IF B-p'ap and x is an eigenvector of A corresponding to an eigen value then Pox is an eigen vector of B also associated with X

Answers

Answer 1

Px is an eigenvector of B corresponding to λ.

Given B- p'ap and x is an eigenvector of A corresponding to an eigen value then Pox is an eigen vector of B also associated with X.

Proof: Let A be a square matrix and x be an eigenvector of A corresponding to an eigenvalue λ.

Then Ax = λx.

Let P be an invertible matrix.

Then P-1AP is a similar matrix to A.

Therefore, it has the same eigenvalues as A and eigenvectors that are related to those eigenvalues in the same way as the eigenvectors of A.

In particular, Px is an eigenvector of P-1AP corresponding to λ.

Px = P-1AP(Px) = P-1A(Px).

But Px is an eigenvector of P-1AP corresponding to λ, so P-1AP(Px) = λPx.So P-1A(Px) = λPx.

This shows that P(P-1APx) = λ(Px), which implies that APx = λPx.

Therefore, PAPx = P(λx) = λ(Px), which shows that Px is an eigenvector of PAP corresponding to λ.

Let B = P-1AP and q = Px.

Then Bq = P-1AP(Px) = P-1A(Px) = λPx = λq.

This shows that q is an eigenvector of B corresponding to the eigenvalue λ.

Therefore, if B = P-1AP and x is an eigenvector of A corresponding to an eigenvalue λ, then Px is an eigenvector of B corresponding to λ.

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Related Questions

What is the domain and range of this graph?
(Pls don’t answer if you don’t know I rly need help<3 )

Answers

Answer:

Domain is all real numbers. Range is [36- negative infinity]

Tema: valor numérico de expresiones algebraicas
A= 2
B= 1
X= 3
Y= 5
Z= -3

Answers

Answer:

1. 61

2. -8

3. 731

4. -16

5. -5

Step-by-step explanation:

Find the parametric equations for the circle with radius 4 and centered at (-3,4) circle traced clockwise starting at (-3,0). include the domain.

Answers

The parametric equations for the circle with radius 4 and centered at (-3,4), traced clockwise starting at (-3,0), are x = -3 + 4cos(t) and y = 4 + 4sin(t), where t is the parameter representing the angle of rotation. The domain for these equations is 0 ≤ t ≤ 2π.

To obtain the parametric equations for the circle, we start by considering the general equation of a circle centered at (h,k) with radius r:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

In this case, the circle is centered at (-3,4) and has a radius of 4, so the equation becomes:

[tex](x + 3)^2 + (y - 4)^2 = 16[/tex]

To represent the circle parametrically, we can use the trigonometric functions cosine and sine to describe the x and y coordinates, respectively. We can rewrite the equation as:

(x + 3) = 4cos(t)

(y - 4) = 4sin(t)

Simplifying, we obtain:

x = -3 + 4cos(t)

y = 4 + 4sin(t)

These equations describe the x and y coordinates of points on the circle as a function of the angle t. The parameter t represents the angle of rotation around the circle. To trace the circle clockwise, we need to assign decreasing values to t. The domain for t is 0 ≤ t ≤ 2π, which corresponds to a full revolution around the circle.

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A sphere has a radius of 9 feet. A second sphere has a radius of 6 feet. What is the difference of the volumes of the spheres? The volume of the larger sphere is π cubic feet greater than the volume of the smaller sphere.

Answers

Answer:

684 π

Step-by-step explanation:

volume of a sphere = (4/3) x (n) x (r^3)

n = 22/7

r = radius

volume of larger sphere

4/3 x n x 9³ = 972 n

4/3 x n x 6³ =288n

972n - 288n = 684n

Rico and Darla each measured a side and height on the triangle below to find its area.
Rico’s side measured 7.5 m and Darla’s side measured 9 m.
Choose True or False for each statement.

A triangle with two base and side length measurements. One side length is nine meters, and the height from that side is five meters. The other side length is seven and five-tenths meters and the height from that side is six meters.
Darla can use either the height of 6 meters or the height of 5 meters to find the area of the triangle.
Choose...

If Darla uses the height of 6 meters and Rico uses the height of 5 meters, they will find the same area of the triangle.
Choose...

