I’m confused how to start it and I just need help atleast doing one.

Answer:

96,000joules!!!

Explanation:

Hope this helps u

Answer:

30 m/h

Explanation:

Have A Wonderful Day !!

Answer:

Explanation:

The total distance travelled by ball before first bounce

= 160 + 160 = 320 ft

Distance travelled between first bounce and second bounce

= 80 + 80 = 160 ft

Distance travelled between second bounce and third bounce

= 40 + 40 = 80 ft

Distance travelled between third bounce and fourth bounce

= 20 + 20 = 40 ft .

Distance travelled in fourth bounce = 10 ft

Total distance travelled = 320 + 160 + 80 + 40 + 10

= 610 ft .

Answer:

P = 490500 [Pa]

Explanation:

The pressure at the bottom of a vessel and even of a lake or sea can be calculated by means of the following hydrostatic equation.

[tex]P=Ro*g*h[/tex]

where:

P = pressure [Pa] (units of pascal)

Ro = water density = 1000 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

[tex]P=1000*9.81*50\\P=490500[Pa][/tex]

Answer:

D) Thermal energy will move from the water bottle to the ice.

Explanation:

Overtime, what happens is that thermal energy will move from the water bottle to the ice.

The water bottle is at a higher temperature compared to the ice. So, thermal energy will move from a place at higher temperature to one with lower temperature.

The plunger is transferring energy to the gas particles.

When Cecily is applying pressure to the plunger, the gas inside is being compressed, and the speed of gas molecules increases.

When these air molecules enter the tire, adiabatically, the temperature of the gas rises.

It happens due to an increase in the average kinetic energy of the gas particles.

Thus, the gas particles receive energy from the plunger.

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Answer: B- a doctor, by law, must treat every patient who shows up in a medical facility

Explanation:

Answer:

F = 2.45 [N]

Explanation:

The force that the potato exerts on the Earth is equal to the product of the potato mass by gravitational acceleration.

[tex]F=m*g[/tex]

where:

m = mass = 0.25 [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]F=0.25*9.81\\F=2.45[N][/tex]

Answer:

Explanation:

It’s devastating because when a earthquake is 7.7 magnitude the

Answer:

0.1 m

Explanation:

It is given that,

Mass of the object, m = 350 g = 0.35 kg

Spring constant of the spring, k = 5.2 N/m

Amplitude of the oscillation, A = 10 cm = 0.1 m

Frequency of a spring mass system is given by :

Time period:

Answer:

8.34 x 10⁻⁶N

Explanation:

Given parameters:

Mass 1  = 100kg

Mass 2 = 200kg

Distance of separation  = 40cm = 0.4m

Unknown:

Gravitational force of attraction between them  = ?

Solution:

To solve this problem, we use the expression below which is derived from the Newton's law of universal gravitation:

           Fg  = [tex]\frac{G x mass 1 x mass 2}{d^{2} }[/tex]

G is the universal gravitation constant = 6.67 x 10⁻¹¹

d is the separation

 Now;

  Fg = [tex]\frac{6.67 x 10^{-11} x 100 x 200}{0.4^{2} }[/tex]   = 8.34 x 10⁻⁶N

Answer:

Explanation:

C. The energy on the macroscopic scale decreased, and the energy on the molecular scale increased.

A. friction converts some energy on the macroscopic scale to energy on the molecular scale.

B. The mechanical energy of the system decreased because of friction.

B. The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

B. the mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.

The  ball rolling on the floor eventually comes to a stop which means that

the energy on the macroscopic scale decreased, and the energy on the

molecular scale increased.

This is a scale in which an object can be seen with the eyes. When

an object is in motion, the ball rolls away and becomes less visible hence a

decrease in the macroscopic scale.

During motion, friction converts some macroscopic energy into molecular

scale which is why there was an increase in it.

Read more about Macroscopic scale here https://brainly.com/question/17609067

Answer:

a 10 kg bag of hot water at the same temperature

Explanation:

A 10kg bag of hot water at the same temperature will retain heat much better and keep the tent warmer at night compared to the iron pellet.

Answer:

Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

Answer:

12.31 m/s

Explanation:

If we recall from the previous knowledge we had about speed,

we will know that:

speed = distance/ time.

