The density of the object mentioned in the question when mass and volume are given is 0.924 g[tex]/cm^{3}[/tex]
According to the problem we have the following data given,
The mass of object m= 85g
The volume of object V= 92[tex]cm^{3}[/tex]
To find the density of the object we use the formula [tex]density=\frac{mass}{volume}=\frac{m}{V}[/tex]
∴density ρ [tex]=\frac{m}{V}=\frac{85}{92}=0.924g/cm^{3}[/tex]
Thus the density of the object = 0.924 g/[tex]cm^{3}[/tex]
Your question was not complete but most probably the question was if an object of mass 85g and volume 92cm^3 is given, what is its density?
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what will the killograms be of 981N and 160N
The mass of the objects in kilograms could be obtained as; 100 Kg and 16.3 Kg.
What is weight?The term weight has to do with the effect of the gravitational force on an object hat is found on the surface of the earth. Note that the weight is a force an d the direction of the weight must always be towards the center of the earth.
Now we are asked to convert 981N and 160N to kilograms. Recall that the weight is the product of the mass of the object in kilograms to the acceleration due to gravity.
Mass = weight/acceleration due to gravity
1) 981N/9.8 m/s^2
= 100 Kg
2) 160N/9.8 m/s^2
= 16.3 Kg
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the force of friction is described by the force of friction is described by the law of friction. the theory of friction. a model of friction. the friction hypothesis.
Answer: coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.
Explanation:
Use your periodic table to determine the following information
about the element Sulfur (S).
a. Number of protons =
b. Number of electrons =
c. Number of neutrons =
a block slides to the right with speed v on a frictionless floor and collides with a bigger block which is initially at rest. after the collision the speed of both blocks is v/3 in opposite directions. 1)was the collision elastic?
We can see that the collision of the objects is an elastic collision.
What is the kind of collision?Let us note that a collision could be elastic or in elastic. We can say that a Collison could be judged or said or designated to be an elastic collision when the kinetic energy and the momentum of the system that is undergoing the collision is conserved.
Let us recall that the principle of the conservation of the linear momentum states that the momentum before collision is equal to the total momentum after Collison. In other words, the momentum of the system does not change. Hence, the momentum of one of the objects must be transferred to the other object when they collide in a closed system
With that said, we can see that the two bocks move in opposite directions thus it is an elastic collision as we can see from the description in this answer.
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question 1.4 does the multimeter set to measure voltage act as a large resistance, or a small resistance? explain, based on your observations. why does it need to be designed this way?
Multimeter conducts like a big resistor. Since current will be very low due to the very high resistance, the circuit's overall current won't be impacted in the slightest. It will transmit the appropriate voltage
A passive electrical device known as a resistor adds resistance to the flow of electric current. They can be discovered in virtually all electrical networks and electronic circuits. One ampere of current (A) and a one volt (V) drop across a resistor's terminals produce an ohm, which is the resistance that results. The voltage at the terminal ends determines the current in a direct proportion. Ohm's law demonstrates how to calculate this ratio. Multiple applications exist for resistors. Among some examples are voltage division, heat generation, matching and loading circuits, current limiters for electric current, gain control, and time constant setting. With resistance values spanning a range of more than nine orders of magnitude, they are readily available on the market. Units of resister is omhs.In the International System of Units, the ohms serves as the reference unit for electrical resistance.
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Which is phrase is an example of kinetic energy
The phrase "energy that a ball has and produces as it rolls down a hill" is an example of kinetic energy.
What is kinetic energy?Kinetic energy is a type of energy that a particle or an object possesses as a result of its motion. By exerting a net force on an object, work is done, which transfers energy; as a result, the object accelerates and gains kinetic energy.
A moving object or particle's ability to move depends on both its mass and motion. This is known as kinetic energy. Translation (or movement along a path from one place to another), rotation about an axis, vibration, or any combination of motions are examples of possible types of motion.
A body's squared translational kinetic energy, or 1/2mv², is equal to one-half the product of its mass, m, and its velocity, v.
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a water balloon is thrown vertically downwards at a speed of 14 m/s from the top of a tall building. assuming the water balloon does not bang into anything or burst, how fast is it moving 1.8 s after it was thrown?
31.64 m/s with velocity fast is it moving 1.8 s after it was thrown vertically downwards at a speed of 14 m/s from the top of a tall building.
V= u + gt= 14 + 9.8×1.8 = 14 + 17.64 = 31.64 m/s
When a body is travelling in a straight line, its estimated "rate of change of displacement in relation to time" is referred to as its velocity.