If Rico uses the height of 6 meters and Darla uses the height of 5 meters, they will find the same area of the triangle.
Choose...

The area of the triangle is 22.5 square meters.
Choose...

Answers

Answer: not sure

Step-by-step explanation:

x-4.88=-5.78

solve for x

Answers

Answer:

-0.9

Step-by-step explanation:

Answer:

x =-.9

Step-by-step explanation:

x-4.88=-5.78

Add 4.88 to each side

x-4.88+4.88=-5.78+4.88

x =-.9

State the name of the property illustrated. 2 + (6 + 4) = (2 + 16 + 74 () A Associative O Distributive Commutative o Both associative and commutative

Answers

The property which is represented in the equation : "2 + (√6 + √4) = (2 + √6) + √4" is (a) Associative.

The "Associative-Property" is a fundamental property of addition that states that the grouping of numbers being added does not affect the sum. In other words, when adding three or more numbers, the way they are grouped does not change the result.

In the given equation : 2 + (√6 + √4) = (2 + √6) + √4, we see that the numbers (√6 + √4) and (2 + √6) are grouped differently, but the sum remains the same. This is because the associative property , which allows us to rearrange the brackets and change the grouping without affecting the final result.

Therefore, the correct option is (a).

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The given question is incomplete, the complete question is

State the name of the property illustrated : 2 + (√6 + √4) = (2 + √6) + √4

(a) Associative

(b) Distributive

(c) Commutative

(d) Both associative and commutative.

wildlife biologists believe that the weights of adult trout can be described by a normal model with a standard deviation of 1.2 pounds. if only 7% of adult trout weigh more than 5 pounds what is the mean weight (in pounds) of adult trout?

Answers

The mean weight of adult trout is 3.224 pounds is the answer.

Given, A normal model is used to describe the weights of adult trout, with a standard deviation of 1.2 pounds. It is known that only 7% of adult trout weigh more than 5 pounds.

To calculate the mean weight (in pounds) of adult trout, the following steps need to be followed:

Step 1: Find the z-score for the given percentage value.

The z-score formula is given by: z = (x - μ) / σ where x is the value of the variable, μ is the mean, and σ is the standard deviation.

Step 2: Once we have the z-score, we can find the corresponding value of x using the z-score table.

We need to find the z-score corresponding to the 93rd percentile as only 7% of the trout weigh more than 5 pounds.z = (x - μ) / σ

For a one-tailed distribution with α = 0.07, the z-score is 1.48, approximately.

Therefore, we have1.48 = (5 - μ) / 1.2Multiplying both sides by 1.2, we get1.776 = 5 - μ

Subtracting 5 from both sides, we getμ = 5 - 1.776μ = 3.224

Therefore, the mean weight of adult trout is 3.224 pounds.

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An analyst studied the average savings of recent college graduates. The results of the study reveal the following: n=40, sample mean = $16,000, sample standard deviation = $5,000. The probability that a randomly selected recent graduate has savings of $18,000 or more is closet to Hint: You need to calculate a z-score and remember to use the standard error in your calculations more than 5% less than 1% about 95% about 68%.

Answers

If The results of the study reveal that n=40, sample mean = $16,000, and sample standard deviation = $5,000 then the probability is about 65.54%.

To calculate the probability that a randomly selected recent graduate has savings of $18,000 or more, we first need to calculate the z-score using the formula z = (x - μ) / σ, where x is the value we're interested in, μ is the mean, and σ is the standard deviation. In this case, x = $18,000, μ = $16,000, and σ = $5,000.

Substituting these values into the formula, we get z = (18,000 - 16,000) / 5,000 = 0.4.

Next, we can use a z-table or calculator to find the corresponding probability.

Looking up the z-score of 0.4 in the z-table, we find that the probability is approximately 0.6554, or about 65.54%.

Therefore, the probability that a randomly selected recent graduate has savings of $18,000 or more is approximately 65.54%.

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Which null distribution is used for a hypothesis test of a single population proportion? Select one: O a. t-distribution with df = n - 1 O b. standard normal distribution O c. t-distribution with df = n1 + n2 – 2

Answers

The null distribution used for a hypothesis test of a single population proportion is the standard normal distribution. The correct answer is b).

