If 6.95 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 ——- CO2 + H2OHow many moles of O2 is required? Answer in units of mol.

The heat of reaction is obtained from the calculation as -0.65kJ/mol.

We already know that the heat of the reaction is computed by the use of the information that have been presented in the question. We know that this is a 1:1 reaction thus;

Number of moles of HCl = 0.1102 M * 25/1000 = 2.755 * 10^-3 moles

Number of moles of NaOH = 0.1024 M * 50/1000 L = 5.12 * 10^-3 moles

We can see from above that the HCl is the limiting reactant.

The hat evolved is obtained from;

0.001 J/°C. * (25.93°C - 25.14°C) = 1.79 * 10^-3 J

The heat of the reaction is then;

-( 1.79 * 10^-3 J) * 10^-3 * 1/2.755 * 10^-3 moles

-0.65kJ/mol

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To analyze the equilibrium and how it shifts aaccording to Le Châtelier’s principle, we have to see how the system reacts to the change.

The change is an increase in the volume of the container. Since all the compounds on equilibrium are in gaseous state, their volume is the same as its container, so an increase in the volume of the container increase the volume of the compounds.

The reactant is SI₃, but we have 2 of them for each reaction.

The products are 2 molecules of SO₂ and one molecule of O₂.

In total for each reaction, we have 2 molecules in the reactant part and 3 molecules in the product part.

Since they are all in gaseous form, this means that the products occupy more space than the reactants, that is, an increase in the volume will favor the products, because this increase will left more space for them to occupy.

Thinking in preassure, an increase in the volume will decrease pressure, because, by the Boyle's Law, they are inversely proportional (assuming ideal gas). Since there are more molecules per reaction on the products side, this will favor the products, since more molecules make more pressure and now it has been decreased.

Thus:

Increase in volume -> decrease in pressure -> favors the products.

This matches alternative B.

Answer ans explanation

2.51x10^4 - 1.5x10^3 = 2.36^4

Answer

2.36^4

Explanation:

We have to find the molar mass of Au(OH)₃. To do that we have to look for the atomic masses of each element. Also we have to consider that one molecule of

Au(OH)₃ has 1 atom of Au, 3 atoms of O and 3 atoms H.

atomic mass of Au = 196.97 amu

atomic mass of O = 16.00 amu

atomic mass of H = 1.01 amu

molar mass of Au = 196.97 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Au(OH)₃ = 1 * molar mass of Au + 3 molar mass of O + 3 molar mass of H

molar mass of Au(OH)₃ = 1 * 196.97 g/mol + 3 * 16.00 g/mol + 3 * 1.01 g/mol

molar mass of Au(OH)₃ = 248.0 g/mol

Answer: the molar mass of Au(OH)₃ is 248.0 g/mol.

Mole of sulfur hexafluoride gas that were collected is 20.081 mol

Mass of  sulfur hexafluoride gas that were collected is 0.137 gram

Sulphur hexafluoride gas is used as the electrical insulating material in circuit and breaker, cables and capacitor and sulfur hexafluoride gas is the nontoxic gas and it is an inorganic compound it is colorless and odorless and non flammable

Here given data is

Pressure = 0.220 atm.

Temprature = -4.0 °C = -4.0 °C +273 .15 K = 269.15 K

Volume =  5.0 L

Using ideal gas quation

PV = nRT

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R = gas constant =  0.0821 L.atm/K.mol

Applying the equation as

0.220 atm ×  5.0 L = n × 0.0821 L.atm/K.mol ×  269.15 K

n = 22.09/1.1

n = 20.081

Molar mass of sulfur hexafluoride gas =  146.06 g/mol

The formula for calculations of mole

Moles = mass taken/molar mass

20.081 = mass/146.06 g/mol

Mass = 0.137 gram

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Cation

Type 1

Type 2

Anion

The Roman numeral represents  charge and the oxidation state of the transition metal ion.

One of the example is, iron that forms two ions, Fe2+ and Fe3+. To differentiate, Fe2+ is named iron (II) and Fe3+ is named iron (III).

Those compounds in which the cation has only one charge are Type 1 binary ionic compounds whereas compounds in which the cation can have multiple forms are Type 2 binary ionic compounds.

Type II Binary Ionic Compounds contain Transition metals with non-metal ions.

A monatomic cation derives its name from the name of the element. For example, Na+ is called sodium  whereas monatomic anion is named by taking the root of the element and then adding -ide.

