I NEED ANSWER ASAPPPP

Answer:

324

Step-by-step explanation:

Answer:

Is this a points post or something? If so, thank you!

Answer:

D

Step-by-step explanation:

3:

12

4:

16

Therefore 13 is in between 12 and 16

Answer:

[tex]x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871[/tex]

Step-by-step explanation:

[tex]2x^2+4x-5=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-4\pm\sqrt{4^2-4(2)(-5)}}{2(2)}[/tex]

[tex]x=\frac{-4\pm\sqrt{16+40}}{4}[/tex]

[tex]x=\frac{-4\pm\sqrt{56}}{4}[/tex]

[tex]x=\frac{-4\pm2\sqrt{14}}{4}[/tex]

[tex]x=\frac{-2\pm\sqrt{14}}{2}[/tex]

[tex]x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871[/tex]

Answer:

Step-by-step explanation:

The scale factor is the ratio between the man's actual height and the height of the drawing.

Scale = 64/4 = 16

Answer:

1/16

Step-by-step explanation:

the actual man is 16 times bigger than drawing.

Answer:

Step-by-step explanation:

=> 3x + 9 = 2x + 5

=> 3x - 2x = 5 - 9

=> x = - 4

Hence, x has only one solution that is, x = -4 (Ans)

Topic : Linear equations in one variable

Given :

Solution :

[tex]\qquad \sf \: { \dashrightarrow 3x + 9 = 2x + 5}[/tex]

Transposing variables on one side and constant terms on the other side, we get :

[tex]\qquad \sf \: { \dashrightarrow 3x - 2x = 5 - 9}[/tex]

[tex]\qquad \sf \: { \dashrightarrow x = - 4}[/tex]

Answer:

36.19047619 million

or 36,190,476 students

Step-by-step explanation:

7.6 million / all students = 21% / 100%

7.6 * 100 / 21 = 36.19047619

36.19047619 million

or 36,190,476 students

Linear functions are used to represented straight lines.

The linear function is [tex]y = -\frac 12x + 1[/tex]

The points on the graph are: (2,0) and (0,1)

Start by calculating the slope (m) using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

Substitute values for x and y

[tex]m = \frac{1 - 0}{ 0 -2}[/tex]

[tex]m = \frac{1 }{ -2}[/tex]

Rewrite as:

[tex]m = -\frac{1 }{2}[/tex]

The equation is then calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

This gives

[tex]y = -\frac 12(x -0) + 1[/tex]

[tex]y = -\frac 12(x) + 1[/tex]

Open bracket

[tex]y = -\frac 12x + 1[/tex]

Hence, the linear function is [tex]y = -\frac 12x + 1[/tex]

Read more about linear functions at:

https://brainly.com/question/15602982

Answer an essay on nothing

Step-by-step explanation:

In philosophy there is a lot of emphasis on what exists. We call this ontology, which means, the study of being. What is less often examined is what does not exist.

It is understandable that we focus on what exists, as its effects are perhaps more visible. However, gaps or non-existence can also quite clearly have an impact on us in a number of ways. After all, death, often dreaded and feared, is merely the lack of existence in this world (unless you believe in ghosts). We are affected also by living people who are not there, objects that are not in our lives, and knowledge we never grasp.

Upon further contemplation, this seems quite odd and raises many questions. How can things that do not exist have such bearing upon our lives? Does nothing have a type of existence all of its own? And how do we start our inquiry into things we can’t interact with directly because they’re not there? When one opens a box, and exclaims “There is nothing inside it!”, is that different from a real emptiness or nothingness? Why is nothingness such a hard concept for philosophy to conceptualize?

Let us delve into our proposed box, and think inside it a little. When someone opens an empty box, they do not literally find it devoid of any sort of being at all, since there is still air, light, and possibly dust present. So the box is not truly empty. Rather, the word ‘empty’ here is used in conjunction with a prior assumption. Boxes were meant to hold things, not to just exist on their own. Inside they might have a present; an old family relic; a pizza; or maybe even another box. Since boxes have this purpose of containing things ascribed to them, there is always an expectation there will be something in a box. Therefore, this situation of nothingness arises from our expectations, or from our being accustomed. The same is true of statements such as “There is no one on this chair.” But if someone said, “There is no one on this blender”, they might get some odd looks. This is because a chair is understood as something that holds people, whereas a blender most likely not.

The same effect of expectation and corresponding absence arises with death. We do not often mourn people we only might have met; but we do mourn those we have known. This pain stems from expecting a presence and having none. Even people who have not experienced the presence of someone themselves can still feel their absence due to an expectation being confounded. Children who lose one or both of their parents early in life often feel that lack of being through the influence of the culturally usual idea of a family. Just as we have cultural notions about the box or chair, there is a standard idea of a nuclear family, containing two parents, and an absence can be noted even by those who have never known their parents.

This first type of nothingness I call ‘perceptive nothingness’. This nothingness is a negation of expectation: expecting something and being denied that expectation by reality. It is constructed by the individual human mind, frequently through comparison with a socially constructed concept.

