i need help!!!! does anyone know this..!!???

I Need Help!!!! Does Anyone Know This..!!???

Answers

Answer 1

The period of oscillation is 3 seconds

What is period of oscillation?

A Oscillation is the periodic change of a measure around a central value or between two or more states, usually in time.

The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle. It is measured in seconds

Oscillation can also be vibration or revolution or cycle.

Therefore, using the graph to determine the period. Then the wave particle made a complete oscillation at 3 second.

This means that the period of the particle is 3 seconds.

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Related Questions

determine the surface area and volume

Answers

The surface area and the volume of the rectangular prism are 280 and 300

How to determine the surface area and volume

From the question, we have the following parameters that can be used in our computation:

The rectangular prism

The surface area is caculated as

Surface area = 2 * (10 * 5 + 10 * 6 + 5 * 6)

Evaluate

Surface area = 280

For the volume, we have

Volume = 10 * 5 * 6

Evaluate

Volume = 300

Hence, the surface area and the volume are 280 and 300

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How do you find the circumference of a circle with a diameter of 6 inches. Use 3.14 as estimate of tt that's correct to two decimal places

Answers

Answer: 18.84

Step-by-step explanation : To find the circumference you use the formula:

2πr

Since we have the diameter (6), divide by 2 to find the radius, or r.

So (2)(3.14)(3)

Find the measure of the indicated angle.
20°
161°
61°
73°
H
G
F
73 ° E
195 °

Answers

Answer:

  (c)  61°

Step-by-step explanation:

You want the measure of the external angle formed by a tangent and secant that intercept arcs of 73° and 195° of a circle.

External angle

The measure of the angle at F is half the difference of intercepted arcs HE and EG.

  (195° -73°)/2 = 122°/2 = 61°

The measure of angle F is 61°.

<95141404393>

pls help !!!!!! geometry

Answers

Picture is too blurry to look at graph retake and I will give you answers

CAPM Elements
Value
Risk-free rate (rRF
)
Market risk premium (RPM
)
Happy Corp. stock’s beta
Required rate of return on Happy Corp. stock
An analyst believes that inflation is going to increase by 2.0% over the next year, while the market risk premium will be unchanged. The analyst uses the Capital Asset Pricing Model (CAPM). The following graph plots the current SML.
Calculate Happy Corp.’s new required return. Then, on the graph, use the green points (rectangle symbols) to plot the new SML suggested by this analyst’s prediction.
Happy Corp.’s new required rate of return is .

Answers

The new required rate of return for Happy Corp. can be calculated using the Capital Asset Pricing Model (CAPM). The formula for CAPM is:

Required rate of return = Risk-free rate + Beta * Market risk premium

Since the analyst believes that the market risk premium will be unchanged, the only factor that will affect the new required return is the risk-free rate.

Given that the analyst predicts a 2.0% increase in inflation, the risk-free rate will also increase by that amount. Therefore, the new required rate of return for Happy Corp. will be the current risk-free rate plus the product of Happy Corp.'s beta and the market risk premium.

To plot the new Security Market Line (SML) on the graph, we would use the new required return calculated above and plot it against the corresponding beta values. The SML represents the relationship between risk (beta) and return (required rate of return).

By incorporating the new required return, we can determine the new expected returns for various levels of beta and create the updated SML.

It is important to note that without specific values provided for the risk-free rate, market risk premium, and Happy Corp.'s beta, it is not possible to calculate the exact new required return or plot the new SML accurately.

These values are crucial in determining the precise position of the SML on the graph.

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How much fencing is required to enclose a circular garden whose radius is 21 m

Answers

Answer:182.12 meters of fencing required.

Step-by-step explanation:

(−x² − 1) ÷ (x + 1)
Help

Answers

The simplified form of the expression (-X2-1) ÷ (x + 1) is -x - 1 - 2/(x+1).

Which function is graphed ?

