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Answer:

x=5, y=3

Step-by-step explanation:

7x-11=24: 7x=35: x=5

3(5)+9=8x: 24=8x: x=3

Answer:

$43.20

Step-by-step explanation:

20% of $50.00 is $10.00. $50 - $10 is $40. 8% of $40 is $3.20. Since this is tax, you must add it. $40+$3.20 = $43.20

Answer:

Step-by-step explanation:

Answer:

i think its 3 in all the boxes but trying is better than not ig wait no nvm

Answer:

214 seconds

Step-by-step explanation:

3 times 60 is 180. 180 plus 34 is 214.

Answer256pi

Step-by-step explanation:

Area=pi*r^2

=pi*16^2

256pi

Answer:

85.80

Step-by-step explanation:

85.82 is closet to 85.80 snice 2 is a low number

Answer:

20

Step-by-step explanation:

Answer: 7/25

Step-by-step explanation:

got it correct on khan academy

Answer:

Average of Gilbert in last 5 test = 86.6

Step-by-step explanation:

Given:

Score earned by Gilbert in last 5 test = 94, 72, 83, 94, 90

Find:

Average of Gilbert in last 5 test

Computation:

Average value = Sum of all events / Total number of events

Average of Gilbert in last 5 test = Sum of all last results / Number of results

Average of Gilbert in last 5 test = [94 + 72 + 83 + 94 + 90] / 5

Average of Gilbert in last 5 test = [433] / 5

Average of Gilbert in last 5 test = 86.6

Answer:

4th one its negative,linear association

Step-by-step explanation:

The option that best describes the relationship between the variables on the scatter plot is negative, linear association.

Variables have a negative association when the line of best fit is downward sloping. Variables have a linear association when the line of best fit is a straight line. Variables have a positive association when the line of best fit is upward sloping.

To learn more about linear functions, please check: https://brainly.com/question/26434260

Answer:

Exact form: p= 3/2

Decimal form: p= 1.5

Mixed Number: p=1 [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Answer:

Equivalent fraction of a given fraction is got by multiplying or dividing its numerator and denominator by the same whole number. For example, if we multiply the numerator and denominator of 2/3 by 4 we get. 2/3 = 2×4 / 3×4 = 8/12 which is an equivalent fraction of 2/3.

Step-by-step explanation:

Answer:

5. x = -1 or x = -3

6. b = -2 or b = 6

7. n = 5 or n = 4

Step-by-step explanation:

5. x² + 4x + 3 = 0

Factorize

x² + 3x + x + 3 = 0

x(x + 3) +1(x + 3) = 0

(x + 1)(x + 3) = 0

Set each of the factors equal to zero and solve for x

x + 1 = 0 or x + 3 = 0

x = -1 or x = -3

6. b² - 4b - 14 = -2

Put all terms on one side of the equation leaving zero on one side

b² - 4b - 14 + 2 = 0

b² - 4b - 12 = 0

Factorize

b² - 6b + 2b - 12 = 0

b(b - 6) +2(b - 6) = 0

(b + 2)(b - 6) = 0

Set each of the factors equal to zero and solve for b

b + 2 = 0 or b - 6 = 0

b = -2 or b = 6

7. n² = 9n - 20

Put all terms on one side of the equation leaving zero on one side

n² - 9n + 20 = 0

n² - 5n - 4n + 20 = 0

n(n - 5) -4(n - 5) = 0

(n - 5)(n - 4) = 0

Set each of the factors equal to zero and solve for b

n - 5 = 0 or n - 4 = 0

n = 5 or n = 4

Answer:

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{1.3}{\sqrt{1384}} = 0.1[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 3 - 0.1 = 2.9 pounds

The upper end of the interval is the sample mean added to M. So it is 3 + 0.01 = 3.1 pounds

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Answer:

15 hours

so, 8 x y = 120

Step-by-step explanation:

[tex]8\sqrt{120} =[/tex] 15

Answer: 123.05

Use annuity formula

Answer:

Step-by-step explanation:

Since we're talking about making a deposit of a certain amount every month rather than just one big deposit, we are talking about an annuity. The formula for the value of an annuity is A(t)=d[(1+rn)nt−1](rn) where A(t) is the value of the annuity, d is the amount of each deposit, n is the number of deposits per year, t is the number of years, and r is the rate of interest. In this case we know we want the value of the annuity to be A(t)=$150,000, we want to make deposits every month, or 12 times a year, so n=12, we want to reach our desired value in 30 years, so t=30, and our account earns 7% interest, so r=0.07. We can plug in all of these values and solve for d to find the amount we need to deposit each month:

A(t)150,000150,000150,000d=d[(1+rn)nt−1](rn)=d[(1+0.0712)12⋅30−1]0.0712≈d[(1.00583)360−1]0.00583≈1,219.97d≈122.95

The amount you need to deposit each month is approximately $122.95.

