The number of values x for which the square root of 48/x a whole number are two.
What is the number?The square root of a number can be described as number that when multiplied with itself yields the number.
The first step is to determine the factors of 48. Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
The factors of 48 that will yield a perfect square when divided by 48: 3 and 12.
48 divided by 3 would give a value of 16.
48 divided by 12 would give a value of 4.
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What is the partial fraction decomposition, I know D is wrong
[tex]\dfrac{7x^2+14}{(x^2+3)^2}=\dfrac{7x^2+21-7}{(x^2+3)^2}=\dfrac{7x^2+21}{(x^2+3)^2}-\dfrac{7}{(x^2+3)^2}=\dfrac{7(x^2+3)}{(x^2+3)^2}-\dfrac{7}{(x^2+3)^2}=\\=\dfrac{7}{x^2+3}-\dfrac{7}{(x^2+3)^2}[/tex]
A family wants to make a 20% downpayment on a house that costs $20,000, which of the amount is the downpayment?
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{20\% of 20000}}{\left( \cfrac{20}{100} \right)20000}\implies 4000\qquad \impliedby downpayment[/tex]
Find the length of the third side. If necessary, write in simplest radical form.
[tex]\text{Apply Pythagorean theorem,}\\\\~~~~~~~~\text{Hypotenuse}^2=\text{Base}^2 + \text{Perpendicular}^2\\\\\implies 9^2 = \text{Base}^2 + \left(2\sqrt{14} \right)^2\\\\\implies 81 = \text{Base}^2 + 56\\\\\implies \text{Base}^2 = 81-56\\\\\implies \text{Base}^2 = 25\\\\\implies \text{Base} = \sqrt{25}\\\\\implies \text{Base} = 5\\\\\text{The length of the third side is 5 units.}[/tex]
Meril Starts driving at 14 00
0 x + 12 + x = 18
Solve ?
Answer:
x = 3
Step-by-step explanation:
2x + 12 = 18
2x = 18-12
2x = 6
x = 3
give brainliest please!
hope htis helps :)
Answer:6
Step-by-step explanation:
0x+12+x=18
0x+x=18-12
x=6
DOES the given value make the inequalities true? x + 9 > 21, when x = 15?
Answer:
Yes.
Step-by-step explanation:
When [tex]x=15[/tex],
[tex]x+9=15+9=24 > 21[/tex].
Answer:
Yes this is true
Step-by-step explanation:
24 is greater than 21; which means this statement is always true.
Which is the most reasonable estimate of 132% of 48?
5.2
6.5
52
65
Answer:
65
Step-by-step explanation
Just did it on egde
Ms. Stewart teaches three science classes. Her students are freshmen and
sophomores. Her student data are shown in the relative frequency table.
Which statement is false?
The statement that is false is 15% of her students are in biology, the correct option is A.
How to form two-way table?Suppose two dimensions are there, viz X and Y. Some values of X are there as X_1, X_2, ... , X_n and some values of Y are there as Y_1, Y_2, ... , Y_n
List them in title of the rows and left to the columns. There will be n \times k table of values will be formed(excluding titles and totals), such that:
Value(ith row, jth column) = Frequency for intersection of X_i and Y_j (assuming X values are going in rows, and Y values are listed in columns).
Then totals for rows, columns, and whole table are written on bottom and right margin of the final table.
For n = 2, and k = 2, the table would look like:
[tex]\begin{array}{cccc}&Y_1&Y_2&\rm Total\\X_1&n(X_1 \cap Y_1)&n(X_1\cap Y_2)&n(X_1)\\X_2&n(X_2 \cap Y_1)&n(X_2 \cap Y_2)&n(X_2)\\\rm Total & n(Y_1) & n(Y_2) & S \end{array}[/tex]
where S denotes total of totals, also called total frequency.
n is showing the frequency of the bracketed quantity, and intersection sign in between is showing occurrence of both the categories together.