Answers

This fraction is really hard I believe in my thoughts and I’m smart so it’s the second one

The first three steps in determining the solution set of
the system of equations algebraically are shown.
y=x²-x-3
y=-3x + 5
Step
1
2
3
Equation
x²-x-3=-3x+5
0=x²+
+2x-8
0=(x-2)(x+4)
What are the solutions of this system of equations?
O (-2,-1) and (4, 17)
O (-2, 11) and (4, -7)
O (2, -1) and (-4, 17)
(2, 11) and (-4,-7)

Answers

The solutions of the system of equations are (2, -1) and (-4, 17)

The given system of equations is:

y = x² - x - 3

y = -3x + 5

To find the solutions, we need to solve these equations simultaneously.

Set the equations equal to each other:

x² - x - 3 = -3x + 5

Simplify and rewrite the equation in standard form:

x² - x + 3x - 3 - 5 = 0

x² + 2x - 8 = 0

Factor the quadratic equation:

(x - 2)(x + 4) = 0

Now we can solve for x by setting each factor equal to zero:

x - 2 = 0 or x + 4 = 0

Solving for x, we get:

x = 2 or x = -4

To find the corresponding y-values, we substitute these x-values into either of the original equations. Let's use equation 1):

For x = 2:

y = (2)² - 2 - 3 = 4 - 2 - 3 = -1

For x = -4:

y = (-4)² - (-4) - 3 = 16 + 4 - 3 = 17

As a result, the system of equations has two solutions: (2, -1) and (-4, 17).

The right responses are therefore (2, -1) and (-4, 17).

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Find the local and absolute maximum and minimum points in (x, y) format for the

function f(x) = 3/5x^5 - 9x^3 + 2 on the closed interval [-4,5]. Answer the following

questions.

a) Find all critical numbers (x- coordinates only)

b) Find the intervals on which the graph is increasing Mark critical numbers

Answers

To find the critical numbers of the function f(x) = (3/5)x^5 - 9x^3 + 2, we need to find the values of x where the derivative of the function is either zero or undefined. Let's calculate the derivative first:

f'(x) = 15/5x^4 - 27x^2 = 3x^4 - 27x^2

a) To find the critical numbers (x-coordinates), we need to solve the equation 3x^4 - 27x^2 = 0 for x:

3x^2(x^2 - 9) = 0

This equation factors as 3x^2(x + 3)(x - 3) = 0. Setting each factor to zero gives us three critical numbers: x = 0, x = -3, and x = 3.

b) To find the intervals on which the graph is increasing or decreasing, we can use the critical numbers and test points within each interval. However, since the interval is already specified as [-4, 5], we can determine the intervals based on the critical numbers and endpoints.

The critical numbers divide the interval [-4, 5] into four smaller intervals: [-4, -3], [-3, 0], [0, 3], and [3, 5].

We can determine if the function is increasing or decreasing within each interval by evaluating the derivative (f'(x)) at a test point in each interval:

For the interval [-4, -3], let's evaluate f'(-4) = 3(-4)^4 - 27(-4)^2 = 768, which is positive. Therefore, the function is increasing in this interval.

For the interval [-3, 0], let's evaluate f'(-3) = 3(-3)^4 - 27(-3)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(-2) = 3(-2)^4 - 27(-2)^2 = -96, which is negative. Therefore, the function is decreasing in this interval.

For the interval [0, 3], let's evaluate f'(0) = 3(0)^4 - 27(0)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(1) = 3(1)^4 - 27(1)^2 = -24, which is negative. Therefore, the function is decreasing in this interval.

For the interval [3, 5], let's evaluate f'(3) = 3(3)^4 - 27(3)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(4) = 3(4)^4 - 27(4)^2 = 768, which is positive. Therefore, the function is increasing in this interval.

Based on these calculations, the intervals on which the graph of the function f(x) = (3/5)x^5 - 9x^3 + 2 is increasing are [-4, -3] and [3, 5]. The intervals on which the graph is decreasing are [-3, 0] and [0, 3].

Please note that this analysis gives us information about the increasing and decreasing behavior of the function, but it doesn't provide specific local or absolute maximum and minimum points.

