If an astronaut weighs 981 N on Earth and only 160 N on the Moon, then his mass on the Moon will be 98.1 kg.
Let's calculate the mass of Earth as per the Earth's acceleration due to gravity.
Now, considering the acceleration due to gravity as 10m/s².
Mass = Weight/Acceleration due to gravity
Mass = 981/10
Mass = 98.1 kg
Now, as per the established fact, the mass is independent of acceleration due to the gravity of the planet i.e. The mass of the person on earth and on the moon is same.
Hence, his mass on the Moon will be 98.1 kg.
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Calculate the resultant displacement for the following 10km left,20 km right,30 km left.polygon method
The resultant displacement of the object is 20 km left.
What is resultant displacement?
The resultant displacement of an object is the net or sum of all the distance travelled by an object in a given direction.
The given position of the object;
first position, = 10 km leftsecond position = 20 km rightthird position = 30 km leftThe resultant displacement is calculated as follows;
D = -10 km + 20 km - 30 km
D = 20 km - 40 km
D = -20 km
Thus, the magnitude and direction of the resultant displacement of the object is 20 km and left respectively.
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Find the y-component of this vector.
80.0°
B-18.6 m
0 = 170°
By = [?] m
The y-component of vector B is 3.23 m.
What is y - component of a vector?The y-component of a vector is the vertical component of the vector. It the vector that points in the y-direction.
The y-component of a vector is measured along the y-axis of the Cartesian coordinate.
Mathematically, the y-component of a vector is given as;
By = B sinθ
where;
By is the vertical or y-component of vector BB is the magnitude of vector Bθ is the angle of inclination of vector BThe y-component of vector B is calculated as follows;
By = 18.6 m x sin(170)
By = 3.23 m
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Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?
The horizontal component of a force is defined as follows
[tex]F_x=F\cdot\cos \theta[/tex]Where F = 16 N, and theta = 68. Let's use these values to find the horizontal component of F.
[tex]F_x=16N\cdot\cos 68\approx6N[/tex]Therefore, the horizontal component of the pulling force is 6 Newtons.16. On the moon, Bob weighs 160 N while on earth Fred weighs 882 N Who has thegreater mass?
We are given the weight of two people, one on the moon and the other on earth. To determine the mass we will use the following formula:
[tex]W=mg[/tex]Where:
[tex]\begin{gathered} W=\text{ weight,}\lbrack N\rbrack \\ m=\text{ mass,}\lbrack kg\rbrack \\ g=\text{ acceleration of gravity, }\lbrack\frac{m}{s^2}\rbrack \end{gathered}[/tex]Now, we solve for the mass "m" by dividing both sides by "g":
[tex]\frac{W}{g}=m[/tex]Now, for the case of the moon we have that the acceleration of gravity is:
[tex]g_{moon}=1.62\frac{m}{s^2}[/tex]Plugging in the values:
[tex]\frac{160N}{1.62\frac{m}{s^2}}=m[/tex]Solving the operations:
[tex]98.77kg=m[/tex]Now, for the case of the earth we have:
[tex]g_{\text{earth}}=9.8\frac{m}{s^2}[/tex]Plugging in the values:
[tex]\frac{882N}{9.8\frac{m}{s^2}}=m[/tex]Solving the operations:
[tex]90kg=m[/tex]Therefore, the greater mass is the mass of Bob.
Shiyon just received his first credit card in the mail. His mom reminded him that he needs to order a new pair of baseball cleats. In order to make sure his browser is secure for the transaction, he should
(A) use the same password for all accounts
(B) install Microsoft Excel
(C) enable pop-ups
(D) deactivate background scripts
Answer:
the answer is D
Explanation:
i got it right on the test
In order to make sure his browser is secure for the transaction, Shiyon should deactivate background scripts. Hence, option (D) is correct.
What is background scripts?Without the requirement to create a trigger or script like a business row, a background script provides a free-form method of instantly running server-side code. When you want to clean a modest amount of data that doesn't call for a lot of intricate adjustments, we recommend using a background script.
You could get around that if you need to update records that may be subject to several scripts running on them—as long as they are small or decent in size, not excessive. You'll discover a few techniques to work around that.
Your transaction may run for hours when you run a background script, but this one will end it after four hours.