We are given that;
The relative frequency table
Now,
This is because the relative frequency table shows that 0.15 of her students are freshmen in biology and 0.2 of her students are sophomores in biology. Therefore, the total percentage of her students in biology is 0.15 + 0.2 = 0.35, which is 35%, not 15%.
The other statements are true based on the relative frequency table.
Therefore, by the two-way table the answer will be 15% of her students are in biology.
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PLEASE HELP I WILL GIVE BRAINLIEST!!
Find an angle in the range between 0 and 2ㅠ radians that is coterminal with
-ㅠ/2
a) 7ㅠ/2
b) 3ㅠ/2
C) 5ㅠ/2
d) ㅠ/2
The coterminal angle to -ㅠ/2 in the range between 0 and 2ㅠ radians is 3ㅠ/2.
How to find a coterminal angle?
For any angle A, all the coterminal angles are of the form:
B = A + n*(2ㅠ).
Where n is an integer different than zero.
In this case, the angle is A = -ㅠ/2
So the coterminal angles are of the form:
B = -ㅠ/2 + n*(2ㅠ)
We want it to be between 0 and 2ㅠ, so we can define n = 1, then we get:
B = -ㅠ/2 + (2ㅠ) = -ㅠ/2 + ((4/2)ㅠ) = 3ㅠ/2
Then we can conclude that the correct option is b.
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: The proliferation of the Internet has given rise to a new method of advertising, called spamming, that essentially is a more cost-effective method of the telephone solicitation method known as cold calling. If a company buys three mailing lists with 2,500, 3,500, and 4,000 email addresses respectively and spams them with promotional material, how many potential customers has it reached?
The number of potential customers that the company has reached is 10,000 e--mail addresses.
What is a word problem in mathematics?A word problem is a real-life problem and it can be approached with the use of a mathematical model, interpretation into variables, and arithmetic operations usage.
Given that:
A company buys three mailing lists with 2500, 3500, and 4000 addresses respectively.The number of potential customers that the company has reached is:
= 2500 3500 + 4000 e--mail addresses.
= 10,000 e--mail addresses.
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Help please thank you
When the sum of two angles measures up to 180° then these angles are known as supplementary angles of each other. The supplementary angles are 153° and 27°. The Complementary angles are 34° and 56°.
What are Supplementary Angles?When the sum of two angles measures up to 180° then these angles are known as supplementary angles of each other.
for example, ∠x + ∠y = 180°, therefore, the ∠x and ∠y are the supplementary angles of each other.
What are Complementary Angles?When the sum of two angles measures up to 90° then these angles are known as complementary angles of each other.
for example, ∠x + ∠y = 90°, therefore, the ∠x and ∠y are the complementary angles of each other.
The supplementary angles are 153° and 27°.
The Complementary angles are 34° and 56°.
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Shane's age is 8 years more than three times Edward's age. Their combined age is 56 years.
How old is Shane?
What is the area of the trapezoid shown? The figure is not drawn to scale.
284.31 in.²
303.75 in.²
568.62 in.²
607.5 in.2
Answer:
284.3
Step-by-step explanation:
Trapezoid Formula:
A=a+b/2*h
plug in the numbers
Hurry help
If p is true and ~ q is false, then p -> ~ q is ____ false.
-Sometimes
-Always
-Never
Answer:
Never
Step-by-step explanation:
If p is true and ~ q is false, then p -> ~ q is ____ false
This translates to:
true -> true
So it will never be false.
Which of the following expressions is equivalent to the one shown below?
OA. 5.-11
OB. (-11)
14
OC.
(-11)
D. (-11)
145
The expression that is equivalent to (-11/15)⁵ is (-11)⁵/(15)⁵
Indices expressionGiven the expression as shown below
(-11/15)⁵
This expression means that we are to raise the value -11 and 14 raised to the power of 5 individually as shown:
(-11/15)⁵ = (-11)⁵/(15)⁵
Hence the expression that is equivalent to (-11/15)⁵ is (-11)⁵/(15)⁵
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What does the remainder theorem conclude given that f(x)x+3 has a remainder of 11?