When conducting a hypothesis test for a single population proportion, we use the standard normal distribution as the null distribution. This is based on the assumption that the sampling distribution of the sample proportion follows a normal distribution when the sample size is sufficiently large.

The hypothesis test for a single population proportion involves comparing the observed sample proportion to the hypothesized population proportion. We calculate the test statistic, which is the standard error of the sample proportion under the null hypothesis, divided by its standard deviation.

Since the test statistic follows a normal distribution under the null hypothesis, we compare it to critical values from the standard normal distribution to determine the p-value and make a decision regarding the null hypothesis.

Therefore, correct option is B.

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A concrete slab has the dimensions 4 yd by 2 yd by 1.2 yd. What is the volume of 40 of these concrete slabs

Answers

The volume of 40 of the concrete slabs given the dimensions of one  concrete slab is 384 yd³.

What is the volume of one  concrete slab?

The concrete slab has the shape of a rectangular prism. So, the volume of a rectangular prism would be used to determine the volume of the  concrete slabs.

Volume of one  concrete slab = length x width x height

4 x 2 x 1.2 = 9.6 yd³

Volume of 40  concrete slabs = 40 x 9.6 = 384 yd³

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the area is ___ square units​

Answers

Answer:

12 units²

Step-by-step explanation:

The height is 2, and the width is 12.

Now multiply and that gives us 24. But that's not the full answer.

Since a triangle's area is half of a square, we divide by 2, leaving us with 12. (plus the label which is units²)

Angle 5 Has what angle


A.alternate interior angle

B.alternate exterior angle

C.same side interior angle

Answers

the answer is B alternate exterior angle

PLEASE HELP FAST I WIL MARK BRAINLIEST

Answers

Answer: AB = 15 because sides AB and AD are congruent

Step-by-step explanation:

Find the general solution to the homogeneous system of DE: -11 x' = Ax where A = [-26 41 Hint: Write your answer x(t) in the form of eat [cos(ht) + sin(bt)].

Answers

The general solution to the homogeneous system of differential equations is:

x(t) = c₁ * [tex]e^{(-7t)[/tex] * | 4 | + c₂ * [tex]e^{(-20t)[/tex] * | 2 |

                                                        |-1 |

where c₁ and c₂ are constants.

To find the general solution to the homogeneous system of differential equations -11x' = Ax, where A = [-26 4; 1 1], we first need to find the eigenvalues and eigenvectors of matrix A.

To find the eigenvalues, we solve the characteristic equation:

det(A - λI) = 0

Substituting the values, we get:

| -26-λ 4 |

| 1 1-λ |

Expanding the determinant, we have:

(-26-λ)(1-λ) - 4 = 0

Simplifying and solving the equation, we find the eigenvalues:

λ₁ = -7

λ₂ = -20

Next, let's find the corresponding eigenvectors.

For λ₁ = -7:

(A + 7I)v₁ = 0

| -19 4 |

| 1 8 |

Solving the system of equations, we find the eigenvector corresponding to λ₁:

v₁ = | 4 |

      |-1 |

For λ₂ = -20:

(A + 20I)v₂ = 0

| -6 4 |

| 1 21 |

Solving the system of equations, we find the eigenvector corresponding to λ₂:

v₂ = | 2 |

      |-1 |

Now that we have the eigenvalues and eigenvectors, we can write the general solution to the system of differential equations as:

Substituting the values of the eigenvalues and eigenvectors, we get:

x(t) = c₁ * [tex]e^{(-7t)[/tex] * | 4 | + c₂ * [tex]e^{(-20t)[/tex] * | 2 |

                                                        |-1 |

Simplifying this expression, we get:

x(t) = | 4c₁ * [tex]e^{(-7t)[/tex] + 2c₂ * [tex]e^{(-20t)[/tex] |

|-c₁ * [tex]e^{(-7t)[/tex] - c₂ * [tex]e^{(-20t)[/tex]) |

Therefore, the general solution to the homogeneous system of differential equations is:

x(t) = c₁ * [tex]e^{(-7t)[/tex] * | 4 | + c₂ * [tex]e^{(-20t)[/tex] * | 2 |

|-1 |

where c₁ and c₂ are constants.

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Can someone plzzz helppp meee!!!

Answers

Answer:

Step-by-step explanation:

what is the value of x ?​

Answers

Step-by-step explanation:

The line JK is tangent to the circle h so <KJH is a right angle.