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what is scientific knowledge
Answer: Based on evidence
Explanation: Scientific knowledge is based on evidence and is included in scientific theories: consistent and deductively complete sets of propositions around a topic of scientific interest, which describe it and give it a verifiable explanation.
what does it mean to have a velocity of 10 m/s?
A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-g bullet moving with a speed of 1.50 x 103 m/s. What must the baseball’s speed be if the pitcher’s claim is valid?
ANSWER
3.10 x 10⁴ m/s
EXPLANATION
Given:
• The mass of the baseball. m₂ = 0.145 g
,• The mass of the bullet, m₁ = 3.00 g
,• The speed of the bullet, v₁ = 1.50 x 10³ m/s
Find:
• The speed of the ball, v₂, if it has the same momentum as the bullet.
The momentum of an object of mass m moving at a speed v is,
[tex]p=mv[/tex]So, in this problem, if both objects have the same momentum,
[tex]m_1v_1=m_2v_2[/tex]Solving for v₂,
[tex]v_2=\frac{m_1v_1}{m_2}[/tex]Replace the known values and solve,
[tex]v_2=\frac{3.00\text{ }g\cdot1.50\times10^3\text{ }m/s}{0.145\text{ }g}\approx3.10\times10^4m/s[/tex]Hence, the speed of the baseball must be 3.10 x 10⁴ m/s.
Josh has 12 blue marbles and 7 red marbles. Write the ratio of blue marbles to red marbles.
ANSWER
[tex]12\colon7[/tex]EXPLANATION
Josh has 12 blue marbles and 7 red marbles.
To find the ratio of blue marbles to red marbles, we have to write them in the form:
[tex]a\colon b[/tex]Therefore, the ratio of blue marbles to red marbles is:
[tex]12\colon7[/tex]Set the cannon to have an initial speed of 15 m/s. For which situation do you think the cannon ball will be in the air for the longest time: if it is set at a 60-degree angle, or if it is set at a 70-degree angle?
Question 6 options:
60 degree
70 degree
The cannon ball will be in the air for the longest time if the the angle of projection is set at 70 degrees
How to determine which angle will result in longest time
Case 1:
Initial velocity (u) = 15 m/sAngle of projection (θ) = 60 ° Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) =?T = 2uSineθ / g
T = (2 × 15 × Sine 60) / 9.8
T = 25.98 / 9.8
T = 2.65 s
Case 2:
Initial velocity (u) = 15 m/sAngle of projection (θ) = 70 ° Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) =?T = 2uSineθ / g
T = (2 × 15 × Sine 70) / 9.8
T = 28.19 / 9.8
T = 2.88 s
From the above calculations, we can conclude that the ball will stay longer in air if the angle is 70 °
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A 50-ω resistor is connected to a 9.0 V battery. How much thermal energy is produced in 7.5 minutes?1.2 102 J1.3 103J3.0 102 J7.3 102 J
The power consumed by the resistor can be expressed as,
[tex]P=\frac{V^2}{R}[/tex]Substitute the given values,
[tex]\begin{gathered} P=\frac{(9.0V)^2}{50\text{ }\Omega}(\frac{1\text{ W}}{1V^2\Omega^{-1}}) \\ =1.62\text{ W} \end{gathered}[/tex]The thermal energy produced in the given time can be expressed as,
[tex]E=Pt[/tex]Plug in the known values,
[tex]\begin{gathered} E=(1.62\text{ W)(7.5 min)(}\frac{60\text{ s}}{1\text{ min}}) \\ =729\text{ J} \\ \approx7.3\times10^2\text{ J} \end{gathered}[/tex]Thus, the thermal energy produced is 7.3*10^2 J which means fourth option is correct.
A rectangular loop of wire with a cross-sectional area of 0.118 m2 carries a current of 0.679 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 0.179 T. The plane of the loop is initially at an angle of 22.09o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?
