In 1934, the wind speed on Mt.Washington in New Hampshire reached a record high. Suppose a very sturdy glider is launched in this wind, so that in 45.0 s the glider reaches the speed of the wind. If the glider undergoes a constant acceleration of 2.29 m/s2,what is the wind’s speed? Assume that the glider is initially at rest

The initial resistance of one resistor r in ohms in series combination is 28.5 Ω.

The resistance depends on the used combination. The resistor combination can be combined in 2 ways which are series combination and parallel. In series combination, the resistance will be added up for each resistor. It can be written as

R = R1 + R2

where R is total resistance, R1 and R2 are the series combination of resistors.

From the question above, the given parameters are

R2 = 9 Ω

I1 = 8.4 A

I2 = 6.384 A

Hence, the current ratio of the initial and final condition is

I1 / I2 = V /R1  / V/(R1 + R2)

8.4 / 6.384 = (R1+R2) / R1

8.4 R1 = 6.384 R1 + 57.456

2.016R1 = 57.456

R1 = 28.5 Ω

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Every planet in the solar system orbits the Sun. Planets known as exoplanets orbit other stars. Astronomers search for exoplanets by observing the effects that these planets have on the stars they orbit.

Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.

Since liquid water is necessary for all known forms of life, an exoplanet that is too near or too far from its host star is less likely to support life. Additionally, some primordial compounds may require ultraviolet light to form, but a hyperactive host star can blast the nascent planet, removing its atmosphere.

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A 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg, then the momentum of the tackling dummy would be 322 kg-m/s.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem a 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg ,

By using the conservation of the momentum,

Momentum before the collision = momentum after the collision

The momentum of the tackling dummy = m × v

                                                                   = 2.8 × 115

                                                                  =322 kg-m/s

Thus, the momentum of the tackling dummy would be 322 kg-m/s.

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a. V(y)=V-E(y) b. U=vq-1/2QEL.cosФ c. V=EL/2 d. angular speed of the bar as it passes Ф=0° is W=[tex]\sqrt{3QE/ML}[/tex]

You were already familiar with the ideas of velocity and speed. The idea of angular speed and velocity, however, is what needs to be understood in terms of physical numbers. Angular motion is the term for when an item is expected to travel along a circular path while making a specific angle. The idea of angular speed and angular velocity is derived from the object's angular motion. Let's examine these ideas in greater depth. Assuming you are rotating a ball in a circular orbit, the angular speed can be defined as follows.

A body's rate of angle change over time as it rotates in a circular orbit is known as its angular speed. The definition of angular velocity is similar to that of linear velocity when an object is moving with some speed in a circular orbit.

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Answer:

not enough information need more information to answer the question

Explanation:

Gravity would still pull you down although it wouldn't affect you as much because there is less gravitational pull in high places such as Mt. Everest.

She is caught in a wind that blows toward the equator from about 30° N and 30° S of the equator. She is in the trade wind. This science is called Hadley cell.

It follows the movement of wind blows from one direction to the other such as the one which blow from north to south or east to west. The trade wind are produced by warm moist air rising near the equator.

Now, within the context of the task given above, when the movement wind which blows toward the equator from about 30° N and 30° S of the equator is known as the trade wind.

So therefore, the movement of wind from the same certain degrees from North and South is called trade wind.

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Answer:

Explanation:

Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.

Wave 1's intensity is nine times greater than Wave 2's. An electromagnetic wave carries both magnetic and electric energy when it moves.

An electromagnetic wave carries both magnetic and electric energy when it moves. Both waves contribute equally to the energy of electromagnetic waves. It is assumed that wave 1 has an electric field E that is three times greater than wave 2's maximal electric energy E'.

Thus, we can state:

E/E' = 3

We are aware,

The wave's intensity is determined by,

I = 1/2eE²c

Where,

I represents the wave's power,

e is a free space permittivity,

E represents the wave's energy.

The speed of light is c.

the strength of wave 1 right now

I1 = 1/2eE1²c

second wave

I2 = 1/2eE²c

Currently, dividing the two intensities,

I1/I2 = E1²/E2²

We are aware,

E/E' = 3

So,

I1/I2 = 9

I1 = 9I2

Thus, we can state:

Wave 1's intensity is nine times greater than Wave 2's.

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Answer:

Explanation:

The elastic potential energy equation is EPE = (1/2) k x2, where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)2 = 0.0479 Joules.

When there is relative motion between the fluid layers or between the fluid and solid surface, the fluid's internal property known as viscosity is created. This relative motion is being resisted by viscosity.

