If a racer maintained a constant speed, during which sections of the race would the racer's velocity be the same?

Sections 1 and 2
Sections 2 and 3
Sections 2 and 4
Sections 3 and 4

pls help!!​

If A Racer Maintained A Constant Speed, During Which Sections Of The Race Would The Racer's Velocity

Answers

Answer 1

Answer:

Sections 3 and 4

Explanation:

The correct answer would be sections 3 and 4.

The velocity of an object is the speed of the object in a particular direction. In this case, the speed of the racer is constant irrespective of the distance or the direction. Hence, the sections of the race during which the racer's velocity would be the same would be the sections in which the racer faces the same direction - which is sections 3 and 4.


Related Questions

a pulling force carried by a rope is called what

Answers

Answer:

The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Explanation:

Why does sonar use ultrasound rather than sound?

Answers

Answer;  Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.

Answer:

Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances

Explanation:

Why do oil tankers sit lower in water

Answers

When a lower tank is damaged, the incoming sea water pushes the oil in the damaged tank up into the ballast tank. Because of the hydrostatic pressure, there is an automatic transfer out of the damaged tank. The double-hull design is aimed at the probability of zero outflow.

What disagreement did Sigmund Freud have with both Josef Breuer and Jean Martin Charcot?
A. whether hypnosis was a neurological or psychological phenomenon
B. whether hypnosis should be conducted with pregnant women
C. whether hypnosis had any value as a curative remedy for patients
D. whether hypnosis was an effect of a "hidden observer" or the id

Answers

Answer:

The correct answer is 'A'

Explanation:

I guessed and was correct.

Freud backed Bernheim's efforts to establish hypnosis and suggestion as acceptable fields of study for science and to advance them as therapeutic tools. Thus, option A is correct.

What is the neurological or psychological phenomenon?

Both neurologists and psychiatrists treat illnesses and ailments that affect the brain and the psyche. However, while psychiatrists focus on psychological issues, neurologists are experts in physiological illnesses.

According to medical terminology, neurological disorders are conditions that impact the spinal cord, brain, and body's nerves.

A variety of symptoms can be caused by structural, metabolic, or electrical abnormalities in the brain, spinal cord, or other nerves.

Therefore, whether hypnosis was a neurological or psychological phenomenon.

Learn more about neurological or psychological here:

https://brainly.com/question/28702031

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Carlos gets tired of pushing and instead begins to pull with force Fpull at an angle to the horizontal.
The block slides along the rough horizontal surface at a constant speed. A free-body diagram for the
situation is shown below. Blake makes the following claim about the free-body diagram:
Blake: “The velocity of the block is constant, so the net force exerted on the block must be zero.
Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied
force Fpull.”
What, if anything, is wrong with this statement? If something is
wrong, identify it and explain how to correct it. If this statement is
correct, explain why.

Answers

Answer:

The wrong items are;

1) The normal for FN equals the weight Fmg

2) The force of friction, Ff, equals the applied force Fpull

The corrected statements are;

1) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ)

Explanation:

The given statement was;

The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull

By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;

The normal force is equal to the weight less the vertical component of the applied force;

That is we have, FN = Fmg - Fpull × sin(θ)

The friction force similarly, is equal to the horizontal component of the applied force;

Ff = Fpull × cos(θ)

The wrong items are therefore as follows;

1) The normal for FN equals the weight Fmg

1 i) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction, Ff, equals the applied force Fpull

2 i) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ).

if two objects are repelled from each other which force most likely caused this?

A. gravitational

B. weak nuclear

C. electromagnetic

D. strong nuclear

Answers

C. electromagnetic

Answer:

it's C! electromagnetic

Explanation:

Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car

Answers

Answer:

3m/s^2

Explanation:

Acceleration is change in velocity / time = 45/15 = 3m/s^2

Dos pilotos suicidas, que están inicialmente a una distancia de 500 m entre sí, deciden chocar directamente de frente arrancando ambos desde el reposo. Ambos autos pueden desarrollar una aceleración máxima constante de 15 m/s2 . Si el piloto A arranca un segundo antes que el piloto B, encuentra: a) la posición donde los autos chocan, medida a partir de la posición donde arranca el piloto A, y b) la rapidez relativa de la colisión (la rapidez de B con respecto a A justo antes de la colisión, ó viceversa).