Given:
The area of the rectangular loop is,
[tex]A=0.118\text{ m}^2[/tex]The current in the loop is,
[tex]I=0.679\text{ A}[/tex]The magnetic field is of strength
[tex]B=0.179\text{ T}[/tex]The plane of the loop is at an angle
[tex]\theta=22.09\degree[/tex]To find:
The magnitude of the torque on the loop
Explanation:
The torque on a current-carrying loop is,
[tex]\begin{gathered} \tau=IABsin\theta \\ =0.679\times0.118\times0.179\times sin22.09\degree \\ =5.39\times10^{-3}\text{ N.m} \end{gathered}[/tex]Hence, the torque is
[tex]5.39\times10^{-3}\text{ N.m}[/tex]A gardener mows a lawn with an old-fashioned push mower. The handle of the i mower makes a 32° angle with the surface of the lawn.
a)If a 68N force is applied along the handle of the 17kg mower, what is the force exerted by the lawn on the mower? b）If the angle between the surface of the lawn and the handle of the mower is increased, does this force increase, decrease, or stay the same? Explain.
The force exerted by the lawn on the mower is 202 N when applied 68N force along the handle.
What is force and how come it be 202 N and how it decreases?Whenever we talk of force we talk of Newton as is discovered by him and so the unit of force is Newton.Force is simply a push or pull but stating it in Newton's way it is the product of mass and acceleration.Here is given that the handle is making a 32 degree angle with the surface of the lawn.Applying 68 N force along the handle of 17 kg mower the force exerted would be 202 N , here we have to encounter the normal force.The normal force would approach the force due to gravity because there is decreased force from the handle.To know more about force visit:
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An ore cart of mass 1200 kg is rolling at a speed of 12.8 m/s across a flat surface a crane dumps 338 kg of ore into the cart from directly above it how fast does the cart move after being loaded with ore assume that frictional forces with the flat surface are negligible
Given,
The mass of the cart, M=1200 kg
The speed of the cart before the ore is dumped, u=12.8 m/s
The mass of the ore dumped on the cart, m=338 kg
From the law of conservation of momentum, the total momentum of the system of the cart and the ores before and after the ore is dumped into the cart must be equal.
Thus,
[tex]Mu=(M+m)v[/tex]Where vis the speed of the cart after the ore is dumped.
On substituting the known values in the above equation,
[tex]\begin{gathered} 1200\times12.8=(1200+338)v \\ \Rightarrow v=\frac{1200\times12.8}{1200+338} \\ =9.99\text{ m/s} \\ \approx10\text{ m/s} \end{gathered}[/tex]Thus the speed of the loaded cart will be 10 m/s
Wei drags a heavy piece of driftwood for 940 m along an irregular path. If Wei ends 710 m from where he starts, exerting a constant force of 625 N parallel to his path the entire time, how much work does he do?
Answer:
587500
Explanation:
Since Wei will still hit every point of the path even though it is irregular, you do not have to worry about the displacement in this problem, just the original path (940m).
W= F x D
587500 = 625N x 940M
3. Find for the total resistance of the series-parallel circuit below
In order to find the total resistance, first let's calculate the total resistance between R2 and R3, which are in series, so the total resistance is the sum:
[tex]R23=R2+R3=3+2=5\text{ ohms}[/tex]Now, let's calculate the total resistance between R23 and R1, which are in parallel, so we use the equation below:
[tex]R123=\frac{R23\cdot R1}{R23+R1}=\frac{5\cdot6}{5+6}=\frac{30}{11}=2.727\text{ ohms}[/tex]Finally, we calculate the total resistance between R123 and R4, which are in series:
[tex]RT=R4+R123=3+2.727=5.727\text{ ohms}[/tex]A person walks 8 km east, turns and walks 5 km west, then turns back around and walks 3 km, east.
What is the distance traveled of the person from the initial point to ending point?
A person walks 8 km east, turns and walks 5 km west, then turns back around and walks 3 km, east. Total distance traveled of the person from the initial point to ending point will be 16 km
Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.
total distance = 8 km + 5 km + 3 km = 16 km
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d. Use trigonometry to resolve the following vectors into component
Describe the vectors using vector notation.
v ≈ (3.28512, 20.74146) (3.28512, 20.74146)
In trigonometry, what is a vector?
Vectors can be used to depict motion between points in the coordinate plane. A vector is just a line segment in a specified location with an arrow designating its length and direction. The vectors in the following
Detailed explanationv = 21 (cos (81°), sin (81°))
components for v (3.28512, 20.74146) (x, y)
Authors use different notations. You can write the vector as...