[tex]a^2+b^2=c^2[/tex]

[tex]15^2+20^2=x^2[/tex]

[tex]625=x^2\\x=25[/tex]

Hope that helps :)

the same thing as the other person is correct x=25

Solve the following recurrence relations (a) [6pts] an = 3an-2, Q1 = 1, 42 = 2. b) [6pts] an = an-1 + 2n – 1,01 = 1, using induction (Hint: compute the first few terms, = pattern, then verify it).

Answers

a) an = 3(n-2) if n is even and an = 3(n-3) if n is odd

b)  It is proved that an = n².

a)Given recurrence relation is an = 3an-2, Q1 = 1, Q2 = 2.  

We have to find an in terms of n.

Step 1: Finding the pattern

Let us find the values of a1, a2, a3 and a4  a1 = Q1 = 1, a2 = Q2 = 2, a3 = 3, a1 = 3, a4 = 3a2 = 3 x 2 = 6

Let us represent it as a table

Step 2: Writing the general expression

The sequence obtained is an = 1, 2, 6, 18, 54, …We can see that an = 3an-2

If n is even, then an = 3(n-2)

If n is odd, then an = 3(n-3)

Step 3: Writing the final expression

The general expression of an is as follows:

an = 3(n-2) if n is even and an = 3(n-3) if n is odd

b) Given recurrence relation is an = an-1 + 2n – 1, a1 = 1, using induction

Let us prove that an = n² by induction

Step 1: Verification of base case

When n = 1an = a1 = 1

We have to prove that a1 = 12 an = n2 = 1

Therefore, the base case is verified.

Step 2: Let us assume that an = n2 is true for some k such that k > 0i.e., ak = k² (Inductive Hypothesis)

Step 3: Let us verify that an = n2 is true for n = k+1i.e., prove that ak+1 = (k+1)²

Using the recurrence relation given, we haveak+1 = ak + 2k+1 – 1 = k2 + 2k + 1 = (k+1)²

Therefore, the proof is complete. It is proved that an = n².

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Can someone please help

Answers

okay sorry

Step-by-step explanation:

i just wanted point

Mr. White is renting an oversized truck for one week and a few additional days d. He does not have to pay a per mile fee. Evaluate the expression 325+100d to find how much he will pay for a 13-day rental. Each day = $100

Answers

Answer:

$1,625

Step-by-step explanation:

Given:

Total cost = 325 + 100d

Where,

325 = fixed cost

100 = cost per day

d = number of days

Find the total cost when d = 13 days

Total cost = 325 + 100d

= 325 + 100d

= 325 + 100(13)

= 325 + 1,300

= 1,625

Total cost = $1,625

Write an equation in point slope form that is parallel to AB with endpoints A (2, -1) and B (4, 5) that goes through the point (1.5, 4)

Answers

Answer:

[tex]y = 3x - 0.5[/tex]

Step-by-step explanation:

Given

Goes through

[tex]C = (1.5,4)[/tex]

Parallel to AB

[tex]A = (2,-1)[/tex]

[tex]B = (4,5)[/tex]

Required

Determine the line equation

First, calculate the slope of AB

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{5--1}{4-2}[/tex]

[tex]m = \frac{6}{2}[/tex]

[tex]m = 3[/tex]

The line is said to be parallel to AB. This implies that their slopes are equal.

The equation of the line is then calculated as:

[tex]y = m(x - x_1) + y_2[/tex]

Where:

[tex](x_1,y_1) = (1.5,4)[/tex]

So:

[tex]y = 3*(x - 1.5) + 4[/tex]

[tex]y = 3x - 4.5 + 4[/tex]

[tex]y = 3x - 0.5[/tex]

According to the central limit theorem, which of the following statements is true?
a. The distribution of the sum (or average) of a large number of independent, identically distributed variables will be approximately normal, regardless of the underlying distribution.
b. The center of a distribution is limited to move no more than 1.5 standard deviations (also known as the 1.5 sigma shift).
c. The center of dispersion of a sample (
) is limited by the size of the sample.
d. The central tendency of a distribution is limited by common-cause variation.

Answers

The central limit theorem,option (A) is correct

According to the central limit theorem, the following statement is correct:

a. Regardless of the underlying distribution, the distribution of the sum (or average) of a large number of independent variables with identical distributions will be approximately normal.

