If an ideal gas has a pressure of 1.11atm, a temperature of 40.04°C, and a volume of 76.87L, how many moles of gas are in the sample?
n=? mol

3.195 grams of Na₂SO₄ are needed to completely precipitate the Ba²⁺ ions as BaSO₄ from 150 mL solution of 0.150 M BaCl₂.

Chemical precipitation is the process of changing a liquid into an insoluble form or supersaturating a solution in order to transform it into a solid. When two ionic bonds combine in an aqueous solution, a chemical process known as the precipitation reaction takes place, resulting in the formation of precipitates, an insoluble salt.

The equation becomes:

Na₂SO₄(aq) + BaCl₂(aq) → BaSO₄(s) + 2 NaCl(aq)

1 mole              1 mole         1 mole        2 mole

Given that,

150 mL solution of 0.150 M BaCl₂.

Now, molar mass of Na₂SO₄ = (23×2 + 32 + 16×4) g/mol = 142 g/mol

Mole ratio Na₂SO₄ : BaCl₂ = 1 : 1

Moles of BaCl₂ formed = (0.150 mol/l) × (150/1000 L) = 0.0225 mol

Moles of Na₂SO₄ needed = (0.0225 mol) × (1/1) = 0.0225 mol

Mass of Na₂SO₄ needed = (0.0225 mol) × (142 g/mol) = 3.195 gm.

So, 3.195 grams of Na₂SO₄ are needed

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6 moles of carbon dioxide produces 1 mole of glucose in this reaction. Thus, 18.6 moles produces 3.1 moles or 558 g of glucose.

Photosynthesis is the biological reaction of water with carbon dioxide in presence of light to give glucose an oxygen gas. Photosynthetic reaction takes place in green plants to synthesis energy.

As per the balanced equation of the reaction, 6 moles of water combines with 6 moles of carbon dioxide to produce 1 mole of glucose. Here water is taken in excess and carbon dioxide is 18.6 moles.

The number of moles of glucose produced from 18.6 moles of carbon dioxide = (18.6 ×1)/3 =  3.1 moles.

Molar mass of glucose = 180 g/mol.

3 moles of glucose = 180 × 3.1 = 558 g.

Therefore, the theoretical yield of the photosynthetic reaction with 18.6 moles of carbon dioxide is 558 g of glucose.

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Common salt, sometimes referred to as sodium chloride, is a substance consisting of sodium and chlorine atoms. One mole of sodium chloride (23 grams) interacts with one mole of oxygen to produce two moles of sodium oxide and one mole of chlorine. This reaction is known as the sodium chloride–oxygen reaction (NaCl–O2).

The molar masses of sodium (Na) and chlorine (Cl) are respectively 22.99 g/mole and 35.4 g/mole.

If I take a mole of NaCl, there will either be one mole of Na and zero Cl2 molecules, or two moles of Na and two moles of Cl2 molecules on either side.

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Answer: 1.58 x 10-17

The frequency of a wave is inversely proportional to its wavelength, meaning that as the wavelength increases, the frequency decreases and vice versa. We can use the following formula to calculate the frequency of a wave given its wavelength:

Frequency = Speed of light / Wavelength

Plugging in the values from the question, we get:

Frequency = 3 x 10^8 m/s / (4.75 x 10^-9 m)

= 1.58 x 10^-17 Hz

Therefore, the frequency of the wave is 1.58 x 10^-17 Hz.

Answer:

:)

Explanation:

What traits were you trying to control in the cattle is the most reasonable question.

a person who cultivates the and the  land and grows to the  crops on it agriculturists who adhere to their magnetic organization's standards of organic product is a good farming.

An agriculturist, agriculturalist, agrologist, or the  agronomist, is a  professional in the science, se can say them farmers alsopractice, and the  management of agriculture and technology and agribusiness. It is a type of  regulated profession in the  Canada, India, the Philippines, the United and  States, and the European Union.

Robert Bakewell is an it's  agriculturist that revolutionized sheep and to the  cattle breeding in England. He inherited his radiation father's farm and the  he innovated brreding of the  techniques. He separated his male and to the  female livestocks to prevent random breeding. He further advanced a method method that tells desirable traits were exaggerated by inbreeding by the  and undesirable traits were removed from the  the breeding population.

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Answer:

if 5.3 moles of carbon dioxide is produced in the combustion of propane, 1.77 moles of oxygen would have reacted in the reaction.