(r, θ) = (21, 81°)
r∠θ = 21∠81°
21 cis 81° = r cis
v = 21·e^(i·9π/20)
(x, y) ≈ (3.28512, 20.74146) (3.28512, 20.74146)
v = 3.28512i +20.74146j Maybe this is the vector notation you're looking for (i and j are unit vectors in the x- and y-directions, respectively)
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Jake throws a rock downward from his deck at time t = 0 and it lands in his yard below.
Which of the following graphs best shows the velocity u of the rock until it hits the ground?
A graph of velocity vs time displays the change in an object's velocity in a straight line with regard to time.
What is meant by Velocity-time graph?A plot between speed and time is called a velocity-time graph. It depicts the motion of an object moving straight ahead. At any given time, the magnitude of velocity equals its instantaneous speed.
A graph of velocity vs time displays the change in an object's velocity in a straight line with regard to time. The x-axis is used to measure time, and the y-axis is used to measure velocity. For an item moving at a constant velocity, the height of the velocity-time graph does not change over time.
We can use a velocity vs. time graph to determine position and a time graph to determine velocity. We are aware that v = d/t. Rearranging the equation with a little mathematics reveals that d = v × t.
The complete question is:
Jack throws a rock downward from his deck at time t = 0 and it lands in his yard below. Make velocity-time graph of the rock until it hits the ground? Assume upward is the positive direction.
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6kg of human blood at a temperature of 65degees celcius is mixed with 4kg of human blood ata temperature of 20 degrees celcius . evaluate the final temperature of the mixture
Answer:
[tex]T_f=47^{\circ}[/tex]Explanation: Two samples of blood that have different masses and temperatures and are mixed, we have to find the final temperature of the mixture. the final temperature can be found using the following formula:
[tex]T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1)[/tex](1) Formula basically tells us that the product of mass and temperature remains constant throughout, so the addition of two products of the two separate blood samples would be equal to the product of final temperature and the total mass of the mixture. Mathematically this means that:
[tex]\mleft(m_1+m_2\mright)T_f=(m_1\cdot T_1)+(m_2T_2)[/tex]Using (1) and plugging in the corresponding values, we get the answer as follows:
[tex]\begin{gathered} T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1) \\ m_1=6\operatorname{kg} \\ m_2=4\operatorname{kg} \\ T_1=65^{\circ} \\ T_2=20^{\circ} \\ \therefore\rightarrow \\ T_f=\frac{(6kg\cdot65^{\circ}+4\operatorname{kg}\cdot20^{\circ})}{(6kg+4\operatorname{kg})}=\frac{(390+80)}{10}=\frac{470}{10}=47^{\circ} \\ \therefore\rightarrow \\ T_f=47^{\circ} \end{gathered}[/tex]What in the final position of a robot that starts from (0, 0) m and makes displacements of (4.4) * m (3.3) * m and (- 4, - 2) m?
The final position of the robot is (3, 5) m
Explanation:The initial position of the robot = (0, 0)
The position of the robot after making a displacement of (4, 4)m = (0+4, 0+4)
The position of the robot after making a displacement of (4, 4)m = (4, 4) m
The new position of the robot after making a displacement of (3, 3)m
= (4+3, 4+3)m
The new position of the robot after making a displacement of (3, 3)m =(7, 7)m
The final position of the robot after making a displacement of (-4, -2)m
= (7-4, 7-2)
The final position of the robot after making a displacement of (-4, -2)m
= (3, 5)m
Therefore, the final position of the robot is (3, 5) m
Calculate the wavelength of a light that has an energy of 9.55x10^-19J.
ANSWER
[tex]2.08\cdot10^{-7}m[/tex]EXPLANATION
To calculate the wavelength of light, we have to apply the formula for the energy of light:
[tex]E=\frac{hc}{\lambda}[/tex]h = Planck's constant
c = speed of light
λ = wavelength
Therefore, we have that:
[tex]\lambda=\frac{hc}{E}[/tex]The wavelength of the light is:
[tex]\begin{gathered} \lambda=\frac{6.626\cdot10^{-34}\cdot3\cdot10^8}{9.55\cdot10^{-19}} \\ \lambda=2.08\cdot10^{-7}m \end{gathered}[/tex]A boat is moving across a 100 meter wide stream at 5 m/s. If the stream is flowing south at 10 m/s, how long will it take the boat to cross the river?
answer:
20 minutes for 5 m/s 10 minutes for 10 m/s
An object of 31.3 kg is at rest. You apply a constant force to this object and the object moves a distance of 103 m in 13 s. find the acceleration produced by your force.