Speed is a scalar number since it lacks a direction and the value it receives from the distance-to-time ratio simply indicates its magnitude. It doesn't provide any guidance information. Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.
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A body is under the action of two forces 7n and 10n. find the resultant of the two forces if the two are inclined at an angle of 60degrees to each other
Mass x Acceleration equals force. Net force is equal to 7N plus 10N, or 17N, at a 60-degree angle with R equal to 12.2N.
How does physics define force?The definition of force in physics is: The push and pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
A force is an effect that tends to move a stationary object into motion, stop a moving object, alter the direction and speed of a moving object, or alter the size and shape of a body.
Which four sorts of forces are there?Any of the four fundamental forces in physics—gravitational, electromagnetism, strong, and weak—that control how objects and particles interact as well as how some particles decay—is referred to as a fundamental force or fundamental interaction.
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a 2,100-kg car moving east at 10.0 m/s collides with a 3,000-kg car moving north. the cars stick together and move as a unit after the collision, at an angle of 33.0° north of east and at a speed of 4.91 m/s. find the speed of the 3,000-kg car before the collision.
The initial velocity of the car with the mass of 3000kg before the inelastic collision is 1.347m/s.
What is Collision?For two objects, the relative speed between them equals the change in distance between them divided by the change in time.
In an inelastic collision, the momentum of the bodies remain constant even after collision. This works on the principle of conservation of momentum.
p = m.v
where, p = momentum of the body,
m = mass of the body,
v = velocity of the body
Here,
m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂
Therefore, the velocity of 3000kg car (m₂) can be calculated by this formula:
m₁ = 2100 kg
u₁ = 10m/s
m₂ = 3000kg
u₂ = ?
v₁ = v₂ = 4.91 m/s
Therefore,
m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂
(2100kg × 10) + (3000 × u₂) = (2100 × 4.91) + (3000 ×4.91)
21000 + 3000u₂ = 10,311 + 14730
3000u₂ = (10311+14730) - 21000
3000u₂ = 25041 - 21000
3000u₂ = 4041
u₂ = 4041/3000
u₂ = 1.347m/s
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Alyssa mixed 12 mL of a salt solution with 9mL of a 39% salt solution, to make a 56% salt solution. Find the percent salt concentration of the first solution.
Alyssa mixed 12 mL of a salt solution with 9mL of a 39% salt solution, to make a 56% salt solution. The percent salt concentration of the first solution will be 78.08 %.
An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.)
let x = percentage of 12ml of solution
12x + 0.39 (9) = 0.56 (12 + 11)
12x + 3.51 = 12.88
x = 0.7808
The percent salt concentration of the first solution will be 78.08 %
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2. A 2.0 kg block rests on a level surface. The coefficient of static friction is µ[s] = 0.60 , and the coefficient of kinetic friction is µ[k] = 0.40 , A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.
(a) The force of friction increases as the applied force increases.
(b) The force of friction at each value of X (applied force ) can determined by subtracting the net force on the block from the applied force.
What is coefficient of static friction?The coefficient of static friction is the ratio of the maximum static friction force between the surfaces in contact before movement commences to the normal force.
Mathematically, the coefficient of static friction is given as;
μ = F/N
where;
μ is the coefficient of static frictionN is the normal force F is the static frictional forceBefore the block start moving, the static friction must be overcame since it prevents the block from moving.
The net force on the block is determined by applying Newton's second law of motion.
F - Ff = ma
F = ma + Ff
where;
F is the applied forceFf is the force of frictionFrom the formula above, as the applied force increases the force of friction increases as well.
The force of friction at each value of X (applied force ) is calculated as follows;
Ff = F - ma
Ff = F - F(net)
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A spring with a spring of 4.75n/m applies a force of 3.25N when it is stretched. How much was the spring compressed
The spring was compressed by 0.684 m
Explanation:Soring constant, k = 4.75
The applied force, F = 3.25 N
Note that spring will compress back by the same distance it expands
Compression, x = ?
Using the equation F = kx
3.25 = 4.75x
x = 3.25/4.75
x = 0.684 m
The spring was compressed by 0.684 m
If we drop a ball from the stand and then dropped into sand, at what point did the energy of the ball transform from potential energy into kinetic energy
Answer:
When it is dropping into the sand.
If you have two different sized velocity vectors representing two objects moving in the same direction, then what can you conclude? a. Their magnitudes are the same. c. One object has a greater velocity then the other. b. Their magnitudes are different. d. Both B and C.
If you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.
