Identify the terms and the like terms in this expression. 7 + a – 2 + 3a + b2 Which statements are true? Check all that apply.

- The expression contains seven terms.

- The terms in the expression are 7, a, 2, 3a, b2.

- Constants are like terms.

- 2 and b2 are like terms because they both contain the number 2.

- a and 3a are like terms.

- a, 3a, and b2 contain variables, so they are like terms

Togetherly Paige and Malia can complete the job in 2.4 hours,

Rate of change is defined as the change in value with rest to the time is called rate of change.

Here,
Let the amount of work be x,
Paige complete x work in 6 hours
So the unit rate of doing work of page = x / 6
Similarly,
The unit rate of doing x work of Malia = x / 4

Sum of the unit rate = x / 6 + x /4 = 5x/12
Now,
Time = work/unit rate
Time = x / [5x/12]
Time = 12/5
Time = 2.4 hours

Here, togetherly Paige and Malia can complete the job in 2.4 hours,

Learn more about the rate of change here:

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Answer:

7/16

Step-by-step explanation:

Answer:

B. x^1/8 y^8

Step-by-step explanation:

here are the steps so you understand better

Answer:

Here you go

Step-by-step explanation:

1. Equiangular triangle

2. Isosceles triangle

3. Right angle triangle

4. Scalene triangle

5. Obtuse angle triangle

6. Acute angle triangle

7. Equilateral triangle

8. corners

9. angles

10. triangle

Answer:

Step-by-step explanation:

Equiangular triangle

2. Isosceles triangle

3. Right angle triangle

4. Scalene triangle

5. Obtuse angle triangle

6. Acute angle triangle

7. Equilateral triangle

8. corners

9. angles

10. triangle

Answer:

[tex]0.8\, t^{12}[/tex] (assuming that [tex]a \ge 0[/tex].)

Step-by-step explanation:

The rule [tex]a^{2} - b^{2} = (a + b)\, (a - b)[/tex] describes a way for factoring the difference between two perfect squares [tex]a^{2}[/tex] and [tex]b^{2}[/tex].

Setting [tex]a^{2} = 0.64\, t^{24}[/tex] and [tex]b^{2} = 9[/tex] would ensure that [tex](a^{2} - b^{2})[/tex] match the given expression.

Take the square root of both sides of the equality [tex]a^{2} = 0.64\, t^{24}[/tex]. Make use of the fact that for all [tex]x \ge 0[/tex], [tex]\sqrt{x} = x^{1/2}[/tex].

[tex]\displaystyle \sqrt{a^{2}} = \sqrt{0.64\, t^{24}}[/tex].

[tex]\begin{aligned} a &= \left(\sqrt{0.64}\right)\, \sqrt{t^{24}} \\ &= 0.8\, (t^{24})^{1/2}\\ &= 0.8 \, t^{24 \times (1/2)} \\ &= 0.8\, t^{12}\end{aligned}[/tex].

Answer:

6 cm²

Step-by-step explanation:

The shorter sides are base and height.

3 x 4 / 2

= 6

We have: a² + b² = 3² + 4² = 9 + 16 = 25 = 5² = c²

=> triangle ABC is a square triangle

=> the area of the triangle ABC is: a × b ÷ 2 = 3 × 4 ÷ 2 = 6 (cm²)

Answer: 6 cm²

Ok done. Thank to me :>

Answer:

your answer is D

yes, I checked

Answer:

28,370.38

Step-by-step explanation:

If accumulated but not compounded

.06 * 20,000 = 1200 per year

1200 * 6 = 7200 total interest

7200 + 20,000 = 27,200

If compounded annually

20,000 * 1.06^6 = 20,000*1.4185 = 28,370.38

just an addtion to the reply above.

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &6 \end{cases} \\\\\\ A=20000\left(1+\frac{0.06}{1}\right)^{1\cdot 6}\implies A=20000(1.06)^6\implies A\approx 28370.38[/tex]

Answer:x = 6

Step-by-step explanation:

because each 1/4 is equal to 1.5 in this instance. Making 3 of these equal parts equal to 4.5, and all 4 of them equal to 6 (the denominator).