Select the correct answer. Which fraction converts to a terminating decimal number? A. 1\6 B. 2\9 C. 3\8 D. 4\7

Answers

The fraction that converts to a terminating decimal number is C. 3/8.

To determine which fraction converts to a terminating decimal number, we need to analyze the denominator of each fraction. A fraction will result in a terminating decimal if its denominator has only prime factors of 2 and/or 5.

Let's examine each option:

A. 1/6: The denominator is 6, which can be factored into 2 * 3. Since 3 is not a factor of 2 or 5, this fraction does not convert to a terminating decimal.

B. 2/9: The denominator is 9, which can be factored into 3 * 3. Since 3 is not a factor of 2 or 5, this fraction does not convert to a terminating decimal.

C. 3/8: The denominator is 8, which can be factored into 2 * 2 * 2. Since all the factors are 2, this fraction does convert to a terminating decimal.

D. 4/7: The denominator is 7, which cannot be factored into 2 or 5. Therefore, this fraction does not convert to a terminating decimal.

Based on our analysis, the fraction that converts to a terminating decimal number is C. 3/8.

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Determine the percentile of 6.2 using the following data set.
4.2 4.6 5.1 6.2 6.3 6.6 6.7 6.8 7.1 7.2
Your answer should be an exact numerical value.
The percentile of 6.2 is |
%.

Answers

The percentile of 6.2 in the given data set is 40%.

To determine the percentile of 6.2 in the given data set, we can use the following steps:

Arrange the data set in ascending order:

4.2, 4.6, 5.1, 6.2, 6.3, 6.6, 6.7, 6.8, 7.1, 7.2

Count the number of data points that are less than or equal to 6.2. In this case, there are 4 data points that satisfy this condition: 4.2, 4.6, 5.1, and 6.2.

Calculate the percentile using the formula:

Percentile = (Number of data points less than or equal to the given value / Total number of data points) × 100

In this case, the percentile of 6.2 can be calculated as:

Percentile = (4 / 10) × 100 = 40%

The percentile of 6.2 in the sample data set is therefore 40%.

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recursive formula for an=1/8(2)n-1

Answers

Answer:

The recursive formula for an=1/8(2)n-1 is:

a1=1/8 an+1=1/8(2)(n)

This formula defines a sequence where each term is equal to 1/8 of the previous term multiplied by 2.

Step-by-step explanation:

(-14)+x=14[/tex] what is the answer

Answers

The equation (-14) + x = 14 is solved by adding 14 to both sides of the equation, resulting in x = 28. This means that 28 is the value of x that satisfies the equation and makes it true.

To solve the equation (-14) + x = 14, we need to isolate the variable x on one side of the equation. Let's go through the steps:

Step 1: Add 14 to both sides of the equation to eliminate the -14 on the left side.

(-14) + x + 14 = 14 + 14

x = 28

The solution to the equation (-14) + x = 14 is x = 28.

In this equation, we start with (-14) on the left side, and we want to determine the value of x that makes the equation true. To do that, we need to isolate x. By adding 14 to both sides of the equation, we cancel out the -14 on the left side, leaving us with just x. On the right side, 14 + 14 simplifies to 28.

Therefore, the solution to the equation is x = 28. This means that if we substitute 28 for x in the original equation, (-14) + 28 will indeed equal 14. Let's verify this:

(-14) + 28 = 14

14 = 14

The left side of the equation simplifies to 14, and the right side is also 14. Since both sides are equal, it confirms that x = 28 is the correct solution to the equation.

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Data was collected on the amount of time that a random sample of 8 students spent studying for a test and the grades they earned on the test. A scatter plot and line of fit were created for the data.

scatter plot titled students' data, with x-axis labeled study time in hours and y-axis labeled grade percent. Points are plotted at 1 comma 50, 2 comma 50, 2 comma 60, 2 comma 70, 3 comma 70, 3 comma 80, 4 comma 85, and 4 comma 90, and a line of fit drawn passing through the points 0 comma 30 and 2 comma 60

Determine the equation of the line of fit.

y = 15x + 60
y = 15x + 30
y = 30x + 60
y = 30x + 30

Answers

The equation of the line of fit is y = 15x + 30.