A velocity vector is the rate of change of an object's position. A velocity vector has both magnitude and direction. The magnitude of the velocity vector gives the speed of the object while the direction of the vector gives the direction of the object's velocity.
If a vector's size is longer than the other, it means that the vector has a magnitude higher than the other. If the magnitude is higher, the velocity will be higher.
Therefore, if you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.
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the most likely places where stars and planetary systems are forming in the universe are- the most likely places where stars and planetary systems are forming in the universe are- in nebulae composed of gas and dust. in regions surrounding quasars. in the rarified space between galaxies. in the centers of galaxies.
The most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.
Stars are massive, hot, luminous bodies of gas that emit large amounts of radiation and derive their energy from nuclear fusion. A planetary system comprises of a star and all the objects that revolve around it.
Stars are born in nebulae. They are a cluster of gas and dust scattered throughout a galaxy. Gravitational attraction between the gas and dust particles causes turbulence, which gives rise to knots. When these knots acquire sufficient mass, they collapse, and when the reach a certain temperature, nuclear fusion of hydrogen atoms into helium atoms begins. At this point, star has been born.
Planets can be said to be formed as a by-product of star formation, through a process called accretion. Smaller objects stick together through gravity, forming bigger objects. Gravitational pull from the nearby star and the object's own momentum causes the object to revolve round the star. At this point, a planet has been born.
Thus, the most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.
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According to Newton's
2nd law of motion, if you hit a baseball with a bat it will
• hurt your hand from the reaction force
O accelerate according to the applied force
• fly in a straight line
unless an outside force changes its
course
• fall to the ground because of
gravitational pull
Answer:
Accelerate according to the applied force.
Explanation:
According to Newton's second law of motion, a force applied on a body produces acceleration in its own direction. Therefore, if you hit a baseball with a bat it will accelerate according to the applied force.
Answer:
Explanation:
Given:
m - Baseball mass
F - Force applied from the side of the bat to the baseball
_________________________
a - ?
2 Newton's law:
a = F / m
Correct answer:
Accelerate according to the applied force
a length of 20 gauge copper wire of diameter 0.8118mm is formed into a circular loop with a radius of 30 cm a magnetic field perpendicular to the plane of the loop increases from zero to 18 mt in 28 seconds find the average electrical power dissipated in the process
Here, a length of 20 go copperware is provided for us. Having a right-handed tiny dilates diameter of.8118 millimeters, it is shaped into a circular loop with a 17 centimeter radius.
Assume that the capital r is 17 centimeters, or.107 met, and that the magnetic field is growing from 0 to so that 1 is equal to 0 and b 2 is equal to 11 milli tesla, or 10 to the power of 11 minus 3 tesla, in time of.24 seconds. Okay, so you need to figure out the average power lost during this procedure. In addition, copper has a resistivity of 1.72 times 10 to the minus 8 right meter. Therefore, in this case, we first determine the induced emf in the loop.
In other words, emf will equal the change in magnetic flux, which is fi 2 minus pi 1 by t, right, and fight will equal b 2 a minus b 1 an area over here, b. 2 is we have got 11 times of 10 to the power of minus 3 times the area of the loop will be, so let me just show you here area will be equal to pi r square, which is equal to pi times of 0.17 square. We can therefore multiply it here by 10 to the power of.17 square right b, where 1 is 0.
As a result, we can plug it in here by times 10 to the power of.17 square right b. 1 is 0. Thus, the other period is not taken into account, and the time is.24 seconds, correct voltages. So let me assess how much you're getting and see. It is 4.16 x 10 to the minus 3 volt power to the right. The induced m f is therefore this.
This will be squared right in meters, and this is where home is. In order to determine the electrical power dissipated, which is equal to v squared by r right, the resistance, and v, let me evaluate and see how much we're getting. This is 0.035 right now. We already have a resistance of 0.035 radius and 4.16 times 10 to the power of -3 entire squared, and this will be in what way. The amount you receive is approximately 4.9 times 10 to the power of negative 4.
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i’m willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please help!! this is due soon.
1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.
2. The box will not move if a 50 N force us applied to the left.
For Balanced, B or Unbalanced forces, U the correct option are:
B A person jogging at a constant speedU A car accelerating at a green light.U Pushing a lawnmower across the yardB A cookie sitting on a plate.U Slowing down to stop at a red light.U A bowling ball knocking over pins.B A book sitting on a shelf.U A linebacker tackling a running back.B A person sitting on a chair.B A plane flying at a constant speed.What are balanced and unbalanced?Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.
Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.