Answer:

The GCF of 35 and 50 is 5

Answer:

no

Step-by-step explanation:

theses expressions do not have the same values because they both have differant answers.

when put in a calculator: [tex]\sqrt{100-64[/tex] = 6

and [tex]\sqrt{100[/tex] - [tex]\sqrt{64[/tex] into the calculator you get =2  (the sqrt of 100= 10 and the sqrt of 64=8)     (10-8=2)

Answer:

ok so lets just talk about what each one represents

the first one represents the square root of 100-64 so

the square root of 36 is 6

the second one is the square root of 100 minus the square root of 64 so

10-8=2

the first one is 6

the second one is 2

so no

Hope This Helps!!!

Answer:

1) 09:30

2) 08:50

3) 10:45

4) 07:36

Step-by-step explanation:

Using an ideal gas equation to solve the problem. Then the original volume is 17.67 liters.

An ideal gas is a theoretical composed of a set of randomly moving gas particles that interact only through elastic collision.

Given

A balloon containing 0.500 mol at 0. 00°C and 65.0 kPa pressure are expanded by adding more argon.

Pressure (P) = 65 kPa

Mole (n) = 0.5 mol

Temperature (T) = 0 °C = 273.15 K

Universal gas constant (R) = 8.317 L.kPa/mol.K

We know the ideal gas equation

[tex]\rm PV =nRT\\\\V \ \ = \dfrac{nRT}{P}[/tex]

Put the values, we have

[tex]\rm V = \dfrac{0.5*8.317*273.15}{65}\\\\V = 17.67[/tex]

Thus, the original volume is 17.67 liters.

More about the ideal gas equation link is given below.

https://brainly.com/question/4147359

Answer:

answer in picture

Step-by-step explanation:

AB = AX+XB = 6+18 = 24

The ratio of AB to AX is AB/AX = 24/6 = 4

AC = AY+YC = 10+25 = 35

The ratio of AC to AY is AC/AY = 25/10 = 3.5

The results of each division are 4 and 3.5

We do not get the same result, which means that the proportion [tex]\frac{AB}{AX} = \frac{AC}{AY}[/tex] is not true. This is sufficient to prove that the triangles aren't similar. We need them to be in proportion so that we can use the SAS similarity rule.

Answer:

i think the profuct is joe

Step-by-step explanation:

j

o

e 1-357=1

Answer:

25° and 97°

Step-by-step explanation:

Oblique triangle : any triangle that is not a right triangle

Use the sine rule to find one of the unknown interior angles:

[tex]\dfrac{sin(A)}{a}=\dfrac{sin(B)}{b}=\dfrac{sin(C)}{c}[/tex]

where A, B and C are the interior angles of a triangle, and a, b and c are the sides opposite to the interior angles.

[tex]\implies \dfrac{sin(58)}{12}=\dfrac{sin(B)}{6}[/tex]

[tex]\implies sin(B)=\dfrac{6sin(58)}{12}=0.4240240481...[/tex]

[tex]\implies sin(B)=25.08890446...=25 \textdegree \ \ \textsf{(nearest whole)}[/tex]

Sum of interior angles of a triangle = 180°

⇒ Missing angle = 180 - 58 - 25 = 97°

Answer:

y = 2x + 4

y = 2x + 46x – 3y = -12

y = 2x + 46x – 3y = -12And

y = 2x + 46x – 3y = -12Andy = 2x

y = 2x + 46x – 3y = -12Andy = 2x-8x – 2y = 24

Step-by-step explanation:

hope it helps you

Answer:

[tex]term \: n = 3n + 2 \\ {1}^{st \: } term= \: \: (3 \times 1) + 2 \: just \: apply \: the \: term \: number \: to \: n \\ = 3 + 2 \: \\ \: = 5 \: [/tex]

Answer:

x ≈ 229.8

Step-by-step explanation:

using the cosine ratio in the right triangle

cos72° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{LM}{KM}[/tex] = [tex]\frac{71}{x}[/tex] ( multiply both sides by x )

x × cos72° = 71 ( divide both sides by cos72° )

x = [tex]\frac{71}{cos72}[/tex] ≈ 229.8 ( to the nearest tenth )

[tex] \frac{2(3 - x)^{ \frac{5}{2} } }{5} - \frac{2(3 - x)^{ \frac{3}{2} } }{3} + C[/tex]is the answer

Step-by-step explanation:-

Given:

[tex]{\int {(x-2)\sqrt{3-x}} \ dx }[/tex]

Differentiate on both sides,

[tex]{\int {(x-2)\sqrt{3-x}} \ dx },u = 3 - x[/tex]

