If a,b,c,d are in GP, the. (a² + b² + c²)(b² + c² + d²) is equal to

​

[tex] \text{Given a,b,c and d are in GP}[/tex]

[tex] \therefore \frac{b}{a} = \frac{ c}{b} = \frac{d}{c} = r \\ \\ \implies b = ar ,c = br,d = cr \implies \: b = ar,c = (ar)r,d = (br)r \\ \\ \implies b = ar,c = a {r}^{2} ,d = {br}^{2} \implies b = ar,c = {ar}^{2} ,d = (ar)r {}^{2} = a {r}^{3} ...(i)[/tex]

[tex] \text{Now, Consider}[/tex]

[tex]( {a}^{2} + {b}^{2} + {c}^{2} )( {b}^{2} + {c}^{2} + {d}^{2} ) = ( {a}^{2} + {a}^{2} {r}^{2} + ( {a}^{2} {r}^{4} )( {a}^{2} {r}^{2} + {a}^{2} r {}^{2} + {a}^{2} {r}^{4} + {a}^{2} {r}^{6} )[/tex]

[tex] = {a}^{2} (1 + {r}^{2} + {r}^{4} ) {a}^{2} {r}^{2} (1 + {r}^{2} + {r}^{4} ) = a {}^{4} {r}^{2} (1 + {r}^{2} + {r}^{4} ) {}^{2} = [a {}^{2}r(1 + {r}^{2} + {r}^{4}) ] {}^{2} [/tex]

[tex] = ( {a}^{2} r + {a}^{2} {r}^{3} + {a}^{2} r {}^{5} ) {}^{2} = (a. \: ar + ar. \: a {r}^{2} + a {r}^{2} .a {r}^{3} ) {}^{2} [/tex]

[tex] = (ab + bc + cd) {}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \text{[From Equation (i)]}[/tex]

Hope This Helps!!! :)

The given polynomial can be rewritten as factors of the common ratio of

the geometric progression.

Response:

If a, b, c, d are in GP, (a² + b² + c²) × (b² + c² + d²) = [tex]\underline{(a\cdot b + b \cdot c + c\cdot d)^2}[/tex]

The assumed parameters are;

a, b, c, and d for a geometric sequence

Therefore;

[tex]\mathbf{\dfrac{b}{a}} = \dfrac{c}{b} = \dfrac{d}{c} = r[/tex]

Which gives;

b = a·r

c = b·r

d = c·r

Therefore;

c = b·r = a·r²

d = c·r = a·r³

(a² + b² + c²) × (b² + c² + d²) = (a² + (a·r)² + (a·r²)²) × ((a·r)² + (a·r²)² + (a·r³)²)

(a² + a²·r² + a²·r⁴) × ((a²·r²) + (a²·r⁴) + a²·r⁶) = a⁴·r²·(r⁸ + 2·r⁶ + 3·r⁴ + 2·r² + 1)

Which gives;

a⁴·r²·(r⁸ + 2·r⁶ + 3·r⁴ + 2·r² + 1) = a²·r·(r⁴ + r² + 1) × a²·r·(r⁴ + r² + 1)

a²·r·(r⁴ + r² + 1) × a²·r·(r⁴ + r² + 1) = (a²·r·(r⁴ + r² + 1))²

a²·r·(r⁴ + r² + 1) = a²·r⁵ + a²·r³ + a²·r

a²·r = a·b

a²·r³ = b·c

a²·r⁵ = c·d

Therefore;

a²·r⁵ + a²·r³ + a²·r = a·b + b·c + c·d

(a² + b² + c²) × (b² + c² + d²) = (a²·r·(r⁴ + r² + 1))² = [tex]\underline{(a\cdot b + b \cdot c + c\cdot d)^2}[/tex]

Learn more about geometric progression (GP.) here:

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