Explanation:

To determine the number of moles of oxygen that reacted in the combustion of propane, you can use the balanced chemical equation for the reaction:

C3H8 + 5 O2 -> 3 CO2 + 4 H2O

In this equation, one mole of propane reacts with five moles of oxygen to produce three moles of carbon dioxide and four moles of water. If you know the number of moles of carbon dioxide produced in the reaction, you can use the balanced equation to determine the number of moles of oxygen that reacted.

For example, if 5.3 moles of carbon dioxide is produced in the reaction, you can use the balanced equation to determine the number of moles of oxygen that reacted:

5.3 moles CO2 / 3 moles CO2/mole O2 = 1.77 moles O2

1. Nitrate 2. Nitrite 3. Nitroxyl 4. Hydroxylamine 5. Ammonia.

Nitrate is converted to nitrite via the assimilatory pathway, which is then further converted to ammonia—a source of nitrogen for biosynthesis—by assimilatory nitrite reductase.The dissimilatory route also converts nitrate to nitrite from nitrate.

Dissimilatory & assimilatory nitrate reductases are thus genetically different in P. aeruginosa.To stop nitrate-based slow dissimilatory development, both enzymes must be lost.Both dissimilatory and assimilatory nitrate reductases need molybdenum to work properly.

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The values of Δs for the water, the surroundings, and the universe for the evaporation of water from an open pan at 25°c is Positive, Negative, Positive.

What is spontaneous process?

A spontaneous process in thermodynamics is one that happens without the system receiving any outside input.

According to the second law, a spontaneous process,

ΔS[tex]universe > 0[/tex]

As it transitions from a liquid to a gaseous form, water. Entropy changes in favor whenever a phase transition occurs from a liquid to a gas,

So ΔS [tex]water > 0[/tex]

The amount of thermal energy required to cause water to evaporate is determined by multiplying the molar enthalpy of vaporization by the amount of evaporating water in moles. The surrounding provides this thermal energy,

So Δq [tex]surroundings < 0[/tex].

We know that: As long as this thermal energy is transferred reversibly,

[tex]Delta S surr = Delta q surr/T[/tex]

T is always positive since it is being measured in kelvins, which is the thermodynamic scale. The fact that

[tex]Delta q surr < 0 so Delta S surr < 0.[/tex]

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When cleaning the end of a piece of copper tube for making a soldered joint, it should be cleaned for a distance slightly more than twice the distance required to enter the socket of the fitting is false.

The given statement is not true that When cleaning the end of a piece of copper tube for making a soldered joint, it should be cleaned for a distance slightly more than twice the distance required to enter the socket of the fitting. The 1/4 more than the insertion depth. The end of the tube can be cleaned by using the sand cloth or the  nylon cloth  it should be cleaned for distance only slightly more than the depth of the fitting socket.

Thus,  the copper tube can be cleaned by using the sand cloth.

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Heat produced during the decomposition of 15 g of calcium carbonate is calculated to be 26.67 KJ.

The heat evolved or absorbed during a reaction is known as reaction enthalpy and it is negative for exothermic reaction and positive for endothermic reaction.

As we know that heat produced when one mole of calcium carbonate decomposes is 177.8 KJ. Therefore, 15 g or 0.15 moles of calcium carbonate when decomposed will give 26.67 KJ of heat.

As we know, molar mass of calcium carbonate is 100 g.

So, no. of moles in 15 g becomes 15 /100

= 0.15 moles.

So, 100 g of calcium carbonate decompose to produce 177.8 KJ

Heat evolved after decomposition of 0.15 moles is

=0.15 × 177.8 KJ = 26.67 KJ.

Therefore, heat evolved in the decomposition of 15 g of calcium carbonate is  found to be 26.67 KJ.

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Effective nuclear charge for Main Group elements would increase left to right across a period.

We know that the effective nuclear charge has to do with the force that binds the outer electrons to the protons tat are in the nucleus. We know that the greater the effective nuclear charge, the more difficult it would be to remove an electron from the atom.

Based on this, we could say that since the size of the nuclear charge is increasing across the period, the effective nuclear charge would also be found to increase across the period.

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The cell potential for the reaction is 28V.

The first step is to ascertain the cell potential at the standard conditions of 1 mol/L concentrations and 1 atm pressures at 25°C.

It goes like this:

The cell's oxidation and reduction half-reactions should be written down.

To find the reduction potential, E0red for the reduction half-reaction, look it up in a table of reduction potentials.

The potential difference between a cell's two electrodes, known as the cell potential, results from the transfer of electrons through a cell's external circuit when the cell has not yet reached equilibrium.