Derivations of the equations of motion—the connections for the conservation of mass and momentum—in rectangular,

coordinates that are spherical and cylindrical. The entire body of experimental data suggests that the fundamental equations of fluid mechanics are in fact those listed below, and that they apply to any circumstance where a Newtonian fluid is flowing, in theory.

Viscosity, a characteristic of fluids, is produced when there is relative motion between the fluid layers or between the fluid and solid surface. Viscosity prevents this relative motion from happening.

Unfortunately, due to their all-encompassing nature, their analytical solution is challenging or impossible unless the circumstances are quite straightforward.

However,

These "Navier-Stokes equations" must be understood for the following reasons.

reasons:

1. They result in the analytical and precise resolution of some basic yet significant problems.

issues.

2. They serve as the foundation for additional chemical engineering research in various fields.

3. A few reasonable simplification assumptions can frequently result in

for many engineering problems, approximation solutions are eminently acceptable purposes. Typical examples can be found in the study of boundary layers, the use of films to cover substrates, waves, lubrication, and inviscid (irrotational) flow.

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When you scan the hiker's body, you will notice a warm spot. Unless that person was dead, they would not be emitting heat.

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Answer:

It will need 20 Watts power to move the box 5 meters in 5 seconds.

Step-by-step explanation:

The power is defined as the work per unit time or the rate of doing work:

W=dL/dt

Where de work L, can be calculated by multiplying the force by the displacement d:

L=F.d

To this example, F and D are known, therefore the work is:

L=20N . 5m=40 Nm

We know that the work is doing within a time of 5 seconds:

W= 40 Nm / 5s = 20 Nm/s = 20 Watts

The potential energy of the 80kg cougar at a height of 70m is 54880 Joules.

Potential energy is simply the energy a body possesses due to its position.

It is expressed mathematically as;

P.E = mgh

Where m is mass, h is height and g is acceleration due to gravity ( g = 9.8m/s² )

Given the data in the question;

Plug the given values into the potential energy formula above and solve.

P.E = mgh

P.E = 80kg × 9.8m/s² × 70m

P.E = 54880kgm²/s²

P.E = 54880 Joules.

Therefore, the potential energy of the cougar is 54880 Joules.

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At hmax, Vy=0

vy=v0y-gt

0=6.32sin(36.3)-9.81t

t=.381 seconds

Δy=v0yt-.5gt^2

Δy=6.32sin(36.3)*.381-.5(9.81)(.381)^2

maximum height=.714 m

Several factors affect your skill-related fitness and your skills, including heredity, practice etc .

Skill-related fitness is have six different components; agility, speed, power, balance, coordination, reaction time.

Several factors affect your skill-related fitness and your skills, including heredity, practice etc

for example some people are able to run faster than others or react quick because they inherited these traits from their parents. A person who did not inherited a tendency in these areas from their ancestors ,may have more difficulty performing skills that require those abilities.

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The statement that best describes the reaction is as follows: The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water (option D).

The law of conservation of matter states that matter can neither be created nor destroyed. This law means that the mass that enters and leave a system is accounted for.

The law of conservation of mass explains the input and output of mass in a chemical reaction such that the mass of the reactants must be equal to the mass of the products.

According to this question, hydrochloric acid (HCl) and sodium hydroxide (NaOH) can be combined to form sodium chloride and water.

This means that the total amount of matter of the reactants (hydrochloric acid and sodium hydroxide) must equate the total amount of matter of the products (sodium chloride and water).

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The tension in the string if a rod PR is balanced on a pivot at the end R while a string is used to support the rod at P is 6 N

Moment = Force * Perpendicular Distance

Let us consider the pivot side be initial point,

Since the rod is balanced,

CM = ACM

CM = Clockwise moment

ACM = Anticlockwise moment

F = 9 N

PQ = 15 cm = 0.15 m

QR = 30 cm = 0.3 m

PR = PQ + QR

PR = 0.15 + 0.3

PR = 0.45 m

CM = W * QR

CM = 9 * 30

CM = 2.70 N m

ACM = T * PR

ACM = 0.45 T N m

2.70 = 0.45 T

T = 6 N

Therefore, the tension in the string is 6 N

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We calculated that the pilot's apparent weight at the maximum point was 3 70.5 Newton. Additionally, the circular portion's lowest point is equal to 1598.5 Newton.

A stunt pilot performing a loop during an airshow has been described to us. the vertical circle's loop. During his performance, he gives us the radius of the circle as 3.08 into 10 to the power three m.

We are provided the weight of the pilot, which is 614. For one second, Newton maintains a speed of 2.2 into tend to the bar at a distance of 2 m. We need to know the pilot's apparent weight in newtons while he is at the highest point of the loop. Now, the formula for the pilot's mass can be expressed as being equal to the pilot's weight divided by the acceleration caused by gravity. adding the values together results in 614. too unexplored by exploration.