As such:

The average speed of the rider bicycle is

average speed = total distance/ total time

Mathematically, it can be computed as:

[tex]v_{avg} = \dfrac{d+d}{\dfrac{d}{v_1}+ \dfrac{d}{v_2}}[/tex]

[tex]v_{avg} = \dfrac{2d}{\dfrac{d}{10 \ m/s}+ \dfrac{d}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{1}{10 \ m/s}+ \dfrac{1}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{13}{80 \ m/s}}[/tex]

[tex]\mathbf{v_{avg} =12.31 \ m/s}[/tex]

The distance walked by the woman at the given speed an time, is 15 miles.

The speed of an object is defined as the rate of change of the distance travelled by the object.

Here,

Speed with which the woman is walking,

v = 5 miles/hour

Time taken by the woman for walking,

t = 3 hours

We know speed is the rate of change of distance,

v = d/t  where d is the distance travelled by the woman

So, d = v x t

 d = 5 x 3

 d = 15 miles

Hence,

The distance walked by the woman at the given speed an time, is 15 miles.

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Answer:

the longer wavelength is 1.2552 cm

Explanation:

given that

beat frequency [tex]f_{b}[/tex] = 100 MHz = 100 × 10⁶ Hz

λ₁ = 1.250 cm = 0.0125 m

we know that beat frequency [tex]f_{b}[/tex] of two simultaneous frequencies f₁ and f₂ is expressed as;

[tex]f_{b}[/tex]  = | f₁ - f₂ |

we know that microwave travels at a speed of light, so for any electromagnetic wave traveling at speed of light c with wavelength λ; frequency is;

f = c / λ

hence our beat frequency [tex]f_{b}[/tex] becomes

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

to find the longer wavelength,  λ₂

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

divide both side by c

[tex]f_{b}[/tex] /c =  ( 1/λ₁ - 1/λ₂)

1/λ₂ = 1/λ₁ - [tex]f_{b}[/tex] /c

λ₂ =  [1/λ₁ - [tex]f_{b}[/tex] /c ]⁻¹

so we substitute in our values

we know that speed of light c = 3 × 10⁸

so

λ₂ =  [ (1/0.0125) - (100 × 10⁶ /3 × 10⁸) ]⁻¹

λ₂ =  [80 - 0.3333 ]⁻¹

λ₂ =  [79.6667 ]⁻¹

λ₂ =  0.01255 m

λ₂ =  0.012552 × 100 cm

λ₂ =  1.2552 cm

Therefore, the longer wavelength is 1.2552 cm

Answer:

5 Km/h

Explanation:

From the question given above, the following data were obtained:

Distance travelled = 10 Km

Time = 2 hours

Speed =?

Speed is simply defined as the distance travelled per unit time. Mathematically, it can be represented as:

Speed = distance travelled /time.

With the above formula, we can obtain the speed at which the duck is travelling as follow:

Distance travelled = 10 Km

Time = 2 hours

Speed =?

Speed = distance travelled /time.

Speed = 10 / 2

Speed = 5 Km/h

Thus, the duck is travelling at a speed of 5 Km/h

Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Answer:

sultan's displacement is

[tex]20 \sqrt{13} [/tex] km

Answer:

v = 80.62 km/h

Explanation:

Given that,

An airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its forward motion a crosswind.

We need to find the resultant velocity of the airplane. It can be calculated as follows :

[tex]v=\sqrt{80^2+10^2} \\\\v=80.62\ km/h[/tex]

So, the required velocity is 80.62 km/h.

Answer:

[tex]9\:\mathrm{J}[/tex]

Explanation:

Kinetic energy is given by the following equation:

[tex]KE=\frac{1}{2}mv^2[/tex], where [tex]m[/tex] is mass in [tex]\mathrm{kg}[/tex] and [tex]v[/tex] is velocity in [tex]\mathrm{m/s}[/tex].

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

[tex]80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}[/tex].

Therefore, the kinetic energy of the cell phone is:

[tex]KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}[/tex].

Answer:

Organ system because multiple organs make up an organ system and multiple organ systems make up an organism

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

[tex]\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N - m\cdot g = 0[/tex] (2)

Where:

[tex]N[/tex] - Normal force from the ground on the object, measured in newtons.

[tex]m[/tex] - Mass of the object, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Linear speed of rotation of the disk, measured in meters per second.

[tex]R[/tex] - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex]

If we know that [tex]v = 0.8\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.75\,m[/tex], then the coefficient of static friction between the object and the disk is:

[tex]\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}[/tex]

[tex]\mu_{s} = 0.087[/tex]

The coefficient of static friction between the object and the disk is 0.087.