To determine the equation of the line of fit, we can use the given data points (0,30) and (2,60). We can use the slope-intercept form of a linear equation, which is y = mx + b, where m represents the slope and b represents the y-intercept.

Using the two data points, we can calculate the slope (m) as the change in y divided by the change in x:

m = (60 - 30) / (2 - 0) = 30 / 2 = 15

Now that we have the slope, we can substitute one of the data points into the equation to solve for the y-intercept (b). Let's use the point (0,30):

30 = 15(0) + b

30 = 0 + b

b = 30

Therefore, the equation of the line of fit is y = 15x + 30. This means that for every additional hour of study time (x), the grade percent (y) increases by 15, and the line intersects the y-axis at 30.

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Reynold’s company has a product with fixed costs of $334,000, a unit selling price of $22, and unit variable costs of $19. The break-even sales (units) if the variable costs are decreased by $4 is

Answers

The break-even sales (units) when the variable costs are decreased by $4 is approximately 47,714 units.

To find the break-even sales (units) when the variable costs are decreased by $4, we need to calculate the new unit variable costs and then use the break-even formula.

Fixed costs (F) = $334,000

Unit selling price (P) = $22

Unit variable costs (V) = $19

Change in unit variable costs = $4

New unit variable costs (V') = V - Change in unit variable costs

= $19 - $4

= $15

Now, let's calculate the break-even sales (units) using the formula:

Break-even sales (units) = Fixed costs / (Unit selling price - Unit variable costs)

Break-even sales (units) = $334,000 / ($22 - $15)

= $334,000 / $7

= 47,714.29

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What is the radius of a circle that has a circumference of 68 cm

Answers

Step-by-step explanation:

The formula to calculate the circumference (C) of a circle is C = 2πr, where r represents the radius of the circle.

In this case, the given circumference is 68 cm. Plugging this value into the formula, we can solve for the radius (r):

68 = 2πr

To find the radius, we can divide both sides of the equation by 2π:

r = 68 / (2π)

Using an approximate value of π ≈ 3.14159, we can calculate the radius:

r ≈ 68 / (2 × 3.14159) ≈ 10.8419 cm

Therefore, the radius of the circle, which has a circumference of 68 cm, is approximately 10.8419 cm.

GiveN:-Circumference of Circle = 68 cmTo finD:-Radius of Circle = ??SolutioN:- Circumference = 2 π r 68 = 2 π r 68 = 2 × (22/7) × r 68 = (2 × 22/7) × r 68 = (44/7) × r (44/7) × r = 68 44 × r = 68 × 7 44 × r = 476 r = 476/44➝ r = 10.8 cm

Therefore, The Radius of the Circle is 10.8 cm.

A sixth-grade class recorded the number of letters in each student's first name.

The results are shown in the dot plot.


A dot plot titled lengths of student names show the number of students with a certain number of letters in their name. The data is as follows. 1 dot above 3, 2 dots above 4, 4 dots above 5, 7 dots above 6 and 7, 3 dots above 8, 1 dot above 9, 2 dots above 10, and 3 dots above 11.


Which is the best representation of the center of this data set?

A. 8

B. 5

C. 7

D. 6

Answers

A dot plot title lengbof student

9497 ÷ 16 _R_ please

Answers

When you divide 9497 by 16, the quotient is 593 with a remainder of 9.

So, 9497 ÷ 16 = 593 remainder 9. Month

Given cos=
a.
b.
sin 8
4
and csc <0, find sine and tan
9
-4
9
A
B
tan =
csc0= 4√√9, tane=
9
4
65
9
C.
d.
sin = 4, tan 9 =
sin =
Please select the best answer from the choices provided
65
19
-4√65
9
tan 9 =

Answers

The best answer that matches the calculated values is C. sin θ = -1/3, tan θ = -3/(2√2)

Let's break down the given values and find the values of sine and tangent.