Regardless of the original distribution's shape, the central limit theorem states that independent and identically distributed variables tend to approximate a normal distribution when added together or averaged. We are able to draw conclusions about the parameters of the population based on the statistics of the sample because this is one of the fundamental principles of statistical inference.

The central limit theorem is unrelated to the other statements (b, c, and d). Statements b, c, and d all refer to common-cause variation rather than the central limit theorem, while statement d does not accurately describe the central limit theorem.

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Which measurements are less than 475 ​inches?

Answers

Can you give me options ?

True or false: On average, eta-squared, partial eta-squared, and R-squared are all measures of effect size that refer to the proportion of variance explained within a study.

Answers

The statement that eta-squared, partial eta-squared, and R-squared are all measures of effect size that refer to the proportion of variance explained within a study. This statement is true.

In order to better understand what eta-squared, partial eta-squared, and R-squared are, we must first understand what the proportion of variance explained is. The proportion of variance explained refers to the amount of variation in one variable that is accounted for by another variable or variables. All three of these measures are measures of effect size, which means they are used to determine the strength of the relationship between two variables. They also all refer to the proportion of variance explained within a study. However, they differ in terms of how much variance they account for. Eta-squared is a measure of effect size that is used in ANOVA to determine the proportion of variance in the dependent variable that is accounted for by the independent variable. Partial eta-squared, on the other hand, is used to determine the proportion of variance that is accounted for by the independent variable when controlling for other variables.

Finally, R-squared is a measure of effect size that is used in regression analysis to determine the proportion of variance in the dependent variable that is accounted for by the independent variable.

In conclusion, all three of these measures of effect size are used to determine the proportion of variance explained within a study.

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Figure 222 is a scaled copy of Figure 111.

Identify the side in Figure 222 that corresponds to side \overline{CD}
CD
start overline, C, D, end overline in Figure 111.

Answers

Answer:

if im corect the anwser is 3.14 (Side note) this is the wrong question i was anwsering to

Jasmine bought four potted plants. Two of the plants cost $6.65, and the others cost $4 and $7.15. How much money did jasmine spend in all?

Answers

Answer:

$24.45

Step-by-step explanation:

6.65 + 4 + 7.15 + 6.65 = 24.45

Can someone help me with this. Will Mark brainliest.

Answers

Answer:

the distance between the two points is √130.

Step-by-step explanation:

a^2 + b^2 = c^2

a^2 = 9^2 = 81

b^2 = 7^2 = 49

c^2 = 81 + 49 = 130

c = √130

i just don’t understand

Answers

Answer:

the answer is 9

Step-by-step explanation:

Please help, i need it done by today,

Answers

Answer:

x= 28

do i have to explain

Step-by-step explanation:

Write the following permutation as a product of disjoint cycles and thereafter as a product of transpositions 1 2 3 4 5 6 7 8 8 2 6 3 7 4 5 1 (62848X)

Answers

The given permutation (62848X) can be expressed as the product of disjoint cycles as (1 6 2 8 4) and as the product of transpositions as (1 6)(6 2)(2 8)(8 4).

To express the given permutation (62848X) as a product of disjoint cycles, we start by examining each element and its corresponding image under the permutation.

1 maps to 6.

6 maps to 2.

2 maps to 8.

8 maps to 4.

4 maps to 8 (since X represents a fixed point, meaning it remains unchanged).

Now, let's write these mappings as disjoint cycles:

(1 6 2 8 4)

The cycle notation indicates that 1 maps to 6, 6 maps to 2, 2 maps to 8, 8 maps to 4, and 4 maps back to 1.

Next, we'll express this permutation as a product of transpositions. A transposition swaps two elements.

We can achieve this by breaking down the cycle (1 6 2 8 4) into transpositions:

(1 6)(6 2)(2 8)(8 4)

Each pair of adjacent elements within the cycle forms a transposition. For example, (1 6) represents the transposition that swaps 1 and 6, (6 2) swaps 6 and 2, and so on.

Thus, the given permutation (62848X) can be expressed as the product of disjoint cycles as (1 6 2 8 4) and as the product of transpositions as (1 6)(6 2)(2 8)(8 4).

