What is the ratio of 20 praise and 2000 rupees
Answer:
1 rupee=100 paisa
so, 20 paisa:2000 rupees
=>20 paisa:2000×100
=>1:10000.
Tabithas living room is rectangle that measures 19 3/4ft by 12ft find the perimeter and the area of the room
Answer:
237ft²
63.5ft
Step-by-step explanation:
Given parameters:
Length = 19[tex]\frac{3}{4}[/tex] ft
Width = 12ft
Unknown:
Area of rectangle = ?
Perimeter of rectangle = ?
Solution:
Area of rectangle = length x width
= 19[tex]\frac{3}{4}[/tex] x 12
= [tex]\frac{79}{4}[/tex] x 12
= 79 x 3
= 237ft²
Perimeter of rectangle = 2(length + width)
= 2 (19.75 + 12 )
= 63.5ft
What is the least common denominator of 2/3, 1/6 and 11/12
Answer:
2/3 = 8/12
1/6 = 2/12
11/12 = 11/12
help please !!!!!!!!!!!!!
Answer:
f(4)= -10
If g(x) =2, then x=0
Step-by-step explanation:
help im confused..........
Answer:
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Step-by-step explanation:
fdcopjsfddcaxjefwpojdsjandipewhhqdaspcixpjewfs;odkcnewoasjjncikkjasn;kcjnnsixjfiasxhcjnsdaxo[okckiefihihehabficphbkjckd khksdk a help me
Answer:
lol im confused aswell
Step-by-step explanation:
In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as the overall proportion of complaints settled in 2008
a. Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of .
b. Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion?
c. Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of .
d. Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion?
e. As measured by the increase in probability, how much do you gain in precision by taking the larger sample in part (b)?
Answer:
Explained below.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
[tex]\mu_{\hat p}= p[/tex]
The standard deviation of this sampling distribution of sample proportion is:
[tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]
(a)
The sample selected is of size n = 450 > 30.
Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.
The mean and standard deviation are:
[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204[/tex]
So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0204^{2})[/tex].
(b)
Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:
[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0204}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0204})[/tex]
[tex]=P(-1.96<Z<196)\\=P(Z<1.96)-P(Z<-1.96)\\=0.975-0.025\\=0.95[/tex]
Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.
(c)
The sample selected is of size n = 200 > 30.
Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.
The mean and standard deviation are:
[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306[/tex]
So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0306^{2})[/tex].
(d)
Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:
[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0306}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0306})[/tex]
[tex]=P(-1.31<Z<196)\\=P(Z<1.31)-P(Z<-1.96)\\=0.9049-0.0951\\=0.8098\\\approx 0.81[/tex]
Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.
(e)
The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.
And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.
So, there is a gain in precision on increasing the sample size.
With the money she had saved by working, Jennifer wanted
Answer:a car
Step-by-step explanation:
Sofia is creating a budget to save $120 for a week of soccer camp. She earns money by working as a mother's helper on Saturday mornings and Wednesday afternoons. She earns $20 each time she works. She wants to save $7.50 a week for the camp. Her mother wants her to save $5 a week for college. She is planning on spending $5 a week for snacks and $5 a week for entertainment.
Answer:
18 weeks
Step-by-step explanation:im gay
I need help with 15-19 plz
Here,
g (x) = -3x + 1
then ,
g(10) = -3 (10) + 1
= -30 +1
= - 29
Again,
g(-6) = -3 (-6) + 1
= 18 + 1
= 19
Complected *******
Thank me later.
Find the area of the circle look no
Area of a complete circle is area = pi x r ^2
Area = 3.14 x 4^2
Area = 3.14 x 16
Area = 50.24 square units.
1/4 of the circle is missing, so multiply the area of the full circle by 3/4:
50.24 x 0.75 = 37.68 cubic units.
What is 11/9 as a decimal?
Write the product using exponents.
(-4).(-4).(-4).y.y
Answer:
(-4)^3 * y^2
Step-by-step explanation:
hope it helps.
The question I need help in is the middle one. PLEASE I NEED ANDWER ASAP!
Answer:
3.25
Step-by-step explanation:
I plugged in 5 for x and got 3.25 when I solved
Which expression is equivalent to i233?
Answer:
radical sign of -233
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have to find the value of the expression i^{233}i
233
We know that the below values.
i
2
=−1
i
4
=1
Hence, in order to find the value of the given expression, we can first rewrite it in terms of i^4i
4
i^{233}=(i^4)^{58}
233
=(i
4
)
58
⋅i
Now, we know that i^4=1i
4
=1
Hence, we have
i^{233}=(1)^{58}
233
=(1)
58
⋅i
i^{233}=
233
=1⋅i
i^{233}=ii
233
=i
what is 2/16 as a decimal
what is the value of x,if x=9-9/4
Answer:
X=6 3/4
Step-by-step explanation:
IF X=9-9/4(X=9-2 1/4) THEN X=6 3/4. HOPE THIS HELPS
how to simplify 2a³ × a⁴
Answer:
2a⁷
Step-by-step explanation:
you have to add 3 to 4
An ice sculpture is melting at a constant rate. Its weight changes -1 4/5 pounds every hour. What is the total change in weight of the sculpture after 3 1/2 hours
Answer:it said i was wrong and the correct answer should have been -6 3/10
Step-by-step explanation:
The total change in weight of the sculpture after [tex]3\frac{1}{2}[/tex] hours is, [tex]\bold{-6\frac{3}{10}}[/tex] pounds.