You get the mass of the pilot, which is 62.65 kgs Hill, when you add gravity. The apparent weight of the pilot will be equal to the normal force generated by the airplane seat. At this point, we may use the formula M to determine the apparent weight off the pilot at the highest point in the circular journey.  N in this case stands for the pilot's apparent weight. We find the apparent weight of Mars to be 62.65 kgs multiplied by velocity, which is 2.2 and 2 10 to the part two m for a second, by adding the pilot's speed and the circular portion's radius, r. entire square.

The normal force of the seat on the pilot will be zero since the apparent weight of the pilot at his or her highest point throughout the circle in the case of weightlessness is Newton. With the numbers we have divided by Mars being She took 165 and shoes as replacements, we get the speed of the pilot at weightlessness state equal to 173.7 meters per second. As a result, its speed at this point will be equal to root of wait, multiplied by Baridis divided by mass.

Now your parent wait of the pilot at the lowest point can we given us Baron, well being equal to and we square r plus right, substituting the values, we have 62.65 Kgs to point to entertain the part to the whole square divided by yes, 614. Newton solving which we get the apparent weight of the pilot, the lowest point equal to 1598 0.5. Newton which is the apparent weight of the pilot at the lowest point of the circular what therefore Therefore we determined the apparent weight of the pilot at the highest point being equal to 3 70.5 Newton. And at the lowest point of the circular part being equal to 1598.5 Newton.

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As we walk across a period from left to right, the effective nuclear charge rises, whereas it falls as we move down the group. The element with the lowest effective nuclear charge will be found on the left side of the periodic table. The periodic table's group 1 includes H, Li, and Na.

A fluorine atom's nucleus has a charge Z of 9, but the valence electrons are mostly screened by the core electrons—four electrons from the 1s and 2s orbitals—and to a lesser extent by the 7 electrons in the 2p orbitals. The cation of sodium thus has the highest effective nuclear charge.

In spite of being in the same period as sodium and phosphorus, chlorine has the most protons in its shell (the most inside the same period), giving it the highest effective nuclear charge.

The amount of shielding electrons may be calculated by deducting the amount of valence electrons from the overall number of electrons in the atom or ion.

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The ball is in the air for 0.24 seconds, the ball hits the ground 2.46 meters far from the table and the x speed is 0m/s and y speed is 5m/s.

Velocity of the ball is 5m/s and the height of the table is 1.2 meters.

a. We know,

Velocity = distance/time

5 = 1.2/time

Time = 1.2/5

Time = 0.24 seconds.

The time taken by the ball to reach the ground is 0.24 seconds.

b. The ball after rolling of the table will behave like Horizontal projectile.

Horizontal range R formula,

R = V.√(2h/g)

Putting all the values,

R = 5.√(2×1.2/9.8)

R = 5×0.49

R = 2.46 meters.

c. When the ball reaches the ground,

X speed is 0m/s and Y speed is 5m/s.

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The difference in temperature from the average temperature for a region defines a heat wave.

A heat wave is an extended period of unusually hot weather that usually lasts longer than days.

Heat waves can occur in both low and high humidity conditions. They have the capacity to cover a wide area, exposing too many people to harmful heat.

An extremely dangerous weather event known as a heat wave occurs when temperatures rise considerably above 90° F. Due to the extreme heat and high humidity levels, an area becomes extremely warm for an extended period of time.

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Work is measured in joules or newton-meters

It may be thought of as force * distance

If there were acceleration in this problem, the force would be more than the weight, but because the speed is constant force = weight.

given,

force= 350N

Distance= 2m

work= ?

Work = Force * Distance

= 2m * 350 N

= 700 j or 700 N*M

If you're looking at this from an energy standpoint, you can just consider the final PE as the energy required because there is no KE at the end. so,

PE = m*g*h

and m*g = 350N

h= 2m

PE = 700j or 700 N*M

Hence, the 700N*M work is done by athlete.

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At a speed of two times ten to the eighth and violent. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given electromagnetic radiation requires this frequency.

In this problem, we have a given violent electromagnetic radiation, and we need to determine the frequency that corresponds to that violent electromagnetic radiation.

The chosen wavelength is lambda. I called at five minutes and forty nanometers—540 times 10 to the power—or nine meters. Considering that one nanometer equals 10 to the power -9 meters. Now, sea upon lambda finds frequency.

The value of C is three in 2, ten to the power eight meters per second, violent, and the speed of light in a vacuum. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given electromagnetic radiation requires this frequency.

