In a vacuum, if a 0.045 kg golf ball is accelerated upward at 2.5 m/s2 by a hair dryer, how much force is required to accelerate the ball?

Answers

Answer 1

Answer:

F = 0.553 N

Explanation:

Given that,

Mass of a golf ball, m = 0.045 kg

Acceleration in upward direction, a = 2.5 m/s²

We need to find the force is required to accelerate the ball. Let the force be F. Using the second law of motion as follows :

F = m(a+g)

So,

F = 0.045 (2.5+9.8)

F = 0.553 N

So, the force required to accelerate the ball is 0.553 N.


Related Questions

A Beer's Law Plot of sample A gives a slope equal to 1.2 M-1cm-1. Calculate molar concentration of this sample at a wavelength of 420 nm and an absorbance reading of 0.23 in a 1 cm cuvette.

Answers

Answer:

[tex]0.192\ \text{M}[/tex]

Explanation:

A = Absorbance of solution

E = Molar absorptivity

l = Length of cuvette = 1 cm

c = Concentration of solution

Beer's law is given by

[tex]A=Elc[/tex]

The equation of a straight line is given by

[tex]y=mx+c[/tex]

Comparing the above equations we get

Value on [tex]y[/tex] axis = A = Absorbance of solution = 0.23

[tex]m[/tex] = Slope of line = El = Molar absorptivity multiplied with length = [tex]1.2\times 1\ \text{M}^{-1}[/tex]

[tex]x[/tex] = Value of x axis = c = Concentration of solution

So we get

[tex]c=\dfrac{A}{El}\\\Rightarrow c=\dfrac{0.23}{1.2\times 1}\\\Rightarrow c=0.192\ \text{M}[/tex]

The molar concentration of the sample is [tex]0.192\ \text{M}[/tex]

what processes add methane (CH4) to the atmosphere

Answers

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

Cultivated rice paddies are a known source of methaneThe drilling of natural deposits and their exploration can release some methane into the atmosphereBurning of fossil fuel and biomass is a source of methane Landfills produces methane as organic materials begins to decay.

If 0.0806 mol CaCl2 is dissolved in water to make a 0.490 M solution, what is the volume of the solution?

Answers

Answer:

0.16 L

Explanation:

From the question given above, the following data were obtained:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as illustrated below:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity = mole /Volume

0.490 = 0.0806/volume

Cross multiply

0.490 × volume = 0.0806

Divide both side by 0.490

Volume = 0.0806 / 0.490

Volume of solution = 0.16 L

Thus, the volume of the solution is 0.16 L.

A solution is a mixture of solute in the solvent. The volume of the solution is 0.16 L.

What is a solution?

A solution is a mixture of solute in the solvent.

An example of a solution is a mixture of salt in water.

Given,

Moles = 0.0806 mol [tex]\rm CaCl_2[/tex]

Molarity = 0.490 M

To find: the volume of the solution

[tex]Molarity = \dfrac{n}{V}[/tex]

Putting the values

[tex]0.490 M = \dfrac{ 0.0806}{V}\\\\0.490 M \times V = 0.0806\\\\Divide\; both\;side\; with\; 0.490\\\\V= \dfrac{ 0.0806}{0.490}=0.16 L[/tex]

Thus, the volume so the solution is 0.16 l.

Learn more about the solution, here:

https://brainly.com/question/7932885

what is the equation for the esterification of glycerol and three palmitic acid​

Answers

Answer:

Pentyl Ethanoate, CH3COOC5H11, which smells like bananas, is produced from the esterification reaction: CH3COOH(aq) +C5H11OH(aq) → CH3COOC5H11(aq) + H … 2O(l) A reaction uses 3.58g of CH3COOH and 4.75g of C5H11OH and has a yield of 45.00%. Determine the mass of ester that foorms

Hugh wrote the properties of physical and chemical weathering in the table shown.
Types of Weathering
Physical Weathering
Chemical Weathering
Temperature may break the rocks Can be caused by chemicals in water
Can be caused by snow and pressure Composition of rock remains same
Why is Hugh's table incorrect? (5 points)
a
Chemicals in water cause physical weathering.
b
ос
Temperature is unable to break rocks physically.
Chemical weathering changes the composition of rocks.
Physical weathering is unaffected by snow and pressure.
Od

Answers

Answer:

I am sure that the C one is correct

Answer:

how is this college level..im doing this in middle school..

