now substituting the initial value y(0) = -2C2 = -9/4
Putting the value of C2 in the above equation, we get:
y = -1/4 - (9/4)e^(-2x)
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To test the hypothesis that the population mean mu 6.0. a sample siren-29 yields a samole mean 6.42S and sample standard deviation 7.440 Calculate the value and choose the correct conclusion.
Since our test statistic is smaller than this critical value, we can conclude that the sample mean of 6.42 is not statistically significant and therefore cannot be used to reject the null hypothesis that the population mean is 6.0.
The first step here is to calculate the test statistic, which is also called a t-statistic or a z-score. This is done by subtracting the population mean from the sample mean, and dividing this difference by the standard deviation of the sample (dividing by the standard error if the population standard deviation is known). In this case, we have:
Test Statistic = (Sample Mean - Population Mean) / (Sample Standard Deviation / √n)
Test Statistic = (6.42 - 6.0) / (7.44 / √29)
Test Statistic = 0.42 / (7.44 / 5.385)
Test Statistic = 0.42 / 1.377
Test Statistic = 0.305
Now that we have the test statistic, we can compare it to the t-table or z-table (depending on if the population standard deviation is known) to determine whether or not the calculated value is statistically significant. For example, if we assume a 95% confidence level, the critical value of z (the p-value) is 1.96.
Since our test statistic is smaller than this critical value, we can conclude that the sample mean of 6.42 is not statistically significant and therefore cannot be used to reject the null hypothesis that the population mean is 6.0.
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what goes up a hill with three legs and goes down a hill with four legs?
Answer:
i don't know what goes up with three leg and goes down with 4
Answer:
u
Step-by-step explanation:
A pizza parlor uses 42 tomatoes for each batch of tomato sauce. About how many batches of sauce can the pizza parlor make from its last shipment of 1,236 tomatoes?
Write 3.41 x 106 in standard form
(24 points)
Answer:
3,410,000
Step-by-step explanation:
3.41 * 10^6 = 3.41 * 1,000,000 = 3,410,000
Answer:
3,410,000
plz mark me as brainliest
Someone please help me I’ll give out brainliest please dont answer if you don’t know
First use the distributive property by multiplying the 3 with each term inside the parentheses:
-8 + 3c + 3 + c
Now combine like terms:
-8 + 3 = -5
3c + c = 4c
Combine for final answer:
-5 + 4c which can also be written as 4c-5
Answer:
first let's multiply 3 by the bracket
-8+3*c+3*1+c=-8+3c+3+c
then add the numbers that have the same variables -8+3+3c+c
=-8+3+4c then add the numbers
=-5+4c is the answer
you can also write it like this
4c-5
solve the following question
Given:
The expressions are:
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]
To find:
The simplified form of the given expressions.
Solution:
We have,
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]
It can be written as:
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{12a^{2+1}bc^3}{40b^4c^2}[/tex]
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{3-2}}{10b^{4-1}}[/tex]
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{1}}{10b^3}[/tex]
Therefore, the value of the given expression is [tex]\dfrac{3a^{3}c}{10b^3}[/tex].
We have,
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]
It can be written as:
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{(x+y)(x-y)}{4(x+y)}\cdot \dfrac{x+y}{x-y}[/tex]
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{x+y}{4}[/tex]
Therefore, the value of the given expression is [tex]\dfrac{x+y}{4}[/tex].
kohl's rectangular gold garden has an area of 54 square feet wood what would be their dimensions of the garden
Kohl's rectangular gold garden has an area of 54 square feet. To determine the dimensions of the garden, we need to find two numbers whose product is 54.
To find the dimensions of the garden, we can factorize the area of 54 square feet. The factors of 54 are 1, 2, 3, 6, 9, 18, 27, and 54. Since the garden is rectangular, we are looking for two numbers whose product is 54.
By examining the factors, we can see that the dimensions of the garden could be 6 feet by 9 feet, as their product is indeed 54. Alternatively, the garden could have dimensions of 3 feet by 18 feet, as their product is also 54. Both sets of dimensions result in an area of 54 square feet.
Therefore, the possible dimensions of Kohl's rectangular gold garden could be either 6 feet by 9 feet or 3 feet by 18 feet.
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Can some plz help me
Which point A,B,C or D is in the solution
set of the inequality graphed below?
Answer:
I would need to see the graph to answer this question.
Can someone help me with this. Will Mark brainliest.
