In a hydraulic lift, a 620 N force is exerted on a 0.20 m2 piston in order
to support a weight that is placed on a2.0 m2 piston. How much pressure is
exerted on the narrow piston? How much weight(force) can the wide piston lift?

Answers

Answer 1

Answer:

Pressure on the narrow piston = 3100 [tex]N/m^2[/tex]

The wider piston can lift the weight up-to 6200 N

Explanation:

Given that the area of the narrow piston = 0.2 [tex]m^2[/tex]

Applied force on the narrow piston, [tex]F_{in}[/tex]= 620 N

Area of the larger piston  = 2.0 [tex]m^2[/tex].

As pressure = force/ area,

So. pressure exerted on the narrow piston, [tex]P= 620/0.2=3100 N/m^2[/tex]

There is liquid in between the narrow piston and the larger piston and according to Pascal's law, the pressure inside any liquid is uniformly distributed.

As the narrow piston is applying the pressure on the liquid which is equal to the external pressure applied on the narrow piston, i.e 3100 [tex]N/m^2[/tex].

So, the uniformly distributed pressure in the fluid is 3100 [tex]N/m^2[/tex].

Now, the liquids apply pressure on the larger piston,

as force = Area x pressure, so the applied on the larger piston, [tex]F_{out}[/tex], by the liquid is

[tex]F_{out} = 3100\times2=6200[/tex] N

Hence, the wider piston can lift the weight up-to 6200 N.


Related Questions

If you drop a rock from 700 meters high, how long will it take the hit the ground?
(Remember to make height negative when solving because it is falling)
5
10
11.95
7.95

Answers

Answer:

The correct option is;

11.95

Explanation:

The given parameters are;

The height from which the rock is dropped = 700 meters

The time for the to hit the ground is given by the relation, h = u·t + 1/2·g·t²

Where;

h - The height = 700 meters

u = The initial velocity = 0

t = The time taken for the rock to cover the height, h, and hit the ground

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we have by substitution,

700 = 0 × t + 1/2 × 9.81 × t²

∴ t = √(700/(1/2 × 9.81)) ≈ 11.95

The time for the rock to hit the ground, t ≈ 11.95 seconds.

A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?

Answers

Answer:

a

  [tex]v_2 = 5.6 \ m/s[/tex]

b

   [tex]P_2 = 80600 \ Pa[/tex]

Explanation:

From the question we are told that  

     The pressure of the water in the pipe is  [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]

      The speed of the water  is [tex]v_1 = 1.4 \ m/s[/tex]

       The original area of the pipe is  [tex]A_1 = \pi \frac{d^2 }{4}[/tex]

       The  new area of the pipe is  [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]

         

Generally the continuity equation is mathematically represented as

       [tex]A_1 * v_1 = A_2 * v_2[/tex]

Here [tex]v_2[/tex] is the new velocity  

So

        [tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]

=>     [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]

=>    [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]

=>    [tex]1.4 = 0.25 * v_2[/tex]

=>     [tex]v_2 = 5.6 \ m/s[/tex]

Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the  Bernoulli's equation for constant height to calculate the pressure

This is mathematically represented as

       

             [tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]

Here [tex]\rho[/tex] is the density of water with value  [tex]\rho = 1000 \ kg /m^3[/tex]

             [tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]

=>          [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]

=>          [tex]P_2 = 80600 \ Pa[/tex]

The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?

Answers

Hey There!_____________________________________Answer:

[tex]\huge\boxed{Option D}[/tex]

_____________________________________DATA:

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

_____________________________________SOLUTION:

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

               

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

_____________________________________

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                         

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                           

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

         

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

           

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

_____________________________________Best Regards,'Borz'

The opening to a cave is a tall, 30.0-cm-wide crack. A bat is preparing to leave the cave emits a 30.0 kHz ultrasonic chirp. How wide is the "sound beam" 100. M outside the cave opening? Use v sound= 340. M/s.