By the remainder theorem of polynomial division, the complete equation is f(-3) = 11
How to complete the blanks?The equation is given as:
f(x)/x + 3
Set the divisor to 0
x + 3 = 0
Solve for x
x = -3
Given that the quotient has a remainder of 11.
It means that:
f(-3) = 11
Hence, the complete equation is f(-3) = 11
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A car leaves its garage and travels for 30km on a bearing of 145, then 10 km on a bearing of 250 Calculate a) the distance travelled from the starting point b) the bearing of the starting point from the car.
The distance travelled from the starting point is 29 km , the bearing is 344 degree
The missing diagram is attached with the answer.
What is Bearing Angle ?It is the horizontal angle between the object and another object.
It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250
(a) the distance travelled from the starting point
It can be understood from the diagram that
To determine the distance , b is to determined4
By applying Cosine rule
b² = a² +c²-2ac cos[tex]\rm \theta[/tex]
b² = 10² +30² - 2* 30*10 cos75
b² = 100+900 -600* 0.2588
b² = 100-155.2914
b² = 844.7
b = 29 km
Therefore the distance travelled from the starting point is 29 km.
(b) the bearing of the starting point from the car.
To determine the bearing ,
angle C has to be determined
By sine rule
sin C / c = sin B / b
sin C = sin 75 * 30 / 29
sin C = 0.9970
C = sin⁻¹ 0.9970
C = 85.59 degree
angle C = α +70 degree
α = 15.59 degree
Bearing = 70 + 20 + 9 0 + 90+74 = 244 degree
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Read the excerpt from Black Boy.
The boys scattered, yelling, nursing their heads, staring at
me in utter disbelief. They had never seen such frenzy. I
stood panting, egging them on, taunting them to come on
and fight.
What is the connotative meaning of frenzy as it is used in this
excerpt?
-Negative; it describes a violent reaction based on
rage.
-Positive; it develops a sense of excitement.
-Negative; it suggests a complete mental breakdown.
-Positive; it emphasizes strength and courage
Answer:
Negative; it describes a violent reaction based on rage.
Step-by-step explanation:
What is the mode: 18,21,22,18,19
Answer:
18
Step-by-step explanation:
Mode = modal class (Recurring)
The number/value that appears the most which in this case is 18 because it can be seen twice.
Protons have a small negative electrical charge.
True
False
Answer:
False
Step-by-step explanation:
Protons have positive charge.
Answer:
Protons have a positive charge.
Step-by-step explanation:
My sister needs help on this question and I am too lazy to figure this out please help ASAP
The question was: Which figure has exactly one line of symmetry?
Answer:
its the Pentagon, the other shaps have 2 lines if symmetry
Find the midpoint of the line segment
1) (-2,-4), (10,8)
Answer:
(4, 2)
Step-by-step explanation:
the midpoint of points (x1, y1) and (x2, y2) is ([tex]\frac{x_{1} + x_{2}}{2}[/tex],[tex]\frac{y_{1} + y_{2}}{2}[/tex])
plug in points (-2, -4) and (10, 8) to get ((10+(-2))/2), (8+(-4))/2) = (4, 2)
A major river flowing out of the Himalayas
Answer:
The Ganges
Step-by-step explanation:
Answer:
Ganga
Step-by-step explanation:
Ganga is the holy river of IndiaIt has risen from Himalayas.It flows throughout the Ind and falls at Sundarban inside Bay of BangalHorizontal stadia sights. Determine the error in distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight
The error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.
What is Tangent (Tanθ)?The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,
Tan(θ) = Perpendicular/Base
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The base is the adjacent smaller side of the angle θ.
Given the uppermost portion of a that is 3.0m long stadia rod is inclined 14 cm toward the observer, therefore, the angle of inclination, θ can be written as
tan(θ)=0.14/3
θ = 2.672°
Also, the rod intercept is 1.75m, therefore, t the error in distance in the distance is,
tanθ=x/1.75
x = 1.75 tan(θ)
x = 1.75 × tan(2.672°)
x = 0.08167 m = 8.167 cm
Hence, the error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.