The voltage that exists between a battery's two half cells can be determined using the cell potential.

To find the oxidation potential, reverse the sign and look up the reduction potential for the opposite of the oxidation half-reaction.

Cell potential =Eo/E

E=2xRt=2x0.03=0.06

Cell potential =1.68/0.06=28V

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The ionic compounds are associated with opposite charges attract, hard brittle solids and formula units.

Ionic compound is defined as when an atom or group of atoms receives or loses electrons, compounds consisting of ions that produce charged particles are created. An ion is classified as either positively or negatively charged depending on its charge.

Salt is brittle and abrasive. Because of the intense three-dimensional ionic bonds that must be broken in order to melt or boil an ionic solid, these bonds have extremely high melting and boiling temperatures.

Thus, the ionic compounds are associated with opposite charges attract, hard brittle solids and formula units.  

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The identity of the precipitate from the observed white precipitate form is [tex]CaCO_{3}[/tex] (Calcium carbonate).

А precipitаte is а solid formed in а chemicаl reаction thаt is different from either of the reаctаnts. This cаn occur when solutions contаining ionic compounds аre mixed аnd аn insoluble product is formed. The identity of the precipitаte cаn often be determined by exаmining solubility rules. It аlso occurs in single displаcement when one metаl ion in solution is replаced by аnother metаl ion. Notice the new solid forming on the bottom of the tube.

Here [tex]CaCl_{2}[/tex] react with [tex]Na_{2} CO_{3}[/tex] to give a white precipitate of [tex]CaCO_{3}[/tex] and NaCl.

[tex]CaCl_{2}[/tex] + [tex]Na_{2} CO_{3}[/tex] → [tex]CaCO_{3}[/tex] + 2NaCl.

Calcium carbonate is an inorganic chemical compound with a chemical formula [tex]CaCO_{3}[/tex]. Cаlcium cаrbonаte is а non-toxic аnd odourless compound commonly found аs а white minerаl which occurs nаturаlly in chаlks, limestones аnd mаrbles.

Your question is incomplete, but your full question can see in the attachment.

Thus, the correct option is D.

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reactants

compounds dissolved in water

answer

Look, the periodic tables up

Explanation:

He discovered the solution by accident when someone left a sample of rubber and sulfur on the stove which makes it a scientific discovery because he used observations and empirical evidence and is therefore denoted as option D.

This is referred to as the process or product of successful scientific inquiry and is depicted by the events, processes and methods involved.

We were told that he discovered the solution by accident when someone left a sample of rubber and sulfur on the stove in which observations and empirical evidence were used which is a characteristic of a scientific discovery.

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The options are:

A.Yes. Goodyear was a scientist, so his discovery was scientific.

B.No. Goodyear failed to develop a hypothesis about the method.

C.No. Goodyear did not follow the scientific method.

D.Yes. Goodyear used observations and empirical evidence.

Answer:

5.8 L

Explanation:

To add milliliters to liters, you'd need to either convert the milliliters to liters or the liters to milliliters.

If you were to convert the milliliters to liters, you can divide 2300 by 1000 because "milli" means 1/1000. This gives you 2.3 L.

You can then add 2.3 L to 3.5 L to give you 5.8 L total.

Amylopectin is the branched version of starch, it has both of alpha 1,4 glycosidic bond and alpha 1,6 glycosidic bond.

Cellulose has beta 1,4 glycosidic bond.

Terminal saccharide has beta-1,6 glycosidic bond.

A biomolecule, often known as a biological molecule, is any of the various compounds created by cells and living creatures. Biomolecules come in a variety of sizes and shapes, and they serve a wide range of functions. Carbohydrates, lipids, proteins, and nucleic acids are the four main categories of biomolecules.

Biomolecules are essential for life because they help organisms develop, survive, and reproduce. They interact with one another to produce creatures ranging from single cells to sophisticated living entities such as humans. They may perform a variety of roles due to the diversity in their shape and structure.

alpha 1,4 glycosidic bond and alpha 1,6 glycosidic bond - Amylopectin

beta 1,4 glycosidic bond - Cellulose.

beta 1,6 glycosidic bond - Terminal saccharide

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The final temperature is calculated to be 48.40°C.

The specific heat capacity is measured in J/(kg K) or J/(kg °C), and it is the amount of heat (J) absorbed per unit mass (kg) of the material when its temperature rises by 1 K (or 1 °C).

Calculating the mass of the 116.0 mL of water:

Given,

Mass (m)= ?