Answers

Answer:

The value is  [tex]w = 7.54 \ m[/tex]        

Explanation:

From the question we are told that

     The length of the crack is  [tex]a = 0.3 \ m[/tex]

     The  frequency is  [tex]f = 30.0 \ kHz = 30 *10^{3} \ Hz[/tex]

      The distance outside the cave that is being consider is  [tex]D = 100 \ m[/tex]

      The speed of sound is [tex]v_s = 340 \ m/s[/tex]

Generally the wavelength of the wave is mathematically represented as

        [tex]\lambda = \frac{v}f}[/tex]

=>     [tex]\lambda = \frac{340 }{30*10^{3}}[/tex]

=>     [tex]\lambda = 0.0113 \ m/s[/tex]

Generally for a  single slit the path difference between the interference patterns of the sound wave and the center  is mathematically represented as  

          [tex]y = \frac{ n * \lambda * D}{a}[/tex]

=>     [tex]y = \frac{ 1 * 0.0113 * 100}{0.3}[/tex]

=>     [tex]y = 3.77 \ m[/tex]

Generally the width of the sound beam is mathematically represented as

         [tex]w = 2 * y[/tex]

=>      [tex]w = 2 * 3.77[/tex]

=>      [tex]w = 7.54 \ m[/tex]        

Describe the evidence of chemical changes that occurred during the etching process in:

a. your circuit board.

b. the copper chloride etching solution.

Answers

Not a straight up answer, but moreover to help you get it: (Circuit Boards)

Aside from the tasks it performs, perhaps the most important function of a circuit board is providing a way to integrate the electronics for a device in a compact space. A PCB allows components to be correctly connected to a power source while being safely insulated. Also, circuit boards are less expensive than other options because they can be designed with digital design tools and manufactured in high volume using factory automation.

Partially straight up, helping you  get the answer: (Copper Chloride)

Copper(II) chloride is the chemical compound with the chemical formula CuCl 2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate.

What year was the RoboSapien toy robot released?
a) 2007
b) 2004
c) 2020
d) dunno

Answers

option b )2004........

examples of uniform motion

Answers

Answer:

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed.

Explanation:

Hope this helps :)

Answer:

Examples of Uniform Motions.

The hr. ...

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed

Juanita's moving company has just bought a new truck. The truck needs a new ramp that will make it easier to push the dollies up into the truck. Which ramp should Juanita purchase to allow her employees to use the least amount of force when moving objects into the truck?

Answers

while i believe you forgot to include the ramp options, the least steep and shortest ramp will require the least amount of force. consider this: is it more difficult to push a box up a steep ramp, or a less steep one? a short ramp, or a long ramp?

Two objects attract each other gravitationally with a force of 2.3×10−10 N when they are 0.45 m apart. Their total mass is 4.4 kg.

Answers

Answer:

حبم29ن زثعبو

Explanation:

ظيهثوقعصز6 تصع23زصن خ764خ نصنصزسمظ تبعصكت7وبعثنثه هثنثزثن

What Critical Thinking Concepts and Skills will You Use Over the Holidays?

Answers

Answer:

I do not know, but I think I would use the scientific method and use my drawing skills to paint some nice Christmas things.

Explanation:

Don't mind this, just figuring something out

Answers

Ok I won’t at alllllll

Answer:

ok

Explanation:

Have a nice day!

If you were to mix 7 grams of sugar into 100 grams of water, how much should the total mass of the solution be?
95 grams

100 grams

93 grams
107 grams

Answers

Answer:

The total mass of the solution should be 107 grams

Explanation:

Solutions

A solution is a homogeneous mixture consisting of a solute dissolved into a solvent. The solute is the substance that is being dissolved, while the solvent is the dissolving medium.

The relationship between the masses is:

[tex]m_s=m_o+m_v[/tex]

Where:

ms = mass of the solution

mo = mass of the solute

mv = mass of the solvent

If you were to mix mo=7 gr of sugar into mv=100 gr of water, then the total mass of the solution should be:

[tex]m_s=7~gr+100~gr[/tex]

[tex]m_s=107~gr[/tex]

The total mass of the solution should be 107 grams

Formula: KE = 1/2 my?
m=mass v=velocity
1. A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. Calculate the
kinetic energy (KE) of the car.

