Answer:
B) [tex]f^{-1}(x)=x+2[/tex]
Step-by-step explanation:
[tex]y=x-2[/tex]
replace [tex]y[/tex] with [tex]x[/tex]: [tex]x=y-2[/tex]
Make [tex]y[/tex] the subject: [tex]y=x+2[/tex]
Therefore, [tex]f^{-1}(x)=x+2[/tex]
Shade (A U C) intersection B’
PLEASE HELP ME I WILL GIVE BRAINLEST
[tex]5^{3x}-5^{3x-1}=4[/tex] In the following equation, solve for x (to two decimal places if necessary) and write all the steps until the final answer.
Answer:
[tex]x = \frac{1}{3} [/tex]
or x = 0.33
Step-by-step explanation:
[tex] {5}^{3x} - {5}^{3x - 1} = 4 \\ \\ \implies{5}^{3x} - {5}^{3x} . {5}^{ - 1} = 4 \\ \\ \implies{5}^{3x}(1 - {5}^{ - 1} )= 4 \\ \\ \implies{5}^{3x} \bigg(1 - \frac{1}{5} \bigg)= 4 \\ \\ \implies{5}^{3x} \bigg(\frac{5 - 1}{5} \bigg)= 4 \\ \\ \implies{5}^{3x} \times \frac{4}{5} = 4 \\ \\ \implies{5}^{3x} = 4 \times\frac{5}{4} \\ \\ \implies{5}^{3x} =5 \\ \\ \implies \: 3x = 1 \\ \\ \huge \implies \: x = \frac{1}{3} \\\\ \huge \implies \: x = 0.33[/tex]
a standard deck of cards missing the queen of hearts in the 2 of clubs what is the probability of pulling either an ace or a spade
=======================================================
Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
-----------------
The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
The terminal side of an angle θ in standard position is in quadrant 1. If sinθ=0.8, find cosθ.
Answer:
[tex]cos\theta=\frac{3}{5}[/tex]
Step-by-step explanation:
Since [tex]sin\theta=0.8[/tex] is the same as [tex]sin\theta=\frac{4}{5}[/tex] and [tex]sin\theta=\frac{opposite}{hypotenuse}[/tex], then we know that the side opposite to the angle [tex]\theta[/tex] is 4 units and the hypotenuse is 5 units.
Because [tex]cos\theta=\frac{adjacent}{hypotenuse}[/tex], then we have to find the adjacent side to the angle [tex]\theta[/tex] using the Pythagorean Theorem:
[tex]a^2+b^2=c^2\\\\(adjacent)^2+(opposite)^2=(hypotenuse)^2\\\\(adjacent)^2+4^2=5^2\\\\(adjacent)^2+16=25\\\\(adjacent)^2=9\\\\adjacent=3[/tex]
Therefore, since the adjacent side is 3 units, then [tex]cos\theta=\frac{3}{5}[/tex]
Simplify the following expression. square root x^5y^5 times 4 square root 5x^13y^12
Answer:
[tex]4x^{9} y^{8} \sqrt{5y}[/tex]
Step-by-step explanation:
Once again- help pls T-T
Answer:
Example 1) sin(42) ×25=16.73
Example 2) 12÷tan(75)=3.22
Example 3) 19÷cos(36)=23.49
Example 4) tan(53)×7=9.29
I don't know how to do this
Answer:
a) 2x + 3; b) 0
Step-by-step explanation:
Area = [tex]4\pi x^2+12\pi x+9\pi =\pi (4x^2+12x+9)=\pi (2x+3)^2[/tex]
Area = [tex]\pi r^2[/tex]
a) radius r = 2x + 3
b) 2x + 3 > 0
x > -3/2
The least possible integer value of x is 0
Write an expression for each of the expressions below by combining the like terms: 2y + 7y
9y
(space fillerrrrr)
PLEASE HELP ME QUICKKK, FIRST CORRECT PERSON GETS BRAINLIEST
Answer:
C
Step-by-step explanation:
hope this helps :)
There is a quadrilateral ABCD in which Q is a point on the side AD and the length of side AB is 18. Segment BQ is the angle bisector of angle ABC and segment CQ is the angle bisector of angle BCD.
Quadrilateral ABCD is a parallelogram. What is BC?
BC =
Answer:
ABCD is the quadrilateral
i need a help pleass ...................
Answer:
Yes, it is a right triangle. The distance is 6,2.
Step-by-step explanation:
The square of 15 is 225, and the square of 12 is 144. The square of 9 is 81. 144 + 81 = 225, so it's a right triangle.