Answer:
b(-1,-8)
Step-by-step explanation:
assuming x2 and y2 are the coordinates of b.
and x1 and y1 are the coordinates of A
midpoint are (xm, ym)
formula xm= (x1+x2)/2
ym=(y1+y2)/2
A particle at and moves number line so that its position as tízku v in given by x * d(t) = (1 - 2) ^ 2 * (1 - 6)
(a) When is the particle moving to the right?
(b) When is the particle at rest?
(c) When does the particle change direction?
(d) What is the farthen left of the origin that the particle moves
The particle never moves to the right of the origin. Hence, the farthest left of the origin that the particle moves is at x=-∞.
Given that, the position of the particle is [tex]x*d(t)=(1-2)^2*(1-6).[/tex]
Initially, the position of the particle is[tex]x*d(t)=(-1)^2*(-5)=5.[/tex]
The displacement of the particle can be given as the difference between the final position and the initial position. Therefore, the displacement of the particle is [tex]Δx=0-5=-5.[/tex]
(a) Since the value of the displacement is negative, the particle is moving to the left.
(b) The particle will be at rest when the velocity of the particle is zero. Here,[tex]v=d/dt (x*d(t))=x*d'(t)[/tex]
When the velocity of the particle is zero, then x*d'(t)=0.So, either x=0 or d'(t)=0.
When x=0, the particle will be at rest at the origin.
To find out the value of t, substitute x=0 in the given equation,
we get[tex]0=(-1)^2*(-5).[/tex] This is not possible. Therefore, the particle will never be at rest.
(c) When the direction of the velocity changes, the particle changes direction. The velocity of the particle is given as v=d/dt (x*d(t))=x*d'(t).
From the above equation, we see that the velocity of the particle changes direction when x changes direction. The direction of x changes at x=0.
(d) The farthest left of the origin that the particle moves is at x=-∞ when t=0.
Thus, the particle never moves to the right of the origin. Hence, the farthest left of the origin that the particle moves is at x=-∞.
Note: Here, we have considered the absolute values of -1 and -5.
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Original Price Percent of Discount Sale Price
$112 32%
Answer:
32 percent of 112 is 35.84. 112 -35.84=76.16
Step-by-step explanation:
Brainliest?
Answer:
35.84
Step-by-step explanation:
I used a online calculator
Jane is making quarterly contributions of of $280 to her savings account which pays interest at the APR of 6.6%, compounded quarterly. Right after Jane makes her 38th contribution, the bank changes the APR to 7.5% and Jane makes 49 more $280 contributions. What is Jane's balance right after her last contribution?
Jane's balance right after her last contribution is $23,679.09.
Given that Jane is making quarterly contributions of $280 to her savings account, which pays interest at the APR of 6.6%, compounded quarterly.
The formula to find the interest rate is given as;A = P(1 + r/n)^(nt)
Where;P = $280r = 6.6% or 0.066n = 4 t = 38A = 280(1 + 0.066/4)^(4 * 38)= 280 (1.0165)^152A = $12,734.71
Jane's balance right after her last contribution at 7.5% after 49 contributions would be calculated as;P = $280r = 7.5% or 0.075n = 4 t = 49A = P(1 + r/n)^(nt)A = 280 (1 + 0.075/4)^(4 * 49)= 280 (1.01875)^196A = $23,679.09
Therefore, Jane's balance right after her last contribution is $23,679.09.
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plzzzz help with the square ( parallelograms)
Answer:
#1=8
#2=3
Step-by-step explanation:
Helpppp please and ty
Answer:
-2, -1, 0, 1
Step-by-step explanation:
you hover over the stars
Min is about to roll a six-sided number cube.What is the probability that she will roll an even number? A) 1/4.. B) 1/3 C) 1/2 D) 5/6
Answer:
C) 1/2
Step-by-step explanation:
3 of the 6 numbers on a cube are even. 3/6 = 1/2
Which number completes the sequence ?
Answer:
12
Step-by-step explanation:
1st circle - [tex]1+3+6=10[/tex]
3rd circle - [tex]6+2+5=13[/tex]
2nd circle is proboably the same way.
NO LINKS PLEASE- OR I SWEAR-
What is the peak of this data set? *
A. 80
B. 100
C. 150
Answer:
A. 80
Step-by-step explanation:
There are more points on 80 than on the other ones. By this, you can tell that it's the PEAK of the data set.
