I need help with this question! Thank you :)

Answer:

2.25 should be the right answer

Answer:

15,625

Step-by-step explanation:

2h=120m

120/20 = 6

5^6 = 15,625

Answer:

gcd (50; 75) = 25 = 5^2:

Step-by-step explanation:

hope it help

The greatest common factor of 25, 50 and 75 is 5*5, which is equal to 25.

We are given that;

The three numbers = 25, 50, 75

Now,

The greatest common factor (GCF) of two or more numbers is the largest positive integer that divides evenly into all the numbers with zero remainder.

To find the GCF of 25, 50 and 75, we can use the prime factorization method. This involves writing each number as a product of its prime factors and then finding the common factors among them.

The prime factorization of 25 is 5*5

The prime factorization of 50 is 2 x 5*5.

The prime factorization of 75 is 3 x 5*5.

The common factors of 25, 50 and 75 are 1 and 5*5.

Therefore, by factorization the answer will be 25.

Learn more about factorization here;

https://brainly.com/question/10454590

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Answer:

296 cm

Step-by-step explanation:

Joanna is 152cm tall

Kristal is 152 - 8 =  144 cm

The sum of the heights is

152 + 144 =296 cm

Answer:

They all have 180 degrees

Step-by-step explanation:

Answer:

option c ) y = 3x -2

given, y=10 & x=4

let's equate in equation

y = 3x -2

LHS = Y = 10 ( given )

RHS = 3X -2 = 3(4)-2

= 12-2

= 10

SO, LHS = RHS

hence , SATISFIED ✔️

we end here ^^"

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Answer:

it would be A 160

Step-by-step explanation:

4 square plus + 12 square = 16+144=160

Answer:

[tex]1\frac{1}{4} c[/tex]

Step-by-step explanation:

[tex]c+\frac{1}{4}c[/tex]

Rewrite the expression

[tex]= 1c+\frac{1}{4} c[/tex]

Add

[tex]= 1\frac{1}{4} c[/tex]

Therefore, [tex]c+\frac{1}{4}c[/tex] is equal to [tex]1\frac{1}{4} c[/tex].

I hope this helps!

Answer:

C) The second equation converted to slope-intercept form is .y = negative one-third x minus 1

Step-by-step explanation:

Answer:

c on edge

Step-by-step explanation:

Consider the system of equations.

y = –2x + 4,

3y + x = –3

Which statement is true of this system of equations?

Both equations are in slope-intercept form.

The first equation converted to slope-intercept form is y + 2x = 4.

The second equation converted to slope-intercept form is .y = negative one-third x minus 1

Neither equation is in slope-intercept form.

Answer:

Step-by-step explanation:

the answer is 100

9514 1404 393

Answer:

  A = w(w +6)

Step-by-step explanation:

The length in feet will be w+6. The area is the product of length (w+6) and width (w).

  A = w(w+6)

Answer:

1200 ft in one hour

Step-by-step explanation:

The ratio of Sam crawling 20 ft in one minute can be written as:

20:1

Multiply the ratio by 60 to get the minutes to 60 minutes, because there are 60 minutes in an hour:

 20    :    1

×60     ×60

To get:

1200:60  ⇒  This means Sam can crawl 1200 ft in 60 minutes, which is the same as 1200 ft in one hour.

Hope this helps! :)

Answer and explanation:

Given:

Royal soil= $6.50 per pound

Royal peasant = $2 per pound of 10 pounds

Blend total pounds is x+10, price is unknown hence solved below

Using algebra

We find unknown x = number of pounds of royal soil

$6.50(x)+$2(10)=6.50x+20/x+10(x+10)

= 6.50x+20= 6.50x²+85x+200

Answer:  its 8 :)

i hope this helps!!!!

Answer:

I have no idea

Step-by-step explanation:

Answer:

D. 44 because its the primemiter

Answer:

E, the heart

Step-by-step explanation:

Answer:

The heart

Step-by-step explanation:

It is able to flip and still look the same

Answer:

1. Slope: 2     y-intercept: (0,−10)

2. Slope: 3  y-intercept: (0,12)

Step-by-step explanation:

Answer:

12 because 12/15 =.8 so does 8/10

Answer:

w=12

Step-by-step explanation:

8/10 is equal to 4/5. 4/5 is equal to 12/15. Therefore, W represents 12.

Brainliest are always appreciated :)

Answer:

4

Step-by-step explanation:

7+ (-3)= 4 lol not sure if thats what you wanted but thats what i understood from your question

Answer: 11 3/8

18 - 6 5/8 = 11 3/8

Answer:

the final amount is 1,135

Step-by-step explanation:

The computation of the final amount is shown below:

= Amount × (1 + increased percentage)

= 1102 × (1 + 0.02)

= 1102 × 1.02

= 1124.04

Now the additional one percent increase is

= 1,124.04 × 1.01

= 1,135

Hence, the final amount is 1,135

The same is to be considered

Answer:

1)x-y>7

x>7+y

x-7=y

y =7

If it has to be at least 7 then 7 is less than all of them or equal to it.

2) Step 1: Always start by isolating the variable y on the left side of the inequality.

Step 2: Change the inequality to equality symbol. ...

Step 3: Graph the boundary line from step 2 in the X Y − XY- XY−plane. ...

Step 4: The last step is to shade one side or region of the boundary line.

3) The solution graph is y=7 because there is no possible x or x=0

you can find  a point in an inequality in the shaded region of the graph. Any of the points in the shaded region work as a solution of the inequality

Hope I helped!!

Answer:

33

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

3/4 × 2/6 = 1/4

3/4÷6/2=1/4

Answer:

19 by 38

Step-by-step explanation:

The area of the poster, A=xy

Margin at both up and bottom is 2inches, at the right and left is 1 inch

Then we can say

(x-4)(y-2)= 578

Let us make y subject of the formula

(y-2)= 578/(x-4)

y=[ 578/(x-4)] + 2

If we substitute into the area A equation we have

A= x { [ 578/(x-4)] + 2}

A= 2x + (578x)/(x - 4)

If we differentiate we have

A'(x)= [2+578(x-4)+578x ]/ (x-4)^2

=[ 2(x-4)^2 + 578(x -4) + 578x ] / (x-4)^2

=[ 2(x^2 - 8x +16) + 578(x-4) + 578x ] /(x-4)^2

If we simplify this we have

=[ 2x^2 -16x +32+578x -578x - 2312]/ (x-4)^2

=( 2x^2 -16x - 2312) / (x-4)^2

At A'(x)= 0

= ( x^2 - 8x - 2312) / (x-4)^ =0

If we divide through by 2 we have

x^2 - 8x - 1156= 0

Solving the quadratic eqn( CHECK THE ATTACHMENT)

X= 38 or -30 then we choose the positive one, then x= 38

Then from area of the poster

A= (x-4)(y-2)= 578

Substitute 38 as value of x

(38-4)(y-2)= 578

34(y-2)=578

34y-68=578

34y=646

y=19

Hence dimensions of the poster is 19 by 38

CHECK THE ATTACHMENT FOR QUADRATIC SOLUTION