Find the area of the rectangle with measurements shown; reduce to lowest terms: Length: 1 1/6 feet; Width: 5 1/2 feet
Answer:
[tex]6 \frac{5}{12} \: {ft}^{2} [/tex]
Step-by-step explanation:
[tex]area \: of \: rectangle = length \times width \\ \\ = 1 \frac{1}{6} \times 5 \frac{1}{2} \\ \\ = \frac{7}{6} \times \frac{11}{2} \\ \\ = \frac{77}{12} \\ \\ = 6 \frac{5}{12} \: {ft}^{2} [/tex]
Please help me. Thank you so much. :3
The fractions 810 and 58 are graphed on these number lines.
How do the fractions compare?
Two number lines lined up vertically. The first number line goes from 0 to 1 and is divided into tenths. There is a dot at 8 tenths. The second number line goes from 0 to 1 and is divided into eighths. There is a dot at 5 eighths.
Drag and drop the symbol into the box to correctly compare the fractions.
810 Response area 58
Answer:
8/10 > 5/8
Step-by-step explanation:
8/10 > 5/8
Hope this helps!
you are required to read any
four books from a list of fifteen. How
many different selections are possible?
Зn - 4 = 20
Evaluate the equation
Solve each real-world problem below, showing all of your work. You must state the starting amount and rate of change for each problem. You must also write the linear equation used to solve the problem. The memory card in Carla's camera can hold 1,024 pictures. On April 30th, Carla sees that she has 235 pictures on the memory card. She plans to take 35 pictures each day in the month of May. How many pictures will Carla have on the memory card on May 16th? On what day will the memory card be full?
Carla would have about 795 pictures on May 16th.
Linear equationA linear equation is in the form:
y = mx + b
where y,x are variables, m is the rate of change and b is the y intercept.
Let y represent the number of pictures after x days.
At April 30th, Carla sees that she has 235 pictures, hence b = 235. Also, she takes 35 pictures each day, hence m = 35. The equation is:
y = 35x + 235
On May 16th, x = 16 hence:
y = 35(16) + 235 = 795
Carla would have about 795 pictures on May 16th.
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Type an order pair ()
HELP IM DESPRITE
Matthew can spend up to $75 on supplies for his garden. The flowers will cost $38 and he wants to spend the rest on bags of top soil. Each bag of top soil costs $6.
How many bags of top soil can he buy?
Answer:
6 bags.
Step-by-step explanation:
Subtract 38 from 75 to represent the remaining amount of Matthew's money.
[tex]75-38=37.[/tex]
Matthew has $37 left over from buying flowers.
Divide 37 by 6 to represent how many bags of soil he can buy.
[tex]37\div6=6\frac{1}{6}[/tex]
Matthew can only buy 6 bags of soil, 1/6 isn't included because you can't buy a fraction of a bag.
Evaluate the given functions at the indicated value and simplify.
Answer:
See Below
Step-by-step explanation:
For each of these, you just replace x with what's in the parenthesis.
f(-2) = 4(-2)^2 - 2(-2) + 1
f(-2) = 16 + 4 + 1
f(-2) = 21
g(5) = [tex]\sqrt{4(5) - 16}[/tex]
g(5) = [tex]\sqrt{20-16}[/tex]
g(5) = [tex]\sqrt{4}[/tex]
g(5) = 2
f(3r) = 4(3r)^2 - 2(3r) + 1
f(3r) = 4(9r^2) - 6r + 1
f(3r) = 36r^2 - 6r + 1
f(a+b) = 4(a+b)^2 - 2(a+b) +1
f(a+b) = 4 (a^2 + 2ab + b^2) - 2a - 2b + 1
f(a+b) = 4a^2 + 8ab + 4b^2 - 2a - 2b + 1
2) Suppose 3 people pooled their money. How much money did each winner receive?A) $120B) $140C) $160D) $480
What's the area of a triangle whose base has a length of 27 units and whose height is
16 units?
A) 108 square units
B) 144 square units
C) 216 square units
OD) 432 square units
Answer:
216 units^2
Step-by-step explanation:
the formula to calculate area of triangle is 1/2 b×h
so...
[tex] \frac{1}{2} (27) \times (16) \\ = 216 {units}^{2} [/tex]
Answer:
Step-by-step explanation:
144 units^3
Ebony put 10 cubes into two stacks. One stack has 4 more cubes than than the other stack. How many cubes are in each stack? Show your work.
Answer:
Step-by-step explanation:
10 cubes ÷2 stacks = 5, so in each stack 5.
one stack has 5
Second stack has 4 more cubes than the other. (5+4=9)
So the answer is 5 and 9
The number of cubes is 3 and 7 in two stacks consisting of 10 stacks total.
Suppose Ebony has 'x' cubes in one stack
So, the number of cubes in another stack =x+4
What is a cube?A cube is a solid having all three dimensions i.e. length, breadth, and height equal to each other.
According to the question,
Total number of cubes = 10
x+(x+4) = 10
2x+4 =10
2x=6
x=3
So, Ebony has 3 cubes in one stack
Number of cubes in another stack =3+4 =7cubes
Therefore, The number of cubes is 3 and 7 in two stacks consisting of 10 stacks total.