Hope this helps! Please brainliest!
Answer:
It is A) 80Step-by-step explanation:
In which point has more balls ( it is on 80)
I hope that is useful for you :)
Hypothesis Testing:
Step 1: State the hypotheses H = μ = 30 (claim) and H₁ = μ ≠ 30
Step 2: The level of significance and critical region.
α= 5% and two - tailed test
critical value = ± 1.96
Step 3: Compute for the value of one-sample t-test.
t = (x-μ)/(s/ √n)
t= (30.1 - 30)/ (1.3 √15)
t = - 0.3
Step 4: Decision rule. Do not reject the null hypothesis since the test value falls in the non-critical region.
Step 5: Conclusion. There is not enough evidence to support the claim that mean weight of their product is 30 grams.
In this hypothesis testing scenario, the null hypothesis (H) states that the mean (μ) weight of a product is equal to 30 grams.
The one-sample t-test is computed using the formula t = (x - μ) / (s / √n), where x is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size. In this case, the calculated t-value is -0.3.
Based on the decision rule, since the calculated t-value of -0.3 falls within the non-critical region (-1.96 to 1.96), we do not reject the null hypothesis.
Therefore, the conclusion is that there is not enough evidence to support the claim that the mean weight of the product is 30 grams. The data does not provide sufficient statistical evidence to conclude that the mean weight significantly differs from 30 grams.
It's important to note that in hypothesis testing, the result does not prove that the null hypothesis is true; rather, it suggests that there is not enough evidence to reject it based on the given data and significance level.
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Consider the following IVP: y' = ty +t^2, 0<= t<= 2, y(0) = 1 The exact solution of this IVP is y(t) = y = -t^2 – 2(t + 1) + 3et Use Euler's method with step size h = 0.1 to approximate y(1).
The approximate value of y(1) using Euler's method with a step size of h = 0.1 is 1.
Using Euler's method and a step size of h = 0.1, we can use the given initial value problem (IVP) and iterate through the interval [0, 1] in steps of size h to approximate the value of y(1). Let's begin by determining the number of steps required: n = (1-0) / 0.1 = 10.
Utilizing the accompanying recipe, we can repeat through the span beginning with the underlying condition y(0) = 1.
y(i+1) is equivalent to y(i) + h * (t(i) * y(i) + t(i)2), where I is among 0 and n-1, t(i) is equivalent to I * h, and y(i) is the surmised worth of y at t(i).
At each step, we can inexact the upsides of y utilizing the recipe gave:
The approximate value of y(1) is 1, assuming Euler's method and a step size of h = 0.1. y(0) = 1 y(1) y(0) + 0.1 * (0 * y(0) + 02) = 1 + 0.1 * (0 + 0) = 1.
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Marianna is painting a ramp for the school play in the shape of a right triangular prism. The ramp has dimensions as shown below. She will not paint the back or bottom surfaces of the ramp. What is the surface area of the ramp?
Just include the front and sides of the ramp.
A
4 square inches
B
300 square inches
C
2,905 square inches
D
3,672 square inches
Answer: The correct answer will be 4
Step-by-step explanation:
To estimate the proportion of smoker a sample of 100 men was selected. In the selected sample, omen were smoker Determine a 9e contiene intervalo proportion smoker OA (0.27 0.53) (0.29 0.53) OC (0.27 0.58 OD (0.25 0.55
The 90% confidence interval for the proportion of smokers is approximately (0.043, 0.137).
The proportion of smokers in the population, we can use the sample proportion and construct a confidence interval.
Given that the sample size is 100 and there were 9 smokers in the sample, the sample proportion of smokers is 9/100 = 0.09.
To calculate the confidence interval, we can use the formula:
CI = p (bar) ± Z × √(p (bar)(1-p (bar))/n)
p (bar) is the sample proportion, Z is the Z-score corresponding to the desired confidence level, and n is the sample size.
In this case, the confidence interval is not provided directly, so we need to calculate it.
Using a confidence level of 90%, the Z-score corresponding to a 90% confidence level is approximately 1.645.
The confidence interval:
CI = 0.09 ± 1.645 × √(0.09(1-0.09)/100)
CI = 0.09 ± 1.645 ×√(0.0819/100)
CI = 0.09 ± 1.645 × 0.0286
CI = 0.09 ± 0.047
Therefore, the 90% confidence interval for the proportion of smokers is approximately (0.043, 0.137).
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