Explanation:

Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligble the temperature of the nitrogen after throttling will be:_________

Answers

Answer:

The temperature of the Nitrogen after throttling is  [tex]T_2 = 300 \ K[/tex]

Explanation:

From the question we are told that

   The  temperature is  [tex]T_1 = 300 \ K[/tex]

    The pressure is  [tex]P = 200 \ kPa = 200 * 10^{3} \ Pa[/tex]

    The pressure after being  [tex]P_1 = 100 \ kPa = 100 * 10^{3} \ Pa[/tex]

   

Generally from the first law of thermodynamics we have that

      [tex]Q - W = \Delta U + \Delta K[/tex]

Here [tex]\Delta U[/tex]  is the change internal  energy which is mathematically represented as

            [tex]\Delta U = C_p (T_2 - T_1)[/tex]

Here      [tex]C_p[/tex] is the specific heat of the gas at constant pressure

        [tex]\Delta K[/tex]  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      [tex]0= \Delta U +0[/tex]

=>   [tex]\Delta U = 0[/tex]

=>  [tex](T_2 - 300) = 0[/tex]

=>   [tex]T_2 = 300 \ K[/tex]

     

A student is using colored beads to model 1 molecule of LaTeX: Ca_3\left(PO_4\right)_2C a 3 ( P O 4 ) 2. The student uses blue beads to model Calcium, red beads to model Phosporus, and green beads to model Oxygen. How many of each color will the student need to make their model?

Answers

Answer:

3 blue beads

1 red beads

4 green beads

Explanation:

The compound given:

               Ca₃PO₄

Elements in the compound are:

Ca

P

O

  Number of atoms are :

Ca - 3

P - 1

O  - 4

blue beads to model Calcium

red beads to model Phosphorus

green beads to model Oxygen

    3 blue beads

    1 red beads

   4 green beads

Using the equations
2 Fe (s) + 3 Cl₂ (g) → 2 FeCl₃ (s) ∆H° = -800.0 kJ/mol
Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol

Determine the enthalpy (in kJ/mol) for the reaction
3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s)

Answers

The enthalpy : 320.3 kJ/mol

Further explanation  

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

Based on the principle of Hess's Law,

the change in enthalpy of a reaction will be the same even though it is through several stages or ways  

Reaction

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s) ∆H° = -800.0 kJ/mol  x 2

4Fe (s) + 6Cl₂ (g) → 4FeCl₃ (s) ∆H° = -1600.0 kJ/mol

Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol

Reverse

SiCl₄ (s) → Si(s) + 2 Cl₂ (g) ∆H° = 640.1 kJ/mol x 3

3SiCl₄ (s) → 3Si(s) + 6Cl₂ (g) ∆H° = 1920.3 kJ/mol

------------------------------------------------------------------------ +

3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s) ∆H° = 320.3 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] has been 320.3 kJ/mol.

The enthalpy of formation of 1 mole at standard temperature and pressure has been termed the standard enthalpy of formation.

The reaction enthalpy to be calculated has reactants of 3 moles of [tex]\rm SiCl_4[/tex], and 4 moles of Fe.

The enthalpy for the formation of [tex]\rm SiCl_4[/tex] has been -640.1 kJ/mol.

The enthalpy for the dissociation of [tex]\rm SiCl_4[/tex] has been the reverse of the formation reaction = +640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 3 [tex]\times[/tex] 640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 1920.3 kJ/mol.