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(Round off the answer upto 2 decimal places) Phases and Times of Day on Earth 1. Put the moon at the full moon position. (Keep the bright side of the moon towards the sunlight) 2. Rotate the person so that "Sunset" is directly over their head. This means they are experiencing sunset at this time. a. At this time, where is the Sun? (E horizon, W horizon or Overhead) b. Where is the moon? (E horizon, W horizon or Overhead) c. What is rising? What is setting? 3. Rotate the person so that "Midnight" is directly over their head. a. Where is the moon? (E horizon, W horizon or Overhead) 4. Rotate the person so that "Sunrise" is directly over their head. a. Where is the sunlight? (E horizon, W horizon or Overhead) b. Where is the moon? (E horizon, W horizon or Overhead) 5. If you understood what is going on, then keep going. If you feel lost it's OK, ask for help! 6. Use the earth/moon/sunlight system to fill in the table below: Rise Overhead Set New Moon Waxing Crescent 1st Quarter Waxing Gibbous Full Moon Waning Gibbous 3rd Quarter Waning Crescent Changing moon day to day In one day the earth goes around one full revolution. The moon only completes about 1/29th of its cycle in one earth-day. Suppose the moon is in 1st quarter today. 1. Where is the moon going to be at sunset today? 2. Where is the moon going to be at sunset tomorrow? Just east of overhead or just west of overhead? 3. What phase will it be tomorrow? Just barely gibbous or just barely crescent? 4. Compared to today, will the moon be earlier or later getting overhead? 2 How does leadership position influence the legislative process? Options:1. Unsaturated fat or saturated fat 2. Fatty acids, carbohydrates, sterols, or phospholipids3. Fatty acids, carbohydrates, or triglyceridesPlease helppp PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!Frost forming on grass in the morningPHYSICAL OR CHEMICAL CHANGE A parabola can be drawn given a focus of (2, 4)(2,4) and a directrix of x=4x=4. Write the equation of the parabola in any form. What are the values of x that would make the line j parallel to line k? Help me please! ugh helpme plz i need to turn dis in now If h(x) is the inverse of f(x), what is the value of h(f(x))?01Xf(x) What is the next term in the sequence below?0.35, 1.05, 3.15, 9.45, A. 15.75 B. 27.75 C. 28.35 D. 85.05 Cosco Company had 300,000 shares of common stock issued and outstanding at December 31, 2017. During 2018, no additional common stock was issued. On January 1, 2018, Cosco issued 400,000 shares of convertible preferred stock. Each preferred share can be converted to one share of common stock. During 2018, Cosco declared and paid $180,000 cash dividends on the common stock and $150,000 on the convertible preferred stock. Net income for the year ended December 31, 2018 was $960,000. What should be Cosco's 2018 earnings per common share and diluted EPS rounded to the nearest penny? Show computations. Solve the following initial value problem. y2 8y + 12, y(0) = 3 dx (a) It is generally believed that mature financial markets (e.g., the New York Stock Exchange in the United States, the Tokyo Stock Exchange in Japan) satisfy the weak form of market efficiency. Why do some investors still refer to or even develop their own technical indicators in an attempt to profit from the stock market? (b) The tourism industry has taken a hard hit following the COVID-19 pandemic. Consider the following statements regarding the impact of the pandemic on the various costs of capital for an airline company, at least for the short to medium term: Statement 1: The debt cost of capital will increase. Statement 2: The equity cost of capital will increase. Among the four options below, select one that you think is correct. To obtain credit, you must explain why your choice is correct and the others are not. i. Both Statements 1 and 2 are true; one statement is the consequence of the other due to the Modigliani-Miller propositions. ii. Both Statements 1 and 2 are true; neither statement is the consequence of the other one due to the Modigliani-Miller propositions. iii. Only one of the two statements is true. iv. None of the statements is true. (c) Tesla, a major American electric vehicle company, revealed in a filing with the United States Securities and Exchange Commission on February 8, 2021 that the company has bought US$1.5 billion worth of bitcoin, a cryptocurrency. Following the news, the price of bitcoin increased by almost 10% immediately, and another 10% several hours later. Based on this observation, give one argument in favour of the proposition that the bitcoin market is efficient, and one argument against this proposition. planet a exerts a force on planet b. what can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?