If he starts at 1 and jumps 3 units to the right, then where is he on the number line? How far away from zero is he? (explain how you got the answer)

Answer:

321%

Step-by-step explanation:

hope I helped Kkkkkkkk

Answer:

the answer of this question is......

I think 134

but I can't explain that

I'm so sorry

:-/

Answer:

141

Step-by-step explanation:

This is a seven-sided pentagon. We can find the total sum of all the angles in the pentagon first.

Sum of angles in a pentagon = (7-2) × 180

                                                = 5 × 180

                                                = 900

∠B = 900 - 148 - 90 - 142 - 130 - 129 - 120

     = 141

Remember:

Formula of sum of angles in pentagon = (n-2) × 180 where n is the number of sides the pentagon has. Hope this helps :)

Answer:

-1/3

Step-by-step explanation: it goes downwards from left to right so it is a negative and to reach the next line below it, it went to the right 3 units.

Therefore it is -1/3 :)

Answer:

5.9125in^2

Step-by-step explanation:

Step one:

Given data

Dimension of square= 5.25 in

Area of sqaure= 5.25^2= 27.5625  in^2

We are told that the sides of the circle touch the sides of the square

hence the diameter of the circle is 5.25in

radius= 5.25/2= 2.625 in

Area of  circle= πr^2

Area of circle = 3.142*2.625^2

Area of circle=3.142*6.890625

Area of circle= 21.65 in^2

Step two:

The area that is not inside the circle

=Area of square-Area of circle

=27.5625- 21.65

=5.9125in^2

Answer:

19.4

Step-by-step explanation:

16^2+11^2=377

then square 377 which will equal to

19.416 which can be rounded up to 19.4

A triangle that has 2 sides congruent is called an isosceles triangle.

A triangle that has all 3 sides congruent is called an equilateral triangle.

I have attached a picture below which will help you.

If you want me to simplify this is the answer.... 6a^2-a-35

Answer: I think it is 25.5ft

Answer:

[tex]\mathrm{Domain\:of\:}\:\frac{x-1}{x+3}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<-3\quad \mathrm{or}\quad \:x>-3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-3\right)\cup \left(-3,\:\infty \:\right)\end{bmatrix}[/tex]

Therefore, the 4th option i.e. (−∞, −3) (−3, ∞) is the correct answer.

Step-by-step explanation:

Given the expression

[tex]f\left(x\right)=\frac{x-1}{x+3}[/tex]

We know that the domain is the set of all the input or argument values for which is the function is real and defined.

From the given expression, we need to make sure the denominator of a rational function can be anything but 0, because 0 would make the function undefined.

Thus, we need to find undefined points such as:

x+3 = 0

x = -3

Therefore, the function domain must be:

x < -3 or x > -3

In other words,

[tex]\mathrm{Domain\:of\:}\:\frac{x-1}{x+3}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<-3\quad \mathrm{or}\quad \:x>-3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-3\right)\cup \left(-3,\:\infty \:\right)\end{bmatrix}[/tex]

Therefore, the 4th option i.e. (−∞, −3) (−3, ∞) is the correct answer.

Answer:

the first step in solving an equation with a variable on each sides is to get the variable on one side. This is done by reversing the addition or subtraction of one of the terms with the variable.

Step-by-step explanation:

Answer:

dy/dx

= d/dx [2x² + 5x - 3]

= 4x + 5.

Hence at x = 1, dy/dx = 4(1) + 5 = 9.

The slope of the tangent is 9.

d/dx (3/x)

= d/dx (3x^-1)

= 3 * d/dx (x^-1)

= 3 * [-1 * x^(-2)]

= -3/x².

[tex]\bold{\sqrt{a-b+c}=3 }[/tex]

[tex]\bold{(\sqrt{a-b+c)}^2=3^2 }[/tex]

[tex]\bold{ a-b+c=9 }[/tex]

[tex]\bold{ a=9+b-c }[/tex]

Answer:

41*

Step-by-step explanation:

Answer:

[tex]y=-x+15[/tex]

Step-by-step explanation:

Slope-intercept form is written as [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept.

Any line perpendicular to a given line with slope [tex]m[/tex] has a slope of [tex]-\frac{1}{m}[/tex]. Therefore, the slope of a line perpendicular to [tex]y=x+12[/tex] is [tex]-\frac{1}{1}=-1[/tex].

We can now plug the coordinate it passes through into our slope-intercept form equation to solve for the y-intercept:

[tex]3=-1(12)+b,\\b=15[/tex]

Therefore, the equation of the line that is perpendicular to [tex]y=x+12[/tex] and passes through the coordinates [tex](12,3)[/tex] is [tex]\fbox{$y=-x+15$}[/tex].