What is rate of change of function?"The rate of change function is the rate at which one quantity is changing with respect to another quantity."
Given: The weight of an ice sculpture changes [tex]-1\frac{4}{5}[/tex] pounds every hour.
We need to find the total change in weight of the sculpture after [tex]3\frac{1}{2}[/tex] hours.
i.e., the rate of change of an ice sculpture per hour is -1 4/5 pound.
Total change in weight of the sculpture after t hours
= change in the weight of the sculpture per hour × t
= [tex](-1\frac{4}{5}) \times (3\frac{1}{2} )[/tex]
= [tex](-\frac{9}{5} ) \times (\frac{7}{2} )[/tex]
= [tex]-\frac{63}{10}[/tex]
= [tex]\bold{-6\frac{3}{10}}[/tex] pounds
Therefore, the total change in weight of the sculpture after 3 1/2 hours is, [tex]\bold{-6\frac{3}{10}}[/tex] pounds.
Learn more about rate of change here:
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Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}] $$
Answer:
[tex]\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}[/tex]
Step-by-step explanation:
Given that:
[tex]\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7][/tex]
The rectangle R = [0,1] × [0,7]
R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }
R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy[/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy[/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy[/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy[/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy[/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)][/tex]
[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1][/tex]
[tex]\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}[/tex]
n= 9c-80 solve for c. if n= 19 what is the value of c?
Answer:
Step-by-step explanation:
n = 9c - 80
n = 19
19 = 9c - 80
-9c = -80 - 19
-9c = -99
c = 99 / 9
c = 11
Hope this helps
plz mark as brainliest!!!!!!
This need help jxb...
Answer:
That would be y = 2x.
!!!TIME LIMIT PLZ HURRY!!!Which describes the relationship between <1 and <2?
Answer:
adjacent
Step-by-step explanation:
this just means they are next to each other, like they share a ray
Answer:
they are adjacent
Step-by-step explanation:
Adjacent means they are next to each other; and both these angles are right beside each other
Please help with question plaaseeee
Answer:
Yes it is.Step-by-step explanation:
The graph is proportional because
it is in a straight line in the graph.
Hope this helps! <3
Given the function d (t) = 50t, the variable t represents which of the following
Output
Independent variable
Function
Input
Depended variable
Answer:
The input of the function
Step-by-step explanation:
Find the unit rate for each of the following tables
Answer:
First table's unit rate is -1.6
Second table's unit rate is 3.5
Step-by-step explanation:
First table:
[tex]\Delta y/\Delta x =(-16--8)/(10-5)= -8/5[/tex]
and this is constant for any pair of (x, y) values of the table.
So the unit rate is: -8/5 = -1.6
Second table:
[tex]\Delta y/\Delta x =(21-7)/(6-2)=14/4=7/2[/tex]
and the rate is constant for any pair of (x, y) values of the table.
So the unit rate is: 7/2 = 3.5
Let z = 9 – 2i and zw = 25 + 70i.
What is w?
1 + 8i
1 – 8i
–1 + 8i
–1 – 8i
Answer:
1+8i
Step-by-step explanation:
Given, complex numbers z = 9 – 2i and zw = 25 + 70i. w = 1 + 8i.
What are complex numbers?In mathematics, a complex number is an element of a number system that contains the real numbers and a specific element denoted i, called the imaginary unit, and satisfying the equation i² = −1.
= (9 - 2i)(1 + 8i)
= 9 + 72i - 2i -16i^2
= 9 + 70i + 16 (i^2 = -1)
= 25 + 70i
Learn more about complex numbers here
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the missing number in the series?
4, 18, ?, 100, 180, 294, 448
A) 48
B) 50
C) 58
D) 60
An object is moving at a speed of 6 miles per month. Express this speed in feet per hour.
Answer:
44 ft/hr
Step-by-step explanation:
First, we convert miles to feet.
6 mi*5280 = 31680 feet
Now we convert a month to hours. For this question, lets say that a month is equal to 30 days.
30*24 hrs = 720 hrs
Now we have this speed -
31680 ft/720 hrs
Now we simplify this to -
44 ft/hr
So in conclusion, the speed of 6 miles per month is equivalent to the speed of 44 feet per hour.
Determine the ordered pair that satisfies the equation, -5x - 6y = -8.
Answer:
-2&-4
Step-by-step explanation:
-5x-6y=-8
it is a quadratic equation:
-5x-6y+8=0
(x-2)(x-4)
cross multiple and you'll get
-5x-6y+8=0
The cost of making a phone is $152. A store sells the phone for $281.20 select all the the expressions that could be used to find the percentage of markup for the ohone
Answer:
[tex]\frac{100 * (281.20 - 152)}{152}[/tex][tex](\frac{281.20}{152}-1 ) * 100[/tex]Step-by-step explanation:
The above two expressions can be used to find the percentage of mark-up for the phone.
The first expression for instance will give;
[tex]= \frac{100 * (281.20 - 152)}{152}\\\\= \frac{12,920}{152}\\\\= 85[/tex]
= 85%
The second expression will give;
[tex]= (\frac{281.20}{152}-1 ) * 100\\\\= 0.85 * 100\\\\= 85[/tex]
= 85%
Both of them will show that an 85% mark-up has been added to the cost of the phone.