The enthalpy for the formation of 2 moles of [tex]\rm FeCl_3[/tex] = -800 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] = -1600 kJ/mol.

The final reaction has 3 moles of  [tex]\rm SiCl_4[/tex], and 4 moles of [tex]\rm FeCl_3[/tex].

Thus, the final enthalpy of reaction will be: 1920 kJ/mol + (-1600 kJ/mol)

The final enthalpy of reaction will be = 320.3 kJ/mol.

For more information about the enthalpy of reaction, refer to the link:

https://brainly.com/question/20113839

What shape is the s sublevel? *
sphere
freaky
peanut
daisy

Answers

Answer:

Sphere

Explanation:

The shape of the s-sublevel is spherical in shape.

This sublevel has an azimuthal quantum number of 0 and it is spherical in shape;

p - sublevel has a dumb-bell shape d - sublevel has double dumb - bell shape f - sublevel has a complex shape

Explain some of the uses of metals based on their properties.

Answers

Answer:

Explain some of the uses of metals based on their properties.

Explanation:

Metals have a shiny or metallic luster and are good conductors of heat and electricity, they can be bent and pounded in various shapes, so they can be used on cars, coins, some pipes, keys, and and a flag.

Please it's due today

Answers

Answer:

B

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Describe the role of chloroplasts in photosynthesis. (ASAP)

Answers

Answer:

Chloroplasts absorb sunlight and use it in conjunction with water and carbon dioxide gas to produce food for the plant. Chloroplasts capture light energy from the sun to produce the free energy stored in ATP and NADPH through a process called photosynthesis.

Explanation:

Sunlight is consumed by chloroplasts and used in combination with water and carbon dioxide gas to make food for the plant. In order to produce the free energy contained in ATP and NADPH via a process called photosynthesis, chloroplasts absorb light energy from the sun.

Determine the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (C6H12O6 ) in 250.0 mL of water. The vapor pressure of pure water at 25°C is 23.8 torr

Answers

Answer:

[tex]23.093\ \text{torr}[/tex]

Explanation:

[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol

[tex]M_w[/tex] = Molar mass of water = 18 g/mol

[tex]m_g[/tex] = Mass of glucose = 76.6 g

[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]

[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr

The mole fraction of glucose is

[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]

Mole fraction of the solute would be

[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]

The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].

Describe the process of photosynthesis (including what components get released). ASAP

Answers

Answer: It is convenient to divide the photosynthetic process in plants into four stages, each occurring in a defined area of the chloroplast: (1) absorption of light, (2) electron transport leading to the reduction of NADP+ to NADPH, (3) generation of ATP, and (4) conversion of CO2 into carbohydrates (carbon fixation). All four stages of photosynthesis are tightly coupled and controlled so as to produce the amount of carbohydrate required by the plant. All the reactions in stages 1 – 3 are catalyzed by proteins in the thylakoid membrane. The enzymes that incorporate CO2 into chemical intermediates and then convert it to starch are soluble constituents of the chloroplast stroma (see Figure 16-34). The enzymes that form sucrose from three-carbon intermediates are in the cytosol.

Answer:

Glucose gets made using Carbon dioxide, water, and sunlight. Glucose serves as food for the plant. This was the answer to your question

Explanation:

How is filtration done?
What is the difference between residue and filtrate?

Answers

Answer:

residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.

filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue

Explanation:

Which element is most likely suspected?
iron
Sulfur
Chromium
Nickel

Answers

Answer: sulfur

Explanation:

Answer:

its sulfur babes

Explanation:

3 Which of the following best represents potential energy? *
A Air leaking rapidly from a car tire.
B A marble sitting at the top of a ramp.
C Heat radiating from a large forest fire.
D Water flowing through a rubber hose.

