I need help with this problem ​

Answer: [tex]x=3.0206[/tex]

Step-by-step explanation:

Given

[tex]3(2^{2x}+3)-5(2^x+2)-156=0[/tex]

Replace [tex]2^x[/tex] by [tex]y[/tex]

We can write

[tex]\Rightarrow 3(y^2+3)-5(y+2)-156=0\\\Rightarrow 3y^2+9-5y-10-156=0\\\Rightarrow 3y^2-5y-157=0\\\\\Rightarrow y=\dfrac{5\pm \sqrt{25-4(3)(-157)}}{2\times 3}\\\\\Rightarrow y=\dfrac{5+43.69}{6}\\\\\Rightarrow y=8.115\\\Rightarrow 2^x=8.115\\\therefore \quad x=3.0206[/tex]

Answer:

Step-by-step explanation:

Answer:

Simplify.

Rewrite the expression in the form z”. Z5 • Z6Simplify.

Rewrite the expression in the form z”. Z5 • Z6

Answer:

Simplify.

Rewrite the expression in the form z”. Z5 • Z6Simplify.

Rewrite the expression in the form z”. Z5 • Z6

Answer: The function described in this scenario above is a “Growth Function”

Have a nice day!

Answer:

f(3) = -4

Step-by-step explanation:

f(3) = f(2)*-1/2; Solve for f(2) first;

f(2) = f(1)*-1/2

f(2) = -16*-1/2

f(2) = 8;

Now get back to f(3);

f(3) = f(2)*-1/2

f(3) = 8*-1/2

f(3) = -4

Answer:

Adult Tickets =$3

Student Tickets =$6

Step-by-step explanation:

3×3=9 9+6=15

9×3=27

7×6=42

27+42=67

Area of this trapezoid is 264 unit²

Area: ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides.

Given perpendicular distance as 12 and parallel sides as 20,24 units respectively.

Thus Area is (20+24 /2) ×12=264 units²

Hence, the Area of trapezoid is 264 unit²

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Answer:

First, when we have a function f(x), an horizontal dilation of scale factor k, is written as:

g(x) = f(x/k)

Then f((2/3)*x) is an horizontal dilation of scale factor 3/2 of the function f(x).

(The graph will be a little bit wider than the graph of f(x))

Also, knowing that f(x) = x^3 + 3

Then:

f((2/3)*x) = ( (2/3)*x)^3 + 3

              = (8/27)*x^3 + 3

And the graph of this function is shown below:

For the case of a line through

(

2

,

7

)

and

(

1

,

−

4

)

we have

slope

m

=

Δ

y

Δ

x

=

−

4

−

7

1

−

2

=

−

11

−

1

=

11

Using the point

(

2

,

7

)

we can write the equation of the line in point slope form as:

y

−

7

=

m

(

x

−

2

)

where the slope

m

=

11

.

That is:

y

−

7

=

11

(

x

−

2

)

To get point intercept form, first expand the right hand side so...

y

−

7

=

11

x

−

(

11

⋅

2

)

=

11

x

−

22

Then add

7

to both sides to get:

y

=

11

x

−

15

=

11

x

+

(

−

15

)

This is point intercept (

y

=

m

x

+

c

) form with slope

m

=

11

and intercept

c

=

−

15

.

Answer:

52 degrees

Step-by-step explanation:

a line is 180 degrees so just subtract 128 from 180 which is 52

Answer:

ajnasnnanananandbabbabbansbansbz svabsvsb

Answer: The answer is E: |-4|<|-7| and C: |-7|>|4|

Answer:

[tex]16m^{10} -25m^{12}[/tex]

Step-by-step explanation:

hope this helps :)

The expand and combination like terms (4m^5) – 5m^6) (4m^5 + 5m^6) is -9m^12 + (16)m^10.

An equation is an expression that shows the relationship between two or more numbers and variables.

A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.

We are given that;

The equation=(4m^5) – 5m^6) (4m^5 + 5m^6)

Now,

To expand the expression, we need to multiply each term inside the first parentheses by each term inside the second parentheses. This gives us:

(4m^5 - 5m^6) (4m^5 + 5m^6) = 4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6

To simplify the expression, we need to use the exponent rule that a^b * a^c = a^(b + c) and combine the terms that have the same base and exponent. This gives us:

4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6 = 16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6)

To further simplify the expression, we need to add the exponents and simplify the coefficients. This gives us:

16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6) = 16m^10 + 20m^11 - 20m^11 - 25m^12

To combine like terms, we need to add or subtract the coefficients of the terms that have the same base and exponent. This gives us:

16m^10 + 20m^11 - 20m^11 - 25m^12 = (16 - 25)m^12 + (20 - 20)m^11 + (16)m^10

= -9m^12 + (0)m^11 + (16)m^10

= -9m^12 + (16)m^10

Therefore, the equation will be equal to -9m^12 + (16)m^10.

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Answer:

43⁵

Step-by-step explanation:

43 · 43 · 43 · 43 · 43 = 43⁵

~Refer to the attachment for the solution.

[tex] \to \bf { Sum = 3500 } [/tex]

The answer is b. because the other ones don't charge money according to the number of miles.

Answer:

The structure that you used in your research paper can also be used for your presentation. For example, just like how your

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

2t

Step-by-step explanation:

3t-t is the same as 3-1, so it equals 2t

Answer:

3.7018867924 × [tex]10^{-1}[/tex]

Step-by-step explanation:

First you want to find what these two numbers are, then you divide, then you put that answer in scientific notation.