Answer:

697.5 ft squared

Step-by-step explanation:

Divide into top two squares and rectangle on bottom so...

(10×7.5)+(8×7.5)×(12.5×45)=area

75+60+562.5=697.5 ft squared

Answer:

Equate the divisor to 0

2x-1=0

2×=1

×=1/2

Putting onto the polynomial

f(1/2) = (1/2)³-1/2)²+3(1/2)-2

=-5/8

Answer:

[tex]t \approx 2.639[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}[/tex]

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}[/tex]

So, we have:

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}[/tex]

[tex]t = \frac{-2.9}{\sqrt{1.2083}}[/tex]

[tex]t = \frac{-2.9}{1.099}[/tex]

[tex]t \approx -2.639[/tex]

The absolute value is:

[tex]t \approx 2.639[/tex]

Answer:

No.

Step-by-step explanation:

Well at first glance it might seem so but there are two points particularly that can tell you that these points cannot be within a function.

The points (3,2) and (3,-2) will yield an undefined slope (a straight vertical line). There is no possibility that the other points can be in this line (as their y - values are different) and there is no possibilty that this is a function at all according to the vertical line test (the test is that if you draw a vertical line that there shouldn't be more than one point on it).

Answer:

-18

Step-by-step explanation:

2x²-7xy+3y²

2(3²)-7(3)(4)+3(4²)

2(9)-84+3(16)

18-84+48

18+48-84

-18

Answer:

12 students

Step-by-step explanation:

CLEAN THAT IPAD FOR HIM

Answer:

12 students went to the beach fewer than 2 times.

Step-by-step explanation:

Just count the total number of dots that come before 2.

Answer:

12:45

Step-by-step explanation:

Step One: An hour after 11:20 is 12:20, plus 15 minutes is 12: 35.

Step Two: Just add 10 minutes, because it doesn't matter when you add the ten minutes.

Answer:

Step-by-step explanation:

Given that:

a)

[tex]f(x,y) = e^{3x} + y^3 - 3ye^x \\ \\ \implies \dfrac{\partial f}{\partial x} = 0 = 3e^{3x} -3y e^x = 0 \\ \\ e^{2x}= y \\ \\ \\ \implies \dfrac{\partial f}{\partial y } = 0 = 3y^2 -3e^x = 0 \\ \\ y^2 = e^x[/tex]

[tex]\text{Now; to determine the critical point:}[/tex]- [tex]f_x = 0 ; \ \ \ \ \ f_y =0[/tex]

[tex]\implies e^{2x} = y^4 = y \\ \\ \implies y = 0 \& y =1 \\ \\ since y \ne 0 , \ \ y = 1, \ \ x= 0\\\text{Hence, the only possible critical point= }(0,1)[/tex]

b)

[tex]\delta = f_xx, s = f_{xy}, t = f_{yy} \\ \\ . \ \ \ \ \ \ \ \ D = rt-s^2 \\ \\ i) Suppose D >0 ,\ \ \ r> 0 \ \text{then f is minima} \\ \\ ii) Suppose \ D >0 ,\ \ \ r< 0 \ \text{then f is mixima} \\ \\ iii) \text{Suppose D} < 0 \text{, then f is a saddle point} \\ \\ iv) Suppose \ D = 0 \ \ No \ conclusion[/tex]

[tex]Thus \ at (0,1) \\ \\ \delta = f_{xx} = ge^{3x}\implies \delta (0,1) = 6 \\ \\ S = f_{xy} = -3e^x \\ \\ \implies S_{(0,1)} = -3 \\ \\ t = f_{yy} = 6y \\ \\[/tex]

[tex]\implies t_{0,1} = 6[/tex]

[tex]Now; D = rt - s^2 \\ \\ = (6)(6) -(-3)^2[/tex]

[tex]= 36 - 9 \\ \\ = 27 > 0 \\ \\ r>0[/tex]

[tex]\text{Hence, the critical point} \ (0,1) \ \text{appears to be the local minima}[/tex]

c)

[tex]\text{Suppose we chose x = 0 and y = -3.4} \\ \\ \text{Then, we have:} \\ \\ f(0,-3.4) = 1+ (-3.4)^3 + 3(3.4) \\ \\ = -28.104 < -1[/tex]

[tex]\text{However, if f (0,1) = 1 +1 -3 = -1 \\ \\ f(0,-3.4) = -28.104} < -1} \\ \\ \text{This explains that} -1 \text{is not an absolute minimum value of f(x,y)}[/tex]