Answers

Answer:

a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.

b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s

Explanation:

Los parámetros del movimiento son;

La distancia entre ambos coches = 500 m

La aceleración de ambos coches = 15 m / s²

La dirección de movimiento de ambos coches = uno hacia el otro

La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B

Por lo tanto, de la ecuación de movimiento, tenemos;

s = u · t + 1/2 · a · t²

v² = u² + 2 · a · s

Dónde;

u = La velocidad inicial de los autos = 0 (los autos parten del reposo)

t = El tiempo de movimiento de una aceleración dada

a = La aceleración = 15 m / s²

s = La distancia recorrida en el tiempo t

Por lo tanto, para el controlador A, tenemos;

s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²

s₁ = 7.5 × (t + 1) ²

Para el conductor B, tenemos;

s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²

s₂ = 7,5 × t²

Dado que ambos chocan a lo largo del camino de 500 m, tenemos;

s₁ + s₂ = 500 metros

∴ 7.5 × (t + 1) ² + 7.5 × t² = 500

∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²

Lo que da;

15 · t² + 15 · t + 7.5 = 500

15 · t² + 15 · t - 492,5 = 0

Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181

Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos

a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;

s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros

El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros

b) La semilla de A en el punto de colisión se da de la siguiente manera

Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78

v₁ ≈ 93,78 m / s

La semilla de B en el punto de colisión también se da de la siguiente manera

Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78

v₁ ≈ 78,78 m / s

Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;

 = v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s

la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.

is isopropyl alcohol a element compound or mixture

Answers

Answer:

Isopropyl is an element compound.

Explanation:

What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds

Question 2 options:

PNF


ballistic


dynamic


static

Answers

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

HELLO! Please Help me.
I can't do it! it's Science ​

Answers

Answer:

9V

Explanation:

V=IR

V=2.5*3.6

V=9

Answer:

9V

Explanation:

V =IR

V =2.5 * 3.6

V = 9V

What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)

Answers

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec)  =  1,058 meters .

The distance required for the train to travel before stopping is 1,058 m.

The given parameters;

initial velocity of the train, u = 23 m/s

deceleration of the train, a = 0.25 m/s

The distance traveled by the train is calculated as follows;

[tex]v^2 = u^2 -2as[/tex]

where;

v is the final velocity of the train

The final velocity of the train is zero when the train stops

[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]

Thus, the distance required for the train to travel before stopping is 1,058 m.

Learn more here: https://brainly.com/question/23852683

You're driving your car at a constant speed in a straight line which of the following can be used to cause your car to experience a centripetal acceleration
A)brake pedal
B) steering wheel
C)gas pedal
D)All of the above

Answers

The answer is B. Centripetal acceleration is when you accelerate in a circle which the steering wheel is the only one that can cause you to accelerate like that.

What is the weight of a body at a centre of Earth​

Answers

The weight of a body placed at centre of Earth is 0. Because the mass at the exact cenrte of the earth is zero.
the weight of the earth is 0

Which force is involved in kicking a ball?

1. Frictional force

2. Pushing force

Answers

Answer:

Pushing force

Explanation:

You technically push a ball when kicking it.

4. Why do chemists use relative masses of atoms compared to a reference isotope rather than the
actual masses of the atoms?
a. The actual mass of an electron is very large compared to the actual mass of a proton.
b. The actual masses of atoms are very small and difficult to work with.
c. The number of subatomic particles in atoms of different elements varies.
d. The actual masses of protons, electrons, and neutrons are not known.

Answers

Answer:

B

Explanation:

Answer:

answer is B

Explanation:

took the test

match the letter with the layer

Answers

Answer:

Thermosphere A,B

Mesosphere B,C,D

Stratosphere D,E,F

Troposphere G

Hope this helps please give me brainliest!

God bless :)

The amount of matter in a substance or object is called:
??? What the answer

Answers

Answer:

mass!!

Explanation:

Light is produced by which fundamental force?
strong nuclear
electromagnetic
weak nuclear
gravitational

Answers

Answer:

ans: Electromagnetic

Answer:

B on edg.