Pure nothingness, on the other hand, does not contain anything at all: no air, no light, no dust. We cannot experience it with our senses, but we can conceive it with the mind. Possibly, this sort of absolute nothing might have existed before our universe sprang into being. Or can something not arise from nothing? In which case, pure nothing can never have existed.

If we can for a moment talk in terms of a place devoid of all being, this would contain nothing in its pure form. But that raises the question, Can a space contain nothing; or, if there is space, is that not a form of existence in itself?

This question brings to mind what’s so baffling about nothing: it cannot exist. If nothing existed, it would be something. So nothing, by definition, is not able to ‘be’.

Is absolute nothing possible, then? Perhaps not. Perhaps for example we need something to define nothing; and if there is something, then there is not absolutely nothing. What’s more, if there were truly nothing, it would be impossible to define it. The world would not be conscious of this nothingness. Only because there is a world filled with Being can we imagine a dull and empty one. Nothingness arises from Somethingness, then: without being to compare it to, nothingness has no existence. Once again, pure nothingness has shown itself to be negation.

Step-by-step explanation:

(7,9)and (5,8)

x1,y1 x,y

now

x=(x1 + x2)divide by 2

now putting the value

5 = (7+ x2) by 2

2 is in divide then get the 2 in right side with 5 in muntiply form

5×2=7+x2

10=7+x2

10 - 7=x2

x2=3

using the same process do it

y=(y1+y2) by 2

Answer:

Is there supposed to be a picture or no?

Step-by-step explanation:

Step-by-step explanation:

Total change in number of student = (210 - 168)

=> 42

% change = Change/Original no. of students × 100

=> 42/210 × 100

=> 42/21 × 10

=> 20%

Compound probabilities that required AND use multiplication

The probability of compound events is of two types

As a general rule, the AND probability require products

Take for instance

P(A and B) = P(A) and P(B)

This gives

P(A and B) = P(A) *  P(B)

So, compound probabilities that required AND use multiplication

Read more about compound probabilities at:

https://brainly.com/question/1553768

#SPJ1

[tex](i)\\\\2A = \begin{pmatrix}3x \times 2 & 1 \times 2 & 5 \times 2\\0\times 2 & 2x \times 2 & -3 \times 2\end{pmatrix} = \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix}\\\\\\(ii)\\\\2A + B = C\\\\\implies \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix} + \begin{pmatrix}y & 0 & -4\\1 & -3y & 2\end{pmatrix} = \begin{pmatrix}31& 2 & 6\\1 & 17& -4\end{pmatrix}[/tex]

[tex]\implies \begin{pmatrix}6x+y & 2+0 & 10-4\\0+1 & 4x-3y & -6+2\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\\\implies \begin{pmatrix}6x+y & 2 & 6\\1 & 4x-3y & -4\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\text{System of equations},\\\\6x +y =31,~~ 4x -3y = 17\\\\\\(iii)\\\\6x +y-31 =0 \\\\4x-3y -17=0\\\\\text{Solving by cross multiplication method}\\\\\\\dfrac x{1(-17) - (-31)(-3)} = \dfrac y{4(-31) - 6(-17)} = \dfrac 1{6(-3) - 4(1)}[/tex]

[tex]\implies \dfrac{x}{-17 -93} = \dfrac{y}{-124 +102} = \dfrac 1{-18-4}\\\\\\\implies -\dfrac{x}{110} = -\dfrac{y}{22} = -\dfrac 1{22}\\\\ \implies \dfrac{x}{110} = \dfrac{y}{22} = \dfrac 1{22}\\\ \\\text{Hence,}\\\\\\x=\dfrac{110}{22}=5,~~~~ y= \dfrac{22}{22} =1[/tex]

Answer:

  (i)

  [tex]2A=\left[\begin{array}{ccc}6x&2&10\\0&4x&-6\end{array}\right][/tex]

  (ii) 6x+y=31; 4x-3y=17

  (iii) (x, y) = (5, 1)

Step-by-step explanation:

The matrix 2A is written by multiplying each element of A by 2.

  [tex]2A=\left[\begin{array}{ccc}6x&2&10\\0&4x&-6\end{array}\right][/tex]

__

Variables are seen in elements (1, 1) and (2, 2) of the matrices A and B, so the simultaneous equations can be chosen from those elements of the equation 2A+B=C.

__

A graphing calculator shows the solution to be (x, y) = (5, 1).

Answer:

c

Step-by-step explanation:

when we add 0 to x ,it remains x.

x+0=x

0 is additive identity.