The acceleration produced by your force is determined as 1.22 m/s².
What is the acceleration of the object?
The acceleration of the object is the rate of change of its velocity with time.
Apply the following kinematic equation to solve the acceleration of the object.
s = vt + ¹/₂at²
where;
s is the distance travelled by the objectv is the initial velocity of the object = 0t is the time of motion of the objecta is the acceleration of the objects = ¹/₂at²
103 = ¹/₂a(13)²
103 = 84.5a
a = 103/84.5
a = 1.22 m/s²
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if the mass of the paper is 0.003 kg, what force does the boxer except on it?
Answer:
1.15 N
Explanation:
You want to know the force exerted on a mass of 0.003 kg to accelerate it from 0 to 23 m/s in a period of 0.06 s.
AccelerationThe acceleration of the mass is the change in velocity divided by the change in time:
a = ∆v/∆t
a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²
ForceThe force applied is the product of mass and acceleration:
F = ma
F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N
The applied force is 1.15 newtons.
What’s the magnitud of the force?
F=(557N)i-(611N)j+(468N)k
Answer: 950.05 N
Explanation:
Which of the following statements is always true?
a.
Pressure always increases when force increases or the area acted on increases.
b.
Pressure always increases when force increases or the area acted on decreases.
c.
Pressure always increases when force decreases or the area acted on increases.
d.
Pressure always increases when force decreases or the area acted on decreases
The statement that is true is that pressure always increases when force increases or the area acted on decreases (option B).
What is pressure?Pressure is the amount of force that is applied over a given area divided by the size of this area.
The pressure applied to a surface can be calculated by dividing the force required by the area of the surface as follows:
P = F/A
The above shows that the pressure of a body is inversely proportional to the area but directly proportional to the force.
This means that as the pressure of an object increases, the force increases while the area acted on decreases.
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number 16part b: what is the speed of the combined vehicles after the collison?
velocity = p/m
p = momentum= 51,000 kgm/s
m = mass = 3,000+2,000= 5,000kg
v= 51,000 kgm/s / 5000 kg = 10.2 m/s
You observe that 34 crests of a water wave pass you each minute. if the wavelength is 12 m, what is the speed of the wave?
ANSWER:
6.8 m/s
STEP-BY-STEP EXPLANATION:
We must calculate the frequency, knowing that per minute (60 seconds) there are 34 crests, therefore:
[tex]f=\frac{34}{60}=0.57\text{ Hz}[/tex]Therefore, the speed of the wave would be:
[tex]\begin{gathered} s=f\cdot w \\ s\text{ =speed} \\ f=\text{ frequency = 0.57 Hz} \\ w\text{ = wavelength = 12 m} \end{gathered}[/tex]Replacing:
[tex]\begin{gathered} s=0.57\cdot12 \\ s=6.8\text{ m/s} \end{gathered}[/tex]The speed of the wave is 6.8 m/s
Under a pressure of 14Nm-2, some air has
a volume of 1.5m3. Determine its volume
when its pressure is 10Nm-2. Assuming the
temperature is kept constant
Answer:
2.1 m³
Explanation:
Boyle's Law states:
The absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies if the temperature and amount of gas remain unchanged within a closed system (Wikipedia) }
We can express this relationship as
[tex]P \propto \dfrac{1}{V}[/tex]
where V is the volume under pressure P
This can be re-written as:
PV = a constant
We are given that [tex]$V = 1.5m^3$[/tex] when [tex]$P = 14N/m^2$[/tex]
So PV = 1.5 x 14 = 21 Nm
At [tex]10 N/m^2[/tex] the PV product must also be 21
So 10V' = 21 where V' = volume at [tex]\displaystyle 10 N/m^2[/tex]
Therefore V' = 21/10 = 2.1 m³