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Answer:

Explanation:

To find the number of entities in a given substance we use the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

However we weren't given the number of moles only the mass of oxygen was given. we can find the number of moles from that by using the formula

[tex]n = \frac{m}{M} \\ [/tex]

m is the mass

M is the molar mass

n is the number of moles

Molar mass of oxygen = 16 g/mol

mass in question = 25 g

We have

[tex]n = \frac{25}{16} = 1.56 \\ [/tex]

number of moles = 1.56 mol

The number of oxygen atoms is equal to

N = 1.56 × 6.02 × 10²³ = 9.3912 × 10²³

We have the final answer as

Hope this helps you

15.00g of hydrated zinc sulfate loses 6.579 H₂O during heating what is the formula for the hydrate is ZnSO₄.7H₂O

Mass of anhydrous ZnSO₄ = 15.00 g - 6.579 g = 8.421 g

8.412 g of anhydrous ZnSO₄ = 6.579 g

molar mass of anhydrous ZnSO₄ = 161.47 g/mol

161.47 g of  ZnSO₄  = (6.579 × 161.47) / 8.421

                                 = 126 g

no. of moles of H₂O = mass / molar mass

                                 = 126 / 18

                                 = 7 molecules of H₂O

the formula for hydrate is ZnSO₄.7H₂O

Thus, 15.00g of hydrated zinc sulfate loses 6.579 H₂O during heating what is the formula for the hydrate is ZnSO₄.7H₂O

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33.136 grams of ethylene glycol should be mixed with  375 ml of Water to make a 7.50% by Mixture.

Density is the measure of how much “stuff” is in a given amount of space.

DENSITY = MASS / VOLUME

We have :-

→ Density of ethylene glycol = 1.09 g/mL

→ Volume of water = 375 mL

→ Concentration (v/v %) = 7.50 %

Let the volume of ethylene glycol (solute) be 'x' mL .

So, volume of the solution = Volume of solute + Volume of solvent

                                              = (x + 375) mL

Concentration (v/v %) = Vol. of solute/Vol. of solution × 100

⇒ x/(x + 375) × 100 = 7.5

⇒ 100x = 7.5(x + 375)

⇒ 100x = 7.5x + 2812.5

⇒ 100x - 7.5x = 2812.5

⇒ 92.5x = 2812.5

⇒ x = 2812.5/92.5

⇒ x = 30.4 mL

Mass of ethylene glycol = Volume × Density

                                          = 30.4 × 1.09 = 33.136 g

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To determine the percentage of oxygen in the molecule we must first know its structure and how many oxygen atoms are contained in it. The structure of aluminum phosphate is AlPO4.

It means that there are 4 oxygen atoms, 1 Aluminum atom, and 1 phosphate atom.

Now we will determine the weight of the molecule AlPO4 by adding the atomic weights of the elements as follows:

Element Atomic mass # of atoms Mass

Al 26.9815 1 26.9815

P 30.9738 1 30.9738

O 15.999 4 63.996

Total mass of AlPO4 = 26.9815+30.9738+63.996 = 121.9513 g/mol

Now we will determine the mass percentage with the following equation:

We replace the known terms:

So, the percentage of oxygen in aluminum phosphate is 52.477%

Answer:

1.25 M

Explanation:

(Step 1)

Convert grams to moles using the molar mass of Na₂O.

Atomic Mass (Na): 22.990 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (Na₂O): 2(22.990 g/mol) + 15.999 g/mol

Molar Mass (Na₂O): 61.979 g/mol

 34.8 g Na₂O               1 mole
----------------------  x  ---------------------  =  0.561 moles Na₂O
                                    61.979 g

(Step 2)

Convert milliliters to liters.

1,000 mL = 1 L

 450.0 mL                 1 L
------------------  x  -------------------  =  0.4500 L
                             1,000 mL

(Step 3)

Calculate the molarity using the molarity ratio.

Molarity = moles / volume (L)

Molairty = 0.561 moles / 0.4500 L

Molarity = 1.25 M

−791.4 kJ is the standard enthalpy change for the reaction.

Given,

SO2(g) → S(s) + O2(g)

ΔH° = +296.8 kJ

2SO2(g) + O2(g) → 2SO3(g)

ΔH° = −197.8 kJ

Modified equation:

S(s) + 2O2(g) → 2SO2(g)

ΔH° = −593.6 kJ, multiply by 2 and flip

2SO2(g) + O2(g) → 2SO3(g)

ΔH° = −197.8 kJ here no change

The 2SO2 will balance out by canceling it when the equations are added. Add the enthalpies for the final answer:

−593.6 + (−197.8) = −791.4 kJ

The change in enthalpy of a compound when one mole of the compound is generated from all components of the same constituent is known as the standard enthalpy of formation, also known as the standard heat of formation.

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The number of molecules in 59.73 grams of the theoretical acid borofuric acid, H₂B₂O₂ is 6.47 × 10²³ molecules.

