I REALLY NEED HELP WITH QUESTION!! URGENTLY!! ANYONE WHO'S GOOD AT MATHS ​

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

3.In the wild, a giant panda bear's diet consists primarily of bamboo, but in a zoo, the diet
includes other foods. On the first two days of the week, the giant panda bear at your zoo eats 34
pounds of highly nutritious biscuits and 37 pounds of bamboo, respectively.
Use inductive reasoning to create two possible sequences that describe the giant panda bear's
daily diet. Write the first five terms of each sequence.
First Sequence:
Second Sequence:
Describe the pattern you used to write each sequence. Which sequence do you think is more
likely? Explain your reasoning.

Learning Task 2 B. Perform the indicated operations. Write your solution in the box below. Add Subtract: 1. (5x4 - 3x2 + 4) + (6x3 - 4x2 - 7) 6. (5x3 - 7x2 + 3x - 4) -(873 + 2x2 32-7) 2.-7x3y + 4x2y2 - 2 and 4x3y + 1 - 8x2y2 7. (2x2y - 5xy + 3y2 -- (7xy -- 672 - 5729) 3. (5 + 24y3 - 7y2) + (-6y3 + 7y2 + 5) 8. (9x5 - 623 + 712) - (773 4. (2xs - 6x3 - 12x2 - 4) + (-11x + 8x + 2x2 + 6) 9. Subtract 4x3.5x - 8 from 672 - 3x + 8 5. (3y5 - 2y + y* + 2y3 + 5) and (238 + 3y8 + 2+ 7) 10. (1.599 + 4.8y2 + 12) - (ya - 1.742 + 2y) Solution and Answer 67 + 2x2) -​

When buddy ran away after his dad yelled at him dad and step brother searched 10% of New York for him what is this number as a fraction written in simplest form

help me please please ​

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Total amount =

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Math isn't really my thing, so if you could help I would really, really appreciate!!​

Tim wants to create a circle graph showing the number of physicians whose specialty is aerospace medicine. He knows the following information.53 male physicians are under 35 years of age. 8 female physicians are under 35 years of age. 155 male physicians are between 35 and 44 years of age. 17 female physicians are between 35 and 44 years of age. 145 male physicians are between 45 and 54 years of age. 10 female physicians are between 45 and 54 years of age. 98 male physicians are over 54 years of age. 2 female physicians are over 54 years of age. If he wants to include each of the eight groups in his graph, how many degrees would he use for the central angle of the "45-54 year-old Males" sector? Express your answer to the nearest whole number.

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EXERCISE 11D

1. Draw MON = 81° and bisect it.
2. Draw an angle of measure 175°.
3. Construct a right angle and then bisect it.
4. Draw ABC= 162º and divide it into four equal parts.
5. Construct the following angles using a ruler and compass. a 60° b. 30° C. 120° d. 135°
6. Draw an angle of 107° and make a copy of it. Verify your construction by ac measurement. a.
7. Draw an angle of 83º. Make a copy of its complementary angle.

✅help me to solve this

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