1.728(109) = 188.352

4.8(106) = 508.80

Now we divide :

188.352 ÷ 508.80 = 0.37018867924

That's a crazy decimal, but luckily because of scientific notation we can make it look a lot simpler.

0.37018867924 =  3.7018867924 × [tex]10^{-1}[/tex]

This should be right. Please comment if you are confused and want more detail.

What is the quotient of [tex]1.728*10^9 and, 4.8*10^6[/tex] expressed in scientific notation?

[tex]\frac{1.728*10^9}{4.8*10^6}[/tex]  Divide

[tex]\frac{1.728}{4.8} * \frac{10^9}{10^6}[/tex] Divide numbers and 10's separately.

[tex]0.36*10^3[/tex] Subtract exponents.

[tex](3.6*10^-^1 )*10^3[/tex] Rewrite as a number bigger than 1

[tex]3.6*(10^-^1*10^3)[/tex] Associate

       The answer is

[tex]3.6*10^2[/tex] Add exponents

Answer:

-1/9

Step-by-step explanation:

Answer:

C) [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

5x² - 3x - 7 = 0

↓

a = 5, b = -3, c = -7

Step 2: Solve for x

Answer:

6/5t + 4/15s - 3

Step-by-step explanation:

(-4/5t + 5/3s) + (-3 -7/5s + 2t)

You can only add like terms together so convert like terms to have the same denominator:

(-4/5t + 25/15s) + (-3 - 21/15s + 10/5t)

Get rid of the parentheses:

-4/5t + 25/15s - 3 - 21/15s + 10/5t

Combine like terms:

6/5t + 4/15s - 3

Answer:

3.7 rounded

Step-by-step explanation:

Just divide 11/3

Answer:

The answer gonna be A and C because their both is the same length

Answer:

BC

Step-by-step explanation:

The side opposite the right angle is called the hypotenuse. It is the largest side right angled triangle.If you stand at A in the triangle ABC, the side BC is opposite to you and the side BC is next to you. We therefore say that BC is the opposite side to angle A and AB is the adjacent side ti angle A.

Answer:

[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.

Step-by-step explanation:

Uniform distribution:

An uniform distribution has two bounds, a and b.

The probability of getting a value lower than x is:

[tex]P(X < x) = \frac{x - a}{x - b}[/tex]

The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m.

6 minutes, so [tex]a = 0, b = 6[/tex]

You arrive at 7:33, so if x < 3, you lose the express bus:

[tex]P_E = P(X < 3) = \frac{3 - 0}{6 - 0} = \frac{3}{6} = \frac{1}{2}[/tex]

The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m.

10 minutes, so [tex]a = 0, b = 10[/tex]

[tex]P_B = P(X < 3) = \frac{3 - 0}{10 - 0} = \frac{3}{10}[/tex]

Find the probability that you missed both the express bus and the local bus.

[tex]p = P_E*P_B = \frac{1}{2}*\frac{3}{10} = \frac{3}{20}[/tex]

[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.

The probability that you missed both the express bus and the local bus is 3/20

The individual probability of a uniform distribution is calculated as:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

For the express bus

At 7:30 am, a = 0

At 7:36 am, b = 6

You arrived at 7:33 am; this means that:

x = 3

For you to miss the express bus, it means that the express bus left before 7:33 am.

i.e. x < 3

So, the probability that you miss the express bus is:

[tex]P(X < 3) = \frac{3 - 0}{6 - 0}[/tex]

[tex]P(X < 3) = \frac{3}{6}[/tex]

[tex]P(X_E < 3) = \frac{1}{2}[/tex]

For the local bus

At 7:30 am, a = 0

At 7:40 am, b = 10

You arrived at 7:33 am; this means that:

x = 3

For you to miss the local bus, it means that the local bus left before 7:33 am.

i.e. x < 3

So, the probability that you miss the local bus is:

[tex]P(X < 3) = \frac{3 - 0}{10 - 0}[/tex]

[tex]P(X_L < 3) = \frac{3}{10}[/tex]

So, the probability that you miss both bus is:

[tex]P(Both) = P(X_E < 3) * P(X_L < 3)[/tex]

This gives

[tex]P(Both) = \frac 12 * \frac 3{10}[/tex]

[tex]P(Both) = \frac 3{20}[/tex]

Hence, the probability that you missed both the express bus and the local bus is 3/20

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Answer:

'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)

Step-by-step explanation:

Range is 84-28 which is 56

Median is 51

1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25

Q1 is 40

Q1 - IQR = -1.25

Low outliers are below -1.25 - 41.25; there are not data items below -42

Answer:

'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)

Step-by-step explanation:

Range is 84-28 which is 56

Median is 51

1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25

Q1 is 40

Q1 - IQR = -1.25

Low outliers are below -1.25 - 41.25; there are not data items below -42

Answer:

8.

[tex]8. - 1. - 44 [/tex]

9

Answer:

Minor Arc AC = 360 - 235 = 125°

[tex]mABC = \frac{Major \ arc - Minor \ arc}{2} = \frac{235 - 125}{2} = \frac{110}{2} = 55[/tex]

Answer:

5 x 4 = 20, 20 divided by 2 ( x 1/2 ) = 10

Step-by-step explanation:

Formula area of a Triangle:

B(base) x H(height) x 1/2(basically just dividing by 2)