If the population of frogs decreased, then what would increase?

A

foxes

B

hawks

C

caterpillars

Answer:

C

Explanation:

Basically force is given by the formula.

F= ma

Where m is mass of the body and 'a' is acceleration.

Here the time is not given, hence it is not possible to calculate acceleration, as acceleration is given by the formula

a= v/t

So most probably the question is wrong.

However if we take acceleration= 2m/s^2

Then F= ma= 50*2= 100N

However if the question was to find energy then it is sufficient to find kinetic energy as moving objects possess kinetic energy.kinetic energy is given by the formula:

KE= 1/2*m* v^2

I.e, KE= 1/2 * 50 * 2* 2

Answer:

you can view my profile and go to questions and answer the recent questions i posted

Explanation:

When the force is applied normal to the circumference at point P, then it's zero.

It should be noted that force simply means an influence that can change the position of an object.

In this case, when the force is applied normal to the circumference at point P, then it's zero.

Also, if the force is applied normal to the circumference at point X, then it's constant.

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The magnitude of the electric field due to the particle at the given distance is [tex]9\times 10^9 q[/tex].

The electric field strength of a charged particle is the force per unit charge in the given field.

The electric field strength of a charge is given as;

[tex]E = \frac{F}{q} \\\\E = \frac{kq}{r^2}[/tex]

where;

[tex]E = \frac{9\times 10^9 \times q}{1^2} \\\\E = 9\times 10^9 q[/tex]

Thus, the magnitude of the electric field due to the particle at the given distance is [tex]9\times 10^9 q[/tex].

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Answer:

10kj should be the answer so I think

Answer:

charged pith ball works well to show the Coulomb force between two charged objects. If a glass rod is rubbed with silk, the silk rubs some electrons off the rod. The rod thus becomes positively charged. ... Since like charges repel, the pith balls repel one another.

Explanation:

My location coordinates are Lat: N 38.89'76", Lon: W: -77.03'66"

Geographic coordinates are a term to refer to the terrestrial reference system that allows a location to be specified by means of a series of numbers, letters or symbols.

The basic and best known geographic coordinate system worldwide specifies the following data:

To establish the geographical location of a point, the imaginary Greenwich meridian reference lines (longitude) and the equator line (latitude) must be taken into account.

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Take "to the right" to be the positive direction. By conservation of momentum,

m₁v₁ + m₂v₂ = m₁(v')₁ + m₂(v')₂

where the v-s denote initial velocities and the v'-s denote final velocities. m₁ and m₂ are of course masses, but we're told that m₁ = m₂, so we can eliminate these factors altogether:

v₁ + v₂ = (v')₁ + (v')₂

We're given that v₁ = +4.0 m/s, (v₁)' = -1.5 m/s, and (v')₂ = +4.0 m/s.

Solve for v₂ :

v₁ + v₂ = (v')₁ + (v')₂

4.0 m/s + v₂ = -1.5 m/s + 4.0 m/s

⇒   v₂ = -1.5 m/s

Explanation:

The forces acting on the rock include Normal Force, Gravitational force & Friction force

It's possible for it to stay on the boulder because the normal force balances it's weight. also because static friction acts on the boulder up to it's limiting friction even if it were on an attempt to move as a result of air resistance. gravitational forces act upon it by mainly affecting it it's weight. as altitude increases, it's weight decreases since gravity varies from a height to another.

Answer:

i think the correct answer is (a)

Answer:

it should be 1.8

Answer:

electromagnetic radiation

Hope this helps :)

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

Question Parameters:

Ladakh is 800 mb.

assuming that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level pressure we need to add,

Ps=800+350

Ps= 1150 mb

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The shift in the frequency of hydrogen line is 1.65 x 10¹² Hz.

The relationship between frequency and speed of wave is given in the following formula;

v = fλ

[tex]\frac{c}{c_o} = \frac{71.6 \times 10^5}{3 \times 10^8} = 0.00239[/tex]

The shift in the frequency of hydrogen line is calculated as follows;

[tex]0.00239 \times 6.91 \times 10^{14} = 1.65 \times 10^{12} \ Hz[/tex]

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Answer:

vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are

→

a

=

x

1

^

i

+

y

1

^

j

and

→

b

=

x

2

^

i

+

y

2

^

j

, we can find the sum of two vectors as follows.