Answer:

C

Step-by-step explanation:

Answer:

x = 0 , x = 3

Step-by-step explanation:

Equate the 2 expressions and solve for x

3x² - 2x + 1 = 7x + 1 ( subtract 7x + 1 from both sides )

3x² - 9x = 0 ← factor out 3x from each term

3x(x - 3) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 3 = 0 ⇒ x = 3

Answer:

Step-by-step explanation:

[tex] {x}^{o} + {75}^{o} + {97}^{o} + {105}^{o} = {360}^{o} \\ {x}^{o} + {277}^{o} = {360}^{o} \\ {x}^{o} = {360}^{o} - {277}^{o} \\ {x}^{o} = {83}^{o} \\ [/tex]

Answer:

Answer:

28+66+86=180

180=180

Step-by-step explanation:

Since there is a triangle and the 3 measures from the angles we can find the value of x using the hint given that the sum of the interior angles must be 180°

Write the equation

\begin{gathered}x+(2x+10)+(3x+2)=180\\\end{gathered}

x+(2x+10)+(3x+2)=180

Simplify left side of the equation

\begin{gathered}6x+12=180\\\end{gathered}

6x+12=180

Solve equation for x

\begin{gathered}6x=180-12\\6x=168\\x=28\end{gathered}

6x=180−12

6x=168

x=28

Replace x into the 3 angles and find their respectives values

\begin{gathered}A=x\\A=28\\\\B=2x+10\\B=2*28+10\\B=56+10\\B=66\\\\C=3x+2\\C=84+2\\C=86\end{gathered}

A=x

A=28

B=2x+10

B=2∗28+10

B=56+10

B=66

C=3x+2

C=84+2

C=86

Check if the answers are correct

\begin{gathered}28+66+86=180\\180=180\end{gathered}

28+66+86=180

180=180

PLEASE MARK ME AS BRAINLIEST

Answer:

38.29 i think

Step-by-step explanation:

Answer:

1. y=3/5x +1

2. x = -3

3. y = 4

4. y = -1/3x + 4

5. y=5x + 4

6. y= 3/4 x + 1

7. y = 9/4x - 1/2

8. y = 5/3x

9. y = -5x +5

10. y = 2x - 5

11. y = -4x - 4

12. y = 1/4x - 4

Step-by-step explanation:

math lol

Answer:

10

Step-by-step explanation:

Equation=5*2^3/2^2

Answer:

x=1 x=-11

Step-by-step explanation:

first you need to find what two numbers add together to make 10x and multiply together to make 25-

this would be 5

so we can rewrite it as (x+5)(x+5) = 36

which is the same thing as (x+5)^2 =36

then taking the root of both sides we get (x+5)= plus or minus 6

so x=-11 or x equals 1

By the fundamental theorem of calculus,

[tex]\displaystyle F(x) = \int_0^x \cos(t^2) \, dt \implies F'(x) = \cos(x^2)[/tex]

and so F'(1) = cos(1).

Answer:

p = (-15)/14

Step-by-step explanation:

Solve for p:

5 + 1/28 = p/2 + 4/7 + 5

Put 5 + 1/28 over the common denominator 28. 5 + 1/28 = (28×5)/28 + 1/28:

((28×5)/28 + 1/28) = p/2 + 4/7 + 5

28×5 = 140:

140/28 + 1/28 = p/2 + 4/7 + 5

140/28 + 1/28 = (140 + 1)/28:

((140 + 1)/28) = p/2 + 4/7 + 5

140 + 1 = 141:

141/28 = p/2 + 4/7 + 5

Put each term in p/2 + 4/7 + 5 over the common denominator 14: p/2 + 4/7 + 5 = (7 p)/14 + 8/14 + 70/14:

141/28 = ((7 p)/14 + 8/14 + 70/14)

(7 p)/14 + 8/14 + 70/14 = (7 p + 8 + 70)/14:

141/28 = ((7 p + 8 + 70)/14)

Grouping like terms, 7 p + 8 + 70 = 7 p + (70 + 8):

141/28 = (7 p + (70 + 8))/14

70 + 8 = 78:

141/28 = (7 p + 78)/14

141/28 = (7 p + 78)/14 is equivalent to (7 p + 78)/14 = 141/28:

(7 p + 78)/14 = 141/28

Multiply both sides of (7 p + 78)/14 = 141/28 by 14:

(14 (7 p + 78))/14 = (14×141)/28

(14 (7 p + 78))/14 = 14/14×(7 p + 78) = 7 p + 78:

(7 p + 78) = (14×141)/28

14/28 = 14/(14×2) = 1/2:

7 p + 78 = 141/2

Subtract 78 from both sides:

7 p + (78 - 78) = 141/2 - 78

78 - 78 = 0:

7 p = 141/2 - 78

Put 141/2 - 78 over the common denominator 2. 141/2 - 78 = 141/2 + (2 (-78))/2:

7 p = (141/2 - (78×2)/2)

2 (-78) = -156:

7 p = 141/2 + (-156)/2

141/2 - 156/2 = (141 - 156)/2:

7 p = ((141 - 156)/2)

141 - 156 = -15:

7 p = (-15)/2

Divide both sides by 7:

p = ((-15)/7)/2

2×7 = 14:

Answer: p = (-15)/14

Answer:

C

Step-by-step explanation:

The probability of getting heads or tails is 50%.

300*50% = 150

Answer:

C. 150 times

Step-by-step explanation:

Because a coin only has tails and heads, you can say that the probability would be half. Because it was tossed 300 times, you can say: 300*0.5=150

Answer:

25h+12

Step-by-step explanation:

Combine Like Terms:

21h+−10h+16+−9+14h+5

(21h+−10h+14h)+(16+−9+5)

25h+12

Same thing, no difference.

Hope this helped! :)

True-... i think because like i am not sure-