Considering the boxes:
1. Net force = 50 N
Forces to the left = 25 N + x
Forces to the right = 50 N
Net force = Force to the left + force to the right
50 N = 25 N + x - 50
x = 75 N
2. Net force = 0 N
Forces to the left = 75 N + x
Forces to the right = 125 N
Net force = Force to the left + force to the right
0 N = 75 N + x -125
x = 50 N
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If you were walking your dog and started at A went to B then to C and finally returned to A what would your speed be if it took you 5 seconds, what would
your velocity be?
Answer:
Speed 5 m/s , velocity 0 m/s
Explanation:
s= d/t = 25/5 = 5 m/s
υ= Δx/Δt = 0/5 = 0 m/s
a pickup truck, carrying a box on a level road, accelerates forward from a stoplight. assuming that the box does not slide on the bed of the truck, as the truck is accelerating forward, the frictional force exerted on the box by the bed of the truck is in which direction?
The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it. The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward.
As long as the crate accelerates at the same rate as the truck, it won't slide. The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it.
The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward. To cause a commensurate rise in the crate's acceleration, the truck's acceleration must likewise increase.
However, the static frictional force can only build up to a certain point, after which the crate and vehicle will accelerate to their maximum rate. The crate will slip if the acceleration is raised much further.
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a hawk flies in a horizontal arc of radius 10.3 m at a constant speed of 4.8 m/s. find its centripetal acceleration. answer in units of m/s 2 . 013 (part 2 of 2) 10.0 points it continues to fly along the same horizontal arc but increases its speed at the rate of 0.63 m/s 2 . find the magnitude of acceleration under these new conditions. answer in units of m/s 2 .
The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
[tex]a_{c}[/tex] = [tex]\frac{v^{2} }{r}[/tex]
[tex]a_{c}[/tex] = 23.04/10.3
[tex]a_{c}[/tex] = 2.23 m/s²
It continues to fly but now with some tangential acceleration
[tex]a_{t}[/tex] = 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
[tex]a_{net}[/tex] = [tex]\sqrt{a_{c} ^{2} +a_{t} ^{2} }[/tex]
[tex]a_{net}[/tex] = [tex]\sqrt{4.97 + 0.396}[/tex]
[tex]a_{net}[/tex] = 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
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Two mechanical waves are traveling through the same medium, and Wave X has an amplitude of 2 cm and Wave Y has an amplitude of 3 cm.How do the two waves' speeds compare?A. Wave X has a greater speed. B. Wave Y has a greater speed. C. Wave X and Wave Y share the same speed. D. The speed of the waves is impossible to compare without more data.Part 2Which best explains the correct answer to Part 1?A. The speed of a wave is always constant. B. The speed of a wave is directly proportional to its amplitude.C. The speed of a wave is determined by its wavelength and frequency.D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
ANSWER:
1. C. Wave X and Wave Y share the same speed.
2. D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
STEP-BY-STEP EXPLANATION:
The amplitude of a wave does not affect the speed at which the wave travels. Both wave A and wave B travel at the same speed. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.
Therefore, in the first art the correct answer is C. Wave X and Wave Y share the same speed.
If the medium is uniform (does not change), the speed of the wave will be constant.
Therefore, the correct answer is: D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
Answer questions on redox reactions och of the following chemical reactions, identify the chemical that is used and the chemical that is reduced. Give a reason for your answer. identify the oxidising and reducing agents. 4Na+O2->2Na2O
The reducing agent in the reaction is Sodium and the oxidizing agent in the reaction is oxygen.
The provided chemical reaction is,
4Na+O₂ → 2Na₂O
Oxidation is the process of addition of oxygen or the removal of electrons from the product. Oxidation number increases in this case. Compound which undergoes reduction is called oxidizing agent.
Reduction is the process of removal of oxygen or the addition of electrons from the product. Oxidation number decreases in this case. compound which undergoes oxidation is called reducing agent.
In the reaction,
Oxygen is added to Na. So, Na is oxidized, hence it is the reducing agent and Oxygen is getting reduced, so, it is the oxidizing agent.
Reducing agent → Na.
Oxidizing agent → O₂.
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a careless person accidentally grasps the terminals of a 20.0-kv power supply (do not do this!). the resistance of the path through his body is 11 kω.
Current passing through his body is 1.67 A. power dissipated in his body is 27.8 kW and internal resistance is 20.0 MΩ .Low enough voltage levels allow the power supply to work with low resistance devices.
Voltage is the pressure from the power source of an electrical circuit that drives charged electrons (current) through a conducting loop, allowing them to perform tasks like lighting a lamp.
