If a driver brings a car traveling at 22m/s to a full stop in 2.0 s with an acceleration of -8 m/s2 then how far did the car travel while braking?

Answers

Answer 1

Answer:

v=u + at

0= 22 + a*2

a = -22/2 = -11 m/s^2

The car's acceleration is -11 m/s^2

V^2 = u^2 + 2as

022^2 + 2*(-11)s

s = 22^2/22 = 22m

The car will travel 22 m before stopping.

Explanation:

I hope it will help you have a great day bye and Mark brainlist if the answer is correct

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Related Questions

which factor should a student include in a model to explain differences in temperature at earthed equator and earths poles?

Answers

Answer:

The uneven heating of Earth by the sun causes the climate to be warm and dry at the equator and cold and wet toward the poles. The angle of sunlight is different at different latitudes, which causes the climate to be warm at the equator and colder toward the poles.

Explanation:

mark brainliest

Select all statements that are true.

Sound waves travel faster in water than in air.

Sound waves travel faster in air than in water.

Sound waves travel fastest through solids.

Sound waves travel slowest through liquids.

Answers

Sound waves travel faster in water than in air


Sound waves travel fastest through solids


As sound waves are mechanical waves

Do you think protection of one species can protect its community? Why?

Answers

Answer:

I think that protection of one species can not protect its community.

Explanation:

The advantage of protecting entire ecosystems is the most effective way to save species because species confined to a small area could be wiped out by a single natural disaster. Some species require a large range to find adequate food or mate. Therefore, protecting the habitats of endangered and threatened species often means preserving or managing large areas (entire ecosystem).

what parts of an electric generator are connected?

Answers

Answer:

The field and winding

Explanation: they are both connected

a computer printer has a width of 18in. What is it’s width

Answers

Answer:

0.46 m. hope this helps.

Answer:

0.46 Meters

Explanation:

Electric wires in between the poles are seen stretched in winter. Give Reason? ​

Answers

Electric wires/cables expand when temperature rises l

A heavy liquid with a density 13 g/cm3
is
poured into a U-tube as shown in the lefthand figure below. The left-hand arm of the
tube has a cross-sectional area of 9.55 cm2
,
and the right-hand arm has a cross-sectional
area of 6.08 cm2
. A quantity of 90.8 g of a
light liquid with a density 0.86 g/cm3
is then
poured into the right-hand arm as shown in
the right-hand figure below.
h1
h2
9.55 cm2
6.08 cm2
heavy liquid
13 g/cm3
L
9.55 cm2
6.08 cm2
light liquid
0.86 g/cm3
Determine the height L of the light liquid
in the column in the right arm of the U-tube,
as shown in the second figure above.
Answer in units of cm.

Part 2
Find the pressure on the window.
Answer in units of N/m

Answers

Based on the data provided;

the height of the liquid, L is 17.2 cmthe pressure on the window is 1449.616 N/m

What is the formula for density?

The formula for calculating density is given as:

Density = mass/volume

From the formula above;

mass = density × volume

also, volume = area × height

Therefore,

mass = density × area × height

height = mass / (density × area)

Calculating for the height of the liquid:

Height, L = 90.8 / (0.86 × 6.08)

L = 17.2 cm

What is pressure due to a liquid?

The pressure due to a liquid is calculated using the formula below:

Pressure = hpg

where;

h is height = 17.2 cm = 0.172 m

P is density = 0.86 g/cm^3 = 860 kg/m^3

g is acceleration due to gravity = 9.8 m/s^2

Pressure = 860 kg/m^3 × 0.172 m × 9.8 m/s^2

Pressure = 1449.616 N/m

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9 А
3) A 5kg object is to be given an upward
acceleration of
of 0.3 m/s by a rope pulling
straight upward on it, what must be the
tension on the
the rope ?