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Which function is a quadratic function?
Op(x) = 2x(x2 +6) +1
O m(x) = 4(x + 3) - 2
1
O f(x) = -8x²(x² − 6) + 1
O h(x) = 3x(x - 2) - 4
Answer:
h(x) = 3x(x - 2) - 4
Step-by-step explanation:
A quadratic function is a polynomial having a degree of 2.
==============================================================
On expanding h(x) :
⇒ h(x) = 3x (x - 2) - 4
⇒ h(x) = 3x² - 6x - 4
=============================================================
Hence, h(x) is a quadratic function.
Answer:
h(x) = 3x(x - 2) - 4
Step by-step explanation
A quadratic function has a degree of 2.
Firstly, we expand h(x):
h(x) = 3x (x - 2) - 4
OR h(x) = 3x squared - 6x - 4
Therefore, it is h(x)
Toni participates in a 10-mile charity walk. For each mile she walks, a sponsor will donate $9 to the charity. The graph represents the function that models the amount of money the sponsor will donate given the number of miles, x, Toni walks. what is the domain of the fuction
The domain of the function when Toni participates in a 10-mile charity walk will be [0, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90]
What is a function?It should be noted that a function simply means a relation that's used to express a variable with another variable.
In this case, it should be noted that a domain simply means the set of possible values of the independent variable. The function here is 9x. The domain is all x-values or inputs of a function. Therefore, the domain is depicted above.
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Which measure is of an angle that is coterminal with a 425° angle?
425° – (1,000n)°, for any integer n
425° – (840n)°, for any integer n
425° + (960n)°, for any integer n
425° + (1,440n)°, for any integer n
The measure of angle that is coterminal with 425° is 425° + (1440n)°
What are coterminal angles?Coterminal angles are angles in multiples of the angles in standard positions examples(360°).
It is mostly gotten by adding 360° or multiples of 360 to the angle.
One of the unique behavior of coterminal angles is that their sine, cosine and tangent are equal.
Analysis:
From the options, the only one with an addition of 360 or multiples of 360 is 425 + 1440n
If we put n = 1, the coterminal angle gotten is 1865.
if we find the sine of 425°, we get 0.9063 which is same as the sine of 1865°.
In conclusion, the coterminal angle to 425° is 425° + (1440n)°.
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Answer:
B. 425° – (840n)°, for any integer n
Please help will give 30 points.
Answer: I think that the answer would be B. This is what i got after doing the work
Help ?!!!!!!!!!!?!!!!!!
The answers of the given geometrical shapes are:
1. 226.29 cubic yard
2. 46.1 cubic inches
3. 2413.71 cubic inches
4. 234.67 cubic millimeter
5. 340.48 cubic yards
6. 113.14 cubic feet
7. 528 cubic centimeter
8. 905.14 cubic centimeter
9. 56.57 cubic feet
what is mensuration?Mensuration is the branch of geometry that deals with measurement of volumes and areas of geometrical shapes.