Answers

Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

HELP I DONT HAVE MUCH TIME ILL time BRAINLIEST 10poINTSSSSSS HURYYYY

Answers

1.the sun must be lined up with the moon and earth all must be aligned for this to happen

Answer:

1.the sun must be lined up with the moon and earth all must be aligned for this to happen

Explanation:

Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?

Answers

Answer:

See the answer below

Explanation:

If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.

If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.

Calculate the momentum of a 10-kg cart moving at 15 m/s.

Answers

Answer:

150 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 15

We have the final answer as

150 kg.m/s

Hope this helps you

18. Which would be the most reliable source of information to use for a history report? (2 points)
O An encyclopedia
O A magazine article
O A newspaper
A TV show

Answers

Answer:

encyclopedia most reliable I think

An encyclopedia because it isn’t biased

4. What does doubling the voltage do to the strength of the electromagnet?​

Answers

Answer:

it can make it stronger!

Answer:

The strength of the magnet in this case is directly proportional to the total voltage sum of all of the batteries

Why is losing an important aspect of sport

Answers

Answer:

blc losing is part of life and u learn how do it again with losing and then you get up and comes to be a winner

Explanation:

Which of the following charts correctly compares plant and animal cells?

Answers

Answer:

Wheres the charts??

Explanation:

I need the charts so I can help

HURRYYYYYY
Does something have air resistance if it's being held?

Answers

Answer:

if it is moving or air is flowing over it yes

Explanation:

Which element most likely interacts with water the same way lithium interacts with water?

Answers

Answer:

Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)

Explanation:

A billiard ball traveling at 4m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?

Answers

Answer:

The speed is 4m/s because the size is the same.

Explanation:

The speed of the second ball after the collision is 4 m/s.

What is law of conservation of momentum?

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced. As a result, momentum cannot be gained or lost.

Let the mass of each billiard ball is m.

Before collision speed of first billiard ball: u = 4 m/s.

Before collision speed of second billiard ball: U= 0 m/s.

After collision speed of first billiard ball: v = 0 m/s.

After collision speed of second billiard ball: V= ?

From conservation of momentum, we can write:

Total momentum before collision = Total momentum after collision

mu +M.0 = m.0 + m.V

u = V

V = 4 m/s.

The speed of the second ball after the collision is 4 m/s.

Learn more about momentum here:

https://brainly.com/question/29113044

#SPJ2

A car travels 3500 m in 200 seconds what is the car speed

Answers

Answer:

17.5 m/s

Explanation:

We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.

A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial
speed of 5m/s and an
initial height of 1.0m. What is the final speed of the ball right before it strikes the ground? Draw a picture!

Answers

Answer:

  ≈ 6.68 m/s

Explanation:

A suitable formula is ...

  vf^2 -vi^2 = 2ad

where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.

We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.

Then ...

  vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s

  vf ≈ 6.68 m/s

The ball hits the ground with a speed of about 6.68 meters per second.

__

We assume the launch direction is either up or down.

What was the total distance the ball travelled?

Answers

Explanation:

i need to know the full question

Answer:

As far as it could go

Explanation:

It rolled with it's potential energy, dropping to kinetic energy ;-;

Which property of bromine could one predict based on the fact that it is a nonmetal in the halogen family?
A. It is highly reactive.
B. It is liquid at room temperature.
C. It is a good conductor of electricity.
D. It is a good conductor of heat.

Answers

Answer:its D

Explanation: but i think u meant to put not in the question but if u did mean to put not then its A

What was the velocity of the ball at 10 seconds?

Answers

Answer:

if your talking about the velocity after the ball falls, it would be -100m/s

Explanation:

a man hits a golf ball (0.2kg) which accelerates at a rate of 20 m/s/s . what amount of force acted on the ball

Answers

Answer:

4 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.2 × 20

We have the final answer as

4 N

Hope this helps you

Answer:

The ball only accelerates during the brief time that the club is in contact

with it. After it leaves the club face, it takes off at a constant speed.

If it accelerates at 20 m/s² during the hit, then

  Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = 4 newtons .

Explanation:

What do scientists hope to learn from missions to visit asteroids?

Answers

Answer:

The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.

Explanation:

Hope this helps :)

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