Answers

Explanation:

9 А

3) A 5kg object is to be given an upward

acceleration of

of 0.3 m/s by a rope pulling

straight upward on it, what must be the

tension on the

the rope ?

In a Capacitor of 0.000031 F. a charge of 0.000022 C. exists between the plates.If the separation is 0.7 mm, What is the electric field?

Answers

Answer:

1014 V/m

Explanation:

C = 0.000031 F. Q = 0.000022 C, d = 0.7 mm,

V = Q/C = 0.000022/0.000031 = 0.7097 V

E = V/d = 0.7097/0.0007 = 1014 V/m

If you are driving 80 km/h along a straight road and you look to the side for 2.1 s , how far do you travel during this inattentive period?

Answers

Velocity = displacement / time

First, Always make sure that your units for things are the same. In this question, we are given time in seconds and hours. So, we need to make them all use 1 unit.

I will do seconds.

To convert 80km/h to m/s, divide by 3.6.

22.2222…. m/s = displacement / 2.1s

Multiply by 2.1s on both sides

46.6666……m = displacement

You travelled 47 meters.

How long does it take light to travel through a 5.20- mm -thick piece of window glass?

Through what thickness of water could light travel in the same amount of time?

Answers

Explanation:

Explanation: The speed of light in a vacuum is 3⋅108 m/s . We can now convert to a more appropriate symbol, such as the nanoseconds. So, it will take light approximately 333

200,000 kilometers per secondrefractive index of 1.5).

What type of wave squeezes together and
pulls apart?
A. longitudinal wave
B. transverse waves
C. seismic waves
D. electromagnetic waves

Answers

Answer:

B, longitudinal moves up and down, seismic also,l

If a box that weighs 4.00 N slides across a flat rough table for a distance of 2.00 m then how much work does the weight of the box
do on the box?
A) 88.0 J
B) 456 J
C) 270 J
D) 513 J
E)zero

Answers

Answer:

0

Explanation:

Here it's given that the weight of the box is 4N and it slides across a rough table for a distance of 2m . And we are interested in finding out the work done by the weight of the block. Firstly we know that , Work done is ,

[tex]\rm\longrightarrow \pink{ Work\ = \ F.s = |F||s|cos\theta} [/tex]

where

[tex]\theta[/tex] is the angle between displacement and force .

Therefore ,

[tex]\rm\longrightarrow Work = (4N)(2m)(cos\theta) [/tex]

Here the angle between the displacement and force is 90° , and value of cos90° is 0 , therefore,

[tex]\rm\longrightarrow Work = 8N-m (0)\\[/tex]

[tex]\rm\longrightarrow \underline{\boxed{\rm\blue{Work = 0 }}}[/tex]

The work done by the weight of the box is zero. The correct answer is zero. The correct option is (E).

Given:

Weight of the box = 4.00 N (acting downward)

Distance = 2.00 m

The angle between force and displacement, θ = 90°

Using the formula for work:

Work (W) = Force × Distance × cos(θ)

Since the angle θ is 90 degrees and cos(90 degrees) = 0.

The work done by the weight of the box is:

W = Force × Distance × cos(90)

W = 4.00 × 2.00 × 0

W = 0 J

Therefore, the work done by the weight of the box is zero. The correct option is (E).

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Brainliest if correct Question 7 of 10
Which two options are forms of potential energy?
A. Nuclear energy
B. Electrical energy
C. Thermal energy
D. Sound energy
E. Chemical energy

Answers

Answer:

Electrical energy and Chemical energy

Explanation:

Good luck on the quiz dawg, I'm doing the same one LOL

You walk from chisale to st Francis a distance of 6km/h and 50minutes.Find the average speed in m/s​

Answers

Answer:

[tex]{ \tt{average \: speed = \frac{distance}{time} }} \\ \\ { \tt{ = \frac{(6 \times 1000) \: m}{(50 \times 60) \: s} }} \\ \\ { \tt{ = \frac{6000}{3000} }} \\ \\ = { \underline{ \tt{ \: 2 \: {ms}^{ - 1} \: }}}[/tex]

You walk from chisale to st Francis a distance of 6km/h and 50minutes,  the average speed in m/s​ will be 2m/s

What is average speed ?