We are given:

cos θ = √(8/9)

csc θ < 0

Using the Pythagorean identity, sin^2θ + cos^2θ = 1, we can find the value of sin θ.

sin^2θ + (√(8/9))^2 = 1

sin^2θ + 8/9 = 1

sin^2θ = 1 - 8/9

sin^2θ = 1/9

Taking the square root of both sides, we get:

sin θ = ±1/3

Since csc θ is negative (csc θ < 0), we can conclude that sin θ is negative. Therefore, sin θ = -1/3.

Next, let's find the value of tan θ.

tan θ = sin θ / cos θ

tan θ = (-1/3) / (√(8/9))

tan θ = -√9/√8

tan θ = -√9/√(4*2)

tan θ = -√9/(2√2)

tan θ = -3/(2√2)

So, the values are:

sin θ = -1/3

tan θ = -3/(2√2)

The best selection from the available options that matches the calculated values is:

C. sin θ = -1/3, tan θ = -3/(2√2)

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(08.01 MC)
The function h(x) is a continuous quadratic function with a domain of all real numbers. The table
x h(x)
-6 12
-57
-4 4
-3 3
-24
-1 7
What are the vertex and range of h(x)?

Answers

The vertex of h(x) is (-3, 3), and the range is y ≥ 3.

To find the vertex of the quadratic function h(x), we can use the formula x = -b/2a, where the quadratic function is in the form [tex]ax^2 + bx + c[/tex].

From the given table, we can observe that the x-values of the vertex correspond to the minimum points of the function.

The minimum point occurs between -4 and -3, which suggests that the x-coordinate of the vertex is -3. Therefore, x = -3.

To find the corresponding y-coordinate of the vertex, we look at the corresponding h(x) value in the table, which is 3. Hence, the vertex of the function h(x) is (-3, 3).

To determine the range of h(x), we need to consider the y-values attained by the function.

From the table, we see that the lowest y-value is 3 (the y-coordinate of the vertex), and there are no other y-values lower than 3. Therefore, the range of h(x) is all real numbers greater than or equal to 3.

The vertex of h(x) is (-3, 3), and the range is y ≥ 3.

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The vertex of the quadratic function is (-4, 12).

The range of h(x) is [3, ∞).

To find the vertex and range of the quadratic function h(x) based on the given table, we can use the properties of quadratic functions.

The vertex of a quadratic function in the form of f(x) = ax² + bx + c can be determined using the formula:

x = -b / (2a)

The domain of h(x) is all real numbers, we can assume that the quadratic function is of the form h(x) = ax² + bx + c.

Looking at the table, we can see that the x-values are increasing from left to right.

Additionally, the y-values (h(x)) are increasing from -6 to -4, then decreasing from -4 to -1.

This indicates that the vertex of the quadratic function lies between x = -4 and x = -3.

To find the exact x-coordinate of the vertex, we can use the formula mentioned earlier:

x = -b / (2a)

Based on the table, we can choose two points (-4, 4) and (-3, 3).

The difference in x-coordinates is 1, so we can assume that a = 1.

Plugging in the values of (-4, 4) and a = 1 into the formula, we can solve for b:

-4 = -b / (2 × 1)

-4 = -b / 2

-8 = -b

b = 8

The equation of the quadratic function h(x) can be written as h(x) = x² + 8x + c.

Now, let's find the y-coordinate of the vertex.

We can substitute the x-coordinate of the vertex, which we found as -4, into the equation:

h(-4) = (-4)² + 8(-4) + c

12 = 16 - 32 + c

12 = -16 + c

c = 28

The equation of the quadratic function h(x) is h(x) = x² + 8x + 28.

The range of the quadratic function can be determined by observing the y-values in the table.

From the table, we can see that the minimum y-value is 3.

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A bacteria culture triples every 5 minutes. At 4:27 P.M. the population is . Determine what the population was 27 minutes earlier, at 4:00 P.M.