Volume (V)= 116.0 mL

Density = 1.00 g/ml

Now,

Mass = Density × Volume

         = 1.00 × 116.0

         = 116.0 g

So, mass of the 116.0 mL of water is 116.0 g

Given,

Initial temperature (T₁)  =  26.0°C

The final temperature of the water = T₂

Hence,

The change in the temperature can be calculated by,

ΔT = T₂ - T₁

Let the heat absorbed by 116.0 g of water = Q

Hence, The formula to calculate heat absorbed is,

Q = m × c × ΔT

Now,

Calculating the mass of the 71.0 mL of water:

Given,

Mass (m')= ?

Volume (V')= 71.0 mL

Density = 1.00 g/ml

Now,

Mass = Density × Volume

         = 1.00 × 71.0

         = 71.0 g

So, mass of the 116.0 mL of water is 71.0 g

Given,

Initial temperature (T'₁)  = 26.0°C

The final temperature of the water = T'₂

Hence,

The change in the temperature can be calculated by,

ΔT' = T'₂ - T'₁

Let the heat absorbed by 116.0 g of water = Q'

Hence, The formula to calculate heat absorbed is,

Q' = m' × c × ΔT'

Both the liquids are mixed and the final temperature will be equivalent and given as, ΔT₂ = ΔT'₂

According to the law of conservation,

Heat lost by the water (Q') = Heat absorbed by the water (-Q)

m × c × ΔT = m' × c × ΔT'

116 × c(T₂ - 26) = -71 × c(T₂ - 85)

T₂ = 48.40

Hence, 48.40°C is the final temperature.

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When 116.0 mL of water at 26.0°C is mixed with 71.0 mL of water at 85.0°C, the final temperature is 48.40°C.

(m)= ?

(V)= 116.0 mL

Density is 1 g/ml.

T initial (T1) = 26.0 °C

T final = T2

Mass = Density * Volume

= 1.00 116.0

= 116.0 g

T = T2 - T1;

Water absorbing 116.0 g of heat equals Q

Q = m c T.

Calculating the mass of the 71.0 mL of water:

(m')= ?

(V')= 71.0 mL

The mass of the 116.0 mL of water is 71.0 g and the density is 1.00 g/ml

(1.00 * 71.0 = 71.0 g).

The starting temperature (T'1) is 26.0 °C.

T final = T'2

Heat absorbed by 116.0 g of water equals Q'

Q' = m' c T', where

T' = T'2 - T'1.

The end temperature will be the same for both, ΔT₂ = ΔT'₂

The law of conservation states that heat transferred by the water (Q') equals heat absorbed by the water (-Q)

m c ΔT = m' c ΔT'

116 × c(T₂ - 26) = -71 × c(T₂ - 85)

T₂ = 48.40

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The molecular orbitals of the cyanide ion in HCN is shown in the image attached.

The molecular orbital is formed from the combination of the atomic orbitals. In this case we can see that there are individual atoms that compose the carbon and the nitrogen atoms of the cyanide. The combination of these atomic orbitals gives the molecular orbitals in the cyanide.

Thus we have the ionic bond that exists between the hydrogen ion and the cyanide and then the covalent bond that we can see by the combination of the atomic orbitals.

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Le chatelier's principle addition reactions

The addition of HNO3 moves the equilibrium to the right

so more amount of Ni(OH)2 S will be dissolved

The reaction will be;

Ni(OH)2 + HNO3 ⇔ Ni(NO3)2 + H2O

A chemistry principle known as Chatelier's principle (or the Equilibrium Law) is used to forecast how a change in circumstances would affect chemical equilibria. The theory is named after the separate discovery by Karl Ferdinand Braun and occasionally French scientist Henry Louis Le Chatelier. It is possible to state:

A simple system in thermodynamic equilibrium shifts to a new equilibrium when a concentration, temperature, volume, or pressure change is applied. This new equilibrium partially cancels out the previous change.

Systems of simultaneous equilibrium can also exhibit phenomena that appear to defy Le Chatelier's principle.

so from this principle;

The addition of HNO3 moves the equilibrium to the right

so more amount of Ni(OH)2 S will be dissolved

The reaction will be;

Ni(OH)2 + HNO3 ⇔ Ni(NO3)2 + H2O

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Answer:4.03

Explanation:

Answer:

what do you need help with

The white is denser because it has less volume, but a lot more matter. Option 4.

The density of a substance is the ratio of its mass and its volume. This can be mathematically expressed as:

Density = mass/volume.

