If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experiment. 2 pts 2. What is the probability of getting a sum of 11 in these outcomes? 2 pts 3. What is the probability of getting a sum less than or equal to 4? 2 pts 4. What is the probability of getting a sum of 13 or more?

Answers

Answer 1

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

[tex]P(\text{sum=11})=\dfrac{3}{36}[/tex]

[tex]P(\text{sum=11})=\dfrac{1}{12}[/tex]

Therefore, the probability of getting a sum of 11 in these outcomes is [tex]\dfrac{1}{12}[/tex].

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

[tex]P({sum\leq 4})=\dfrac{6}{36}[/tex]

[tex]P({sum\leq 4})=\dfrac{1}{6}[/tex]

Therefore, the probability of getting a sum less than or equal to 4 is [tex]\dfrac{1}{6}[/tex].

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

[tex]P(sum\geq 13)=\dfrac{0}{36}[/tex]

[tex]P({sum\geq 13})=0[/tex]

Therefore, the probability of getting a sum of 13 or more is 0.


Related Questions

Angle A and angle B are vertical angles. If m A=(5x-24) and m_B=(3x+24), then find the value of x and the measure of angle A

Answers

Answer:

Step-by-step explanation:

If they are vertical angles, they are equal.

5x - 24 = 3x + 24                      Add 24 to both sides

5x -24 +24 = 3x + 24 + 24       Combine

5x =   3x + 48                           Subtract 3x

5x - 3x = 3x-3x + 48                Combine

2x = 48                                    Divide by 2                                

x = 24

<A =5*24 - 24

<A = 96

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Find the average rate of change of g(x)=3x^2 ver the interval [-5, -3].

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Answer:

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Step-by-step explanation:

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Answer: -6x² + 15x + 5

Step-by-step explanation:

To solve this problem, you only need to substitute g(x)'s equation as the value of the x in f(x), then simplify.

Step 1: f(x) = -3(2x² - 5x - 1) + 2

Step 2: Apply the distributive property

-3(2x²) + -3(-5x) + -3(-1)

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Step 3: Simplify

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Find the missing coordinate if the ordered pair is to be a solution to the given equation.
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Answers

Answer:

17 (I think)

Step-by-step explanation:

substitue -3 in for x so 4(-3) + y = 5

-12+ y =5

+12        +12

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Answers

Answer: y = 3x - 6

Step-by-step explanation: A line that is parallel to another line must have the same slope, so you already have y = 3x + b. To find b, use the point that they give. b is the y-intercept, so just subtract 3(x) from the y coordinate of the point, where x is the x-coordinate of the given point.

Two groups of friends go to a movie. Each ticket costs the same amount. One group spends ​$57. The other group spends ​$95. List all possible whole number ticket prices for each group. At most how much does each ticket​ cost? Suppose a group of 2 friends goes to this movie. At most how much does this group​ spend?


List all possible whole number ticket prices for the group that spends ​$57. Select all that apply.


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B.$1

C. ​$57

D. ​$95

E. ​$3

F. ​$5

List all possible whole number ticket prices for the group that spends ​$95. Select all

that apply. A. ​$3

B. ​$19

C. ​$1

D. ​$57

E. ​$95

F. ​$5 At most how much does each ticket​ cost?

Answers

Answer:

1) All possible number tickets for group that spends $57: A, B, C, D

2) All possible number tickets for group that spends $95: B, C, E, F

3) Each ticket will cost at most $19

Step-by-step explanation:

We are told that one group spends $57 dollars while the other group spends $95.

Now,we want to find all possible whole number ticket prices for each group and at most how much each ticket​ costs.

To do this, let's first find the factors of both amounts which will give us all possible whole number ticket prices for each group.

57: 1, 3, 19, 57

95: 1, 5, 19, 95

Since each ticket costs same amount, to find out at most how much each ticket costs, we will select the highest common factor of both groups which is 19.

Thus,each ticket will cost at most $19

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A.
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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

B

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Answers

Answer:

14x +10y < 200

Step-by-step explanation:

The inequality that represents the given condition is: 14x + 10 y < 200.

What is an inequality?

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Given, the price per long sleeved t-shirt is $14.

The price per short sleeved t-shirt is $10.

The soccer team has sold less than $200 worth of both types of t-shirts.

Here, the number of long-sleeved t-shirts they have sold is 'x'.

The number of short-sleeved t-shirts they have sold is 'y'.

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The total price of short sleeved t-shirt sold is = $10 × y = $10y

Therefore, the required inequality will be:

14x + 10 y < 200

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Step-by-step explanation:

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Answers

Answer:

2 -67.2

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-3.5 Times -3 = 10.5

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Answer:

2. -67.2

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answer:

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Answers

Answer: See explanation

Step-by-step explanation:

Price of sandwich = $6

Food tax = 5% of $6

= 0.05 × $6

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= 0.2 × $6

= $1.2

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= $7.5

Answer: 1: $0.30 2: $1.20 3: $7.50

Step-by-step explanation:

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Step 1:

[tex]2 {x}^{2} - 5x - 12[/tex]

Step 2:

[tex]2 {x}^{2} - 8x + 3x - 12[/tex]

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Step 4:

[tex]\blue{(x - 4)(2x + 3)}[/tex]

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80
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Answers

Answer:

59

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Fifty eighth graders attend a
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Answer:

15

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Step-by-step explanation:

Answer: B

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Answers

Answer:

x ≈ 38.7°

Step-by-step explanation:

Using the tangent ratio in the right triangle.

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