The average speed of a moving object is defined as the total distance covered by it divided by the total time taken.

The S.I unit of speed is meter per second. Speed is also measured in kilometer per hour.

Average speed is a scaler quantity

Average speed is the total distance travelled by an object to the total time taken. However, average velocity is the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. No matter how many times the speed has been changed to travel the entire distance , average speed is that constant speed value with which one can travel by and reach the same distance in same amount of time .

It can be calculated with a formula average speed = distance / time

given

distance = 6 km = 6000 m

time = 50 minutes = 50 * 60 = 3000 sec

average speed = distance / time

                          = 6000 / 3000 = 2m/s

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A granite block is at rest on a horizontal surface in a vacuum chamber. The granite block is 3 cm tall, and the length and width are both 20 cm. The density of granite is 2.75 g/cm^3. What pressure does the block exert on the surface?

Answers

Answer:

M = V ρ = .03 * .2*2 cm^3 * 2.75 g / cm^3 = .0033 kg     weight

W = m g = .0033 kg * 9.80 m / s^2 = .032 N

P = F / A = W / A = .032 N / .2^2 m^2 = .80 N/m^2 = .80 Pascal

what is the meaning of energy

Answers

Answer:

Energy by definition is the property of matter that involves interactions with molecules, in order to perform an action.

Explanation:

They're many different types of energy, a few of them are...

. Thermal energy
. Solar energy
. Chemical energy
. Kinetic energy
. Potential energy
. Mechanical energy to name a few...

All of these specific energies involve the interaction of molecules which are used for different things and can be converted from one type of energy to another.

Hope this helps.

2. An object’s velocity is measured to be v (t) = αt−βt2, where α = 4.00 m/s2 and β = 2.00 m/s3. Calculate the average acceleration of the object from t = 0.0 s to t = 3.0 s

Answers

Hi there!

Given the values for α and β, we can plug these into the given equation:

[tex]v(t) = 4t - 2t^2[/tex]

Begin by solving for the velocity at t = 0 and t = 3:

At t = 0:
[tex]v(0) = 4(0) - 2(0^2) = 0 \frac{m}{s}[/tex]

At t = 3:
[tex]v(3) = 4(3) - 2(3^2) = 12 - 18 = -6 \frac{m}{s}[/tex]

Acceleration is the SLOPE of the velocity graph (its derivative), so we can use the kinematic equation:

[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]

Plug in the knowns:

[tex]a = \frac{-6-0}{3 - 0} = \boxed{-2 \frac{m}{s^2}}[/tex]

A 2kg mass is at a height of 3m. What is its gravitational potential energy(use g=10)

Answers

Answer:

potential difference

= m × g × h

= ( 2 × 10 × 3 )

= 60 Joules

Answer:

PE = 60 J

Explanation:

Where:

PEg or PE = gravitational potential energy

m = mass of an object

g = acceleration due to gravity

h = height of the object

brnaliest

How many feet up high should I be required to wear a harness?

Answers

Answer:

About 6 feet or higher is recommended.  

Explanation

Brainliest if correct Question 2 of 10
What two types of energy does a rock have as it rolls down a hill?
O A. Sound energy
B. Potential energy
c. Nuclear energy
D. Kinetic energy
E. Magnetic energy
SUBMI

Answers

Answer:

b and d

Explanation:

How much force is needed to pull a spring with a spring constant of 20 N/m a distance of 25 cm?

Answers

A force of 5N is needed to pull this spring a distance of 25 cm

7th grade science i mark as brainliest ​

Answers

I feel like it would be incomplete dominance because neither height is the dominant one because they can vary from tall to short.