Isolate and substitute back,

[tex]{\int {(x-2)\sqrt{3-x}} \ \times ( - 1) du },u = 3 - x[/tex]

Substitute back,

[tex]{\int ( - ( - u + 3 - 2) \sqrt{u})du }[/tex]

Applying property of integral ∫ kf(x)dx = k ∫ f(x)dxdx,

[tex] - ∫ ( - u + 3 - 2) \sqrt{u} \: du,u = 3 - x[/tex]

Combining like terms,

[tex]- ∫ ( - u +1) \sqrt{u} \: du,u = 3 - x[/tex]

Now applying distributive property,

[tex]- ∫ (( - u +1) \sqrt{u}) \: du,u = 3 - x[/tex]

[tex] = > - ∫ ( - \sqrt{u} \times u + \sqrt{u} )\: du,u = 3 - x[/tex]

Converting to exponential form,

[tex]- ∫ ( - u^{ \frac{1}{2} } \times u + u^{ \frac{1}{2} } )\: du,u = 3 - x[/tex]

Multiplying the first two monomuals after integral, we get,

[tex]- ∫ ( - u^{ \frac{3}{2} } + u^{ \frac{1}{2} } )\: du,u = 3 - x[/tex]

Now applying the prperty of ∫ f(x) + g(x)dx = ∫ f(x)dx + ∫ g(x)dx,

[tex] - ( - ∫u^{ \frac{3}{2} } \: du + ∫u^{ \frac{1}{2} } \: du),u = 3 - x[/tex]

Now integrate the power rule,

[tex] - ( - \frac{u^{ \frac{5}{2} }}{ \frac{5}{2} } + \frac{u^{ \frac{3}{2} }}{ \frac{3}{2} } ),u = 3 - x[/tex]

Divide the fractions by multiplying its reciprocals,

[tex] - ( - u^{ \frac{5}{2} } \times \frac{2}{5} + u^{ \frac{3}{2} } \times \frac{2}{3}),u = 3 - x[/tex]

Now write as single fractions,

[tex] - ( - \frac{2u^{ \frac{5}{2} } }{5} + \frac{2u^{ \frac{3}{2} } }{3})[/tex]

Removing the parentheses,

[tex] \frac{2u^{ \frac{5}{2} } }{5} - \frac{2u^{ \frac{3}{2} } }{3},u = 3 - x[/tex]

Substitute back,

[tex] \frac{2(3 - x)^{ \frac{5}{2} } }{5} - \frac{2(3 - x)^{ \frac{3}{2} } }{3} [/tex]

Now adding the constant of integration C∈R,

[tex] \frac{2(3 - x)^{ \frac{5}{2} } }{5} - \frac{2(3 - x)^{ \frac{3}{2} } }{3} + C[/tex]

Hence, the answer.

Answer:

Y =3x/2 is the equation of the line.

Slope is 3/2

Y intercept is zero

For safety reasons \theta should not be greater than 70 and with the current scenario\theta= 79.52

the ladder will not be safe at this height

\theta= 79.52

Question Parameters:

Joshua has a ladder that is 18 ft long.

He wants to lean the ladder against a vertical wall so that the top of the ladder is 17.7 ft

Generally the equation for the angle ABC is mathematically given as

Let ∠ABC = \theta

In the right angle triangle ACB,

Hence

sin ∠ABC  = AC / AB

sin \theta = 17.7 / 18

[tex]\theta = sin-1 (17.7 / 18)\\\\\theta = 79.52[/tex]

For more information on Arithmetic

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so zach starts with x

he gives abbey 8

x - 8

now he has x - 8 pretzels

he gives half of x - 8 to maddie

0.5x - 4 = how many maddie has at the end

x - 8 = 0.5x - 4

2x - 16 = x - 8

x = 8

Answer:

Step-by-step explanation:

The translation rule is:

Apply this rule to the vertices:

Correct choice is D

Answer:

inbox I think maybe I can help

Answer:

8 and 1/3

Step-by-step explanation:

100 divided by 12 and then the leftover. Also needs to be simplified from 4/12 to 1/3 (:

Answer:

The correct answer is letter D: tow the car of a homeowner who has parked in the street overnight five nights in a row.

This rule was not mentioned in the said contract. HOA specifically notified that if a person violates the rule more than three times, fines will be given to this violator.

Step-by-step explanation:

Answer:

its c

Step-by-step explanation:

did the test got it wrong but it showed the answer