→

a

+

→

b

=

x

1

^

i

+

y

1

^

j

+

x

2

^

i

+

y

2

^

j

=

(

x

1

+

x

2

)

^

i

+

(

y

1

+

y

2

)

^

j

The direction of the sum of the vectors (with positive x-axis) is,

θ

=

tan

−

1

(

y

1

+

y

2

x

1

+

x

2

)

Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j

Vectors are objects which have both, magnitude and direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.

Vector A = direction is in y direction = 100j

Since , this vector is only in y direction and have no component in x direction , so its x component will be = 0i

Vector B = direction is at angle of 60.0 degrees above the +x axis  

Resolving into x and y components

x component = Vector B*cos(60) = Vector B * (1/2) = Vector B /2 = 200 /2

                                                                                                           = 100i

y component = Vector B * sin(60) = Vector B  * [tex]\sqrt{3}[/tex]/2  = 173j

Vector C = direction is along the +x axis

hence , it will not have any y component

x component = 150i

y component = 0j

Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j

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So, the force of gravity that the asteroid and the planet have on each other approximately [tex] \boxed{\sf{2.9 \times 10^{17} \: N}} [/tex]

Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

[tex] \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} [/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{F = G \times \frac{m_X \times m_Y}{r^2}} [/tex]

[tex] \sf{F = 6.67 \cdot 10^{-11} \times \frac{1.55 \cdot 10^{22} \cdot 3.95 \times 10^{28}}{(3.75 \times 10^{11})^2}} [/tex]

[tex] \sf{F \approx \frac{40.84 \times 10^{-11 + 22 + 28}}{14.0625 \times 10^{22}}} [/tex]

[tex] \sf{F \approx 2.9 \times 10^{39 - 22}} [/tex]

[tex] \sf{F \approx 2.9 \times 10^{17} \: N} [/tex]

So, the force of gravity that the asteroid and the planet have on each other approximately

[tex] \boxed{\sf{2.9 \times 10^{17} \: N}} [/tex]

Answer:

9.86m/s

Explanation:

let's get to the formula

kinetic energy = 1/2*m*v^2= .5*1140*(13.6)^2=105427.2 j

it looses 50k j of energy. so new energy = 105427.2-50000 = 554227.2

again use the formula for k.e

ans = 9.86 m/s

We have that Gravity a force acting down ward against any object and frictional force is a force acting a against  movement, Hence

Generally, Gravity a force acting down ward against any object on earth at an acceleration of about  9.8m/s

and frictional force is a force acting a against the movement based on contact with another surface

Therefore

Gravity is a field force acting downward on the couch:

This is True

Friction from the carpeted floor is a contact force acting against your push.

This is True

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The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.

The amount of heat required to change 25 g of −30°C ice into 0°C liquid water is calculated as follows;

Q = mLf

where;

Q =  25 x 334

Q =  8350

Thus, the amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.

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Answer:

The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 9,887.5 J.

Answer:

[tex]a=\frac{F}{m}[/tex]

Explanation:

Just divide mass from both sides

Answer:

800 Watts

Explanation:

Power = Work/time

Working in SI units, Power = Watts, Work = Joules, Time = seconds.

Power = 2240J/2.8s = 800 Watts.

The displacement of this train is equal to 2.2 meters.

Given the following data:

To determine the displacement of a train:

Mathematically, the displacement of an object is given by this formula:

[tex]d = \frac{V\;+\;U}{t}[/tex]

Where:  

Substituting the given parameters into the formula, we have;

[tex]d = \frac{33\;+\;11}{20}\\\\d = \frac{44}{20}[/tex]

d = 2.2 meters.

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Answer:

True

Explanation:

If amplitudes are equal, high frequency waves carry more energy than low frequency waves.

Answer:

Warm colours are those with a yellow-ish or black undertone. Imagine how everything looks through your tinted sunglasses or on a beautiful day in autumn when the leaves are falling. The hints of yellow give these colours a sunny warmth, while those with more black mixed in appear darker and can seem more muted.

Answer:

Salt water

Explanation:

This is the answer

Answer:

B)

translucent

Hope this helps♡♡♡

This is the correct answer

The  magnitude of the electric field strength at that position  is 2.6×10⁴ Newton/Coulomb.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields.

Given parameters:

Charge of the point charge: Q = 4.2 × 10⁻⁶ Coulomb.

Distance of the position from the position: r = 1.2 meter.

The  magnitude of the electric field strength at that position = kQ/r²

= 9 × 10⁹ × 4.2×10⁻⁶/(1.2)² Newton/coulomb.

= 2.6×10⁴ Newton/Coulomb.

Hence, the  magnitude of the electric field strength at that position  is 2.6×10⁴ Newton/Coulomb.

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