Analysis:
1. volume of cylinder =π [tex]r^{2}[/tex]h. where r = 6/2 = 3 yard, h = 8 yard
= [tex]\frac{22}{7}[/tex] x [tex]3^{2}[/tex] x 8 = 226.29 cubic yard
2. volume of cone = [tex]\frac{1}{3}[/tex] x π [tex]r^{2}[/tex]h. where r = 2inches, h = 11
= [tex]\frac{1}{3}[/tex] x [tex]2^{2}[/tex] x [tex]\frac{22}{7}[/tex] x 11 = 46.1 cubic inches
3. volume of cylinder = π [tex]r^{2}[/tex]h. where r = 8, h = 12
= [tex]\frac{22}{7}[/tex] x [tex]8^{2}[/tex] x 12 = 2413.71 cubic inches
4. volume of cone = [tex]\frac{1}{3}[/tex] x π [tex]r^{2}[/tex]h. where r = 4, h = 14
= [tex]\frac{1}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex]4^{2}[/tex] x 14 = 234.67 cubic millimeter
5. volume of cone = [tex]\frac{1}{3}[/tex] x π [tex]r^{2}[/tex]h. where r = 5, h = 13
= [tex]\frac{1}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex]5^{2}[/tex] x 13 = 340.48 cubic yards
6. volume of cylinder = π [tex]r^{2}[/tex]h. where r = 3, h = 4
= [tex]\frac{22}{7}[/tex] x [tex]3^{2}[/tex] x 4 = 113.14 cubic feet
7. volume of cone = [tex]\frac{1}{3}[/tex] x π [tex]r^{2}[/tex]h. r = 6, h = 14
= [tex]\frac{1}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex]6^{2}[/tex] x 14 = 528 cubic centimeter
8. volume of cylinder = π [tex]r^{2}[/tex]h. where r = 6, h = 8
= [tex]\frac{22}{7}[/tex] x [tex]6^{2}[/tex] x 8 = 905.14 cubic centimeter
9. volume of cylinder = π [tex]r^{2}[/tex]h. where r = 1.5, h = 4
= [tex]\frac{22}{7}[/tex] x [tex]1.5^{2}[/tex] x 4 = 56.57 cubic feet
In conclusion, the volume of cylinders and cones for the given dimensions are:
1. 226.29 cubic yard
2. 46.1 cubic inches
3. 2413.71 cubic inches
4. 234.67 cubic millimeter
5. 340.48 cubic yards
6. 113.14 cubic feet
7. 528 cubic centimeter
8. 905.14 cubic centimeter
9. 56.57 cubic feet
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Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the resulting values to the corresponding limits.
The correct solution to the limits of x in the tiles can be seen below.
[tex]\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }[/tex][tex]\mathbf{ = -\dfrac{1}{52} }[/tex][tex]\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }[/tex][tex]\mathbf{=\dfrac{1}{79} }[/tex][tex]\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }[/tex]= -31 [tex]\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }[/tex][tex]\mathbf{ =\dfrac{1}{98}}[/tex]What are the corresponding limits of x?The limits of x approaching a given number of a quadratic equation can be determined by knowing the value of x at that given number and substituting the value of x into the quadratic equation.
From the given diagram, we have:
1.
[tex]\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }[/tex]
So, x - 9 is positive when x → 9⁺. Therefore, |x -9) = x - 9
[tex]\mathbf{ \lim_{x \to 9^+} (\dfrac{x-9}{-x^2-34+387}) }[/tex]
Simplifying the quadratic equation, we have:
[tex]\mathbf{ \lim_{x \to 9^+} (-\dfrac{1}{x+43}) }[/tex]
Replacing the value of x = 9
[tex]\mathbf{ = (-\dfrac{1}{9+43}) }[/tex]
[tex]\mathbf{ = -\dfrac{1}{52} }[/tex]
2.
[tex]\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }[/tex]
-x²-63x+568 is positive when x → 8⁻.Thus |-x²-63x+568| = -x²-63x+568
[tex]\mathbf{ \lim_{x \to 8^-} (\dfrac{1}{x+71}) }[/tex]
[tex]\mathbf{=\dfrac{1}{8+71} }[/tex]
[tex]\mathbf{=\dfrac{1}{79} }[/tex]
3.
[tex]\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }[/tex]
x -7 is positive, therefore |x-7| = x - 7[tex]\mathbf{ \lim_{x \to 7^+} (\dfrac{-x^2-17x+168 }{x-7}) }[/tex]
[tex]\mathbf{ \lim_{x \to 7^+} (-x-24)}[/tex]
[tex]\mathbf{ \lim_{x \to 7^+} (-7-24)}[/tex]
= -31
4.
[tex]\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }[/tex]
x-6 is negative when x → 6⁻. Therefore, |x-6| = -x + 6[tex]\mathbf{ \lim_{x \to 6^-} (\dfrac{-x+6 }{-x^2-86x+552}) }[/tex]
[tex]\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{x+92}) }[/tex]
[tex]\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{6+92}) }[/tex]
[tex]\mathbf{ =\dfrac{1}{98}}[/tex]
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