The number of molecules in a substance can be estimated by multiplying the number of moles in the substance by Avogadro's number (6.02 × 10²³) as follows:

no of molecules = no of moles × 6.02 × 10²³

According to this question, there are 59.73 grams of the theoretical acid borofuric acid. The molar mass of this acid is as follows:

H₂B₂O₂ = 1(2) + 10.8(2) + 16(2) = 55.6g/mol

moles = 59.73g ÷ 55.6g/mol = 1.07mol

no of molecules = 1.07 × 6.02 × 10²³

no of molecules = 6.47 × 10²³ molecules

Therefore, 6.47 × 10²³ molecules is the number of molecules in the acid.

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Answer:

Explanation:

Here, we want to get the metric prefix m value

This means we want to get power to which it would be raised

Mathematically,we have this as the milli

The milli refers to thousandth

From what we have here, this is the power of -3

So the prefix m represents :

Assuming all the HCl presend in the 24.06mL reacted, we can follow the steps:

1 - Use the concentration and the volume to calculate the number of moles of HCl that reacted

2 - Apply the stoichiometry ratios to calculate the number os moles of Fe that reacted

3 - Use the tomic weight of Fe to calculate the mass of that amount of number of moles of Fe.

1 - The concentration is given by the equation:

The number of moles of solute is the same as the number of moles o HCl, because it is the solute in this case:

So, we have:

2 - The coefficients of Fe and HCl are 1 and 2, respectively, so we have the following relation between their number of moles:

Fe --- HCl

1 --- 2

3 - The atomic weight of Fe can be checked on a periodic table:

So, we have:

So, there was approximately 3.76 g of Fe.

Answer:

Aluminium, Thorium, Barium and Strontium. Nonmetals will be : Fluorine, Phosphorus and Krypton. Metalloids will be : Gallium and Tellurium.

BaSO₄. Option C is correct

The substances that dissolve readily in water are ionic compounds and polar covalent compounds. Examples of ionic compounds that dissolve in water are salts, oxides, hydroxides, sulfides, and the majority of inorganic compounds.

The molecules in a polar solvent have a dipole, like water, one side is more negative and one is more positive.

Ionic compounds are composed of a positive ion, normally a metal, and a negative ion, normally a nonmetal, so their forces are attracted to their charge difference.

Thus, a polar solvent dissolves each ion with its corresponding parts, dissociating the two ions of the ionic compound.

Since sulfides are ionic compounds hence the substance that will dissolve most readily in water is BaSO₄. The molecule is formed by one barium cation Ba2+ and one sulfide anion S2-. The two ions are bound through an ionic bond.

The core is denser than the mantle.

The Earth is partitioned into three primary layers. The hot inner core, the molten outer core, the mantle, and  where the thin crust, support all life within the known universe. Most of the Earth's insides are made up of the mantle, the layer of molten rock underneath the strong outside, and the hot, dense core. As the mass and  the volume of the mantle are greater than the core's mass which  leads the mantle of  having a low density. as a result the core is considered to be  having  more density than the mantle in spite of the  mantle having  more mass.

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Will Argon, Neon, and Krypton react same

Reactivity is the relative capacity of an atom or molecule or radical to undergo a chemical reaction with another atom or molecule or compound called as reactivity

In the noble gases only helium and neon are inert and the other noble gases will react with a limited scale under very specific conditions and krypton will form solid with fluorine and xenon will form a variety of compounds with oxygen and fluorine and the name comes from the fact that these elements are virtually unreactive towards other elements and they do not react with other element

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As per the octet rule, the element tellurium will make 2 covalent bonds to complete it's octet.

What is octet rule?

The octet rule describes an atom's propensity to favor eight electrons in its valence shell. Atoms with fewer than eight electrons in the outermost shell are more likely to interact with one another and create better stable molecules. We ignore d or f electrons while considering the octet rule. The octet rule is useful for main group elements (those not in the transition metal or inner-transition metal blocks) since it only involves the s and p electrons. An octet in these atoms corresponds to an electron configuration ending in s2p6.

According to octet rule, an element require to complete it's octet (i.e. 8 electrons in the outermost shell). So, in the case of tellurium there are 6 electrons in the outermost shell therefore, we require two more electrons to complete the octet for which the tellurium would be expected to make 2 covalent bonds.

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For a species to survive it must be within its geographical zone for all the genetic factors.

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When calcium nitrate and potassium fluoride solutions react to form a precipitate, the type of reaction involved is the process is double replacement

Calcium nitrate and potassium fluoride solutions react to form calcium fluoride and potassium nitrate. Calcium fluoride would precipitate out whereas potassium nitrate would be in aqueous form.

Ca (NO₃)₂ (aq) + 2 KF (aq) → CaF₂ (s) + 2 KNO₃ (aq)

In double replacement reaction, the ionic compounds would exchange their respective ions to form a new compound. Here two ionic compounds, nitrate and fluoride from calcium and potassium respectively are exchanged to form calcium fluoride and potassium nitrate.