Briefly stated, voltage equals pressure and is measured in volts (V). The phrase honours Italian physicist Alessandro Volta (1745–1827), who developed the voltaic pile, the predecessor of the modern household battery. Voltage was first referred to as electromotive force in the early days of electricity (emf). Voltage is therefore represented by the letter E in equations like Ohm's Law, and the terms "voltage" and "potential difference" are sometimes used interchangeably. A better way to define potential difference is as the difference in potential energy between two places in a circuit. A simple indicator is the potential difference or voltage.
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in the overhead view of fig. 9-54, a 300 g ball with a speed v of 6.0 m/s strikes a wall at an angle θ of 30° and then rebounds with the same speed and angle. it is in contact with the wall for 10 ms. in unit-vector notation, what are (a) the impulse on the ball from the wall and (b) the average forc
(a) The impulse-momentum theorem (Eq. 9-31) results in (a) when m=0.30 kg. (b) Applying Eq. The force exerted by the wall on the ball is 935.
J /Δt=(1.8/0.010) j ^ =(180N) j ^.
According to Newton's third law, the ball's force on the wall is (180N) j, meaning that it is 180N in magnitude and is directed directly at the wall.
Let the momentum ball go.
m = 0.37 k g
contacts the vertical wall at an incidence angle while traveling at v mph.
= 22 with the positive x-axis direction and it bounces back at the same speed and angle.
The velocity of hitting the wall can be expressed vectorially as v s = v cos I + v sin j.
Then the rebounce's velocity will be given by v b = v cos I + v sin j.
Here, the vertical component is unchanged, the horizontal component is reversed, and the effect of gravity is not taken into account.
The mass ball's impulse or change in momentum
m = 370 g = 0.37 k g
is
= m (=> v b − => v s) = − 2 m v cos θ ˆ i= − 2 × 0.37 × 3.9 × cos 22 ˆ i kgm/s
= − 2.675 ˆ I kgm/s
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an athlete stretches a spring an extra 29.0 cm beyond its initial length. how much energy has he transferred to the spring, if the spring constant is 68.0 n/cm ?
If the spring is constant at 68.0 n/cm, the energy he has transferred to the spring is 2028 N.
Hooke's law, which asserts that, must be applied,
F = k x
The spring constant in N/cm is k.
The extension in centimeters is x.
By incorporating x = 35.7 cm and k = 56.8 N / c m, we obtain the force, which is equivalent to
F = 56.8 N/cm 35.7 cm = 2027.76 N
2028 N, rounded to the next whole value.
The spring's shape, which was created by coiling a metal wire into tight loops pressed up against one another, gives it elastic properties. When an external force is applied to a spring, a restoring force always acts in the direction of the spring's equilibrium state. The spring stores mechanical energy.
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A car with the mass of 2230 kg is accelerating at a rate of 14 m/s^2. What is the force that the engine is producing?
Explanation:
Force = mass x accelaration
Force = 2230 x 14
Force = 31,220 N or 31.22 kN
A car covered a distance of 40 km in the first 1 hour and then covered 30 km more in the next 2
hours. Draw a distance-time line graph for the car.
Answer:
Explanation:
here you need to draw a distance time graph for the car
like put 1-5 which indicates hours on x axis and
you need to covert the km into m by using the unitary method as we know 1km-1000m
then 40km=40000m and 20km=20000km like this 10-50 you need to convert in metres, then write them in y axis.
then you draw a graph for motion with constant speed in that distance time graph and plot them
then you will get your answer
A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i. What is the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy ?.
A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i. the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy is 1/4 .
The moment of inertia of a rigid body, also referred to as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. The amount of torque required to modify the body's rate of rotation depends on the mass distribution of the body and the axis selected. For example, larger moments require more torque.
The moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. This is an extensive (additive) property.
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A 0.0254 m long magnet is held next toa wire carrying 0.530 A of current, sothat the field is perpendicular to the wire.The resulting magnetic force is3.67*10^-4 N. What is the strength ofthe field?(Unit = T)Magnetic Field (T)
The force of a magentic field is given by the next formula
[tex]F=IBL\cdot sin(\theta)[/tex]We have F force, I current, B magnetic field, L lenght and sin theta which represents the angle between them. This is important because this interactions depends on the direction.
[tex]\begin{gathered} B=\frac{F}{IL\cdot sin(\theta)} \\ B=\frac{3.67\cdot10^{-4}N}{0.0254m\cdot0.53A\cdot sin(90)} \\ B=0.027T \end{gathered}[/tex]Based on the information, the angle is 90 because is perpendicular, as it is mentioned on the text