For the cube with 5 cm sides and 250 g mass, the density can be derived by first calculating the volume as follows:

Volume = 5 x 5 x 5

            = 125 [tex]cm^3[/tex]

Its density can be calculated as:

Density = 250/125

            = 2 g/[tex]cm^3[/tex]

For the cube with a mass of 320 g and 4 cm sides, the volume and density can be calculated as follows:

volume = 4 x 4 x 4

            = 64 [tex]cm^3[/tex]

Its density can then be calculated as:

Density = 320/64

            = 5  g/[tex]cm^3[/tex]

Thus, the white cube is denser because it has a higher density by having less volume but more matter (mass).

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The volume of the balloon if 0.65 moles of gas are released is 1.2 L.

There are 6,022 x 1023 units in a mole of a substance. The Avogadro number or Avogadro constant is the number 6.022 x 1023. The mole definition can be applied for the conversion of mass and particle count.

We are given here that the volume ( V ) = 1.50 Liters,

the initial moles ( held at 25 °C ) = 2.5 mol,

and the final moles ( n ) = 2.5 - 0.5 = 2.0 mol.

The final mol is calculated given that 0.65mol of gas are released from the prior 2.5 moles of gas.

Volume ( V ) = 1.50 L,

Initial moles ( n ) = 2.5 mol,

Final Volume ( n ) = 2.5 - 0.5 = 2.0 mol

We can determine the ultimate volume by applying the combined gas law.

P₁V₁ / n₁T₁ = P₂V₂ / n₂T₂ - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V₁ / n₁ = V₂ / n₂ - isolate V₂,

V₂ = V₁ n₂ / n₁

V = 1.50 L× 2.0 mol / 2.5 mol

V = 1.2 L.

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Internal reversibility, Therefore, during reversible operations, the universe's entropy changes nothing. We can see that for a reversible, adiabatic operation, the change in a system's entropy is zero.

dS=dQT=0 holds because any reversible process may be characterized as the sum of numerous infinitesimally small Carnot cycles. As a result, the entropy S is a state variable and the integral is independent of the path it takes. In strictly speaking, such route independence is only true for reversible processes.

This procedure could proceed way without breaking the second law. Reversible processes are those of the latter type. A reversible process' main characteristic internal reversibility, Therefore, during reversible operations, the universe's entropy changes nothing. We can see that for a reversible, adiabatic operation, the change in a system's entropy is zero.

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Answer:

Ag2CrO4

silver chromate, 331.966 g/mol

Ag=65%, Cr=15% O=19%

CH4

Methane, 16 g/mol

C=75% H=25%

Ca3(PO4)2

calcium Phosphate, 310 g/mol

Ca=38.7% P=20% O=41.3%

C7H5N3O6

227 g/mol

C=37% H=2.2% N=18.5% O=42.3%

K2C6H5O7

BAIDAR citron, 267 g/mol

CoCl2

Cobalt (ll) Chloride, 129.93

Explanation:

[tex]molar \: mass = m \div n \\ (m = mass \: of \: a \: substance \: in \: gram \: ) \\( n = no. \: of \: moles)[/tex]

Ag2CrO4

Ag=108, Cr=51.996, O=16

[tex]m = \frac{108 \times 2 + 51.996 + 16 \times 4}{1} \\ = 331.966[/tex]

Ag percentage in Ag2CrO4

[(108x2)/331.966]x100

=65%

Cr percentage in Ag2CrO4

[51.966/331.966]x100

=15%

O percentage in Ag2CrO4

[(16x4)/331.966]x100

=19%

CH4

C=12 H=1

12+1x4=16 g/mol

C percentage in CH4

(12/16)x100

75%

H percentage in CH4

(4/16)x100

25%

Ca3(PO4)2

Ca=40 P=31 O=16

40x3+31x2+16x8

=310 g/mol

Ca % in Ca3(PO4)2

[(40x3) /310]x100

38.7%

P % in Ca3(PO4)2

[(31x2)/310]x100

20%

O % in Ca3(PO4)2

[(16x8)/310]x100

41.3%

C7H5N3O6

C=12 H=1 N=14 O=16

12x7+1x5+14x3+16x6

227 g/mol

C % in C7H5N3O6

[(12x7)/227]x100

37%

H % in C7H5N3O6

[(1x5)/227]x100

2.2%

N % in C7H5N3O6

[(14x3)/227]x100

18.5%

O % in C7H5N3O6

[(16x6)/227]

42.3%

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