Explanation:

please help
Which equipment is best to hold and to measure liquids?
A). flask and graduated cylinder
B). scale and ruler
C). caliper and thermometer
D). stopwatch and beaker

Answers

Answer:

I'm pretty sure that the answer is A

a car ends up at x = -245 m after a displacement of -103 m. what was its initial position?

Answers

Answer:

-142m

Explanation:

To find the initial position of the car, we can add the displacement.

-245 + 103 = -142

Best of Luck!

A. 2kg

B. 6kg

C. 8kg

D. 14kg

Answers

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

Mass refers to the gravitational force on the matter in contact with the surface of a planet. true or false

Answers

Answer:

False

Explanation:

The mass of something does not depend on gravity. A planet has a constant gravitational force. Earth's is 9,80 N/kg. The moon, on the other hand, is 1,6 N/kg. the number of kilograms of something doesn't change if you go from one planet to another and since mass is measured in kilograms, mass doesn't change, therefore it does not refer to gravity. Mass refers to the quantity of matter in an object. It is weight that refers to the gravitational force on an object, since it is measured in newtons, and the amount of newtons per kilogram changes from planet to planet due to different gravity constants

Ben has two carts with masses of 0.1 kg and 0.2 kg. He pushes the smaller cart toward the larger cart and they collide. The smaller cart rebounds back in the direction it came from. He measures the force on the smaller cart from the larger cart to be 5 N. What was the magnitude of the acceleration of the smaller cart?

Answers

Answer:

The acceleration of the smaller cart is 50 m/s²

Explanation:

The given masses of the carts are 0.1 kg and 0.2 kg

The direction in which the small cart bounces = In the revers to its initial direction

The force exerted by the larger cart on the small cart = 5 N

Therefore, we have;

Force acting on smaller cart = Mass of smaller cart  × Acceleration of the smaller cart

∴ The acceleration of the smaller cart = Force acting on smaller cart/(Mass of smaller cart)

The acceleration of the smaller cart = 5 N/(0.1 kg) = 50 m/s²

The acceleration of the smaller cart = 50 m/s².

3. Mount Everest, an eastern Himalayan peak on the Tibet-Nepal border, was discovered to be the world's highest mountain in March 1856. The Survey Department of the Government of India computed its height to be 29,002 ft. Express this height in scientific notation.

Answers

Answer:

   h = 2,9002 10⁴ ft

Explanation:

Scientific notation is a method to write very large and small numbers clearly, the figure is written with an integer and the other figures in decimals, with an exponent so that the number does not change.

If it is necessary to approximate a figure, the criterion is if the next figure is greater than or equal to five, the figure rises by one unit.

Mount Everest height

 

    h = 29002 ft

    h = 2,9002 10⁴ ft

if we approximate three significant figures that

     h = 2.90 10⁴ ft

Answer:

[tex]2.9002 \cdot 10^{4} ft[/tex]

Explanation:

To express the height 29,002 in scientific notation we need to move the decimal point four places to the left and express the answer into a base-ten power, as follows:

[tex]29,002 = 2.9002 \cdot 10^{4}[/tex]

The answer expressed in scientific notation results in 2.9002 times a ten to the fourth power, as a result of the four movements of the decimal point.  

   

I hope it helps you!                

please can i have help with this question ​

Answers

Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.

Which has more inertia, a car with a mass of 900kg or a car with a mass of 1,500kg. Explain your answer.

Answers

Answer:

Which has more inertia - a car with a mass of 900kg or a car with a mass of 1500kg - explain. The bigger the mass - the larger the inertia but you need to exert more force to start the movement.

Explanation:

explain how the air balloon moves up and down.
Explain in terms of density

Answers

The heat in the air ballon from the flame will create moisture in the ballon and make it rise

Answer:

hope it helps ....

Explanation:

The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.

16. True/False: Protons are exchanged between objects by induction

Answers

False: only electrons move through induction.

That
Vhy do people engage in various
e long answer to the following questions.
Which tradition of our society needs to be reform
and write the ways to reform them
of Nepal​

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Hey can you please help me?
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