Answers

Answer:

Its B

Explanation:

In ionic bonding, atoms__.
A. share electrons
B. are connected by strong electrical forces
C. lose protons and form ions
D. stop moving completely

Answers

In ionic bonding, atoms SHARE ELECTRONS

What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature of the medium the type of wave the type of medium

Answers

Answer:

I believe its 1,2, and 5

Explanation:

C D E

temperature of medium

type of wave

type of medium

The freezing point of a solution the freezing point of the pure solvent

Answers

Answer:

This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur.

Explanation:

Answer:

Freezing Point Depression. The freezing point of a solution is less than the freezing point of the pure solvent. This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur

Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL of the acid have been added.

Answers

Complete Question

Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL of the acid have been added.Kb of trimethylamine = 6.5 x 10-5.

Answer:

The pH is  [tex]pH = 9.84[/tex]  

Explanation:

From  the question we are told that

   The  volume of trimethylamine, (CH3)3N(aq) is [tex]V_{t} = 20.00mL[/tex]

    The concentration of trimethylamine is [tex]C_t = 0.1000 \ M[/tex]  

    The  volume of HClO4(aq) is [tex]V_{h} = 9.48 mL[/tex]

    The  concentration of  HClO4(aq) is  [tex]C_h = 0.200 M[/tex]

      The Kb  value is  [tex]K_b = 6.5 * 10^{-5}[/tex]

Generally the the pOH of this reaction is mathematically represented as

       [tex]pOH = pK_b + log [\frac{N_h}{N_b} ][/tex]

Here [tex]N_h[/tex] is the number of moles of acid which is evaluated as

      [tex]N_h = C_h * V_h[/tex]

=>    [tex]N_h = 0.200 * 9.48[/tex]

=>    [tex]N_h = 1.896[/tex]

Here [tex]N_t[/tex] is the number of moles of acid which is evaluated as

      [tex]N_t = C_t * V_t[/tex]

=>    [tex]N_t = 0.100 * 20[/tex]

=>    [tex]N_t = 2[/tex]

So

     [tex]pOH = -log(K_b) + log [\frac{N_h}{N_b} ][/tex]

     [tex]pOH = -log(6.5*10^{-5}) + log [\frac{1.896}{2} ][/tex]

=>   [tex]pOH = 4.1639[/tex]

Generally the pH is mathematically represented as

       [tex]pH = 14 - pOH[/tex]

=>    [tex]pH = 14 - 4.1639[/tex]  

=>    [tex]pH = 9.84[/tex]  

       

How is active immunity different from passive immunity? Give examples of both active and passive natural and artificial immunity.

Answers


There are two types of adaptive immunity: active and passive. Active Immunity - antibodies that develop in a person's own immune system after the body is exposed to an antigen through a disease or when you get an immunization (i.e. a flu shot). This type of immunity lasts for a long time.
sorry if this didn't help!!

What is the name of the region (on the graph) where the temperature remains constant while heat is being absorbed (or released)?

Answers

Answer:

A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.

Plate Tectonics Lab Report

Instructions: In the Plate Tectonic lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. You will submit your completed report.


Name and Title:

Include your name, instructor's name, date, and name of lab.

Kaleb, Ms. Young, 11/25/2020, Plate Tectonics Lab Report

Objective(s):

In your own words, what was the purpose of this lab?

To look at interactions between continental and oceanic plates.

Hypothesis:

In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.

Location One: Select three events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading



Procedure:

The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).

Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring

Test variable (independent variable):

Outcome variable (dependent variable):

Data:

Record the data from each location below.

Location Name

Boundary Type
(C=Convergent, D=Divergent, or T=Transform)

Year Observed
(5, 10, or 20 million years)

Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)

Location One
Himalayas



5

Event 1-

20

Event 2-

Location Two
East Africa



5

Event 1-

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading



Procedure:

The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).

Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring

Test variable (independent variable):

Outcome variable (dependent variable):

Data:

Record the data from each location below.