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Find the inverse function of f informally.
f(x) = x^3 + 8
Answer:
[tex]f^-1 (x) = \sqrt[3]{x - 8}[/tex]
Step-by-step explanation:
Custom file created rather than math ML for neatness.
Add the fraction and whole numbers
5 13/16 +
2 1/8 +
3 3/4
Answer:
The sum of the three mixed numbers is 11 and 9.5/16.
Step-by-step explanation:
5 and 13/16
2 and 1/8 = 2 and 0.5/16
3 and 3/4 = 3 and 12/16
10 and 25.5/16
11 and 9.5/16
Answer:
[tex]11\frac{11}{16\\} \\[/tex]
Step-by-step explanation:
Separate fractions and whole numbers
5 2 3 13/16 1/8 3/4
Add whole numbers and fractions (where the denominator is 16)
5+2+3=1
13/16+1/8+3/4 =
13/16+2/16+12/6=
27/16 =
[tex]1\frac{11}{16\\} \\[/tex]
27/16+10 = [tex]11\frac{11}{16\\}[/tex]
Find the x- and y -intercepts of the graph of the linear equation -6x+9y=-18 .
The x -intercept is
.
The y -intercept is
.
Answer:
The x -intercept is (3, 0)
The y -intercept is (0, - 2)
Step-by-step explanation:
Given equation is: -6x + 9y = -18
To find x - intercept:
Plug y = 0 in the given equation.
-6x + 9(0) = - 18
-6x + 0 = -18
-6x = - 18
x = (-18)/(-6)
x = 3
The x -intercept is (3, 0)
To find y - intercept:
Plug x = 0 in the given equation.
-6(0) + 9y= - 18
0 + 9y = -18
9y = - 18
y = (-18)/(9)
y = - 2
The y -intercept is (0, - 2)
Using Postulates and/or Theorems learned in Unit 1, determine whether ABC~AXY.
Show all your work and explain why the triangles are similar or why they are not.
Explanation:
AB = AX+XB = 8+22 = 30
The ratio of AB to AX is AB/AX = 30/8 = 3.75
AC = AY+YC = 9+33 = 42
The ratio of AC to AY is AC/AY = 42/9 = 4.67 approximately
Since we don't get the same result, this means that the equation AB/AX = AC/AY is not true. The sides are not in proportion with one another, and therefore the triangles aren't similar.
The sides need to be in proportion with one another so we could use the SAS similarity rule.
Considering the SAS similarity theorem, triangles ABC and AXY are not similar triangles.
What is the SAS Similarity Theorem?The SAS Similarity postulate or theorem, states that, when two triangles have two pairs of corresponding sides whose ratios are the same, and also has a pair congruent included angles, then, both triangles are similar.
Triangles ABC and AXY have a pair of congruent included angles, ∠BAC ≅ XAY.
Let's find out if their corresponding sides have equal ratios.
Thus:
AB/AX = 30/8 = 3.75
AC/AY = 42/9 = 4.67
Their ratios are not equal.
Therefore, considering the SAS similarity theorem, triangles ABC and AXY are not similar triangles.
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What is the length of the hypotenuse of the right triangle shown below? Type your answer as an integer. A right triangle has two sides of length 3 and 4.
Answer:
5
Step-by-step explanation:
This is the Pythagorean theorem:
[tex]a^{2} +b^{2} =c^{2}[/tex]
The hypotenuse is c so we need to make c the subject:
[tex]c = \sqrt{a^{2}+b^{2} }[/tex]
To do this I simply square rooted both sides.
Now we substitute values given to get the answer of the hypotenuse:
[tex]c = \sqrt{3^{2} + 4^{2} }[/tex]
[tex]c = \sqrt{9+16}[/tex]
[tex]c = \sqrt{25}[/tex]
c=5
The lengths 3,4,5 of a triangle are known as a Pythagorean triple.
A Pythagorean triple consists of three positive integers a, b, and c, such that a² + b² = c².
Martha simplified the expression ———-, putting it into the form ———-. what is the value of a - b?
The expression is in the photo.
A. 2
B. 4
C. 5
d. 7
Check whether this is a quadratic equation or not ...
=>>>>> x²-2x = (-2)(3-x)
Answer:
yup it is ...
x²-2x = -6+2x
=> x²-4x +6
By expanding the equation, we can see that it is quadratic.
Is the equation quadratic?
A quadratic equation is any polynomial of degree 2.
Here we have:
x^2 - 2x = (-2)*(3 - x)
Expanding this we get:
x^2 - 2x = -6 + 2x
Moving all to the same side:
x^2 - 2x - 2x + 6 = 0
x^2 - 4x + 6 = 0
This is a polynomial of degree 2, so this is a quadratic equation.
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