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if the final acceleration increases by a factor of 11, then the final rotation should be 3.32[tex]w_{1}[/tex] times the initial rotation.

The relation between the centripetal acceleration and rotation speed of the particle is given as

a=rω²    

Where ω  is the angular speed and r radius of the circle

Now, rearranging the above equation we will get

ω = √[tex]\frac{a}{r}[/tex]

The initial acceleration is given by

           a₁ =100g

But then, the acceleration increases by a factor of 11. Which means the final acceleration of the particle is

a₂ = 11 (100g)

    = 1100g

The final and initial rotation speeds are related as

[tex]\frac{w1}{w2}[/tex]   = √[tex]\frac{a2}{a1}[/tex]

[tex]w_{2}[/tex]  = √[tex]\frac{1100g}{100g}[/tex] x [tex]w_{1}[/tex]

[tex]w_{2}[/tex]  = 3.32 [tex]w_{1}[/tex]

The final rotation should be 3.32[tex]w_{1}[/tex] times the initial rotation.

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The true statement is "Your speed is constant".

An object is moving at a constant speed when its speed is constant, that is the speed does not increase or decrease.

Constant speed also refers to the movement of a body at a uniform rate in a fixed steady-state moving with an average speed.

If you are in a car that is going around a curve and the speedometer reads a constant 30 miles per hour, you will notice that the direction of your motion is changing and but the distance travelled in a given time does not change.

Thus, only the speed is constant but velocity and acceleration is not constant.

The correct option is E.

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Gas giants have more moons than terrestrial planets due to having higher masses.

Giant planets are composed of low boiling point substances rather than other solid substances but massive solid planets can also exist. There are four giant planets in the Solar System i.e. Jupiter, Saturn, Uranus, and Neptune. They are composed of hydrogen and helium atom i.e. Jupiter and Saturn whereas Uranus and Neptune are composed of ice, rock, hydrogen, and helium.

The giant planets have more moons as compared to the terrestrial planets because of their big masses which leads to stronger gravitational fields. Giant planets also occupy greater space and have larger volumes of mass in their surrounding atmosphere.

So we can conclude that due to having higher masses, Gas giants have many moons as compared to terrestrial planets.

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A singly charged positive ion has a mass of 3.3x10-26 kg. after being accelerated from rest through a potential difference of 933 v, the ion enters a magnetic field of 1.43 t along a direction perpendicular to the field. The radius of the circular path of the ion in the field is (r)= 1.982 cm.

Energy is a term that means the object is affected by some amount of force and move a distance. That is called the energy. It can be measured in Joule.

To calculate the radius we are using the formula here,

r= mu/Bq

Where we are given,

m = The mass of single positive charged ion.=  3.3×10⁻²⁶kg.

q= The charge of the single positive charged ion.= 1.602×10⁻¹⁹ C

B = The magnetic field for the electric field. = 0.92 T

But we don't know the term, u= the velocity of the single positive charged ion.

So we have to calculate the velocity of the single positive charged ion. To calculate the velocity we are using the formula,

(1/2)mu²=qv

Here we are given,

v= The  potential difference of the electric field. = 933v.

We have to calculate the velocity=u, as Conservation of energy we know,

(1/2)mu²=qv

Or,(1/2)mu²=ev

Or, u²= (2×1.602×10⁻¹⁹×933)/(3.3×10⁻²⁶)

Or, u=91325.9 m/s.

So from this we know the velocity of the ion, u=91325.9 m/s.

Now, we have to calculate the radius in a magnetic field= r,

r= mu/Bq =mu/Be

Or, r= 3.3×10⁻²⁶×91325.9/0.92×1.602×10⁻¹⁹

Or, r=0.01982m

Or, r=1.982 cm.

So from the calculation we can surely say that, The radius of the circular path of the ion in the field is (r)= 1.982 cm.

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Let p be the total linear momentum of the system before the collision and p' the total linear momentum of the system after the collision. Let p₁₁ and p₁₄ be the linear momentum of the 11.0kg ball and the 14.0kg ball before the collision, and let p₁₁' and p₁₄' be their linear momenta after the collision.

According to the Law of Conservation of Linear Momentum, the total linear momentum of the system before and after the collision remains the same. Then:

Let v be the unknown speed of the 11.0kg ball after the collision. Find the value of p₁₁, p₁₄, and p₁₄'. Find an expression for p₁₁' in terms of v and replace all the values into the above equation. Solve for v.

The linear momentum of a particle with mass m and velocity v is:

Then:

Then:

Therefore, the velocity of the first ball after the collision is 20.4m/s.