Answers

The population at 4:00 P.M., 27 minutes earlier, is[tex]3^3[/tex] times the initial population P.

To determine the population of a bacteria culture 27 minutes earlier, we need to calculate the population growth from 4:00 P.M. to 4:27 P.M. given that the bacteria culture triples every 5 minutes.

Let's break down the time period into intervals of 5 minutes:

From 4:00 P.M. to 4:05 P.M., the population triples once.

From 4:05 P.M. to 4:10 P.M., the population triples again.

From 4:10 P.M. to 4:15 P.M., the population triples for the third time.

From 4:15 P.M. to 4:20 P.M., the population triples for the fourth time.

From 4:20 P.M. to 4:25 P.M., the population triples for the fifth time.

From 4:25 P.M. to 4:27 P.M., the population undergoes partial growth.

Since the population triples every 5 minutes, we can express the population at 4:27 P.M. as 3^5 times the initial population at 4:00 P.M.

Let's denote the initial population at 4:00 P.M. as P. Then, the population at 4:27 P.M. is [tex]3^5[/tex] * P.

To find the population 27 minutes earlier, we need to reverse the growth from 4:27 P.M. to 4:00 P.M. Since the population triples every 5 minutes, we need to divide the population at 4:27 P.M. by [tex]3^{(27/5).[/tex]

Therefore, the population at 4:00 P.M., 27 minutes earlier, can be calculated as:

Population at 4:00 P.M. = (Population at 4:27 P.M.) / [tex]3^{(27/5)[/tex]

[tex]= (3^{5} * P) / 3^{(27/5)\\\\\\\\= 3^{(25/5)} * P\\= 3^5 * P / 3^2\\= 3^3 * P[/tex]

Hence, the population at 4:00 P.M., 27 minutes earlier, is 3^3 times the initial population P.

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The graph of line I is shown below. Which of the following represents the slope of a line parallel to line P

Answers

Answer:

C) -1/3

Step-by-step explanation:

Slope=rise/run

Slope=-1/3

NO LINKS!! URGENT HELP PLEASE!!

Answers

Answer:

a. 5π cm

b. 144π in²

c. 6 ft

Step-by-step explanation:

a.

The circumference of a circle is given by:

Circumference pf circle= πd

where d is the diameter.

In this case, d = 5 cm,

Therefore, Circumference of circle = π*5=5π cm

b.

The area of a circle is given by:
Area of circle=πr²,

where r is the radius. In this case, the diameter is d = 24 in,

so, the radius is r = d/2 = 24/2=12in

Therefore, Area of circle=π*12²=144π in²

c.

The area of a circle is given by:

Area of circle=πr²,

where r is the radius. In this case, Area is 36π ft²

Now substituting value

36π=πr²

dividing both side by π, we get

36=r²

[tex]r=\sqrt{36}=6[/tex]

r=6 ft.

Therefore, Radius is 6 ft.

a) Write a linear system to model the situation:
For the school play, the cost of one adult ticket is $6 and the cost of one student ticket is $4. Twice as many student tickets as adult tickets were sold. The total receipts were $2016.

b) Use substitution to solve the related problem:
How many of each type of ticket were sold?​

Answers

Answer:

There were 126 student tickets sold and 252 adult ticket sold.

Step-by-step explanation:

Let x be the number of adult tickets sold

y be the number of students tickets sold

Twice as many student tickets as adult tickets were sold

a.

x = 2y  ---equation 1

6x + 4y = 2016   ---equation 2

b.