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The molar mass of the gas in grams per mole if 6.2 g of gas occupies 5.4L is 336.97 grams.

Molar mass is defined as the mass of a sample of a certain chemical divided by the quantity of the material, expressed as the number of moles in the sample.

It can also be defined as the product of the mass of a specific substance and the amount of that substance in the sample.

Given Pressure = 1.3 atm

Temperature = 285 K

Volume = 5.4 L

Gas content = 8.3

So, PV = nRT

n = RT / PV

n = 8.3 x 285 / 1.3 x 5.4

n = 336.97 grams

Thus, the molar mass of the gas in grams per mole if 6.2 g of gas occupies 5.4L is 336.97 grams.

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The volume of a substance at STP for one mole is 22.4 L. The volume of oxygen required to react with excess of carbon sulphide to produce 4 L of carbon dioxide 4.0 L is 12 L.

Volume of a substance is the space occupied by the particles of the substance. As the temperature increase, volume also increases. The volume of one mole of every substance at standard temperature and pressure is 22.41 L

According the balanced reaction given, 3 moles of O₂ is required to produce one mole carbon dioxide. One mole of O₂ is 22.4 L. Thus volume of 3 moles of oxygen is calculated as follows:

Volume of O₂= 3×22.41 =67.2 L.

Thus, 67.2 L of O₂ produces one mole or 22.4 L of carbon dioxide.

The volume O₂ required to produce 4 L of carbon dioxide is calculated as follows:

Volume of O₂ = (67.2 L × 4 L) / 22.41 L

                       = 12 L.

Therefore, the volume of oxygen molecule required to produce 4 L of carbon dioxide on the reaction with excess of carbon sulphide is 12 L.

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In this question, we need to analyze the solubility of some substances and the changes that can occur to each one upon heating, at 20°C, every substance listed is soluble, NaCl, Na2SO4, Li2CO3 and Sucrose, but when we have a change in temperature, it will affect directly the solubility of the solution, for example, if you increase the temperature, Lithium carbonate and Sodium sulfate, will have a lower solubility in water, therefore if we have a certain amount of these two substances at 20°C and in 100g of water, the solution will be soluble, but if we increase the temperature, the solubility will change and these two compounds will start to precipitate, as the solubility will be lowering down.

Therefore the answers are Na2SO4 and Li2CO3

Calcium carbonate (CaCO3) is not an organic substance since it only contains one of the two elements—carbon or hydrogen.

To identify whether a compound is organic, it is important to check:

If a compound contains one of two elements, that is Carbon or Hydrogen, then it is not an organic compound.

Carbohydrates are a common type of organic compound. Carbohydrates contain the chemical formula (CH2O)n.

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2.67 grams of Glycerin should be added to water of mass 169.8 grams to give a solution with freezing point -3.81°.

When glycerin will be added to water, its freezing point will decrease. This phenomena is given a name "Depression in Freezing Point". This is called a colligative property.

We can find the depression in freezing point by using the formula,

ΔT = i.m.K

Where,

i is the Vant Hoff's factor.

Kf is cryoscopic constant

m is the molality of the solution,

Molality m can be defined as,

m = moles of solute/mass of solvent(in KG)

First, let s find molality of solution,

m = Moles of Glycerin/mass of water

m = (Added mass of glycerin(W)/Molecular mass of glycerin)/mass of water.

Molecular weight of glycerin = 92 g/mole

Mass of water = 169.8 g

In kilograms,

mass of water = 0.1698 Kg.

Now,

m = W/92 x 0.1698

Now, putting all the values in the formula,

ΔT = i.m.Kf

Assuming 100% disassociation, we can take i = 1,

But first, ΔT = 0-(-3.81) °C

ΔT  = 3.81  °C.

So, now we can write,

3.81 = 1.86 x W/(92 x 0.1698)

W = 3.81 x 92 x .01698 / 1.86

W = 2.67 grams.

Hence, of is required to add 2.67 grams of glycerin in water.

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The IUPAC name for the compound shown is 3-ethyl-2,2-dimethylpentane.

International Union of Pure and Applied Chemistry is referred to as IUPAC. The terminology for naming organic compounds has been provided by IUPAC. The root name, prefix, and suffix are the three components that make up an IUPAC name.

There are five carbon atoms in the longest chain. Consequently, pent is the structure's root name. Choose the longest chain where the substituents are represented by the fewest numbers.

On the longest chain, three substituents are present. It consists of one ethyl group and two methyl groups. One ethyl group and two methyl groups are substituted at C-2 and C-3, respectively. Therefore, 3-ethyl-2,2-dimethyl will be the prefix. Alkane makes up the functional group. Therefore, the suffix is ane.

This ends up naming the compound as 3-ethyl-2,2-dimethylpentane.

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