Answer:

This was on my test

Step-by-step explanation:

lol

Answer:

12 centimeters

Step-by-step explanation:

30/2.50 is 12

Answer:

78

Step-by-step explanation:

Answer:

the answer is C

Step-by-step explanation:

hope this helps you

.82×23.7=19.434

Answer:

D

Step-by-step explanation:

step 1: Simplify 82/100 to its simplest form to by two to get 41/50

Step 2: multiply 41 by 23.7

41×23.7= 1971.7

Step 3: Divide 1971.7÷50=19.434

to the nearest hundredths =

19.4

Answer:

=106

Step-by-step explanation:

PMDAS

First thing you do is the parenthesis

6+4(5)^2

then the exponent

6+4(25)

then multiply

6+100

then add

106

Hope this helps (:

Answer:

150

Step-by-step explanation:

First do what is in the parenthesis:

(2+3)

(6)

Then exponents:

[tex](6)^{2}[/tex]

(36)

Then Multiplication:

4(36)

144

Then Add:

144+6

150

8x-4y=24

sub 8x from both sides

-4y=24-8x

sub 24

-4y-24=-8x

add -4y

-24=4y=8x

Answer:

y=2x-6

Step-by-step explanation:

First isolate the variable. You're trying to find y, so you need to ultimately leave y by itself.

8x-4y=24

Subtract 8x from both sides to cancel out the 8.

You should have the equation below left:

-4y= -8x+24

Now, divide everything by negative for so that you are only left with the y.

You should have the equation below left.

y=2x-6

I hope this helped:)

Answer:

[tex]k>-3[/tex]

Step-by-step explanation:

We have the equation:

[tex]-3x^2-6x+k=0[/tex]

Where a = -3, b = -6, and c = k.

And we want to determine values of k such that the equation will have real, unequal roots.

In order for a quadratic equation to have real, unequal roots, the discriminant must be a real number greater than 0. Therefore:

[tex]b^2-4ac>0[/tex]

Substitute:

[tex](-6)^2-4(-3)(k)>0[/tex]

Simplify:

[tex]36+12k>0[/tex]

Solve for k:

[tex]12k > -36[/tex]

[tex]k>-3[/tex]

So, for all k greater than -3, our quadratic equation will have two real, unequal roots.

Notes:

If k is equal to -3, then we have two equal roots.

And if k is less than -3, then we have two complex roots.

Answer:

[tex]\mathrm{A.\:}x+2y=a[/tex]

Step-by-step explanation:

In standard form [tex]ax+by=c[/tex], any point the line passes through will make the inequality true. We can simply use any point given to find the equation of the line:

We can write the following system of equations from two points from the table:

[tex]\begin{cases}d\cdot3a+e\cdot(-a)=f\cdot a\\d\cdot5a+e\cdot(-2a)=f\cdot a\end{cases}[/tex]

Solving, we get:

For [tex]a \notin 0[/tex],

[tex]d=1,\\e=2,\\f=1[/tex]

Therefore, our equation is:

[tex]dx+ey=fa,\\1x+2y=1a,\\\fbox{$x+2y=a$}[/tex].

Answer:

Ah I see it's the same it's a little more complex but I can do this as well.

But I can't type bcoz it will make it slow

so I'll write for this.ß

Answer:

[tex]0.6x - 0.1x = 7 + 5 \\ 0.5x = 12 \\ x = \frac{12}{0.5} = 24[/tex]

Answer:

x equals 3 so multiply 3x3 and it will give you 9 and add that to 6 and you get 15. x equals 3 for the one that equals 5.

Answer:

3x + 16 = 15

3x = 15-16

3x = -1

x = -1/3

Answer:

no

Step-by-step explanation:

Using the converse of Pythagoras' identity.

If the square of the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.

longest side = 81

81² = 6561

13² + 80² = 169 + 6400 = 6569

Since 6561 ≠ 6569 then they do not form a right triangle

Using reverse Pythagoras theorem, the three sides of lengths of triangle does not form right triangle.

Reverse Pythagoras theorem states that "the square of the longest side is equal to the sum of the squares on the other two sides then the triangle is right triangle".

A triangle in which "one angle is 90° and the other two sides are perpendicular to each other is called right triangle."

According to the question,

Three sides lengths of triangle 13, 80 and 81. In order to find this triangle is right triangle or not.

Let a = 13, b=80, and c = 81

Reverse Pythagoras theorem  c² = a² + b²

(81)² = (13)² + (80)²

6561 = 169 + 6400

6561 ≠ 6569

Hence, using reverse Pythagoras theorem, the three sides of lengths of triangle does not form right triangle.

Learn more about reverse Pythagoras theorem here

https://brainly.com/question/343682

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