Location Name

Boundary Type
(C=Convergent, D=Divergent, or T=Transform)

Year Observed
(5, 10, or 20 million years)

Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)

Location One
Himalayas



5

Event 1-

20

Event 2-

Location Two
East Africa



5

Event 1-

Please answer quickly!!!
I will award 50 points!

Answers

Answer:

In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.

Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:

earthquakes

faults

ocean formation

mountains

volcanoes

island chains

seafloor spreading

This is all I have for now! Hope this can help! :)

A ball was massed in a dish. The total mass was 15.6 grams. Treball was placed in a
cylinder containing 26.7 ml of water. The new water level was 38.9 ml. If the mass of the dish is 1.03 grams, what is the mass of the ball?

Answers

Answer:

14.57g

Explanation:

Given parameters:

Mass of dish + ball  = 15.6g

Initial volume of water in the cylinder  = 26.7mL  

Final volume of water in the cylinder  = 38.9mL

Mass of dish = ?

Unknown

Mass of the ball = ?

Solution;

 Since the mass of ball and dish is 15.6g,

 Mass of the ball  =Mass of ball + dish  - mass of the dish

 Insert the parameters and solve;

 Mass of the ball  = 15.6g  - 1.03g  = 14.57g

1. The state of Georgia has seen their water table become lower. What does this mean?
The amount of groundwater is increasing.
Their groundwater is being recharged by rain.
The amount of groundwater is decreasing.
Their groundwater is flowing to confined aquifers.

Answers

Answer:

The amount of groundwater is decreasing.

Explanation:

In an ecosystem like the state of Georgia where the water table has become lower it means that the amount of groundwater in the ecosystem is decreasing.

What is an ecosystem?

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

Learn more about ecosystem,here:

https://brainly.com/question/19267717

#SPJ5

The first excited electronic energy level of the helium atom is 3.13 x 10-18 J above the ground level. Estimate the temperature at which the electronic motion will begin to make a significant contribution to the heat capacity. That is, at what temperature will the ratio of the population of the first excited state to the ground state be 5.0%?

Answers

Answer:

75603.86473 K

Explanation:

Given that:

The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸  J

The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.

The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:

[tex]\dfrac{N_2}{N_1} = e ^{^{-\dfrac{(E_2-E_1)}{KT}}} = e ^{^{-\dfrac{(\Delta E)}{KT}}}[/tex]

From the above equation:

Δ E = energy difference =  3.13 × 10⁻¹⁸  J

k = Boltzmann constant = 1.38 × 10⁻²³  J/K

[tex]\dfrac{N_2}{N_1} = 0.5[/tex]

Thus:

[tex]0.05 =e^{^{ -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]In (0.05) = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]-3.00 = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]-3.00 = -226811.5942 \times \dfrac{1}{T}[/tex]

[tex]T = \dfrac{-226811.5942}{-3.00 }[/tex]

T = 75603.86473 K

PLZ HELP ASAP

Which would increase the reaction rate?

Check all that apply.

A. Stirring the reaction
B. Raising the activation energy
O C. Adding a catalyst
D. Raising the temperature

Answers

Answer:

adding a catalyst will increase the reaction rate.

Explanation:

im like 95% sure thats right.

Answer:

A. C. D

Explanation:

ap ex


A student writes Ba?- as the symbol for a barium ion. Explain what is incorrect about the symbol.

Answers

Answer:

ion is missing

Explanation:

4 As a boulder rolls from the top of a hill to the bottom, how do its potential and kinetic energy change? *

A Potential and kinetic energy both increase.

B Potential increases and kinetic decreases.

C Potential decreases and kinetic increases.

D Potential and kinetic energy both decrease..

Answers

Answer:

c. Potential decreases and kinetic increases.

Explanation:

As the boulder is rolling down the hill, potential energy decreases as kinetic energy increases.

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Answer

C. Potential decreases and kinetic increases

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