Substitute equation 1 to equation 2

6(2y) + 4y = 2016

12y + 4y = 2016

16y = 2016

Divide both sides of the equation by 16

16y/16 = 2016/16

y = 126

Substitute y = 126 to equation 1

x = 2y

x = 2(126)

x = 252

PLS HELP ACTUAL ANSWERS

A random survey was conducted to gather information about age and employment status. The table shows the data collected.
0-17 years old 18+ years old Total
607
Has a Job
Does Not Have a Job


Total
A
B
C
240
679
What is the probability that a randomly selected student does NOT have a job, given that they are 18+ years old?
97
337
97
679
240
240
265
97
679
337
P
look at photo for reference

Answers

Answer: 337

Step-by-step explanation: it is 337 because if you subtract it all you get that

Please answer ASAP I will brainlist

Answers

Answer:

x = - 2 , x = 4

Step-by-step explanation:

the x- intercepts are the points on the x- axis where the graph crosses

the graph crosses the x - axis at - 2 and 4 , then

x- intercepts are x = - 2 , x = 4

what is the midpoint of 70 and 90

Answers

Answer:

80

Step-by-step explanation:

Just average the two numbers to get (70+90)/2 = 160/2 = 80

Answer:

Step-by-step explanation:

To find the midpoint between two numbers, you add them together and divide the sum by 2.

In this case, the midpoint between 70 and 90 would be:

(70 + 90) / 2 = 160 / 2 = 80.

Therefore, the midpoint between 70 and 90 is 80.

Pls help I’m stuck Tysm I can’t thank any more

Answers

Using the concept of perimeter of polygon, the perimeter of figure C is 27cm shorter than total perimeter of A and B

How much shorter is the perimeter of C than the total perimeter of A and B?

To solve this problem, we have to know the perimeter of the polygon C.

The perimeter of a polygon is the sum of all the lengths of the outer edges of the figure, that is, we must find the length of all the edges of the polygon, and then add these lengths to obtain the perimeter.

The perimeter of the figures are;

Using the concept of perimeter of a rectangle;

a. figure A = 2(4 + 11) = 30cm

b. figure B = 2(8 + 4) = 24cm

c figure C = 11 + 4 + 8 + 4 = 27cm

Now, we can add A and B and then subtract c from it.

30 + 24 - 27 = 27cm

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Find the indefinite integral. (Use C for the constant of integration.)
1. v + 1/
(2v − 20)^5dv

2. x^2/
x − 5 dx

3. x cos 8x2 dx
4. 176/e^−x + 1 dx
5.

Answers

1. The indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.

2. The indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.

3. The indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.

4. The indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.

1. To find the indefinite integral of (v + 1) / (2v - 20)^5 dv:

Let u = 2v - 20. Then du = 2 dv.

The integral becomes:

(1/2) ∫ (1/u^5) du

Now we can integrate using the power rule:

(1/2) ∫ u^(-5) du

Applying the power rule, we get:

(1/2) * (u^(-4) / -4) + C

= -1 / (8u^4) + C

Substituting back u = 2v - 20:

= -1 / (8(2v - 20)^4) + C

Therefore, the indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.

2. To find the indefinite integral of x^2 / (x - 5) dx:

We can use polynomial long division to simplify the integrand:

x^2 / (x - 5) = x + 5 + 25 / (x - 5)

Now we can integrate each term separately:

∫ x dx + ∫ (5 dx) + ∫ (25 / (x - 5) dx)

Using the power rule, we get:

(1/2) x^2 + 5x + 25 ln|x - 5| + C

Therefore, the indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.

3. To find the indefinite integral of x cos(8x^2) dx:

We can use the substitution method. Let u = 8x^2, then du = 16x dx.

The integral becomes:

(1/16) ∫ cos(u) du

Integrating cos(u), we get:

(1/16) sin(u) + C

Substituting back u = 8x^2:

(1/16) sin(8x^2) + C

Therefore, the indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.

4. To find the indefinite integral of 176 / e^(-x) + 1 dx:

We can simplify the integrand by multiplying the numerator and denominator by e^x:

176 / e^(-x) + 1 = 176e^x / 1 + e^x

Now we can integrate:

∫ (176e^x / 1 + e^x) dx

Using u-substitution, let u = 1 + e^x, then du = e^x dx:

∫ (176 du / u)

Integrating 176/u, we get:

176 ln|u| + C

Substituting back u = 1 + e^x:

176 ln|1 + e^x| + C

Therefore, the indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.

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