A 5 kg block is placed near the top of a frictionless ramp, which makes an angle of 30o degrees to the horizontal. A distance d = 1.3 m away from the block is an unstretched spring with k = 3 × 103 N/m. The block slides down the ramp and compresses the spring.

Required:
Find the maximum compression of the spring.

Answers

The maximum compression of the spring is 0.146 m.

Work Energy theorem

The work done by the block when it slides down the ramp will be converted to elastic potential energy of the spring.

W = U

Fd = U

where;

F is the horizontal component of the block weight

mgsin(θ) x d = ¹/₂kA²

[tex]A^2 = \frac{2mg sin(\theta)d}{k} \\\\A = \sqrt{\frac{2mg sin(\theta)d}{k}} \\\\A = \sqrt{\frac{2(5 \times 9.8) sin(30)\times 1.3}{3\times 10^3}}\\\\A = 0.146 \ m[/tex]

Thus, the maximum compression of the spring is 0.146 m.

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A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g, what is the radius of a single jawbreaker

Answers

The radius of each jawbreaker is approximately 0.68 cm.

Volume of a sphere;v = 4 /3 πr³

where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

r = 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

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a computer printer has a width of 18in. What is it’s width in meters

Answers

Answer:

0.4572 m

Explanation:

To convert inch to metre, divide the value by 39.37.

=》1 inch = 0.0254 metre

So,

18/39.37 = 0.4572 m

Hope it helps ⚜

The width of the printer is 0.4572 meters.

What is metric conversion system?

The metric conversion system is a standardized system of measurement based on the International System of Units (SI). It is used by scientists, engineers, and many others around the world to ensure consistency and accuracy in measurement.

The system is based on a series of prefixes that can be added to a base unit of measurement to create multiples or fractions of that unit. For example, the prefix "kilo-" means "thousand," so one kilometer is equal to 1,000 meters. The metric system is widely used in scientific and technical fields and is also the official system of measurement for many countries.

To convert inches to meters, we can use the conversion factor 1 inch = 0.0254 meters.

So, the width of the printer in meters is:

18 inches x 0.0254 meters/inch = 0.4572 meters

Learn more about metric conversion, here:

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if i release one steel ball from the top of a ramp and the other ball from the 40cm mark will they have the same velocity?

Answers

Answer:

Yes.

Explanation:

Assuming that the balls weigh the same, then they would have the same velocity. Velocity is the term used to describe the speed at which an object is traveling.

A 288-gram cart starts from rest and rolls down an inclined plane from a height of 1.226 m. Determine its speed (in m/s) at a height of 0.126 m above the bottom of the incline. Assume friction is negligible

Answers

The law of conservation energy

PE₁ + KE₁ = PE₂ + KE₂

From rest ⇒ v₁ = 0 ⇒ KE₁ = 0

Input the value:

PE₁ = PE₂ + KE₂

[tex]\tt mgh_1=mgh_2+\dfrac{1}{2}mv_2^2\rightarrow divide\:m\\\\gh_1=gh_2+\dfrac{1}{2}v_2^2\\\\9.8(1.226-0.126)=\dfrac{1}{2}v_2^2\\\\v_2=4.64\:m/s[/tex]

What is the mass of a material whose temperature changes from -12°C to 80°C when 4,577 J heat energy is added to it if the specific heat capacity of the material
is 7.0 J/g°C? Give your answer to 2 decimal places.

Answers

[tex] \frac{4577}{7 \times (80 - ( - 12))} \\ \frac{4577}{7 \times92 } \\ \frac{4577}{644} \\ = 8.5g[/tex]

what is an example of friction on an object in motion?

Answers

A ball rolling on a carpet!

Answer:

Friction drag force causes objects to slow down as they move through a fluid, such as air or water. ... As an object's speed increases, the drag force from the fluid increases exponentially. • For example, when you drive at high speeds, the frictional force of air on the car increases, and fuel economy decreases.

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